connection to database with password containing dollar signs and exclamation marks
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1
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I am trying to open a connection using psql to a database.
The connection string looked like this
psql -A -t -c "sql query" postgresql://$1@$2/$3
Where I passed as first parameter
$1 = login:password
$2 = localhost:5432
$3 = dbname
It worked fined when login and password was pretty much standard like 123 and so on.
But when I try to connect using a password like 123412@15!12$ it fails with the incorrect password.
How to escape it property?
bash git-bash
asked Nov 22 at 9:58
lapots
3,5411258125
add a comment |
up vote
1
down vote
favorite
I am trying to open a connection using psql to a database.
The connection string looked like this
psql -A -t -c "sql query" postgresql://$1@$2/$3
Where I passed as first parameter
$1 = login:password
$2 = localhost:5432
$3 = dbname
It worked fined when login and password was pretty much standard like 123 and so on.
But when I try to connect using a password like 123412@15!12$ it fails with the incorrect password.
How to escape it property?
bash git-bash
asked Nov 22 at 9:58
lapots
3,5411258125
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I am trying to open a connection using psql to a database.
The connection string looked like this
psql -A -t -c "sql query" postgresql://$1@$2/$3
Where I passed as first parameter
$1 = login:password
$2 = localhost:5432
$3 = dbname
It worked fined when login and password was pretty much standard like 123 and so on.
But when I try to connect using a password like 123412@15!12$ it fails with the incorrect password.
How to escape it property?
bash git-bash
asked Nov 22 at 9:58
lapots
3,5411258125
I am trying to open a connection using psql to a database.
The connection string looked like this
psql -A -t -c "sql query" postgresql://$1@$2/$3
Where I passed as first parameter
$1 = login:password
$2 = localhost:5432
$3 = dbname
It worked fined when login and password was pretty much standard like 123 and so on.
But when I try to connect using a password like 123412@15!12$ it fails with the incorrect password.
How to escape it property?
bash git-bash
bash git-bash
asked Nov 22 at 9:58
lapots
3,5411258125
asked Nov 22 at 9:58
lapots
3,5411258125
asked Nov 22 at 9:58
lapots
3,5411258125
asked Nov 22 at 9:58
lapots
3,5411258125
asked Nov 22 at 9:58
lapots
3,5411258125
3,5411258125
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
I would use safer variable placing:
psql -A -t -c "sql query" "postgresql://${1}@${2}/${3}"
In addition parameters $1, $2, $3 should be passed as:
script.sh 'login:password' 'localhost:5432' 'dbname'
answered Nov 22 at 10:14
Kubator
5078
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
I would use safer variable placing:
psql -A -t -c "sql query" "postgresql://${1}@${2}/${3}"
In addition parameters $1, $2, $3 should be passed as:
script.sh 'login:password' 'localhost:5432' 'dbname'
answered Nov 22 at 10:14
Kubator
5078
add a comment |
up vote
1
down vote
accepted
I would use safer variable placing:
psql -A -t -c "sql query" "postgresql://${1}@${2}/${3}"
In addition parameters $1, $2, $3 should be passed as:
script.sh 'login:password' 'localhost:5432' 'dbname'
answered Nov 22 at 10:14
Kubator
5078
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
I would use safer variable placing:
psql -A -t -c "sql query" "postgresql://${1}@${2}/${3}"
In addition parameters $1, $2, $3 should be passed as:
script.sh 'login:password' 'localhost:5432' 'dbname'
answered Nov 22 at 10:14
Kubator
5078
I would use safer variable placing:
psql -A -t -c "sql query" "postgresql://${1}@${2}/${3}"
In addition parameters $1, $2, $3 should be passed as:
script.sh 'login:password' 'localhost:5432' 'dbname'
answered Nov 22 at 10:14
Kubator
5078
answered Nov 22 at 10:14
Kubator
5078
answered Nov 22 at 10:14
Kubator
5078
answered Nov 22 at 10:14
Kubator
5078
5078
add a comment |
add a comment |
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