SymPy can print Exponentiation base and exponent?











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0
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Thank you in advance and sorry for the bad english!



I want



1.x : how to Determination of Exponentiation , Determination possible?



2.print : base=b ,exponent=n



 WrongScript.py



from sympy import *
var('x y z a b n')
x=b**n
y=3**n
z=a
# output 1.---------------------------------
print("x=",x) # x= b**n,**
print("y=",y) # y= 3**n,**
print("z=",z) # z= a, not **
# output 2.---------------------------------
print(MyBaseOut(x),MyExponentOut(x)) # b,n
print(MyBaseOut(y),MyExponentOut(y)) # 3,n

def MyBaseOut(p):
# ans=?
return ans
def MyExponentOut(q):
# ans=?
return ans


2018-11-26------------------------------



FullScript.py



from sympy import *
var('b n')
def MyBaseOut(p):
return p.as_base_exp()[0]
def MyExponentOut(q):
return q.as_base_exp()[1]
x=b**n
y=3**n
print(MyBaseOut(x),MyExponentOut(x))
print(MyBaseOut(y),MyExponentOut(y))
# b n
# 3 n









share|improve this question




























    up vote
    0
    down vote

    favorite












    Thank you in advance and sorry for the bad english!



    I want



    1.x : how to Determination of Exponentiation , Determination possible?



    2.print : base=b ,exponent=n



     WrongScript.py



    from sympy import *
    var('x y z a b n')
    x=b**n
    y=3**n
    z=a
    # output 1.---------------------------------
    print("x=",x) # x= b**n,**
    print("y=",y) # y= 3**n,**
    print("z=",z) # z= a, not **
    # output 2.---------------------------------
    print(MyBaseOut(x),MyExponentOut(x)) # b,n
    print(MyBaseOut(y),MyExponentOut(y)) # 3,n

    def MyBaseOut(p):
    # ans=?
    return ans
    def MyExponentOut(q):
    # ans=?
    return ans


    2018-11-26------------------------------



    FullScript.py



    from sympy import *
    var('b n')
    def MyBaseOut(p):
    return p.as_base_exp()[0]
    def MyExponentOut(q):
    return q.as_base_exp()[1]
    x=b**n
    y=3**n
    print(MyBaseOut(x),MyExponentOut(x))
    print(MyBaseOut(y),MyExponentOut(y))
    # b n
    # 3 n









    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Thank you in advance and sorry for the bad english!



      I want



      1.x : how to Determination of Exponentiation , Determination possible?



      2.print : base=b ,exponent=n



       WrongScript.py



      from sympy import *
      var('x y z a b n')
      x=b**n
      y=3**n
      z=a
      # output 1.---------------------------------
      print("x=",x) # x= b**n,**
      print("y=",y) # y= 3**n,**
      print("z=",z) # z= a, not **
      # output 2.---------------------------------
      print(MyBaseOut(x),MyExponentOut(x)) # b,n
      print(MyBaseOut(y),MyExponentOut(y)) # 3,n

      def MyBaseOut(p):
      # ans=?
      return ans
      def MyExponentOut(q):
      # ans=?
      return ans


      2018-11-26------------------------------



      FullScript.py



      from sympy import *
      var('b n')
      def MyBaseOut(p):
      return p.as_base_exp()[0]
      def MyExponentOut(q):
      return q.as_base_exp()[1]
      x=b**n
      y=3**n
      print(MyBaseOut(x),MyExponentOut(x))
      print(MyBaseOut(y),MyExponentOut(y))
      # b n
      # 3 n









      share|improve this question















      Thank you in advance and sorry for the bad english!



      I want



      1.x : how to Determination of Exponentiation , Determination possible?



      2.print : base=b ,exponent=n



       WrongScript.py



      from sympy import *
      var('x y z a b n')
      x=b**n
      y=3**n
      z=a
      # output 1.---------------------------------
      print("x=",x) # x= b**n,**
      print("y=",y) # y= 3**n,**
      print("z=",z) # z= a, not **
      # output 2.---------------------------------
      print(MyBaseOut(x),MyExponentOut(x)) # b,n
      print(MyBaseOut(y),MyExponentOut(y)) # 3,n

      def MyBaseOut(p):
      # ans=?
      return ans
      def MyExponentOut(q):
      # ans=?
      return ans


      2018-11-26------------------------------



      FullScript.py



      from sympy import *
      var('b n')
      def MyBaseOut(p):
      return p.as_base_exp()[0]
      def MyExponentOut(q):
      return q.as_base_exp()[1]
      x=b**n
      y=3**n
      print(MyBaseOut(x),MyExponentOut(x))
      print(MyBaseOut(y),MyExponentOut(y))
      # b n
      # 3 n






      sympy






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      edited Nov 26 at 12:05

























      asked Nov 22 at 12:59









      mrrclb48z

      356




      356
























          1 Answer
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          The attribute is_Pow will tell you if it has an exponent other than 1 and the method as_base_exp() will tell you what the base and exponent are -- select element 0 for the base and element 1 for the exponent:



          >>> [(i.is_Pow, i.as_base_exp()) for i in (y,1/y,y**2,y**z)]
          [(False, (y, 1)), (True, (y, -1)), (True, (y, 2)), (True, (y, z))]





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            1 Answer
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            active

            oldest

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            1 Answer
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            active

            oldest

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            active

            oldest

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            active

            oldest

            votes








            up vote
            1
            down vote



            accepted










            The attribute is_Pow will tell you if it has an exponent other than 1 and the method as_base_exp() will tell you what the base and exponent are -- select element 0 for the base and element 1 for the exponent:



            >>> [(i.is_Pow, i.as_base_exp()) for i in (y,1/y,y**2,y**z)]
            [(False, (y, 1)), (True, (y, -1)), (True, (y, 2)), (True, (y, z))]





            share|improve this answer

























              up vote
              1
              down vote



              accepted










              The attribute is_Pow will tell you if it has an exponent other than 1 and the method as_base_exp() will tell you what the base and exponent are -- select element 0 for the base and element 1 for the exponent:



              >>> [(i.is_Pow, i.as_base_exp()) for i in (y,1/y,y**2,y**z)]
              [(False, (y, 1)), (True, (y, -1)), (True, (y, 2)), (True, (y, z))]





              share|improve this answer























                up vote
                1
                down vote



                accepted







                up vote
                1
                down vote



                accepted






                The attribute is_Pow will tell you if it has an exponent other than 1 and the method as_base_exp() will tell you what the base and exponent are -- select element 0 for the base and element 1 for the exponent:



                >>> [(i.is_Pow, i.as_base_exp()) for i in (y,1/y,y**2,y**z)]
                [(False, (y, 1)), (True, (y, -1)), (True, (y, 2)), (True, (y, z))]





                share|improve this answer












                The attribute is_Pow will tell you if it has an exponent other than 1 and the method as_base_exp() will tell you what the base and exponent are -- select element 0 for the base and element 1 for the exponent:



                >>> [(i.is_Pow, i.as_base_exp()) for i in (y,1/y,y**2,y**z)]
                [(False, (y, 1)), (True, (y, -1)), (True, (y, 2)), (True, (y, z))]






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 22 at 13:26









                smichr

                3,368810




                3,368810






























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