Python XML SAX Parsing of Requests Object Produces ValueError: unknown url type

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I'm attempting to parse an RSS XML file using Diffused XML in Python 3.7. The relevant code is as follows:



def parse_xml_links(file, path, output):
handler = GenericContentHandler(path, output)
dsax.parse(file, handler)

def fetch_changes():
r = requests.get(rss_url)
return r

updates = fetch_changes()
parse_xml_links(updates.text, path, output)


The XML file header is:



<?xml version="1.0" encoding="utf-8" ?>
<rss version="0.91">


I get the following error on parsing:




ValueError: unknown url type: '?xml version="1.0" encoding="utf-8" ?>nn




The error occurs only when I attempt to parse a requests object, i.e. updates.text. No error occurs if I point to a local XML file.



I've tried this solution using this code:



parser = dsax.make_parser()
parser.setFeature(handler.feature_external_ges, False)
parser(file, handler, path, output)


However, the handler object doesn't have the attribute "feature_external_ges".



What is the error source, and how do you recommend I fix it? Obviously, I could save the requests object and parse the saved file; however, I'd like to understand if it's possible to parse the requests object.










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    up vote
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    I'm attempting to parse an RSS XML file using Diffused XML in Python 3.7. The relevant code is as follows:



    def parse_xml_links(file, path, output):
    handler = GenericContentHandler(path, output)
    dsax.parse(file, handler)

    def fetch_changes():
    r = requests.get(rss_url)
    return r

    updates = fetch_changes()
    parse_xml_links(updates.text, path, output)


    The XML file header is:



    <?xml version="1.0" encoding="utf-8" ?>
    <rss version="0.91">


    I get the following error on parsing:




    ValueError: unknown url type: '?xml version="1.0" encoding="utf-8" ?>nn




    The error occurs only when I attempt to parse a requests object, i.e. updates.text. No error occurs if I point to a local XML file.



    I've tried this solution using this code:



    parser = dsax.make_parser()
    parser.setFeature(handler.feature_external_ges, False)
    parser(file, handler, path, output)


    However, the handler object doesn't have the attribute "feature_external_ges".



    What is the error source, and how do you recommend I fix it? Obviously, I could save the requests object and parse the saved file; however, I'd like to understand if it's possible to parse the requests object.










    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm attempting to parse an RSS XML file using Diffused XML in Python 3.7. The relevant code is as follows:



      def parse_xml_links(file, path, output):
      handler = GenericContentHandler(path, output)
      dsax.parse(file, handler)

      def fetch_changes():
      r = requests.get(rss_url)
      return r

      updates = fetch_changes()
      parse_xml_links(updates.text, path, output)


      The XML file header is:



      <?xml version="1.0" encoding="utf-8" ?>
      <rss version="0.91">


      I get the following error on parsing:




      ValueError: unknown url type: '?xml version="1.0" encoding="utf-8" ?>nn




      The error occurs only when I attempt to parse a requests object, i.e. updates.text. No error occurs if I point to a local XML file.



      I've tried this solution using this code:



      parser = dsax.make_parser()
      parser.setFeature(handler.feature_external_ges, False)
      parser(file, handler, path, output)


      However, the handler object doesn't have the attribute "feature_external_ges".



      What is the error source, and how do you recommend I fix it? Obviously, I could save the requests object and parse the saved file; however, I'd like to understand if it's possible to parse the requests object.










      share|improve this question















      I'm attempting to parse an RSS XML file using Diffused XML in Python 3.7. The relevant code is as follows:



      def parse_xml_links(file, path, output):
      handler = GenericContentHandler(path, output)
      dsax.parse(file, handler)

      def fetch_changes():
      r = requests.get(rss_url)
      return r

      updates = fetch_changes()
      parse_xml_links(updates.text, path, output)


      The XML file header is:



      <?xml version="1.0" encoding="utf-8" ?>
      <rss version="0.91">


      I get the following error on parsing:




      ValueError: unknown url type: '?xml version="1.0" encoding="utf-8" ?>nn




      The error occurs only when I attempt to parse a requests object, i.e. updates.text. No error occurs if I point to a local XML file.



      I've tried this solution using this code:



      parser = dsax.make_parser()
      parser.setFeature(handler.feature_external_ges, False)
      parser(file, handler, path, output)


      However, the handler object doesn't have the attribute "feature_external_ges".



      What is the error source, and how do you recommend I fix it? Obviously, I could save the requests object and parse the saved file; however, I'd like to understand if it's possible to parse the requests object.







      xml python-3.x python-requests sax valueerror






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      edited Nov 25 at 2:07

























      asked Nov 22 at 1:32









      DivideByZero

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