How to create laravel migration for tables with multiple foreign keys?












0














I want to create a table with multiple foreign keys. Here is the sql:



CREATE TABLE `customers` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(50) DEFAULT NULL,
`address` varchar(100) DEFAULT NULL,
`email` varchar(50) DEFAULT NULL,
`type_id` tinyint(3) unsigned DEFAULT NULL,
`district_id` tinyint(3) unsigned DEFAULT NULL,
`city_id` tinyint(3) unsigned DEFAULT NULL,
`business_id` tinyint(3) unsigned DEFAULT NULL,
`group_id` tinyint(3) unsigned DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `FK_customer_1` (`district_id`,`city_id`),
KEY `FK_customer_2` (`business_id`),
KEY `FK_customer_3` (`group_id`),
KEY `FK_customer_4` (`type_id`),
CONSTRAINT `FK_customer_1` FOREIGN KEY (`district_id`, `city_id`)
REFERENCES `cities` (`district_id`, `city_id`) ON DELETE CASCADE,
CONSTRAINT `FK_customer_2` FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`) ON DELETE CASCADE,
CONSTRAINT `FK_customer_3` FOREIGN KEY (`group_id`) REFERENCES `groups` (`group_id`) ON DELETE CASCADE,
CONSTRAINT `FK_customer_4` FOREIGN KEY (`type_id`) REFERENCES `types` (`type_id`) ON DELETE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;


I wrote a migration file with the following:



Schema::create('customers', function (Blueprint $table) {
$table->increments('id');
$table->string('name',50);
$table->string('address',100)->nullable();
$table->string('email',50)->nullable();
$table->integer('type_id')->unsigned()->index();
$table->integer('district_id')->unsigned()->index();
$table->integer('city_id')->unsigned()->index();
$table->integer('business_id')->unsigned()->index();
$table->integer('group_id')->unsigned()->index();
$table->timestamps();

$table->foreign(['district_id','city_id'])->references(['district_id','city_id'])->on('cities')->onDelete('cascade');
$table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
$table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
$table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
});


But when I run the migration it gives me the following error.



SQLSTATE[HY000]: General error: 1005 Can't create table `wastewater`.`#sql-5a8_18a` (errno: 150 "Foreign key constraint is incorrectly formed") (SQL: alter table `customers` add constraint `customers_district_id_city_id_foreign` foreign key (`district_id`, `city_id`) references `cities` (`district_id`, `city_id`) on delete cascade)`


How can I this?










share|improve this question





























    0














    I want to create a table with multiple foreign keys. Here is the sql:



    CREATE TABLE `customers` (
    `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
    `name` varchar(50) DEFAULT NULL,
    `address` varchar(100) DEFAULT NULL,
    `email` varchar(50) DEFAULT NULL,
    `type_id` tinyint(3) unsigned DEFAULT NULL,
    `district_id` tinyint(3) unsigned DEFAULT NULL,
    `city_id` tinyint(3) unsigned DEFAULT NULL,
    `business_id` tinyint(3) unsigned DEFAULT NULL,
    `group_id` tinyint(3) unsigned DEFAULT NULL,
    PRIMARY KEY (`id`),
    KEY `FK_customer_1` (`district_id`,`city_id`),
    KEY `FK_customer_2` (`business_id`),
    KEY `FK_customer_3` (`group_id`),
    KEY `FK_customer_4` (`type_id`),
    CONSTRAINT `FK_customer_1` FOREIGN KEY (`district_id`, `city_id`)
    REFERENCES `cities` (`district_id`, `city_id`) ON DELETE CASCADE,
    CONSTRAINT `FK_customer_2` FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`) ON DELETE CASCADE,
    CONSTRAINT `FK_customer_3` FOREIGN KEY (`group_id`) REFERENCES `groups` (`group_id`) ON DELETE CASCADE,
    CONSTRAINT `FK_customer_4` FOREIGN KEY (`type_id`) REFERENCES `types` (`type_id`) ON DELETE CASCADE
    ) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;


    I wrote a migration file with the following:



    Schema::create('customers', function (Blueprint $table) {
    $table->increments('id');
    $table->string('name',50);
    $table->string('address',100)->nullable();
    $table->string('email',50)->nullable();
    $table->integer('type_id')->unsigned()->index();
    $table->integer('district_id')->unsigned()->index();
    $table->integer('city_id')->unsigned()->index();
    $table->integer('business_id')->unsigned()->index();
    $table->integer('group_id')->unsigned()->index();
    $table->timestamps();

    $table->foreign(['district_id','city_id'])->references(['district_id','city_id'])->on('cities')->onDelete('cascade');
    $table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
    $table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
    $table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
    });


    But when I run the migration it gives me the following error.



    SQLSTATE[HY000]: General error: 1005 Can't create table `wastewater`.`#sql-5a8_18a` (errno: 150 "Foreign key constraint is incorrectly formed") (SQL: alter table `customers` add constraint `customers_district_id_city_id_foreign` foreign key (`district_id`, `city_id`) references `cities` (`district_id`, `city_id`) on delete cascade)`


    How can I this?










    share|improve this question



























      0












      0








      0







      I want to create a table with multiple foreign keys. Here is the sql:



      CREATE TABLE `customers` (
      `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
      `name` varchar(50) DEFAULT NULL,
      `address` varchar(100) DEFAULT NULL,
      `email` varchar(50) DEFAULT NULL,
      `type_id` tinyint(3) unsigned DEFAULT NULL,
      `district_id` tinyint(3) unsigned DEFAULT NULL,
      `city_id` tinyint(3) unsigned DEFAULT NULL,
      `business_id` tinyint(3) unsigned DEFAULT NULL,
      `group_id` tinyint(3) unsigned DEFAULT NULL,
      PRIMARY KEY (`id`),
      KEY `FK_customer_1` (`district_id`,`city_id`),
      KEY `FK_customer_2` (`business_id`),
      KEY `FK_customer_3` (`group_id`),
      KEY `FK_customer_4` (`type_id`),
      CONSTRAINT `FK_customer_1` FOREIGN KEY (`district_id`, `city_id`)
      REFERENCES `cities` (`district_id`, `city_id`) ON DELETE CASCADE,
      CONSTRAINT `FK_customer_2` FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`) ON DELETE CASCADE,
      CONSTRAINT `FK_customer_3` FOREIGN KEY (`group_id`) REFERENCES `groups` (`group_id`) ON DELETE CASCADE,
      CONSTRAINT `FK_customer_4` FOREIGN KEY (`type_id`) REFERENCES `types` (`type_id`) ON DELETE CASCADE
      ) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;


      I wrote a migration file with the following:



      Schema::create('customers', function (Blueprint $table) {
      $table->increments('id');
      $table->string('name',50);
      $table->string('address',100)->nullable();
      $table->string('email',50)->nullable();
      $table->integer('type_id')->unsigned()->index();
      $table->integer('district_id')->unsigned()->index();
      $table->integer('city_id')->unsigned()->index();
      $table->integer('business_id')->unsigned()->index();
      $table->integer('group_id')->unsigned()->index();
      $table->timestamps();

      $table->foreign(['district_id','city_id'])->references(['district_id','city_id'])->on('cities')->onDelete('cascade');
      $table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
      $table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
      $table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
      });


      But when I run the migration it gives me the following error.



      SQLSTATE[HY000]: General error: 1005 Can't create table `wastewater`.`#sql-5a8_18a` (errno: 150 "Foreign key constraint is incorrectly formed") (SQL: alter table `customers` add constraint `customers_district_id_city_id_foreign` foreign key (`district_id`, `city_id`) references `cities` (`district_id`, `city_id`) on delete cascade)`


      How can I this?










      share|improve this question















      I want to create a table with multiple foreign keys. Here is the sql:



      CREATE TABLE `customers` (
      `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
      `name` varchar(50) DEFAULT NULL,
      `address` varchar(100) DEFAULT NULL,
      `email` varchar(50) DEFAULT NULL,
      `type_id` tinyint(3) unsigned DEFAULT NULL,
      `district_id` tinyint(3) unsigned DEFAULT NULL,
      `city_id` tinyint(3) unsigned DEFAULT NULL,
      `business_id` tinyint(3) unsigned DEFAULT NULL,
      `group_id` tinyint(3) unsigned DEFAULT NULL,
      PRIMARY KEY (`id`),
      KEY `FK_customer_1` (`district_id`,`city_id`),
      KEY `FK_customer_2` (`business_id`),
      KEY `FK_customer_3` (`group_id`),
      KEY `FK_customer_4` (`type_id`),
      CONSTRAINT `FK_customer_1` FOREIGN KEY (`district_id`, `city_id`)
      REFERENCES `cities` (`district_id`, `city_id`) ON DELETE CASCADE,
      CONSTRAINT `FK_customer_2` FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`) ON DELETE CASCADE,
      CONSTRAINT `FK_customer_3` FOREIGN KEY (`group_id`) REFERENCES `groups` (`group_id`) ON DELETE CASCADE,
      CONSTRAINT `FK_customer_4` FOREIGN KEY (`type_id`) REFERENCES `types` (`type_id`) ON DELETE CASCADE
      ) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;


      I wrote a migration file with the following:



      Schema::create('customers', function (Blueprint $table) {
      $table->increments('id');
      $table->string('name',50);
      $table->string('address',100)->nullable();
      $table->string('email',50)->nullable();
      $table->integer('type_id')->unsigned()->index();
      $table->integer('district_id')->unsigned()->index();
      $table->integer('city_id')->unsigned()->index();
      $table->integer('business_id')->unsigned()->index();
      $table->integer('group_id')->unsigned()->index();
      $table->timestamps();

      $table->foreign(['district_id','city_id'])->references(['district_id','city_id'])->on('cities')->onDelete('cascade');
      $table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
      $table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
      $table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
      });


      But when I run the migration it gives me the following error.



      SQLSTATE[HY000]: General error: 1005 Can't create table `wastewater`.`#sql-5a8_18a` (errno: 150 "Foreign key constraint is incorrectly formed") (SQL: alter table `customers` add constraint `customers_district_id_city_id_foreign` foreign key (`district_id`, `city_id`) references `cities` (`district_id`, `city_id`) on delete cascade)`


      How can I this?







      laravel-5






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 23 '18 at 7:59









      DestinatioN

      1,2581326




      1,2581326










      asked Nov 23 '18 at 2:47









      Abaij

      3272722




      3272722
























          2 Answers
          2






          active

          oldest

          votes


















          0














          Can you please Try this way, Just removed array and define with comma-separated only.



          Schema::create('customers', function (Blueprint $table) {
          $table->increments('id');
          $table->string('name',50);
          $table->string('address',100)->nullable();
          $table->string('email',50)->nullable();
          $table->integer('type_id')->unsigned()->index();
          $table->integer('district_id')->unsigned()->index();
          $table->integer('city_id')->unsigned()->index();
          $table->integer('business_id')->unsigned()->index();
          $table->integer('group_id')->unsigned()->index();
          $table->timestamps();

          $table->foreign('district_id','city_id')->references('district_id','city_id')->on('cities','cities')->onDelete('cascade','cascade');
          $table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
          $table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
          $table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
          });





          share|improve this answer























          • no, I think that's not the case. The second argument will create index name, not a key.
            – Abaij
            Nov 23 '18 at 9:36



















          0














          Try the following way, it will work.



          Schema::create('customers', function (Blueprint $table) {
          $table->increments('id');

          $table->integer('type_id', false, true);
          $table->foreign('type_id')->references('type_id')->on('types')
          ->onDelete('cascade');

          $table->integer('district_id', false, true);
          $table->foreign('district_id')
          ->references('district_id')->on('cities')
          ->onDelete('cascade');

          $table->integer('city_id', false, true);
          $table->foreign('city_id')
          ->references('city_id')->on('cities')
          ->onDelete('cascade');

          $table->integer('business_id', false, true);
          $table->foreign('business_id')->references('business_id')
          ->on('businesses')->onDelete('cascade');

          $table->integer('group_id', false, true);
          $table->foreign('group_id')->references('group_id')->on('groups')
          ->onDelete('cascade');
          $table->string('name',50);
          $table->string('address',100)->nullable();
          $table->string('email',50)->nullable();
          $table->timestamps();
          });





          share|improve this answer





















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            2 Answers
            2






            active

            oldest

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            2 Answers
            2






            active

            oldest

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            active

            oldest

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            active

            oldest

            votes









            0














            Can you please Try this way, Just removed array and define with comma-separated only.



            Schema::create('customers', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name',50);
            $table->string('address',100)->nullable();
            $table->string('email',50)->nullable();
            $table->integer('type_id')->unsigned()->index();
            $table->integer('district_id')->unsigned()->index();
            $table->integer('city_id')->unsigned()->index();
            $table->integer('business_id')->unsigned()->index();
            $table->integer('group_id')->unsigned()->index();
            $table->timestamps();

            $table->foreign('district_id','city_id')->references('district_id','city_id')->on('cities','cities')->onDelete('cascade','cascade');
            $table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
            $table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
            $table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
            });





            share|improve this answer























            • no, I think that's not the case. The second argument will create index name, not a key.
              – Abaij
              Nov 23 '18 at 9:36
















            0














            Can you please Try this way, Just removed array and define with comma-separated only.



            Schema::create('customers', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name',50);
            $table->string('address',100)->nullable();
            $table->string('email',50)->nullable();
            $table->integer('type_id')->unsigned()->index();
            $table->integer('district_id')->unsigned()->index();
            $table->integer('city_id')->unsigned()->index();
            $table->integer('business_id')->unsigned()->index();
            $table->integer('group_id')->unsigned()->index();
            $table->timestamps();

            $table->foreign('district_id','city_id')->references('district_id','city_id')->on('cities','cities')->onDelete('cascade','cascade');
            $table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
            $table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
            $table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
            });





            share|improve this answer























            • no, I think that's not the case. The second argument will create index name, not a key.
              – Abaij
              Nov 23 '18 at 9:36














            0












            0








            0






            Can you please Try this way, Just removed array and define with comma-separated only.



            Schema::create('customers', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name',50);
            $table->string('address',100)->nullable();
            $table->string('email',50)->nullable();
            $table->integer('type_id')->unsigned()->index();
            $table->integer('district_id')->unsigned()->index();
            $table->integer('city_id')->unsigned()->index();
            $table->integer('business_id')->unsigned()->index();
            $table->integer('group_id')->unsigned()->index();
            $table->timestamps();

            $table->foreign('district_id','city_id')->references('district_id','city_id')->on('cities','cities')->onDelete('cascade','cascade');
            $table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
            $table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
            $table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
            });





            share|improve this answer














            Can you please Try this way, Just removed array and define with comma-separated only.



            Schema::create('customers', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name',50);
            $table->string('address',100)->nullable();
            $table->string('email',50)->nullable();
            $table->integer('type_id')->unsigned()->index();
            $table->integer('district_id')->unsigned()->index();
            $table->integer('city_id')->unsigned()->index();
            $table->integer('business_id')->unsigned()->index();
            $table->integer('group_id')->unsigned()->index();
            $table->timestamps();

            $table->foreign('district_id','city_id')->references('district_id','city_id')->on('cities','cities')->onDelete('cascade','cascade');
            $table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
            $table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
            $table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
            });






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 23 '18 at 6:39









            DestinatioN

            1,2581326




            1,2581326










            answered Nov 23 '18 at 6:29









            Mayank Majithya

            1,014314




            1,014314












            • no, I think that's not the case. The second argument will create index name, not a key.
              – Abaij
              Nov 23 '18 at 9:36


















            • no, I think that's not the case. The second argument will create index name, not a key.
              – Abaij
              Nov 23 '18 at 9:36
















            no, I think that's not the case. The second argument will create index name, not a key.
            – Abaij
            Nov 23 '18 at 9:36




            no, I think that's not the case. The second argument will create index name, not a key.
            – Abaij
            Nov 23 '18 at 9:36













            0














            Try the following way, it will work.



            Schema::create('customers', function (Blueprint $table) {
            $table->increments('id');

            $table->integer('type_id', false, true);
            $table->foreign('type_id')->references('type_id')->on('types')
            ->onDelete('cascade');

            $table->integer('district_id', false, true);
            $table->foreign('district_id')
            ->references('district_id')->on('cities')
            ->onDelete('cascade');

            $table->integer('city_id', false, true);
            $table->foreign('city_id')
            ->references('city_id')->on('cities')
            ->onDelete('cascade');

            $table->integer('business_id', false, true);
            $table->foreign('business_id')->references('business_id')
            ->on('businesses')->onDelete('cascade');

            $table->integer('group_id', false, true);
            $table->foreign('group_id')->references('group_id')->on('groups')
            ->onDelete('cascade');
            $table->string('name',50);
            $table->string('address',100)->nullable();
            $table->string('email',50)->nullable();
            $table->timestamps();
            });





            share|improve this answer


























              0














              Try the following way, it will work.



              Schema::create('customers', function (Blueprint $table) {
              $table->increments('id');

              $table->integer('type_id', false, true);
              $table->foreign('type_id')->references('type_id')->on('types')
              ->onDelete('cascade');

              $table->integer('district_id', false, true);
              $table->foreign('district_id')
              ->references('district_id')->on('cities')
              ->onDelete('cascade');

              $table->integer('city_id', false, true);
              $table->foreign('city_id')
              ->references('city_id')->on('cities')
              ->onDelete('cascade');

              $table->integer('business_id', false, true);
              $table->foreign('business_id')->references('business_id')
              ->on('businesses')->onDelete('cascade');

              $table->integer('group_id', false, true);
              $table->foreign('group_id')->references('group_id')->on('groups')
              ->onDelete('cascade');
              $table->string('name',50);
              $table->string('address',100)->nullable();
              $table->string('email',50)->nullable();
              $table->timestamps();
              });





              share|improve this answer
























                0












                0








                0






                Try the following way, it will work.



                Schema::create('customers', function (Blueprint $table) {
                $table->increments('id');

                $table->integer('type_id', false, true);
                $table->foreign('type_id')->references('type_id')->on('types')
                ->onDelete('cascade');

                $table->integer('district_id', false, true);
                $table->foreign('district_id')
                ->references('district_id')->on('cities')
                ->onDelete('cascade');

                $table->integer('city_id', false, true);
                $table->foreign('city_id')
                ->references('city_id')->on('cities')
                ->onDelete('cascade');

                $table->integer('business_id', false, true);
                $table->foreign('business_id')->references('business_id')
                ->on('businesses')->onDelete('cascade');

                $table->integer('group_id', false, true);
                $table->foreign('group_id')->references('group_id')->on('groups')
                ->onDelete('cascade');
                $table->string('name',50);
                $table->string('address',100)->nullable();
                $table->string('email',50)->nullable();
                $table->timestamps();
                });





                share|improve this answer












                Try the following way, it will work.



                Schema::create('customers', function (Blueprint $table) {
                $table->increments('id');

                $table->integer('type_id', false, true);
                $table->foreign('type_id')->references('type_id')->on('types')
                ->onDelete('cascade');

                $table->integer('district_id', false, true);
                $table->foreign('district_id')
                ->references('district_id')->on('cities')
                ->onDelete('cascade');

                $table->integer('city_id', false, true);
                $table->foreign('city_id')
                ->references('city_id')->on('cities')
                ->onDelete('cascade');

                $table->integer('business_id', false, true);
                $table->foreign('business_id')->references('business_id')
                ->on('businesses')->onDelete('cascade');

                $table->integer('group_id', false, true);
                $table->foreign('group_id')->references('group_id')->on('groups')
                ->onDelete('cascade');
                $table->string('name',50);
                $table->string('address',100)->nullable();
                $table->string('email',50)->nullable();
                $table->timestamps();
                });






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                answered Nov 23 '18 at 9:19









                engrhussainahmad

                1258




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