Difference flow dependence & anti dependence











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I'm trying to understand a paper concerning the detection of dependence for parallelizing tasks and I'm struggling a bit with an example. Considering A, B, C and D are vectors object:



    do I=2,N
S1: A(I) = B(I) + C(I)
S2: D(I) = A(I + 1) + 1
S3: C(I) = D(I)


Focusing on dependence between S1 and S2. To me, it is a flow dependence S1 -> S2, A is in OUT(S1) and IN(S2) and A is indeed used in S2, verifying the flow dependence definition given by Woolfe & Banerjee. However, the explication states that it is an antidependence S2 -> S1. Is it because we're inside a loop ? And in that case, does it mean that in a loop, any flow dependence is reverse antidependence and inversely ?










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    I'm trying to understand a paper concerning the detection of dependence for parallelizing tasks and I'm struggling a bit with an example. Considering A, B, C and D are vectors object:



        do I=2,N
    S1: A(I) = B(I) + C(I)
    S2: D(I) = A(I + 1) + 1
    S3: C(I) = D(I)


    Focusing on dependence between S1 and S2. To me, it is a flow dependence S1 -> S2, A is in OUT(S1) and IN(S2) and A is indeed used in S2, verifying the flow dependence definition given by Woolfe & Banerjee. However, the explication states that it is an antidependence S2 -> S1. Is it because we're inside a loop ? And in that case, does it mean that in a loop, any flow dependence is reverse antidependence and inversely ?










    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm trying to understand a paper concerning the detection of dependence for parallelizing tasks and I'm struggling a bit with an example. Considering A, B, C and D are vectors object:



          do I=2,N
      S1: A(I) = B(I) + C(I)
      S2: D(I) = A(I + 1) + 1
      S3: C(I) = D(I)


      Focusing on dependence between S1 and S2. To me, it is a flow dependence S1 -> S2, A is in OUT(S1) and IN(S2) and A is indeed used in S2, verifying the flow dependence definition given by Woolfe & Banerjee. However, the explication states that it is an antidependence S2 -> S1. Is it because we're inside a loop ? And in that case, does it mean that in a loop, any flow dependence is reverse antidependence and inversely ?










      share|improve this question















      I'm trying to understand a paper concerning the detection of dependence for parallelizing tasks and I'm struggling a bit with an example. Considering A, B, C and D are vectors object:



          do I=2,N
      S1: A(I) = B(I) + C(I)
      S2: D(I) = A(I + 1) + 1
      S3: C(I) = D(I)


      Focusing on dependence between S1 and S2. To me, it is a flow dependence S1 -> S2, A is in OUT(S1) and IN(S2) and A is indeed used in S2, verifying the flow dependence definition given by Woolfe & Banerjee. However, the explication states that it is an antidependence S2 -> S1. Is it because we're inside a loop ? And in that case, does it mean that in a loop, any flow dependence is reverse antidependence and inversely ?







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      edited 2 days ago

























      asked Nov 21 at 18:51









      Sam The Sid

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          Okay, finally it depends not of the object, but of the memory location being used. In this example, A(I) and A(I + 1) may not refer to the same memory (in case there is no aliasing). So there is no dependence between them in the current iteration. However, if we unroll the loop a bit, we get:



          do I=2,N
          S1: A(I) = B(I) + C(I)
          S2: D(I) = -> A(I + 1) + 1
          S3: C(I) = D(I)
          S1: -> A(I + 1) = B(I + 1) + C(I + 1)
          S2: D(I + 1) = A(I + 2) + 1
          S3: C(I + 1) = D(I + 1)


          Now, the anti dependence appears clearly.



          Seems obvious now..






          share|improve this answer





















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            1 Answer
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            active

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            oldest

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            active

            oldest

            votes








            up vote
            0
            down vote



            accepted










            Okay, finally it depends not of the object, but of the memory location being used. In this example, A(I) and A(I + 1) may not refer to the same memory (in case there is no aliasing). So there is no dependence between them in the current iteration. However, if we unroll the loop a bit, we get:



            do I=2,N
            S1: A(I) = B(I) + C(I)
            S2: D(I) = -> A(I + 1) + 1
            S3: C(I) = D(I)
            S1: -> A(I + 1) = B(I + 1) + C(I + 1)
            S2: D(I + 1) = A(I + 2) + 1
            S3: C(I + 1) = D(I + 1)


            Now, the anti dependence appears clearly.



            Seems obvious now..






            share|improve this answer

























              up vote
              0
              down vote



              accepted










              Okay, finally it depends not of the object, but of the memory location being used. In this example, A(I) and A(I + 1) may not refer to the same memory (in case there is no aliasing). So there is no dependence between them in the current iteration. However, if we unroll the loop a bit, we get:



              do I=2,N
              S1: A(I) = B(I) + C(I)
              S2: D(I) = -> A(I + 1) + 1
              S3: C(I) = D(I)
              S1: -> A(I + 1) = B(I + 1) + C(I + 1)
              S2: D(I + 1) = A(I + 2) + 1
              S3: C(I + 1) = D(I + 1)


              Now, the anti dependence appears clearly.



              Seems obvious now..






              share|improve this answer























                up vote
                0
                down vote



                accepted







                up vote
                0
                down vote



                accepted






                Okay, finally it depends not of the object, but of the memory location being used. In this example, A(I) and A(I + 1) may not refer to the same memory (in case there is no aliasing). So there is no dependence between them in the current iteration. However, if we unroll the loop a bit, we get:



                do I=2,N
                S1: A(I) = B(I) + C(I)
                S2: D(I) = -> A(I + 1) + 1
                S3: C(I) = D(I)
                S1: -> A(I + 1) = B(I + 1) + C(I + 1)
                S2: D(I + 1) = A(I + 2) + 1
                S3: C(I + 1) = D(I + 1)


                Now, the anti dependence appears clearly.



                Seems obvious now..






                share|improve this answer












                Okay, finally it depends not of the object, but of the memory location being used. In this example, A(I) and A(I + 1) may not refer to the same memory (in case there is no aliasing). So there is no dependence between them in the current iteration. However, if we unroll the loop a bit, we get:



                do I=2,N
                S1: A(I) = B(I) + C(I)
                S2: D(I) = -> A(I + 1) + 1
                S3: C(I) = D(I)
                S1: -> A(I + 1) = B(I + 1) + C(I + 1)
                S2: D(I + 1) = A(I + 2) + 1
                S3: C(I + 1) = D(I + 1)


                Now, the anti dependence appears clearly.



                Seems obvious now..







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 2 days ago









                Sam The Sid

                216




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