Homotheties: Let A and B be distinct points of a circle o. What is the set of possible centroids of triangles...
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Question: Let A and B be distinct points of a circle o. What is the set
of possible centroids of triangles ABC with C ∈ o?
Here is what I have:
The angle at C will always be the same as it is always subtended by the same arc as A and B are fixed.
There are 2 cases: Either C lies on the small arc of AB or C lies on the big arc of AB.
In the case where C lies on the large arc, by looking at the possible positions of C one can observe that at some point C and A are on the same diameter and at another point C and B are on the same diameter. Also, it is worth mentioning that the midpoint at which c intersects on the chord AB does not depend on C and is thus always the same.
One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points C all seem to lie on a smaller circle contained in the original circle o.
One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale r1/r2 where r1 is the radius of the larger circle and r2 is the radius of the smaller circle(I am really not sure about this).
I am not sure what to say about the case where c lies on the small arc and am not sure where to continue with the problem.
Any help is appreciated.
geometry euclidean-geometry
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up vote
3
down vote
favorite
Question: Let A and B be distinct points of a circle o. What is the set
of possible centroids of triangles ABC with C ∈ o?
Here is what I have:
The angle at C will always be the same as it is always subtended by the same arc as A and B are fixed.
There are 2 cases: Either C lies on the small arc of AB or C lies on the big arc of AB.
In the case where C lies on the large arc, by looking at the possible positions of C one can observe that at some point C and A are on the same diameter and at another point C and B are on the same diameter. Also, it is worth mentioning that the midpoint at which c intersects on the chord AB does not depend on C and is thus always the same.
One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points C all seem to lie on a smaller circle contained in the original circle o.
One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale r1/r2 where r1 is the radius of the larger circle and r2 is the radius of the smaller circle(I am really not sure about this).
I am not sure what to say about the case where c lies on the small arc and am not sure where to continue with the problem.
Any help is appreciated.
geometry euclidean-geometry
New contributor
add a comment |
up vote
3
down vote
favorite
up vote
3
down vote
favorite
Question: Let A and B be distinct points of a circle o. What is the set
of possible centroids of triangles ABC with C ∈ o?
Here is what I have:
The angle at C will always be the same as it is always subtended by the same arc as A and B are fixed.
There are 2 cases: Either C lies on the small arc of AB or C lies on the big arc of AB.
In the case where C lies on the large arc, by looking at the possible positions of C one can observe that at some point C and A are on the same diameter and at another point C and B are on the same diameter. Also, it is worth mentioning that the midpoint at which c intersects on the chord AB does not depend on C and is thus always the same.
One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points C all seem to lie on a smaller circle contained in the original circle o.
One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale r1/r2 where r1 is the radius of the larger circle and r2 is the radius of the smaller circle(I am really not sure about this).
I am not sure what to say about the case where c lies on the small arc and am not sure where to continue with the problem.
Any help is appreciated.
geometry euclidean-geometry
New contributor
Question: Let A and B be distinct points of a circle o. What is the set
of possible centroids of triangles ABC with C ∈ o?
Here is what I have:
The angle at C will always be the same as it is always subtended by the same arc as A and B are fixed.
There are 2 cases: Either C lies on the small arc of AB or C lies on the big arc of AB.
In the case where C lies on the large arc, by looking at the possible positions of C one can observe that at some point C and A are on the same diameter and at another point C and B are on the same diameter. Also, it is worth mentioning that the midpoint at which c intersects on the chord AB does not depend on C and is thus always the same.
One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points C all seem to lie on a smaller circle contained in the original circle o.
One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale r1/r2 where r1 is the radius of the larger circle and r2 is the radius of the smaller circle(I am really not sure about this).
I am not sure what to say about the case where c lies on the small arc and am not sure where to continue with the problem.
Any help is appreciated.
geometry euclidean-geometry
geometry euclidean-geometry
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asked 3 hours ago
rico
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2 Answers
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[This is just a translation of Carl Schildkraut's answer into synthetic language.]
Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.
add a comment |
up vote
3
down vote
Here's a moderately obnoxious idea:
If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).
There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.
Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
– rico
3 hours ago
In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
– Eric Wofsey
3 hours ago
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
[This is just a translation of Carl Schildkraut's answer into synthetic language.]
Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.
add a comment |
up vote
2
down vote
accepted
[This is just a translation of Carl Schildkraut's answer into synthetic language.]
Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
[This is just a translation of Carl Schildkraut's answer into synthetic language.]
Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.
[This is just a translation of Carl Schildkraut's answer into synthetic language.]
Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.
answered 2 hours ago
Eric Wofsey
177k12202328
177k12202328
add a comment |
add a comment |
up vote
3
down vote
Here's a moderately obnoxious idea:
If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).
There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.
Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
– rico
3 hours ago
In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
– Eric Wofsey
3 hours ago
add a comment |
up vote
3
down vote
Here's a moderately obnoxious idea:
If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).
There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.
Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
– rico
3 hours ago
In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
– Eric Wofsey
3 hours ago
add a comment |
up vote
3
down vote
up vote
3
down vote
Here's a moderately obnoxious idea:
If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).
There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.
Here's a moderately obnoxious idea:
If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).
There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.
answered 3 hours ago
Carl Schildkraut
10.9k11439
10.9k11439
Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
– rico
3 hours ago
In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
– Eric Wofsey
3 hours ago
add a comment |
Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
– rico
3 hours ago
In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
– Eric Wofsey
3 hours ago
Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
– rico
3 hours ago
Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
– rico
3 hours ago
In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
– Eric Wofsey
3 hours ago
In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
– Eric Wofsey
3 hours ago
add a comment |
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rico is a new contributor. Be nice, and check out our Code of Conduct.
rico is a new contributor. Be nice, and check out our Code of Conduct.
rico is a new contributor. Be nice, and check out our Code of Conduct.
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