scala getting read,write and reject records with simplified regex
I'm working on a log file to parse the read/written/rejected records using scala and convert them into a Map. The values are present in different lines - "read" followed by "written" in next line and then "rejected"..
The snippet of the code I'm using is
val log_text =
"""
|server.net|Wed Apr 8 05:44:24 2018|acct_reformat.000||finish|
| 120 records ( 7200 bytes) read
| 100 records ( 6000 bytes) written
| 20 records ( 1200 bytes) rejected|
|server.net|Wed Apr 8 05:44:24 2018|acct_reformat_rfm_logs
""".stripMargin
val read_pat = """(d+) (records) (.*)""".r
val write_pat = """(?s)records .*? (d+) (records)(.*)""".r
val reject_pat = """(?s).* (d+) (records)""".r
val read_recs = read_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val write_recs = write_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val reject_recs = reject_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val log_summ = List("Read",read_recs,"Write",write_recs,"Reject",reject_recs).sliding(2,2).map( p => p match { case List(x,y) => (x,y)}).toMap
which results in
log_summ: scala.collection.immutable.Map[String,String] = Map(Read -> 120, Write -> 100, Reject -> 20)
Somehow I feel, I'm doing it in a roundabout/redundant way.. Is there a better way to accomplish this?.
scala scala-collections
add a comment |
I'm working on a log file to parse the read/written/rejected records using scala and convert them into a Map. The values are present in different lines - "read" followed by "written" in next line and then "rejected"..
The snippet of the code I'm using is
val log_text =
"""
|server.net|Wed Apr 8 05:44:24 2018|acct_reformat.000||finish|
| 120 records ( 7200 bytes) read
| 100 records ( 6000 bytes) written
| 20 records ( 1200 bytes) rejected|
|server.net|Wed Apr 8 05:44:24 2018|acct_reformat_rfm_logs
""".stripMargin
val read_pat = """(d+) (records) (.*)""".r
val write_pat = """(?s)records .*? (d+) (records)(.*)""".r
val reject_pat = """(?s).* (d+) (records)""".r
val read_recs = read_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val write_recs = write_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val reject_recs = reject_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val log_summ = List("Read",read_recs,"Write",write_recs,"Reject",reject_recs).sliding(2,2).map( p => p match { case List(x,y) => (x,y)}).toMap
which results in
log_summ: scala.collection.immutable.Map[String,String] = Map(Read -> 120, Write -> 100, Reject -> 20)
Somehow I feel, I'm doing it in a roundabout/redundant way.. Is there a better way to accomplish this?.
scala scala-collections
add a comment |
I'm working on a log file to parse the read/written/rejected records using scala and convert them into a Map. The values are present in different lines - "read" followed by "written" in next line and then "rejected"..
The snippet of the code I'm using is
val log_text =
"""
|server.net|Wed Apr 8 05:44:24 2018|acct_reformat.000||finish|
| 120 records ( 7200 bytes) read
| 100 records ( 6000 bytes) written
| 20 records ( 1200 bytes) rejected|
|server.net|Wed Apr 8 05:44:24 2018|acct_reformat_rfm_logs
""".stripMargin
val read_pat = """(d+) (records) (.*)""".r
val write_pat = """(?s)records .*? (d+) (records)(.*)""".r
val reject_pat = """(?s).* (d+) (records)""".r
val read_recs = read_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val write_recs = write_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val reject_recs = reject_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val log_summ = List("Read",read_recs,"Write",write_recs,"Reject",reject_recs).sliding(2,2).map( p => p match { case List(x,y) => (x,y)}).toMap
which results in
log_summ: scala.collection.immutable.Map[String,String] = Map(Read -> 120, Write -> 100, Reject -> 20)
Somehow I feel, I'm doing it in a roundabout/redundant way.. Is there a better way to accomplish this?.
scala scala-collections
I'm working on a log file to parse the read/written/rejected records using scala and convert them into a Map. The values are present in different lines - "read" followed by "written" in next line and then "rejected"..
The snippet of the code I'm using is
val log_text =
"""
|server.net|Wed Apr 8 05:44:24 2018|acct_reformat.000||finish|
| 120 records ( 7200 bytes) read
| 100 records ( 6000 bytes) written
| 20 records ( 1200 bytes) rejected|
|server.net|Wed Apr 8 05:44:24 2018|acct_reformat_rfm_logs
""".stripMargin
val read_pat = """(d+) (records) (.*)""".r
val write_pat = """(?s)records .*? (d+) (records)(.*)""".r
val reject_pat = """(?s).* (d+) (records)""".r
val read_recs = read_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val write_recs = write_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val reject_recs = reject_pat.findAllIn(log_text).matchData.map( m=> m.subgroups(0) ).take(1).mkString
val log_summ = List("Read",read_recs,"Write",write_recs,"Reject",reject_recs).sliding(2,2).map( p => p match { case List(x,y) => (x,y)}).toMap
which results in
log_summ: scala.collection.immutable.Map[String,String] = Map(Read -> 120, Write -> 100, Reject -> 20)
Somehow I feel, I'm doing it in a roundabout/redundant way.. Is there a better way to accomplish this?.
scala scala-collections
scala scala-collections
asked Nov 22 at 13:27
stack0114106
2,0051416
2,0051416
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Given the similarity of the read/write/reject text, you could simplify the multiple Regex matching patterns into a generic one and use zip
to generate your Map
, as shown below:
val pattern = """(d+) records .*""".r
val keys = List("Read", "Write", "Reject")
val values = pattern.findAllIn(log_text).matchData.map(_.subgroups(0)).toList
// values: List[String] = List(120, 100, 20)
val log_summ = (keys zip values).toMap
// log_summ: scala.collection.immutable.Map[String,String] =
// Map(Read -> 120, Write -> 100, Reject -> 20)
Great answer!..you simplified greatly..
– stack0114106
Nov 22 at 19:35
add a comment |
Looks fine to me. Just three things to improve:
1) IntelliJ
is your friend. It gives you two intentions immediately:
m.subgroups(0)
->m.subgroups.head
map(p => p match { case List(x, y) => (x, y) })
->map { case List(x, y) => (x, y) }
2) DRY. Don't repeat read/write/reject related code three times. Just keep it somewhere once. E.g.:
case class Processor(name: String, patternString: String) {
lazy val pattern: Regex = patternString.r
}
val processors = Seq(
Processor("Read", """(d+) (records) (.*)"""),
Processor("Write", """(?s)records .*? (d+) (records)(.*)"""),
Processor("Reject", """(?s).* (d+) (records)"""),
)
def read_recs(processor: Processor) = processor.pattern.findAllIn(log_text).matchData.map(m => m.subgroups.head).take(1).mkString
3) List[Tuple2]
can be converted to a Map
with a simple toMap
val log_summ = processors.map(processor => processor.name -> read_recs(processor)).toMap
This also works.. thanks for the answer..
– stack0114106
Nov 22 at 19:36
add a comment |
It can be done in a single pass if you're willing to use the log's wording for the Map
keys.
val Pattern = raw"(d+) records .*) ([^|]+)".r.unanchored
log_text.split("n").flatMap{
case Pattern(num, typ) => Some(typ -> num)
case _ => None
}.toMap
//res0: immutable.Map[String,String] = Map(read -> 120, written -> 100, rejected -> 20)
Could you please add explanation on the unanchored?.. right now in travel will check tomorrow.. thanks for the answer..
– stack0114106
Nov 22 at 19:55
btw.. why flatMap after the split? Will not just map() do the work?..
– stack0114106
Nov 22 at 19:57
unanchored: Regex patterns in Scala are, by default, "anchored" to the start/end of the string, meaning, "This pattern describes the entire string from beginning to end." "unanchored", on the other hand, means, "This pattern describes some part of the string, which might, or might not, include the start and/or end."
– jwvh
Nov 22 at 21:09
flatMap: Notice that I'm returning anOption
(Some
orNone
) from the map operation. If I had usedmap()
the return type would beArray[Option[(String,String)]]
, which can't be turned into aMap
. You can use.flatten
to flatten a collection ofOption[X]
elements into a collection of just[X]
elements, and all theNone
values will disappear.flatMap()
is the combination ofmap(...).flatten
.
– jwvh
Nov 22 at 21:18
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Given the similarity of the read/write/reject text, you could simplify the multiple Regex matching patterns into a generic one and use zip
to generate your Map
, as shown below:
val pattern = """(d+) records .*""".r
val keys = List("Read", "Write", "Reject")
val values = pattern.findAllIn(log_text).matchData.map(_.subgroups(0)).toList
// values: List[String] = List(120, 100, 20)
val log_summ = (keys zip values).toMap
// log_summ: scala.collection.immutable.Map[String,String] =
// Map(Read -> 120, Write -> 100, Reject -> 20)
Great answer!..you simplified greatly..
– stack0114106
Nov 22 at 19:35
add a comment |
Given the similarity of the read/write/reject text, you could simplify the multiple Regex matching patterns into a generic one and use zip
to generate your Map
, as shown below:
val pattern = """(d+) records .*""".r
val keys = List("Read", "Write", "Reject")
val values = pattern.findAllIn(log_text).matchData.map(_.subgroups(0)).toList
// values: List[String] = List(120, 100, 20)
val log_summ = (keys zip values).toMap
// log_summ: scala.collection.immutable.Map[String,String] =
// Map(Read -> 120, Write -> 100, Reject -> 20)
Great answer!..you simplified greatly..
– stack0114106
Nov 22 at 19:35
add a comment |
Given the similarity of the read/write/reject text, you could simplify the multiple Regex matching patterns into a generic one and use zip
to generate your Map
, as shown below:
val pattern = """(d+) records .*""".r
val keys = List("Read", "Write", "Reject")
val values = pattern.findAllIn(log_text).matchData.map(_.subgroups(0)).toList
// values: List[String] = List(120, 100, 20)
val log_summ = (keys zip values).toMap
// log_summ: scala.collection.immutable.Map[String,String] =
// Map(Read -> 120, Write -> 100, Reject -> 20)
Given the similarity of the read/write/reject text, you could simplify the multiple Regex matching patterns into a generic one and use zip
to generate your Map
, as shown below:
val pattern = """(d+) records .*""".r
val keys = List("Read", "Write", "Reject")
val values = pattern.findAllIn(log_text).matchData.map(_.subgroups(0)).toList
// values: List[String] = List(120, 100, 20)
val log_summ = (keys zip values).toMap
// log_summ: scala.collection.immutable.Map[String,String] =
// Map(Read -> 120, Write -> 100, Reject -> 20)
answered Nov 22 at 14:22
Leo C
10.1k2616
10.1k2616
Great answer!..you simplified greatly..
– stack0114106
Nov 22 at 19:35
add a comment |
Great answer!..you simplified greatly..
– stack0114106
Nov 22 at 19:35
Great answer!..you simplified greatly..
– stack0114106
Nov 22 at 19:35
Great answer!..you simplified greatly..
– stack0114106
Nov 22 at 19:35
add a comment |
Looks fine to me. Just three things to improve:
1) IntelliJ
is your friend. It gives you two intentions immediately:
m.subgroups(0)
->m.subgroups.head
map(p => p match { case List(x, y) => (x, y) })
->map { case List(x, y) => (x, y) }
2) DRY. Don't repeat read/write/reject related code three times. Just keep it somewhere once. E.g.:
case class Processor(name: String, patternString: String) {
lazy val pattern: Regex = patternString.r
}
val processors = Seq(
Processor("Read", """(d+) (records) (.*)"""),
Processor("Write", """(?s)records .*? (d+) (records)(.*)"""),
Processor("Reject", """(?s).* (d+) (records)"""),
)
def read_recs(processor: Processor) = processor.pattern.findAllIn(log_text).matchData.map(m => m.subgroups.head).take(1).mkString
3) List[Tuple2]
can be converted to a Map
with a simple toMap
val log_summ = processors.map(processor => processor.name -> read_recs(processor)).toMap
This also works.. thanks for the answer..
– stack0114106
Nov 22 at 19:36
add a comment |
Looks fine to me. Just three things to improve:
1) IntelliJ
is your friend. It gives you two intentions immediately:
m.subgroups(0)
->m.subgroups.head
map(p => p match { case List(x, y) => (x, y) })
->map { case List(x, y) => (x, y) }
2) DRY. Don't repeat read/write/reject related code three times. Just keep it somewhere once. E.g.:
case class Processor(name: String, patternString: String) {
lazy val pattern: Regex = patternString.r
}
val processors = Seq(
Processor("Read", """(d+) (records) (.*)"""),
Processor("Write", """(?s)records .*? (d+) (records)(.*)"""),
Processor("Reject", """(?s).* (d+) (records)"""),
)
def read_recs(processor: Processor) = processor.pattern.findAllIn(log_text).matchData.map(m => m.subgroups.head).take(1).mkString
3) List[Tuple2]
can be converted to a Map
with a simple toMap
val log_summ = processors.map(processor => processor.name -> read_recs(processor)).toMap
This also works.. thanks for the answer..
– stack0114106
Nov 22 at 19:36
add a comment |
Looks fine to me. Just three things to improve:
1) IntelliJ
is your friend. It gives you two intentions immediately:
m.subgroups(0)
->m.subgroups.head
map(p => p match { case List(x, y) => (x, y) })
->map { case List(x, y) => (x, y) }
2) DRY. Don't repeat read/write/reject related code three times. Just keep it somewhere once. E.g.:
case class Processor(name: String, patternString: String) {
lazy val pattern: Regex = patternString.r
}
val processors = Seq(
Processor("Read", """(d+) (records) (.*)"""),
Processor("Write", """(?s)records .*? (d+) (records)(.*)"""),
Processor("Reject", """(?s).* (d+) (records)"""),
)
def read_recs(processor: Processor) = processor.pattern.findAllIn(log_text).matchData.map(m => m.subgroups.head).take(1).mkString
3) List[Tuple2]
can be converted to a Map
with a simple toMap
val log_summ = processors.map(processor => processor.name -> read_recs(processor)).toMap
Looks fine to me. Just three things to improve:
1) IntelliJ
is your friend. It gives you two intentions immediately:
m.subgroups(0)
->m.subgroups.head
map(p => p match { case List(x, y) => (x, y) })
->map { case List(x, y) => (x, y) }
2) DRY. Don't repeat read/write/reject related code three times. Just keep it somewhere once. E.g.:
case class Processor(name: String, patternString: String) {
lazy val pattern: Regex = patternString.r
}
val processors = Seq(
Processor("Read", """(d+) (records) (.*)"""),
Processor("Write", """(?s)records .*? (d+) (records)(.*)"""),
Processor("Reject", """(?s).* (d+) (records)"""),
)
def read_recs(processor: Processor) = processor.pattern.findAllIn(log_text).matchData.map(m => m.subgroups.head).take(1).mkString
3) List[Tuple2]
can be converted to a Map
with a simple toMap
val log_summ = processors.map(processor => processor.name -> read_recs(processor)).toMap
answered Nov 22 at 13:55
ygor
884513
884513
This also works.. thanks for the answer..
– stack0114106
Nov 22 at 19:36
add a comment |
This also works.. thanks for the answer..
– stack0114106
Nov 22 at 19:36
This also works.. thanks for the answer..
– stack0114106
Nov 22 at 19:36
This also works.. thanks for the answer..
– stack0114106
Nov 22 at 19:36
add a comment |
It can be done in a single pass if you're willing to use the log's wording for the Map
keys.
val Pattern = raw"(d+) records .*) ([^|]+)".r.unanchored
log_text.split("n").flatMap{
case Pattern(num, typ) => Some(typ -> num)
case _ => None
}.toMap
//res0: immutable.Map[String,String] = Map(read -> 120, written -> 100, rejected -> 20)
Could you please add explanation on the unanchored?.. right now in travel will check tomorrow.. thanks for the answer..
– stack0114106
Nov 22 at 19:55
btw.. why flatMap after the split? Will not just map() do the work?..
– stack0114106
Nov 22 at 19:57
unanchored: Regex patterns in Scala are, by default, "anchored" to the start/end of the string, meaning, "This pattern describes the entire string from beginning to end." "unanchored", on the other hand, means, "This pattern describes some part of the string, which might, or might not, include the start and/or end."
– jwvh
Nov 22 at 21:09
flatMap: Notice that I'm returning anOption
(Some
orNone
) from the map operation. If I had usedmap()
the return type would beArray[Option[(String,String)]]
, which can't be turned into aMap
. You can use.flatten
to flatten a collection ofOption[X]
elements into a collection of just[X]
elements, and all theNone
values will disappear.flatMap()
is the combination ofmap(...).flatten
.
– jwvh
Nov 22 at 21:18
add a comment |
It can be done in a single pass if you're willing to use the log's wording for the Map
keys.
val Pattern = raw"(d+) records .*) ([^|]+)".r.unanchored
log_text.split("n").flatMap{
case Pattern(num, typ) => Some(typ -> num)
case _ => None
}.toMap
//res0: immutable.Map[String,String] = Map(read -> 120, written -> 100, rejected -> 20)
Could you please add explanation on the unanchored?.. right now in travel will check tomorrow.. thanks for the answer..
– stack0114106
Nov 22 at 19:55
btw.. why flatMap after the split? Will not just map() do the work?..
– stack0114106
Nov 22 at 19:57
unanchored: Regex patterns in Scala are, by default, "anchored" to the start/end of the string, meaning, "This pattern describes the entire string from beginning to end." "unanchored", on the other hand, means, "This pattern describes some part of the string, which might, or might not, include the start and/or end."
– jwvh
Nov 22 at 21:09
flatMap: Notice that I'm returning anOption
(Some
orNone
) from the map operation. If I had usedmap()
the return type would beArray[Option[(String,String)]]
, which can't be turned into aMap
. You can use.flatten
to flatten a collection ofOption[X]
elements into a collection of just[X]
elements, and all theNone
values will disappear.flatMap()
is the combination ofmap(...).flatten
.
– jwvh
Nov 22 at 21:18
add a comment |
It can be done in a single pass if you're willing to use the log's wording for the Map
keys.
val Pattern = raw"(d+) records .*) ([^|]+)".r.unanchored
log_text.split("n").flatMap{
case Pattern(num, typ) => Some(typ -> num)
case _ => None
}.toMap
//res0: immutable.Map[String,String] = Map(read -> 120, written -> 100, rejected -> 20)
It can be done in a single pass if you're willing to use the log's wording for the Map
keys.
val Pattern = raw"(d+) records .*) ([^|]+)".r.unanchored
log_text.split("n").flatMap{
case Pattern(num, typ) => Some(typ -> num)
case _ => None
}.toMap
//res0: immutable.Map[String,String] = Map(read -> 120, written -> 100, rejected -> 20)
answered Nov 22 at 19:43
jwvh
25.4k52038
25.4k52038
Could you please add explanation on the unanchored?.. right now in travel will check tomorrow.. thanks for the answer..
– stack0114106
Nov 22 at 19:55
btw.. why flatMap after the split? Will not just map() do the work?..
– stack0114106
Nov 22 at 19:57
unanchored: Regex patterns in Scala are, by default, "anchored" to the start/end of the string, meaning, "This pattern describes the entire string from beginning to end." "unanchored", on the other hand, means, "This pattern describes some part of the string, which might, or might not, include the start and/or end."
– jwvh
Nov 22 at 21:09
flatMap: Notice that I'm returning anOption
(Some
orNone
) from the map operation. If I had usedmap()
the return type would beArray[Option[(String,String)]]
, which can't be turned into aMap
. You can use.flatten
to flatten a collection ofOption[X]
elements into a collection of just[X]
elements, and all theNone
values will disappear.flatMap()
is the combination ofmap(...).flatten
.
– jwvh
Nov 22 at 21:18
add a comment |
Could you please add explanation on the unanchored?.. right now in travel will check tomorrow.. thanks for the answer..
– stack0114106
Nov 22 at 19:55
btw.. why flatMap after the split? Will not just map() do the work?..
– stack0114106
Nov 22 at 19:57
unanchored: Regex patterns in Scala are, by default, "anchored" to the start/end of the string, meaning, "This pattern describes the entire string from beginning to end." "unanchored", on the other hand, means, "This pattern describes some part of the string, which might, or might not, include the start and/or end."
– jwvh
Nov 22 at 21:09
flatMap: Notice that I'm returning anOption
(Some
orNone
) from the map operation. If I had usedmap()
the return type would beArray[Option[(String,String)]]
, which can't be turned into aMap
. You can use.flatten
to flatten a collection ofOption[X]
elements into a collection of just[X]
elements, and all theNone
values will disappear.flatMap()
is the combination ofmap(...).flatten
.
– jwvh
Nov 22 at 21:18
Could you please add explanation on the unanchored?.. right now in travel will check tomorrow.. thanks for the answer..
– stack0114106
Nov 22 at 19:55
Could you please add explanation on the unanchored?.. right now in travel will check tomorrow.. thanks for the answer..
– stack0114106
Nov 22 at 19:55
btw.. why flatMap after the split? Will not just map() do the work?..
– stack0114106
Nov 22 at 19:57
btw.. why flatMap after the split? Will not just map() do the work?..
– stack0114106
Nov 22 at 19:57
unanchored: Regex patterns in Scala are, by default, "anchored" to the start/end of the string, meaning, "This pattern describes the entire string from beginning to end." "unanchored", on the other hand, means, "This pattern describes some part of the string, which might, or might not, include the start and/or end."
– jwvh
Nov 22 at 21:09
unanchored: Regex patterns in Scala are, by default, "anchored" to the start/end of the string, meaning, "This pattern describes the entire string from beginning to end." "unanchored", on the other hand, means, "This pattern describes some part of the string, which might, or might not, include the start and/or end."
– jwvh
Nov 22 at 21:09
flatMap: Notice that I'm returning an
Option
(Some
or None
) from the map operation. If I had used map()
the return type would be Array[Option[(String,String)]]
, which can't be turned into a Map
. You can use .flatten
to flatten a collection of Option[X]
elements into a collection of just [X]
elements, and all the None
values will disappear. flatMap()
is the combination of map(...).flatten
.– jwvh
Nov 22 at 21:18
flatMap: Notice that I'm returning an
Option
(Some
or None
) from the map operation. If I had used map()
the return type would be Array[Option[(String,String)]]
, which can't be turned into a Map
. You can use .flatten
to flatten a collection of Option[X]
elements into a collection of just [X]
elements, and all the None
values will disappear. flatMap()
is the combination of map(...).flatten
.– jwvh
Nov 22 at 21:18
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