excel To return the Header from the last number that >100 in a row











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I wish to To return the Header from the last number in row B that >100 , but currently I only manage to get the first number that >100 which is "july", But the answer that I want is "Aug" please help...



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    up vote
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    down vote

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    I wish to To return the Header from the last number in row B that >100 , but currently I only manage to get the first number that >100 which is "july", But the answer that I want is "Aug" please help...



    enter image description here










    share|improve this question
























      up vote
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      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I wish to To return the Header from the last number in row B that >100 , but currently I only manage to get the first number that >100 which is "july", But the answer that I want is "Aug" please help...



      enter image description here










      share|improve this question













      I wish to To return the Header from the last number in row B that >100 , but currently I only manage to get the first number that >100 which is "july", But the answer that I want is "Aug" please help...



      enter image description here







      excel-formula






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      asked Nov 22 at 10:35









      Issac_n

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      157
























          1 Answer
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          This array formula (ctrl+shift+enter !) should do the trick:
          {=INDEX($P$1:$AA$1,MAX(IF(P2:AA2>100,COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2,1,1))+1)))}



          The way this works is the following (and you can follow this if you select a part in the formula bar in Excel and type F9 to see the intermediate result) :





          • COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2;1;1))+1 creates a very simple array withe the column numbers of your range result={1,2,3,4,5,6,7,8,9,10,11,12}

          • The P2:AA2>100 also creates an array with TRUE/FALSE when the condition is met result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,TRUE,TRUE,FALSE,FALSE,FALSE,FALSE}

          • The IF combines both : result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,7,8,FALSE,FALSE,FALSE,FALSE}

          • With the MAX you select the largest value, which will be 8 in our case

          • And with the INDEX you get then the 8th value of the range, which is Aug


          So the trick is combining a matching condition with a simple sequential array with the same number of values as there are in your range.






          share|improve this answer























          • it works!!!!!, but can really understand your coding.. could u pls explain it?
            – Issac_n
            Nov 22 at 11:50










          • Ok, I'll update my answer with some explanation (and please accept the answer if it is to your satisfaction ;))
            – Peter K.
            Nov 22 at 12:01










          • possible coidng ctrl+shift+enter into vba?
            – Issac_n
            Nov 22 at 12:32










          • I never use VBA, so I cannot help you with that.
            – Peter K.
            Nov 22 at 12:58










          • @Issac_n For VBA, see this SO question and accepted answer : stackoverflow.com/questions/27604084/…
            – Peter K.
            Nov 23 at 12:36













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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          1
          down vote



          accepted










          This array formula (ctrl+shift+enter !) should do the trick:
          {=INDEX($P$1:$AA$1,MAX(IF(P2:AA2>100,COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2,1,1))+1)))}



          The way this works is the following (and you can follow this if you select a part in the formula bar in Excel and type F9 to see the intermediate result) :





          • COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2;1;1))+1 creates a very simple array withe the column numbers of your range result={1,2,3,4,5,6,7,8,9,10,11,12}

          • The P2:AA2>100 also creates an array with TRUE/FALSE when the condition is met result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,TRUE,TRUE,FALSE,FALSE,FALSE,FALSE}

          • The IF combines both : result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,7,8,FALSE,FALSE,FALSE,FALSE}

          • With the MAX you select the largest value, which will be 8 in our case

          • And with the INDEX you get then the 8th value of the range, which is Aug


          So the trick is combining a matching condition with a simple sequential array with the same number of values as there are in your range.






          share|improve this answer























          • it works!!!!!, but can really understand your coding.. could u pls explain it?
            – Issac_n
            Nov 22 at 11:50










          • Ok, I'll update my answer with some explanation (and please accept the answer if it is to your satisfaction ;))
            – Peter K.
            Nov 22 at 12:01










          • possible coidng ctrl+shift+enter into vba?
            – Issac_n
            Nov 22 at 12:32










          • I never use VBA, so I cannot help you with that.
            – Peter K.
            Nov 22 at 12:58










          • @Issac_n For VBA, see this SO question and accepted answer : stackoverflow.com/questions/27604084/…
            – Peter K.
            Nov 23 at 12:36

















          up vote
          1
          down vote



          accepted










          This array formula (ctrl+shift+enter !) should do the trick:
          {=INDEX($P$1:$AA$1,MAX(IF(P2:AA2>100,COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2,1,1))+1)))}



          The way this works is the following (and you can follow this if you select a part in the formula bar in Excel and type F9 to see the intermediate result) :





          • COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2;1;1))+1 creates a very simple array withe the column numbers of your range result={1,2,3,4,5,6,7,8,9,10,11,12}

          • The P2:AA2>100 also creates an array with TRUE/FALSE when the condition is met result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,TRUE,TRUE,FALSE,FALSE,FALSE,FALSE}

          • The IF combines both : result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,7,8,FALSE,FALSE,FALSE,FALSE}

          • With the MAX you select the largest value, which will be 8 in our case

          • And with the INDEX you get then the 8th value of the range, which is Aug


          So the trick is combining a matching condition with a simple sequential array with the same number of values as there are in your range.






          share|improve this answer























          • it works!!!!!, but can really understand your coding.. could u pls explain it?
            – Issac_n
            Nov 22 at 11:50










          • Ok, I'll update my answer with some explanation (and please accept the answer if it is to your satisfaction ;))
            – Peter K.
            Nov 22 at 12:01










          • possible coidng ctrl+shift+enter into vba?
            – Issac_n
            Nov 22 at 12:32










          • I never use VBA, so I cannot help you with that.
            – Peter K.
            Nov 22 at 12:58










          • @Issac_n For VBA, see this SO question and accepted answer : stackoverflow.com/questions/27604084/…
            – Peter K.
            Nov 23 at 12:36















          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          This array formula (ctrl+shift+enter !) should do the trick:
          {=INDEX($P$1:$AA$1,MAX(IF(P2:AA2>100,COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2,1,1))+1)))}



          The way this works is the following (and you can follow this if you select a part in the formula bar in Excel and type F9 to see the intermediate result) :





          • COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2;1;1))+1 creates a very simple array withe the column numbers of your range result={1,2,3,4,5,6,7,8,9,10,11,12}

          • The P2:AA2>100 also creates an array with TRUE/FALSE when the condition is met result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,TRUE,TRUE,FALSE,FALSE,FALSE,FALSE}

          • The IF combines both : result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,7,8,FALSE,FALSE,FALSE,FALSE}

          • With the MAX you select the largest value, which will be 8 in our case

          • And with the INDEX you get then the 8th value of the range, which is Aug


          So the trick is combining a matching condition with a simple sequential array with the same number of values as there are in your range.






          share|improve this answer














          This array formula (ctrl+shift+enter !) should do the trick:
          {=INDEX($P$1:$AA$1,MAX(IF(P2:AA2>100,COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2,1,1))+1)))}



          The way this works is the following (and you can follow this if you select a part in the formula bar in Excel and type F9 to see the intermediate result) :





          • COLUMN(P2:AA2)-COLUMN(INDEX(P2:AA2;1;1))+1 creates a very simple array withe the column numbers of your range result={1,2,3,4,5,6,7,8,9,10,11,12}

          • The P2:AA2>100 also creates an array with TRUE/FALSE when the condition is met result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,TRUE,TRUE,FALSE,FALSE,FALSE,FALSE}

          • The IF combines both : result={FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,7,8,FALSE,FALSE,FALSE,FALSE}

          • With the MAX you select the largest value, which will be 8 in our case

          • And with the INDEX you get then the 8th value of the range, which is Aug


          So the trick is combining a matching condition with a simple sequential array with the same number of values as there are in your range.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 22 at 12:12

























          answered Nov 22 at 11:32









          Peter K.

          67111




          67111












          • it works!!!!!, but can really understand your coding.. could u pls explain it?
            – Issac_n
            Nov 22 at 11:50










          • Ok, I'll update my answer with some explanation (and please accept the answer if it is to your satisfaction ;))
            – Peter K.
            Nov 22 at 12:01










          • possible coidng ctrl+shift+enter into vba?
            – Issac_n
            Nov 22 at 12:32










          • I never use VBA, so I cannot help you with that.
            – Peter K.
            Nov 22 at 12:58










          • @Issac_n For VBA, see this SO question and accepted answer : stackoverflow.com/questions/27604084/…
            – Peter K.
            Nov 23 at 12:36




















          • it works!!!!!, but can really understand your coding.. could u pls explain it?
            – Issac_n
            Nov 22 at 11:50










          • Ok, I'll update my answer with some explanation (and please accept the answer if it is to your satisfaction ;))
            – Peter K.
            Nov 22 at 12:01










          • possible coidng ctrl+shift+enter into vba?
            – Issac_n
            Nov 22 at 12:32










          • I never use VBA, so I cannot help you with that.
            – Peter K.
            Nov 22 at 12:58










          • @Issac_n For VBA, see this SO question and accepted answer : stackoverflow.com/questions/27604084/…
            – Peter K.
            Nov 23 at 12:36


















          it works!!!!!, but can really understand your coding.. could u pls explain it?
          – Issac_n
          Nov 22 at 11:50




          it works!!!!!, but can really understand your coding.. could u pls explain it?
          – Issac_n
          Nov 22 at 11:50












          Ok, I'll update my answer with some explanation (and please accept the answer if it is to your satisfaction ;))
          – Peter K.
          Nov 22 at 12:01




          Ok, I'll update my answer with some explanation (and please accept the answer if it is to your satisfaction ;))
          – Peter K.
          Nov 22 at 12:01












          possible coidng ctrl+shift+enter into vba?
          – Issac_n
          Nov 22 at 12:32




          possible coidng ctrl+shift+enter into vba?
          – Issac_n
          Nov 22 at 12:32












          I never use VBA, so I cannot help you with that.
          – Peter K.
          Nov 22 at 12:58




          I never use VBA, so I cannot help you with that.
          – Peter K.
          Nov 22 at 12:58












          @Issac_n For VBA, see this SO question and accepted answer : stackoverflow.com/questions/27604084/…
          – Peter K.
          Nov 23 at 12:36






          @Issac_n For VBA, see this SO question and accepted answer : stackoverflow.com/questions/27604084/…
          – Peter K.
          Nov 23 at 12:36




















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