How to do “If div class is 0 then start from 1 to append”












0














I'm trying to make multiple upload images via ajax with XMLHttpRequest. Everything is okay. Images post successfully and data returns as expected. So returned images are appending to related div class. But every time i upload images one by one, div class start from zero.



With this code,before to send file(s) i'm creating progressbar div, after each image loaded successfully, image replace to loder.



for (var i = 0; i < input.files.length; i++) {
var fileId = i;
$('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
'<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
'</div>');
}


With this function, no matter how many files, im uploading them:



for (var i = 0; i < this.files.length; i++) { //Progress bar and status label's for each file genarate dynamically
var fileId = i

$('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
'<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
'</div>');

}

function uploadSingleFile(file, i) {

var fileId = i;
var ajax = new XMLHttpRequest();
//Progress Listener
ajax.upload.onprogress = function (e) {
var percent = (e.loaded / e.total) * 100;
$('#progressbar_' + fileId).animate({"width": percent + "%"},800);
};

//Load Listener
ajax.onreadystatechange = function (e) {
if (this.readyState == 4 && this.status == 200) {
var data = ajax.responseText;
var rep = JSON.parse(data);

$('#progressbar_' + fileId).css("width", "100%");
setTimeout(function(){
$('#progressbar_' + fileId).remove();
$('.uploaded_photo_grid.'+ fileId).html('');
$.each(file, function(){

if(rep.error !== ''){
$(".uploaded_photo_grid."+ fileId ).html(rep.name + ' yüklenemedi');
} else {
$(".uploaded_photo_grid."+ fileId ).html(
'<img class="previewItem" src="'+rep.fcontent+'" id="img_'+rep.id+'">');
}

});
},1500);
}
};

Rest of code...
}


Also i tried editing these lines of code. It increases the value of div for each file but just first image appears.



var zero = $('.uploaded_photo_grid.0').length;
for (var i = 0; i < this.files.length; i++) { //Progress bar and status label's for each file genarate dynamically
var fileId;
if(zero == 0){
uploadSingleFile(this.files[i], i);
console.log(this.files[i]);
fileId = i;
} else {
uploadSingleFile(this.files[i+1], i+1);
fileId = i+1;
console.log(this.files[i]);
}

$('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
'<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
'</div>');

}


What should i do? Is there a way to do this better? I mean upload images without form via XML with progressbar for each file. I don't choose to use plugin, that's not for me.










share|improve this question



























    0














    I'm trying to make multiple upload images via ajax with XMLHttpRequest. Everything is okay. Images post successfully and data returns as expected. So returned images are appending to related div class. But every time i upload images one by one, div class start from zero.



    With this code,before to send file(s) i'm creating progressbar div, after each image loaded successfully, image replace to loder.



    for (var i = 0; i < input.files.length; i++) {
    var fileId = i;
    $('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
    '<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
    '</div>');
    }


    With this function, no matter how many files, im uploading them:



    for (var i = 0; i < this.files.length; i++) { //Progress bar and status label's for each file genarate dynamically
    var fileId = i

    $('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
    '<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
    '</div>');

    }

    function uploadSingleFile(file, i) {

    var fileId = i;
    var ajax = new XMLHttpRequest();
    //Progress Listener
    ajax.upload.onprogress = function (e) {
    var percent = (e.loaded / e.total) * 100;
    $('#progressbar_' + fileId).animate({"width": percent + "%"},800);
    };

    //Load Listener
    ajax.onreadystatechange = function (e) {
    if (this.readyState == 4 && this.status == 200) {
    var data = ajax.responseText;
    var rep = JSON.parse(data);

    $('#progressbar_' + fileId).css("width", "100%");
    setTimeout(function(){
    $('#progressbar_' + fileId).remove();
    $('.uploaded_photo_grid.'+ fileId).html('');
    $.each(file, function(){

    if(rep.error !== ''){
    $(".uploaded_photo_grid."+ fileId ).html(rep.name + ' yüklenemedi');
    } else {
    $(".uploaded_photo_grid."+ fileId ).html(
    '<img class="previewItem" src="'+rep.fcontent+'" id="img_'+rep.id+'">');
    }

    });
    },1500);
    }
    };

    Rest of code...
    }


    Also i tried editing these lines of code. It increases the value of div for each file but just first image appears.



    var zero = $('.uploaded_photo_grid.0').length;
    for (var i = 0; i < this.files.length; i++) { //Progress bar and status label's for each file genarate dynamically
    var fileId;
    if(zero == 0){
    uploadSingleFile(this.files[i], i);
    console.log(this.files[i]);
    fileId = i;
    } else {
    uploadSingleFile(this.files[i+1], i+1);
    fileId = i+1;
    console.log(this.files[i]);
    }

    $('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
    '<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
    '</div>');

    }


    What should i do? Is there a way to do this better? I mean upload images without form via XML with progressbar for each file. I don't choose to use plugin, that's not for me.










    share|improve this question

























      0












      0








      0







      I'm trying to make multiple upload images via ajax with XMLHttpRequest. Everything is okay. Images post successfully and data returns as expected. So returned images are appending to related div class. But every time i upload images one by one, div class start from zero.



      With this code,before to send file(s) i'm creating progressbar div, after each image loaded successfully, image replace to loder.



      for (var i = 0; i < input.files.length; i++) {
      var fileId = i;
      $('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
      '<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
      '</div>');
      }


      With this function, no matter how many files, im uploading them:



      for (var i = 0; i < this.files.length; i++) { //Progress bar and status label's for each file genarate dynamically
      var fileId = i

      $('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
      '<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
      '</div>');

      }

      function uploadSingleFile(file, i) {

      var fileId = i;
      var ajax = new XMLHttpRequest();
      //Progress Listener
      ajax.upload.onprogress = function (e) {
      var percent = (e.loaded / e.total) * 100;
      $('#progressbar_' + fileId).animate({"width": percent + "%"},800);
      };

      //Load Listener
      ajax.onreadystatechange = function (e) {
      if (this.readyState == 4 && this.status == 200) {
      var data = ajax.responseText;
      var rep = JSON.parse(data);

      $('#progressbar_' + fileId).css("width", "100%");
      setTimeout(function(){
      $('#progressbar_' + fileId).remove();
      $('.uploaded_photo_grid.'+ fileId).html('');
      $.each(file, function(){

      if(rep.error !== ''){
      $(".uploaded_photo_grid."+ fileId ).html(rep.name + ' yüklenemedi');
      } else {
      $(".uploaded_photo_grid."+ fileId ).html(
      '<img class="previewItem" src="'+rep.fcontent+'" id="img_'+rep.id+'">');
      }

      });
      },1500);
      }
      };

      Rest of code...
      }


      Also i tried editing these lines of code. It increases the value of div for each file but just first image appears.



      var zero = $('.uploaded_photo_grid.0').length;
      for (var i = 0; i < this.files.length; i++) { //Progress bar and status label's for each file genarate dynamically
      var fileId;
      if(zero == 0){
      uploadSingleFile(this.files[i], i);
      console.log(this.files[i]);
      fileId = i;
      } else {
      uploadSingleFile(this.files[i+1], i+1);
      fileId = i+1;
      console.log(this.files[i]);
      }

      $('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
      '<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
      '</div>');

      }


      What should i do? Is there a way to do this better? I mean upload images without form via XML with progressbar for each file. I don't choose to use plugin, that's not for me.










      share|improve this question













      I'm trying to make multiple upload images via ajax with XMLHttpRequest. Everything is okay. Images post successfully and data returns as expected. So returned images are appending to related div class. But every time i upload images one by one, div class start from zero.



      With this code,before to send file(s) i'm creating progressbar div, after each image loaded successfully, image replace to loder.



      for (var i = 0; i < input.files.length; i++) {
      var fileId = i;
      $('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
      '<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
      '</div>');
      }


      With this function, no matter how many files, im uploading them:



      for (var i = 0; i < this.files.length; i++) { //Progress bar and status label's for each file genarate dynamically
      var fileId = i

      $('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
      '<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
      '</div>');

      }

      function uploadSingleFile(file, i) {

      var fileId = i;
      var ajax = new XMLHttpRequest();
      //Progress Listener
      ajax.upload.onprogress = function (e) {
      var percent = (e.loaded / e.total) * 100;
      $('#progressbar_' + fileId).animate({"width": percent + "%"},800);
      };

      //Load Listener
      ajax.onreadystatechange = function (e) {
      if (this.readyState == 4 && this.status == 200) {
      var data = ajax.responseText;
      var rep = JSON.parse(data);

      $('#progressbar_' + fileId).css("width", "100%");
      setTimeout(function(){
      $('#progressbar_' + fileId).remove();
      $('.uploaded_photo_grid.'+ fileId).html('');
      $.each(file, function(){

      if(rep.error !== ''){
      $(".uploaded_photo_grid."+ fileId ).html(rep.name + ' yüklenemedi');
      } else {
      $(".uploaded_photo_grid."+ fileId ).html(
      '<img class="previewItem" src="'+rep.fcontent+'" id="img_'+rep.id+'">');
      }

      });
      },1500);
      }
      };

      Rest of code...
      }


      Also i tried editing these lines of code. It increases the value of div for each file but just first image appears.



      var zero = $('.uploaded_photo_grid.0').length;
      for (var i = 0; i < this.files.length; i++) { //Progress bar and status label's for each file genarate dynamically
      var fileId;
      if(zero == 0){
      uploadSingleFile(this.files[i], i);
      console.log(this.files[i]);
      fileId = i;
      } else {
      uploadSingleFile(this.files[i+1], i+1);
      fileId = i+1;
      console.log(this.files[i]);
      }

      $('.up_preview').append('<div class="uploaded_photo_grid '+ fileId +'">' +
      '<div class="pro_bar" id="progressbar_' + fileId + '" style="width:0%"></div>' + loader +
      '</div>');

      }


      What should i do? Is there a way to do this better? I mean upload images without form via XML with progressbar for each file. I don't choose to use plugin, that's not for me.







      php jquery xml uploader






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 23 at 0:30









      Plunch

      74




      74
























          1 Answer
          1






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          oldest

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          0














          The following is the problematic line.



          uploadSingleFile(this.files[i+1], i+1);


          You want the value for i passed in uploadSingleFile to be the total number of images uploaded incremented by one.



          One approach to do this is to sum $('.up_preview').children().length, i, and 1. 1 is added in the sum because the in the loop i starts at 0.



          // var zero = $('.uploaded_photo_grid.0').length;
          var numImages = $('.up_preview').children().length;

          if (numImages === 0) {
          //...
          } else {
          uploadSingleFile(this.files[i+1], numImages + i + 1);
          }





          share|improve this answer





















          • It works! Thank you so much
            – Plunch
            Nov 23 at 1:58











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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

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          active

          oldest

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          0














          The following is the problematic line.



          uploadSingleFile(this.files[i+1], i+1);


          You want the value for i passed in uploadSingleFile to be the total number of images uploaded incremented by one.



          One approach to do this is to sum $('.up_preview').children().length, i, and 1. 1 is added in the sum because the in the loop i starts at 0.



          // var zero = $('.uploaded_photo_grid.0').length;
          var numImages = $('.up_preview').children().length;

          if (numImages === 0) {
          //...
          } else {
          uploadSingleFile(this.files[i+1], numImages + i + 1);
          }





          share|improve this answer





















          • It works! Thank you so much
            – Plunch
            Nov 23 at 1:58
















          0














          The following is the problematic line.



          uploadSingleFile(this.files[i+1], i+1);


          You want the value for i passed in uploadSingleFile to be the total number of images uploaded incremented by one.



          One approach to do this is to sum $('.up_preview').children().length, i, and 1. 1 is added in the sum because the in the loop i starts at 0.



          // var zero = $('.uploaded_photo_grid.0').length;
          var numImages = $('.up_preview').children().length;

          if (numImages === 0) {
          //...
          } else {
          uploadSingleFile(this.files[i+1], numImages + i + 1);
          }





          share|improve this answer





















          • It works! Thank you so much
            – Plunch
            Nov 23 at 1:58














          0












          0








          0






          The following is the problematic line.



          uploadSingleFile(this.files[i+1], i+1);


          You want the value for i passed in uploadSingleFile to be the total number of images uploaded incremented by one.



          One approach to do this is to sum $('.up_preview').children().length, i, and 1. 1 is added in the sum because the in the loop i starts at 0.



          // var zero = $('.uploaded_photo_grid.0').length;
          var numImages = $('.up_preview').children().length;

          if (numImages === 0) {
          //...
          } else {
          uploadSingleFile(this.files[i+1], numImages + i + 1);
          }





          share|improve this answer












          The following is the problematic line.



          uploadSingleFile(this.files[i+1], i+1);


          You want the value for i passed in uploadSingleFile to be the total number of images uploaded incremented by one.



          One approach to do this is to sum $('.up_preview').children().length, i, and 1. 1 is added in the sum because the in the loop i starts at 0.



          // var zero = $('.uploaded_photo_grid.0').length;
          var numImages = $('.up_preview').children().length;

          if (numImages === 0) {
          //...
          } else {
          uploadSingleFile(this.files[i+1], numImages + i + 1);
          }






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 23 at 1:04









          Oluwafemi Sule

          10.9k1431




          10.9k1431












          • It works! Thank you so much
            – Plunch
            Nov 23 at 1:58


















          • It works! Thank you so much
            – Plunch
            Nov 23 at 1:58
















          It works! Thank you so much
          – Plunch
          Nov 23 at 1:58




          It works! Thank you so much
          – Plunch
          Nov 23 at 1:58


















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