How do I select this element using xpath?
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I'm having a problem selecting a "delete" button that has to be linked to a certain element.
So I have to click the "x" icon, but it has to be related to the text "teste"...
Here's the HTML code:
The button I have to click is the span whose class is "fa fa-times" and it has to be related to the div containing the text "teste" because there are other spans with the same class but they are hidden.
Thanks!
selenium xpath
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up vote
0
down vote
favorite
I'm having a problem selecting a "delete" button that has to be linked to a certain element.
So I have to click the "x" icon, but it has to be related to the text "teste"...
Here's the HTML code:
The button I have to click is the span whose class is "fa fa-times" and it has to be related to the div containing the text "teste" because there are other spans with the same class but they are hidden.
Thanks!
selenium xpath
2
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 at 18:54
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm having a problem selecting a "delete" button that has to be linked to a certain element.
So I have to click the "x" icon, but it has to be related to the text "teste"...
Here's the HTML code:
The button I have to click is the span whose class is "fa fa-times" and it has to be related to the div containing the text "teste" because there are other spans with the same class but they are hidden.
Thanks!
selenium xpath
I'm having a problem selecting a "delete" button that has to be linked to a certain element.
So I have to click the "x" icon, but it has to be related to the text "teste"...
Here's the HTML code:
The button I have to click is the span whose class is "fa fa-times" and it has to be related to the div containing the text "teste" because there are other spans with the same class but they are hidden.
Thanks!
selenium xpath
selenium xpath
edited Nov 21 at 19:54
Dev
1547
1547
asked Nov 21 at 18:49
Bruno Muramatsu
252
252
2
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 at 18:54
add a comment |
2
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 at 18:54
2
2
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 at 18:54
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 at 18:54
add a comment |
1 Answer
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Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
New contributor
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
New contributor
add a comment |
up vote
2
down vote
Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
New contributor
add a comment |
up vote
2
down vote
up vote
2
down vote
Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
New contributor
Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
New contributor
New contributor
answered Nov 21 at 19:14
JaSON
1526
1526
New contributor
New contributor
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its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 at 18:54