why in c# casting object to objects of type T with same value aren't recognized the same?











up vote
4
down vote

favorite












I am getting into generics but there is something I don't understand Here I have this class;



    class Node<T>{
T value;
Node <T> next,prev;
public Node(T vl)
{
this.value=vl;
this.next=this.prev=null;
}
}


I have a class List and a method Insert and it is working fine :



 class Lista<T>
{
public Node<T> Head, Tail;
public int Cnt;

public Lista()
{
this.Head = this.Tail = null;
this.Cnt = 0;
}



public void Insert(T vl)
{
Node<T> nd = new Node<T>(vl);
if (this.IsEmpty())
this.Head = this.Tail = nd;
else
{
this.Tail.next = nd;
nd.prev = this.Tail;
this.Tail = nd;
}
this.Cnt++;
}


}


but I Have a method FindNode:



 public Node<T> FindNode(T vl)
{
if (this.IsEmpty()) return null;
Node<T> tmp = this.Head;
while (tmp != null && ((object)tmp.VL != (object)vl)) tmp = tmp.next;
return tmp;
}


which finds a Node inside the List now the problem is
if I have a Lista<string> it works fine but if I create a Lista<int>
even if the element in list exists while comparing it is ignoring the same values and going next until it goes null , why does that happen ?



Method isEmpty:



public bool IsEmpty()
{
if (this.Head == null && this.Tail == null) return true;
return false;
}









share|improve this question


















  • 1




    Generics was invented to avoid something like (object)tmp.VL.
    – SeM
    Nov 22 at 17:36










  • You haven't overloaded Equals so how is C# going to know you consider them the same? It can only check whether the variables refer to the same instance
    – Panagiotis Kanavos
    Nov 22 at 17:36












  • @SeM I know right but if I say tmp.VL==vl it says that operand== cannot be used to types T and T
    – Johnny Adams
    Nov 22 at 17:38










  • @PanagiotisKanavos how do I do that could you explain please
    – Johnny Adams
    Nov 22 at 17:38










  • @JohnnyAdams instead of trying to cover up the compilation problem, fix it. Override Equals and ==
    – Panagiotis Kanavos
    Nov 22 at 17:39















up vote
4
down vote

favorite












I am getting into generics but there is something I don't understand Here I have this class;



    class Node<T>{
T value;
Node <T> next,prev;
public Node(T vl)
{
this.value=vl;
this.next=this.prev=null;
}
}


I have a class List and a method Insert and it is working fine :



 class Lista<T>
{
public Node<T> Head, Tail;
public int Cnt;

public Lista()
{
this.Head = this.Tail = null;
this.Cnt = 0;
}



public void Insert(T vl)
{
Node<T> nd = new Node<T>(vl);
if (this.IsEmpty())
this.Head = this.Tail = nd;
else
{
this.Tail.next = nd;
nd.prev = this.Tail;
this.Tail = nd;
}
this.Cnt++;
}


}


but I Have a method FindNode:



 public Node<T> FindNode(T vl)
{
if (this.IsEmpty()) return null;
Node<T> tmp = this.Head;
while (tmp != null && ((object)tmp.VL != (object)vl)) tmp = tmp.next;
return tmp;
}


which finds a Node inside the List now the problem is
if I have a Lista<string> it works fine but if I create a Lista<int>
even if the element in list exists while comparing it is ignoring the same values and going next until it goes null , why does that happen ?



Method isEmpty:



public bool IsEmpty()
{
if (this.Head == null && this.Tail == null) return true;
return false;
}









share|improve this question


















  • 1




    Generics was invented to avoid something like (object)tmp.VL.
    – SeM
    Nov 22 at 17:36










  • You haven't overloaded Equals so how is C# going to know you consider them the same? It can only check whether the variables refer to the same instance
    – Panagiotis Kanavos
    Nov 22 at 17:36












  • @SeM I know right but if I say tmp.VL==vl it says that operand== cannot be used to types T and T
    – Johnny Adams
    Nov 22 at 17:38










  • @PanagiotisKanavos how do I do that could you explain please
    – Johnny Adams
    Nov 22 at 17:38










  • @JohnnyAdams instead of trying to cover up the compilation problem, fix it. Override Equals and ==
    – Panagiotis Kanavos
    Nov 22 at 17:39













up vote
4
down vote

favorite









up vote
4
down vote

favorite











I am getting into generics but there is something I don't understand Here I have this class;



    class Node<T>{
T value;
Node <T> next,prev;
public Node(T vl)
{
this.value=vl;
this.next=this.prev=null;
}
}


I have a class List and a method Insert and it is working fine :



 class Lista<T>
{
public Node<T> Head, Tail;
public int Cnt;

public Lista()
{
this.Head = this.Tail = null;
this.Cnt = 0;
}



public void Insert(T vl)
{
Node<T> nd = new Node<T>(vl);
if (this.IsEmpty())
this.Head = this.Tail = nd;
else
{
this.Tail.next = nd;
nd.prev = this.Tail;
this.Tail = nd;
}
this.Cnt++;
}


}


but I Have a method FindNode:



 public Node<T> FindNode(T vl)
{
if (this.IsEmpty()) return null;
Node<T> tmp = this.Head;
while (tmp != null && ((object)tmp.VL != (object)vl)) tmp = tmp.next;
return tmp;
}


which finds a Node inside the List now the problem is
if I have a Lista<string> it works fine but if I create a Lista<int>
even if the element in list exists while comparing it is ignoring the same values and going next until it goes null , why does that happen ?



Method isEmpty:



public bool IsEmpty()
{
if (this.Head == null && this.Tail == null) return true;
return false;
}









share|improve this question













I am getting into generics but there is something I don't understand Here I have this class;



    class Node<T>{
T value;
Node <T> next,prev;
public Node(T vl)
{
this.value=vl;
this.next=this.prev=null;
}
}


I have a class List and a method Insert and it is working fine :



 class Lista<T>
{
public Node<T> Head, Tail;
public int Cnt;

public Lista()
{
this.Head = this.Tail = null;
this.Cnt = 0;
}



public void Insert(T vl)
{
Node<T> nd = new Node<T>(vl);
if (this.IsEmpty())
this.Head = this.Tail = nd;
else
{
this.Tail.next = nd;
nd.prev = this.Tail;
this.Tail = nd;
}
this.Cnt++;
}


}


but I Have a method FindNode:



 public Node<T> FindNode(T vl)
{
if (this.IsEmpty()) return null;
Node<T> tmp = this.Head;
while (tmp != null && ((object)tmp.VL != (object)vl)) tmp = tmp.next;
return tmp;
}


which finds a Node inside the List now the problem is
if I have a Lista<string> it works fine but if I create a Lista<int>
even if the element in list exists while comparing it is ignoring the same values and going next until it goes null , why does that happen ?



Method isEmpty:



public bool IsEmpty()
{
if (this.Head == null && this.Tail == null) return true;
return false;
}






c# generics






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 22 at 17:33









Johnny Adams

276




276








  • 1




    Generics was invented to avoid something like (object)tmp.VL.
    – SeM
    Nov 22 at 17:36










  • You haven't overloaded Equals so how is C# going to know you consider them the same? It can only check whether the variables refer to the same instance
    – Panagiotis Kanavos
    Nov 22 at 17:36












  • @SeM I know right but if I say tmp.VL==vl it says that operand== cannot be used to types T and T
    – Johnny Adams
    Nov 22 at 17:38










  • @PanagiotisKanavos how do I do that could you explain please
    – Johnny Adams
    Nov 22 at 17:38










  • @JohnnyAdams instead of trying to cover up the compilation problem, fix it. Override Equals and ==
    – Panagiotis Kanavos
    Nov 22 at 17:39














  • 1




    Generics was invented to avoid something like (object)tmp.VL.
    – SeM
    Nov 22 at 17:36










  • You haven't overloaded Equals so how is C# going to know you consider them the same? It can only check whether the variables refer to the same instance
    – Panagiotis Kanavos
    Nov 22 at 17:36












  • @SeM I know right but if I say tmp.VL==vl it says that operand== cannot be used to types T and T
    – Johnny Adams
    Nov 22 at 17:38










  • @PanagiotisKanavos how do I do that could you explain please
    – Johnny Adams
    Nov 22 at 17:38










  • @JohnnyAdams instead of trying to cover up the compilation problem, fix it. Override Equals and ==
    – Panagiotis Kanavos
    Nov 22 at 17:39








1




1




Generics was invented to avoid something like (object)tmp.VL.
– SeM
Nov 22 at 17:36




Generics was invented to avoid something like (object)tmp.VL.
– SeM
Nov 22 at 17:36












You haven't overloaded Equals so how is C# going to know you consider them the same? It can only check whether the variables refer to the same instance
– Panagiotis Kanavos
Nov 22 at 17:36






You haven't overloaded Equals so how is C# going to know you consider them the same? It can only check whether the variables refer to the same instance
– Panagiotis Kanavos
Nov 22 at 17:36














@SeM I know right but if I say tmp.VL==vl it says that operand== cannot be used to types T and T
– Johnny Adams
Nov 22 at 17:38




@SeM I know right but if I say tmp.VL==vl it says that operand== cannot be used to types T and T
– Johnny Adams
Nov 22 at 17:38












@PanagiotisKanavos how do I do that could you explain please
– Johnny Adams
Nov 22 at 17:38




@PanagiotisKanavos how do I do that could you explain please
– Johnny Adams
Nov 22 at 17:38












@JohnnyAdams instead of trying to cover up the compilation problem, fix it. Override Equals and ==
– Panagiotis Kanavos
Nov 22 at 17:39




@JohnnyAdams instead of trying to cover up the compilation problem, fix it. Override Equals and ==
– Panagiotis Kanavos
Nov 22 at 17:39












1 Answer
1






active

oldest

votes

















up vote
4
down vote



accepted










The problem is, that for valuetypes like int in your example you are boxing them by casting to object.
Per default, the == operator does ReferenceEquality and this means that it will never return true in your case.



Easiest was to fix this would be to turn this line



while (tmp != null && ((object)tmp.VL != (object)vl)) tmp = tmp.next;


into this



 while (tmp != null && !Equals(tmp.VL , vl)) tmp = tmp.next;


This will use the default equality comparer for a certain type and makes your code work as intended.



you could go further and make and fix by using a generic constraint declared for your class like so:



class Lista<T> where T : IEquateable<T>


and change the same line like this



while (tmp != null && (!tmp.VL.Equals(vl)) tmp = tmp.next;


Or make it possible to inject an IEqualityComparer<T> into your class



  class Lista<T>
{
IEqualityComparer<T> _comparer;
public Lista(IEqualityComparer<T> comparer = null)
{
_comparer = comparer ?? EuqlityComparer<T>.Default;
}

public Node<T> FindNode(T vl)
{
if (this.IsEmpty()) return null;
Node<T> tmp = this.Head;
while (tmp != null && !_comparer.Equals(tmp.VL, vl) tmp = tmp.next;
return tmp;
}
}





share|improve this answer























  • thanks this was simple and worked like charm , but from the both methods you suggested which one would you recommend to use
    – Johnny Adams
    Nov 22 at 17:47






  • 1




    @JohnnyAdams the last one, using the IEqualityComparer is usually common practice. But if you dont need it, the first one is just fine.
    – CSharpie
    Nov 22 at 17:47












  • okay thanks for your answer
    – Johnny Adams
    Nov 22 at 17:49











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
4
down vote



accepted










The problem is, that for valuetypes like int in your example you are boxing them by casting to object.
Per default, the == operator does ReferenceEquality and this means that it will never return true in your case.



Easiest was to fix this would be to turn this line



while (tmp != null && ((object)tmp.VL != (object)vl)) tmp = tmp.next;


into this



 while (tmp != null && !Equals(tmp.VL , vl)) tmp = tmp.next;


This will use the default equality comparer for a certain type and makes your code work as intended.



you could go further and make and fix by using a generic constraint declared for your class like so:



class Lista<T> where T : IEquateable<T>


and change the same line like this



while (tmp != null && (!tmp.VL.Equals(vl)) tmp = tmp.next;


Or make it possible to inject an IEqualityComparer<T> into your class



  class Lista<T>
{
IEqualityComparer<T> _comparer;
public Lista(IEqualityComparer<T> comparer = null)
{
_comparer = comparer ?? EuqlityComparer<T>.Default;
}

public Node<T> FindNode(T vl)
{
if (this.IsEmpty()) return null;
Node<T> tmp = this.Head;
while (tmp != null && !_comparer.Equals(tmp.VL, vl) tmp = tmp.next;
return tmp;
}
}





share|improve this answer























  • thanks this was simple and worked like charm , but from the both methods you suggested which one would you recommend to use
    – Johnny Adams
    Nov 22 at 17:47






  • 1




    @JohnnyAdams the last one, using the IEqualityComparer is usually common practice. But if you dont need it, the first one is just fine.
    – CSharpie
    Nov 22 at 17:47












  • okay thanks for your answer
    – Johnny Adams
    Nov 22 at 17:49















up vote
4
down vote



accepted










The problem is, that for valuetypes like int in your example you are boxing them by casting to object.
Per default, the == operator does ReferenceEquality and this means that it will never return true in your case.



Easiest was to fix this would be to turn this line



while (tmp != null && ((object)tmp.VL != (object)vl)) tmp = tmp.next;


into this



 while (tmp != null && !Equals(tmp.VL , vl)) tmp = tmp.next;


This will use the default equality comparer for a certain type and makes your code work as intended.



you could go further and make and fix by using a generic constraint declared for your class like so:



class Lista<T> where T : IEquateable<T>


and change the same line like this



while (tmp != null && (!tmp.VL.Equals(vl)) tmp = tmp.next;


Or make it possible to inject an IEqualityComparer<T> into your class



  class Lista<T>
{
IEqualityComparer<T> _comparer;
public Lista(IEqualityComparer<T> comparer = null)
{
_comparer = comparer ?? EuqlityComparer<T>.Default;
}

public Node<T> FindNode(T vl)
{
if (this.IsEmpty()) return null;
Node<T> tmp = this.Head;
while (tmp != null && !_comparer.Equals(tmp.VL, vl) tmp = tmp.next;
return tmp;
}
}





share|improve this answer























  • thanks this was simple and worked like charm , but from the both methods you suggested which one would you recommend to use
    – Johnny Adams
    Nov 22 at 17:47






  • 1




    @JohnnyAdams the last one, using the IEqualityComparer is usually common practice. But if you dont need it, the first one is just fine.
    – CSharpie
    Nov 22 at 17:47












  • okay thanks for your answer
    – Johnny Adams
    Nov 22 at 17:49













up vote
4
down vote



accepted







up vote
4
down vote



accepted






The problem is, that for valuetypes like int in your example you are boxing them by casting to object.
Per default, the == operator does ReferenceEquality and this means that it will never return true in your case.



Easiest was to fix this would be to turn this line



while (tmp != null && ((object)tmp.VL != (object)vl)) tmp = tmp.next;


into this



 while (tmp != null && !Equals(tmp.VL , vl)) tmp = tmp.next;


This will use the default equality comparer for a certain type and makes your code work as intended.



you could go further and make and fix by using a generic constraint declared for your class like so:



class Lista<T> where T : IEquateable<T>


and change the same line like this



while (tmp != null && (!tmp.VL.Equals(vl)) tmp = tmp.next;


Or make it possible to inject an IEqualityComparer<T> into your class



  class Lista<T>
{
IEqualityComparer<T> _comparer;
public Lista(IEqualityComparer<T> comparer = null)
{
_comparer = comparer ?? EuqlityComparer<T>.Default;
}

public Node<T> FindNode(T vl)
{
if (this.IsEmpty()) return null;
Node<T> tmp = this.Head;
while (tmp != null && !_comparer.Equals(tmp.VL, vl) tmp = tmp.next;
return tmp;
}
}





share|improve this answer














The problem is, that for valuetypes like int in your example you are boxing them by casting to object.
Per default, the == operator does ReferenceEquality and this means that it will never return true in your case.



Easiest was to fix this would be to turn this line



while (tmp != null && ((object)tmp.VL != (object)vl)) tmp = tmp.next;


into this



 while (tmp != null && !Equals(tmp.VL , vl)) tmp = tmp.next;


This will use the default equality comparer for a certain type and makes your code work as intended.



you could go further and make and fix by using a generic constraint declared for your class like so:



class Lista<T> where T : IEquateable<T>


and change the same line like this



while (tmp != null && (!tmp.VL.Equals(vl)) tmp = tmp.next;


Or make it possible to inject an IEqualityComparer<T> into your class



  class Lista<T>
{
IEqualityComparer<T> _comparer;
public Lista(IEqualityComparer<T> comparer = null)
{
_comparer = comparer ?? EuqlityComparer<T>.Default;
}

public Node<T> FindNode(T vl)
{
if (this.IsEmpty()) return null;
Node<T> tmp = this.Head;
while (tmp != null && !_comparer.Equals(tmp.VL, vl) tmp = tmp.next;
return tmp;
}
}






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 22 at 17:50

























answered Nov 22 at 17:38









CSharpie

6,17623352




6,17623352












  • thanks this was simple and worked like charm , but from the both methods you suggested which one would you recommend to use
    – Johnny Adams
    Nov 22 at 17:47






  • 1




    @JohnnyAdams the last one, using the IEqualityComparer is usually common practice. But if you dont need it, the first one is just fine.
    – CSharpie
    Nov 22 at 17:47












  • okay thanks for your answer
    – Johnny Adams
    Nov 22 at 17:49


















  • thanks this was simple and worked like charm , but from the both methods you suggested which one would you recommend to use
    – Johnny Adams
    Nov 22 at 17:47






  • 1




    @JohnnyAdams the last one, using the IEqualityComparer is usually common practice. But if you dont need it, the first one is just fine.
    – CSharpie
    Nov 22 at 17:47












  • okay thanks for your answer
    – Johnny Adams
    Nov 22 at 17:49
















thanks this was simple and worked like charm , but from the both methods you suggested which one would you recommend to use
– Johnny Adams
Nov 22 at 17:47




thanks this was simple and worked like charm , but from the both methods you suggested which one would you recommend to use
– Johnny Adams
Nov 22 at 17:47




1




1




@JohnnyAdams the last one, using the IEqualityComparer is usually common practice. But if you dont need it, the first one is just fine.
– CSharpie
Nov 22 at 17:47






@JohnnyAdams the last one, using the IEqualityComparer is usually common practice. But if you dont need it, the first one is just fine.
– CSharpie
Nov 22 at 17:47














okay thanks for your answer
– Johnny Adams
Nov 22 at 17:49




okay thanks for your answer
– Johnny Adams
Nov 22 at 17:49


















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