C++ Using a sequence of values from 'for' loop one at a time in a consecutive order within another function











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I would like to use a 'for' loop (OR anything that works for that matter) to generate a sequence of values.



I iterate many times and need to use values from the loop (OR anything that works) one at a time in a consequent manner. This values are used to represent 'time' value in an equation for population growth. Ultimately I am to have a chart representing solutions for calculations where 'time'is 1,2,3,4...60.



My question is: how to make the equation "value = a * exp(k * t)" consider t = 'time'as a new consecutive value from a vector that 'loop' generated ?



EDIT: I will try to clarify the set up - both reset and update act as iterations. In this specific case reset runs once and update runs n times. What I need is to use a consequent value of 'time' each iteration of update i.e. first time update runs the value of t = first value within the vector, second time update runs t = second value within the vector etc.



void ExponentialGrowth::reset() {update();}



void ExponentialGrowth::update() {value = a * exp(k * t); }










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  • 2




    Store the values from the initial for loop in a table - or am I missing the point?
    – 500 - Internal Server Error
    Nov 22 at 13:01










  • If time is 1,2,3,4,...60, why do you need to calculate it?
    – molbdnilo
    Nov 22 at 13:17










  • I need to calculate value not the time.
    – Vladimir Alexandrovich Mishin
    Nov 23 at 9:56















up vote
-1
down vote

favorite












I would like to use a 'for' loop (OR anything that works for that matter) to generate a sequence of values.



I iterate many times and need to use values from the loop (OR anything that works) one at a time in a consequent manner. This values are used to represent 'time' value in an equation for population growth. Ultimately I am to have a chart representing solutions for calculations where 'time'is 1,2,3,4...60.



My question is: how to make the equation "value = a * exp(k * t)" consider t = 'time'as a new consecutive value from a vector that 'loop' generated ?



EDIT: I will try to clarify the set up - both reset and update act as iterations. In this specific case reset runs once and update runs n times. What I need is to use a consequent value of 'time' each iteration of update i.e. first time update runs the value of t = first value within the vector, second time update runs t = second value within the vector etc.



void ExponentialGrowth::reset() {update();}



void ExponentialGrowth::update() {value = a * exp(k * t); }










share|improve this question




















  • 2




    Store the values from the initial for loop in a table - or am I missing the point?
    – 500 - Internal Server Error
    Nov 22 at 13:01










  • If time is 1,2,3,4,...60, why do you need to calculate it?
    – molbdnilo
    Nov 22 at 13:17










  • I need to calculate value not the time.
    – Vladimir Alexandrovich Mishin
    Nov 23 at 9:56













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I would like to use a 'for' loop (OR anything that works for that matter) to generate a sequence of values.



I iterate many times and need to use values from the loop (OR anything that works) one at a time in a consequent manner. This values are used to represent 'time' value in an equation for population growth. Ultimately I am to have a chart representing solutions for calculations where 'time'is 1,2,3,4...60.



My question is: how to make the equation "value = a * exp(k * t)" consider t = 'time'as a new consecutive value from a vector that 'loop' generated ?



EDIT: I will try to clarify the set up - both reset and update act as iterations. In this specific case reset runs once and update runs n times. What I need is to use a consequent value of 'time' each iteration of update i.e. first time update runs the value of t = first value within the vector, second time update runs t = second value within the vector etc.



void ExponentialGrowth::reset() {update();}



void ExponentialGrowth::update() {value = a * exp(k * t); }










share|improve this question















I would like to use a 'for' loop (OR anything that works for that matter) to generate a sequence of values.



I iterate many times and need to use values from the loop (OR anything that works) one at a time in a consequent manner. This values are used to represent 'time' value in an equation for population growth. Ultimately I am to have a chart representing solutions for calculations where 'time'is 1,2,3,4...60.



My question is: how to make the equation "value = a * exp(k * t)" consider t = 'time'as a new consecutive value from a vector that 'loop' generated ?



EDIT: I will try to clarify the set up - both reset and update act as iterations. In this specific case reset runs once and update runs n times. What I need is to use a consequent value of 'time' each iteration of update i.e. first time update runs the value of t = first value within the vector, second time update runs t = second value within the vector etc.



void ExponentialGrowth::reset() {update();}



void ExponentialGrowth::update() {value = a * exp(k * t); }







c++ loops for-loop indexing reference






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edited Nov 23 at 12:52

























asked Nov 22 at 12:59









Vladimir Alexandrovich Mishin

11




11








  • 2




    Store the values from the initial for loop in a table - or am I missing the point?
    – 500 - Internal Server Error
    Nov 22 at 13:01










  • If time is 1,2,3,4,...60, why do you need to calculate it?
    – molbdnilo
    Nov 22 at 13:17










  • I need to calculate value not the time.
    – Vladimir Alexandrovich Mishin
    Nov 23 at 9:56














  • 2




    Store the values from the initial for loop in a table - or am I missing the point?
    – 500 - Internal Server Error
    Nov 22 at 13:01










  • If time is 1,2,3,4,...60, why do you need to calculate it?
    – molbdnilo
    Nov 22 at 13:17










  • I need to calculate value not the time.
    – Vladimir Alexandrovich Mishin
    Nov 23 at 9:56








2




2




Store the values from the initial for loop in a table - or am I missing the point?
– 500 - Internal Server Error
Nov 22 at 13:01




Store the values from the initial for loop in a table - or am I missing the point?
– 500 - Internal Server Error
Nov 22 at 13:01












If time is 1,2,3,4,...60, why do you need to calculate it?
– molbdnilo
Nov 22 at 13:17




If time is 1,2,3,4,...60, why do you need to calculate it?
– molbdnilo
Nov 22 at 13:17












I need to calculate value not the time.
– Vladimir Alexandrovich Mishin
Nov 23 at 9:56




I need to calculate value not the time.
– Vladimir Alexandrovich Mishin
Nov 23 at 9:56












1 Answer
1






active

oldest

votes

















up vote
3
down vote













if t is integer type (0 to 60)



#include "math.h"

int a = 1;
int k = 2;
for(int time = 0; time < 60; ++time){
int value = a * exp(k * time);
}


if you have to pass the size juste make a function



void func(int _start, int _end){
int a = 1;
int k = 2;
for(int i = _start; i <= _end; ++i){
int value = a * exp(k * i);
}
}





share|improve this answer























  • In C++, the <cmath> header would be preferred, along with std::exp.
    – Mike Borkland
    Nov 22 at 15:37










  • When you say size do you mean just as in 60 ? Because I need 60 different values.
    – Vladimir Alexandrovich Mishin
    Nov 23 at 9:53











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote













if t is integer type (0 to 60)



#include "math.h"

int a = 1;
int k = 2;
for(int time = 0; time < 60; ++time){
int value = a * exp(k * time);
}


if you have to pass the size juste make a function



void func(int _start, int _end){
int a = 1;
int k = 2;
for(int i = _start; i <= _end; ++i){
int value = a * exp(k * i);
}
}





share|improve this answer























  • In C++, the <cmath> header would be preferred, along with std::exp.
    – Mike Borkland
    Nov 22 at 15:37










  • When you say size do you mean just as in 60 ? Because I need 60 different values.
    – Vladimir Alexandrovich Mishin
    Nov 23 at 9:53















up vote
3
down vote













if t is integer type (0 to 60)



#include "math.h"

int a = 1;
int k = 2;
for(int time = 0; time < 60; ++time){
int value = a * exp(k * time);
}


if you have to pass the size juste make a function



void func(int _start, int _end){
int a = 1;
int k = 2;
for(int i = _start; i <= _end; ++i){
int value = a * exp(k * i);
}
}





share|improve this answer























  • In C++, the <cmath> header would be preferred, along with std::exp.
    – Mike Borkland
    Nov 22 at 15:37










  • When you say size do you mean just as in 60 ? Because I need 60 different values.
    – Vladimir Alexandrovich Mishin
    Nov 23 at 9:53













up vote
3
down vote










up vote
3
down vote









if t is integer type (0 to 60)



#include "math.h"

int a = 1;
int k = 2;
for(int time = 0; time < 60; ++time){
int value = a * exp(k * time);
}


if you have to pass the size juste make a function



void func(int _start, int _end){
int a = 1;
int k = 2;
for(int i = _start; i <= _end; ++i){
int value = a * exp(k * i);
}
}





share|improve this answer














if t is integer type (0 to 60)



#include "math.h"

int a = 1;
int k = 2;
for(int time = 0; time < 60; ++time){
int value = a * exp(k * time);
}


if you have to pass the size juste make a function



void func(int _start, int _end){
int a = 1;
int k = 2;
for(int i = _start; i <= _end; ++i){
int value = a * exp(k * i);
}
}






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 22 at 13:11

























answered Nov 22 at 13:05









Skogandr

643




643












  • In C++, the <cmath> header would be preferred, along with std::exp.
    – Mike Borkland
    Nov 22 at 15:37










  • When you say size do you mean just as in 60 ? Because I need 60 different values.
    – Vladimir Alexandrovich Mishin
    Nov 23 at 9:53


















  • In C++, the <cmath> header would be preferred, along with std::exp.
    – Mike Borkland
    Nov 22 at 15:37










  • When you say size do you mean just as in 60 ? Because I need 60 different values.
    – Vladimir Alexandrovich Mishin
    Nov 23 at 9:53
















In C++, the <cmath> header would be preferred, along with std::exp.
– Mike Borkland
Nov 22 at 15:37




In C++, the <cmath> header would be preferred, along with std::exp.
– Mike Borkland
Nov 22 at 15:37












When you say size do you mean just as in 60 ? Because I need 60 different values.
– Vladimir Alexandrovich Mishin
Nov 23 at 9:53




When you say size do you mean just as in 60 ? Because I need 60 different values.
– Vladimir Alexandrovich Mishin
Nov 23 at 9:53


















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