error: cannot find symbol when call JAXB class's methods with Cyrillic symbol











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I have an XSD schema with a mistake - in one method first symbol in utf-8 'с'



<xsd:attribute name="сreationDate" type="xsd:dateTime" use="required">


I generate Java classes from this XSD. But when I call this method in project for example:



quittanceType.setСreationDate(stringToXMLGregorianCalendar(new Date));


My project does not compile and I get error:




error: cannot find symbol




    quittanceType.setСreationDate(stringToXMLGregorianCalendar(paymentsToCharge.getCreationDateStr()));
^
symbol: method setСreationDate(XMLGregorianCalendar)
location: variable quittanceType of type QuittanceType


But on Macbook this project compiles successfully. What should I do? Everything seems to be normal encodings.










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  • Note that sticking to ASCII method names is probably better, see the discussion here : stackoverflow.com/questions/61615/…
    – Arnaud
    Nov 22 at 14:33












  • I know actually. You should not think that I took and specially wrote one character in another encoding. I got such a scheme, and it's too late to correct the symbol. And I have no right to do it.
    – ip696
    Nov 22 at 14:43















up vote
0
down vote

favorite












I have an XSD schema with a mistake - in one method first symbol in utf-8 'с'



<xsd:attribute name="сreationDate" type="xsd:dateTime" use="required">


I generate Java classes from this XSD. But when I call this method in project for example:



quittanceType.setСreationDate(stringToXMLGregorianCalendar(new Date));


My project does not compile and I get error:




error: cannot find symbol




    quittanceType.setСreationDate(stringToXMLGregorianCalendar(paymentsToCharge.getCreationDateStr()));
^
symbol: method setСreationDate(XMLGregorianCalendar)
location: variable quittanceType of type QuittanceType


But on Macbook this project compiles successfully. What should I do? Everything seems to be normal encodings.










share|improve this question
























  • Note that sticking to ASCII method names is probably better, see the discussion here : stackoverflow.com/questions/61615/…
    – Arnaud
    Nov 22 at 14:33












  • I know actually. You should not think that I took and specially wrote one character in another encoding. I got such a scheme, and it's too late to correct the symbol. And I have no right to do it.
    – ip696
    Nov 22 at 14:43













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have an XSD schema with a mistake - in one method first symbol in utf-8 'с'



<xsd:attribute name="сreationDate" type="xsd:dateTime" use="required">


I generate Java classes from this XSD. But when I call this method in project for example:



quittanceType.setСreationDate(stringToXMLGregorianCalendar(new Date));


My project does not compile and I get error:




error: cannot find symbol




    quittanceType.setСreationDate(stringToXMLGregorianCalendar(paymentsToCharge.getCreationDateStr()));
^
symbol: method setСreationDate(XMLGregorianCalendar)
location: variable quittanceType of type QuittanceType


But on Macbook this project compiles successfully. What should I do? Everything seems to be normal encodings.










share|improve this question















I have an XSD schema with a mistake - in one method first symbol in utf-8 'с'



<xsd:attribute name="сreationDate" type="xsd:dateTime" use="required">


I generate Java classes from this XSD. But when I call this method in project for example:



quittanceType.setСreationDate(stringToXMLGregorianCalendar(new Date));


My project does not compile and I get error:




error: cannot find symbol




    quittanceType.setСreationDate(stringToXMLGregorianCalendar(paymentsToCharge.getCreationDateStr()));
^
symbol: method setСreationDate(XMLGregorianCalendar)
location: variable quittanceType of type QuittanceType


But on Macbook this project compiles successfully. What should I do? Everything seems to be normal encodings.







java encoding xsd jaxb






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edited Nov 22 at 21:42









Thomas Fritsch

4,795121933




4,795121933










asked Nov 22 at 14:27









ip696

1,09711135




1,09711135












  • Note that sticking to ASCII method names is probably better, see the discussion here : stackoverflow.com/questions/61615/…
    – Arnaud
    Nov 22 at 14:33












  • I know actually. You should not think that I took and specially wrote one character in another encoding. I got such a scheme, and it's too late to correct the symbol. And I have no right to do it.
    – ip696
    Nov 22 at 14:43


















  • Note that sticking to ASCII method names is probably better, see the discussion here : stackoverflow.com/questions/61615/…
    – Arnaud
    Nov 22 at 14:33












  • I know actually. You should not think that I took and specially wrote one character in another encoding. I got such a scheme, and it's too late to correct the symbol. And I have no right to do it.
    – ip696
    Nov 22 at 14:43
















Note that sticking to ASCII method names is probably better, see the discussion here : stackoverflow.com/questions/61615/…
– Arnaud
Nov 22 at 14:33






Note that sticking to ASCII method names is probably better, see the discussion here : stackoverflow.com/questions/61615/…
– Arnaud
Nov 22 at 14:33














I know actually. You should not think that I took and specially wrote one character in another encoding. I got such a scheme, and it's too late to correct the symbol. And I have no right to do it.
– ip696
Nov 22 at 14:43




I know actually. You should not think that I took and specially wrote one character in another encoding. I got such a scheme, and it's too late to correct the symbol. And I have no right to do it.
– ip696
Nov 22 at 14:43












1 Answer
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You should better specify the Java property name using binding file.



<jaxb:bindings
version="1.0"
xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
xmlns:xs="http://www.w3.org/2001/XMLSchema">

<jaxb:bindings
schemaLocation=".../myschema.xsd"
node="/xs:schema">

<jaxb:bindings node="xs:complexType[@name='SomeType']/xs:attribute[@name='сreationDate']">
<jaxb:property name="creationDate"/>
</jaxb:bindings>
</jaxb:bindings>

</jaxb:bindings>


I'd also notified the schema authors - in case they would want to correct this.






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    1 Answer
    1






    active

    oldest

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    1 Answer
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    active

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    up vote
    0
    down vote













    You should better specify the Java property name using binding file.



    <jaxb:bindings
    version="1.0"
    xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
    xmlns:xs="http://www.w3.org/2001/XMLSchema">

    <jaxb:bindings
    schemaLocation=".../myschema.xsd"
    node="/xs:schema">

    <jaxb:bindings node="xs:complexType[@name='SomeType']/xs:attribute[@name='сreationDate']">
    <jaxb:property name="creationDate"/>
    </jaxb:bindings>
    </jaxb:bindings>

    </jaxb:bindings>


    I'd also notified the schema authors - in case they would want to correct this.






    share|improve this answer

























      up vote
      0
      down vote













      You should better specify the Java property name using binding file.



      <jaxb:bindings
      version="1.0"
      xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
      xmlns:xs="http://www.w3.org/2001/XMLSchema">

      <jaxb:bindings
      schemaLocation=".../myschema.xsd"
      node="/xs:schema">

      <jaxb:bindings node="xs:complexType[@name='SomeType']/xs:attribute[@name='сreationDate']">
      <jaxb:property name="creationDate"/>
      </jaxb:bindings>
      </jaxb:bindings>

      </jaxb:bindings>


      I'd also notified the schema authors - in case they would want to correct this.






      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        You should better specify the Java property name using binding file.



        <jaxb:bindings
        version="1.0"
        xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
        xmlns:xs="http://www.w3.org/2001/XMLSchema">

        <jaxb:bindings
        schemaLocation=".../myschema.xsd"
        node="/xs:schema">

        <jaxb:bindings node="xs:complexType[@name='SomeType']/xs:attribute[@name='сreationDate']">
        <jaxb:property name="creationDate"/>
        </jaxb:bindings>
        </jaxb:bindings>

        </jaxb:bindings>


        I'd also notified the schema authors - in case they would want to correct this.






        share|improve this answer












        You should better specify the Java property name using binding file.



        <jaxb:bindings
        version="1.0"
        xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
        xmlns:xs="http://www.w3.org/2001/XMLSchema">

        <jaxb:bindings
        schemaLocation=".../myschema.xsd"
        node="/xs:schema">

        <jaxb:bindings node="xs:complexType[@name='SomeType']/xs:attribute[@name='сreationDate']">
        <jaxb:property name="creationDate"/>
        </jaxb:bindings>
        </jaxb:bindings>

        </jaxb:bindings>


        I'd also notified the schema authors - in case they would want to correct this.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 23 at 21:23









        lexicore

        30.8k882154




        30.8k882154






























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