How to specify this in an object literal with flow in js
I am using // @flow strict but somehow it does not work properly in an object literal when using this. this seemed to be interpreted as any.
This is the example code
type TestType = {
arr: Array<number>,
fun: () => void,
}
const testObject: TestType = {
arr:,
fun(){
this.arr.toUpperCase();
}
}
testObject.fun();
How can I tell flow that it knows that this.arr.toUpperCase() is not existing, because this.arr is an Array?
javascript flowtype object-literal
asked Nov 22 '18 at 9:26
Martin Mlostek
1,1371230
add a comment |
I am using // @flow strict but somehow it does not work properly in an object literal when using this. this seemed to be interpreted as any.
This is the example code
type TestType = {
arr: Array<number>,
fun: () => void,
}
const testObject: TestType = {
arr:,
fun(){
this.arr.toUpperCase();
}
}
testObject.fun();
How can I tell flow that it knows that this.arr.toUpperCase() is not existing, because this.arr is an Array?
javascript flowtype object-literal
asked Nov 22 '18 at 9:26
Martin Mlostek
1,1371230
add a comment |
I am using // @flow strict but somehow it does not work properly in an object literal when using this. this seemed to be interpreted as any.
This is the example code
type TestType = {
arr: Array<number>,
fun: () => void,
}
const testObject: TestType = {
arr:,
fun(){
this.arr.toUpperCase();
}
}
testObject.fun();
How can I tell flow that it knows that this.arr.toUpperCase() is not existing, because this.arr is an Array?
javascript flowtype object-literal
asked Nov 22 '18 at 9:26
Martin Mlostek
1,1371230
I am using // @flow strict but somehow it does not work properly in an object literal when using this. this seemed to be interpreted as any.
This is the example code
type TestType = {
arr: Array<number>,
fun: () => void,
}
const testObject: TestType = {
arr:,
fun(){
this.arr.toUpperCase();
}
}
testObject.fun();
How can I tell flow that it knows that this.arr.toUpperCase() is not existing, because this.arr is an Array?
javascript flowtype object-literal
javascript flowtype object-literal
asked Nov 22 '18 at 9:26
Martin Mlostek
1,1371230
asked Nov 22 '18 at 9:26
Martin Mlostek
1,1371230
asked Nov 22 '18 at 9:26
Martin Mlostek
1,1371230
asked Nov 22 '18 at 9:26
Martin Mlostek
1,1371230
asked Nov 22 '18 at 9:26
Martin Mlostek
1,1371230
1,1371230
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
There seems to no way to explicitly define this type in function:
In Flow you don’t type annotate this and Flow will check whatever context you call the function with.
As a workaround you can do something like::
const testObject: TestType = {
arr:,
fun(){
const {arr}: TestType = this;
arr.toUpperCase();
}
}
testObject.fun();
answered Nov 23 '18 at 2:47
Alex
3,220621
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53427634%2fhow-to-specify-this-in-an-object-literal-with-flow-in-js%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
There seems to no way to explicitly define this type in function:
In Flow you don’t type annotate this and Flow will check whatever context you call the function with.
As a workaround you can do something like::
const testObject: TestType = {
arr:,
fun(){
const {arr}: TestType = this;
arr.toUpperCase();
}
}
testObject.fun();
answered Nov 23 '18 at 2:47
Alex
3,220621
add a comment |
There seems to no way to explicitly define this type in function:
In Flow you don’t type annotate this and Flow will check whatever context you call the function with.
As a workaround you can do something like::
const testObject: TestType = {
arr:,
fun(){
const {arr}: TestType = this;
arr.toUpperCase();
}
}
testObject.fun();
answered Nov 23 '18 at 2:47
Alex
3,220621
add a comment |
There seems to no way to explicitly define this type in function:
In Flow you don’t type annotate this and Flow will check whatever context you call the function with.
As a workaround you can do something like::
const testObject: TestType = {
arr:,
fun(){
const {arr}: TestType = this;
arr.toUpperCase();
}
}
testObject.fun();
answered Nov 23 '18 at 2:47
Alex
3,220621
There seems to no way to explicitly define this type in function:
In Flow you don’t type annotate this and Flow will check whatever context you call the function with.
As a workaround you can do something like::
const testObject: TestType = {
arr:,
fun(){
const {arr}: TestType = this;
arr.toUpperCase();
}
}
testObject.fun();
answered Nov 23 '18 at 2:47
Alex
3,220621
answered Nov 23 '18 at 2:47
Alex
3,220621
answered Nov 23 '18 at 2:47
Alex
3,220621
answered Nov 23 '18 at 2:47
Alex
3,220621
3,220621
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53427634%2fhow-to-specify-this-in-an-object-literal-with-flow-in-js%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
