Homotheties: Let A and B be distinct points of a circle o. What is the set of possible centroids of triangles...











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Question: Let A and B be distinct points of a circle o. What is the set
of possible centroids of triangles ABC with C ∈ o?



Here is what I have:
The angle at C will always be the same as it is always subtended by the same arc as A and B are fixed.



There are 2 cases: Either C lies on the small arc of AB or C lies on the big arc of AB.



In the case where C lies on the large arc, by looking at the possible positions of C one can observe that at some point C and A are on the same diameter and at another point C and B are on the same diameter. Also, it is worth mentioning that the midpoint at which c intersects on the chord AB does not depend on C and is thus always the same.



One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points C all seem to lie on a smaller circle contained in the original circle o.



One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale r1/r2 where r1 is the radius of the larger circle and r2 is the radius of the smaller circle(I am really not sure about this).



I am not sure what to say about the case where c lies on the small arc and am not sure where to continue with the problem.



Any help is appreciated.










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    up vote
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    favorite












    Question: Let A and B be distinct points of a circle o. What is the set
    of possible centroids of triangles ABC with C ∈ o?



    Here is what I have:
    The angle at C will always be the same as it is always subtended by the same arc as A and B are fixed.



    There are 2 cases: Either C lies on the small arc of AB or C lies on the big arc of AB.



    In the case where C lies on the large arc, by looking at the possible positions of C one can observe that at some point C and A are on the same diameter and at another point C and B are on the same diameter. Also, it is worth mentioning that the midpoint at which c intersects on the chord AB does not depend on C and is thus always the same.



    One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points C all seem to lie on a smaller circle contained in the original circle o.



    One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale r1/r2 where r1 is the radius of the larger circle and r2 is the radius of the smaller circle(I am really not sure about this).



    I am not sure what to say about the case where c lies on the small arc and am not sure where to continue with the problem.



    Any help is appreciated.










    share|cite|improve this question







    New contributor




    rico is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      3
      down vote

      favorite









      up vote
      3
      down vote

      favorite











      Question: Let A and B be distinct points of a circle o. What is the set
      of possible centroids of triangles ABC with C ∈ o?



      Here is what I have:
      The angle at C will always be the same as it is always subtended by the same arc as A and B are fixed.



      There are 2 cases: Either C lies on the small arc of AB or C lies on the big arc of AB.



      In the case where C lies on the large arc, by looking at the possible positions of C one can observe that at some point C and A are on the same diameter and at another point C and B are on the same diameter. Also, it is worth mentioning that the midpoint at which c intersects on the chord AB does not depend on C and is thus always the same.



      One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points C all seem to lie on a smaller circle contained in the original circle o.



      One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale r1/r2 where r1 is the radius of the larger circle and r2 is the radius of the smaller circle(I am really not sure about this).



      I am not sure what to say about the case where c lies on the small arc and am not sure where to continue with the problem.



      Any help is appreciated.










      share|cite|improve this question







      New contributor




      rico is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      Question: Let A and B be distinct points of a circle o. What is the set
      of possible centroids of triangles ABC with C ∈ o?



      Here is what I have:
      The angle at C will always be the same as it is always subtended by the same arc as A and B are fixed.



      There are 2 cases: Either C lies on the small arc of AB or C lies on the big arc of AB.



      In the case where C lies on the large arc, by looking at the possible positions of C one can observe that at some point C and A are on the same diameter and at another point C and B are on the same diameter. Also, it is worth mentioning that the midpoint at which c intersects on the chord AB does not depend on C and is thus always the same.



      One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points C all seem to lie on a smaller circle contained in the original circle o.



      One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale r1/r2 where r1 is the radius of the larger circle and r2 is the radius of the smaller circle(I am really not sure about this).



      I am not sure what to say about the case where c lies on the small arc and am not sure where to continue with the problem.



      Any help is appreciated.







      geometry euclidean-geometry






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      rico is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      Check out our Code of Conduct.









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      asked 3 hours ago









      rico

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      rico is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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      Check out our Code of Conduct.






















          2 Answers
          2






          active

          oldest

          votes

















          up vote
          2
          down vote



          accepted










          [This is just a translation of Carl Schildkraut's answer into synthetic language.]



          Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.






          share|cite|improve this answer




























            up vote
            3
            down vote













            Here's a moderately obnoxious idea:



            If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



            There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.






            share|cite|improve this answer





















            • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
              – rico
              3 hours ago










            • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
              – Eric Wofsey
              3 hours ago











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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            2
            down vote



            accepted










            [This is just a translation of Carl Schildkraut's answer into synthetic language.]



            Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.






            share|cite|improve this answer

























              up vote
              2
              down vote



              accepted










              [This is just a translation of Carl Schildkraut's answer into synthetic language.]



              Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.






              share|cite|improve this answer























                up vote
                2
                down vote



                accepted







                up vote
                2
                down vote



                accepted






                [This is just a translation of Carl Schildkraut's answer into synthetic language.]



                Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.






                share|cite|improve this answer












                [This is just a translation of Carl Schildkraut's answer into synthetic language.]



                Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered 2 hours ago









                Eric Wofsey

                177k12202328




                177k12202328






















                    up vote
                    3
                    down vote













                    Here's a moderately obnoxious idea:



                    If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



                    There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.






                    share|cite|improve this answer





















                    • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                      – rico
                      3 hours ago










                    • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                      – Eric Wofsey
                      3 hours ago















                    up vote
                    3
                    down vote













                    Here's a moderately obnoxious idea:



                    If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



                    There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.






                    share|cite|improve this answer





















                    • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                      – rico
                      3 hours ago










                    • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                      – Eric Wofsey
                      3 hours ago













                    up vote
                    3
                    down vote










                    up vote
                    3
                    down vote









                    Here's a moderately obnoxious idea:



                    If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



                    There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.






                    share|cite|improve this answer












                    Here's a moderately obnoxious idea:



                    If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



                    There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered 3 hours ago









                    Carl Schildkraut

                    10.9k11439




                    10.9k11439












                    • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                      – rico
                      3 hours ago










                    • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                      – Eric Wofsey
                      3 hours ago


















                    • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                      – rico
                      3 hours ago










                    • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                      – Eric Wofsey
                      3 hours ago
















                    Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                    – rico
                    3 hours ago




                    Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                    – rico
                    3 hours ago












                    In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                    – Eric Wofsey
                    3 hours ago




                    In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                    – Eric Wofsey
                    3 hours ago










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