List all files in a folder and sub folders into a table
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1
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Have a folder with sub folders and with various source code files withing those sub folders like .CSS, .java etc. Is it possible to list all these source code files into a table format with two columns(path and filename)
all_files<-list.files(pattern = "*.*", recursive = TRUE) is not working. I tried other functions like lapply cant seem to catch a break.
r
edited Nov 22 at 15:37
David Arenburg
77.6k1092157
asked Nov 22 at 15:32
Sunil Babu Vudimudi
83
add a comment |
up vote
1
down vote
favorite
Have a folder with sub folders and with various source code files withing those sub folders like .CSS, .java etc. Is it possible to list all these source code files into a table format with two columns(path and filename)
all_files<-list.files(pattern = "*.*", recursive = TRUE) is not working. I tried other functions like lapply cant seem to catch a break.
r
edited Nov 22 at 15:37
David Arenburg
77.6k1092157
asked Nov 22 at 15:32
Sunil Babu Vudimudi
83
2
Welcome to SO and 👍🏼 job crafting and tweaking the question (you incrementally made it super clear what you're asking for which really helps folks figure out possible answers). Having said that, what do you mean by "doesn't work"? Isall_filesempty?
– hrbrmstr
Nov 22 at 15:38
Thanks! When I use all_files<-list.files(pattern = ".", recursive = TRUE), the result is a single row with all the file names in a list. I want them in a column one below the other.
– Sunil Babu Vudimudi
Nov 22 at 15:44
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Have a folder with sub folders and with various source code files withing those sub folders like .CSS, .java etc. Is it possible to list all these source code files into a table format with two columns(path and filename)
all_files<-list.files(pattern = "*.*", recursive = TRUE) is not working. I tried other functions like lapply cant seem to catch a break.
r
edited Nov 22 at 15:37
David Arenburg
77.6k1092157
asked Nov 22 at 15:32
Sunil Babu Vudimudi
83
Have a folder with sub folders and with various source code files withing those sub folders like .CSS, .java etc. Is it possible to list all these source code files into a table format with two columns(path and filename)
all_files<-list.files(pattern = "*.*", recursive = TRUE) is not working. I tried other functions like lapply cant seem to catch a break.
r
r
edited Nov 22 at 15:37
David Arenburg
77.6k1092157
asked Nov 22 at 15:32
Sunil Babu Vudimudi
83
edited Nov 22 at 15:37
David Arenburg
77.6k1092157
asked Nov 22 at 15:32
Sunil Babu Vudimudi
83
edited Nov 22 at 15:37
David Arenburg
77.6k1092157
edited Nov 22 at 15:37
David Arenburg
77.6k1092157
edited Nov 22 at 15:37
David Arenburg
77.6k1092157
77.6k1092157
asked Nov 22 at 15:32
Sunil Babu Vudimudi
83
asked Nov 22 at 15:32
Sunil Babu Vudimudi
83
asked Nov 22 at 15:32
Sunil Babu Vudimudi
83
83
2
Welcome to SO and 👍🏼 job crafting and tweaking the question (you incrementally made it super clear what you're asking for which really helps folks figure out possible answers). Having said that, what do you mean by "doesn't work"? Isall_filesempty?
– hrbrmstr
Nov 22 at 15:38
Thanks! When I use all_files<-list.files(pattern = ".", recursive = TRUE), the result is a single row with all the file names in a list. I want them in a column one below the other.
– Sunil Babu Vudimudi
Nov 22 at 15:44
add a comment |
2
Welcome to SO and 👍🏼 job crafting and tweaking the question (you incrementally made it super clear what you're asking for which really helps folks figure out possible answers). Having said that, what do you mean by "doesn't work"? Isall_filesempty?
– hrbrmstr
Nov 22 at 15:38
Thanks! When I use all_files<-list.files(pattern = ".", recursive = TRUE), the result is a single row with all the file names in a list. I want them in a column one below the other.
– Sunil Babu Vudimudi
Nov 22 at 15:44
2
2
Welcome to SO and 👍🏼 job crafting and tweaking the question (you incrementally made it super clear what you're asking for which really helps folks figure out possible answers). Having said that, what do you mean by "doesn't work"? Is
all_files empty?– hrbrmstr
Nov 22 at 15:38
Welcome to SO and 👍🏼 job crafting and tweaking the question (you incrementally made it super clear what you're asking for which really helps folks figure out possible answers). Having said that, what do you mean by "doesn't work"? Is
all_files empty?– hrbrmstr
Nov 22 at 15:38
Thanks! When I use all_files<-list.files(pattern = ".", recursive = TRUE), the result is a single row with all the file names in a list. I want them in a column one below the other.
– Sunil Babu Vudimudi
Nov 22 at 15:44
Thanks! When I use all_files<-list.files(pattern = ".", recursive = TRUE), the result is a single row with all the file names in a list. I want them in a column one below the other.
– Sunil Babu Vudimudi
Nov 22 at 15:44
add a comment |
1 Answer
1
active
oldest
votes
up vote
3
down vote
accepted
fils <- list.files("thedir", recursive = TRUE)
data.frame(
path = dirname(fils),
file = basename(fils),
stringsAsFactors = FALSE
)
answered Nov 22 at 15:36
hrbrmstr
59.7k585146
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
fils <- list.files("thedir", recursive = TRUE)
data.frame(
path = dirname(fils),
file = basename(fils),
stringsAsFactors = FALSE
)
answered Nov 22 at 15:36
hrbrmstr
59.7k585146
add a comment |
up vote
3
down vote
accepted
fils <- list.files("thedir", recursive = TRUE)
data.frame(
path = dirname(fils),
file = basename(fils),
stringsAsFactors = FALSE
)
answered Nov 22 at 15:36
hrbrmstr
59.7k585146
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
fils <- list.files("thedir", recursive = TRUE)
data.frame(
path = dirname(fils),
file = basename(fils),
stringsAsFactors = FALSE
)
answered Nov 22 at 15:36
hrbrmstr
59.7k585146
fils <- list.files("thedir", recursive = TRUE)
data.frame(
path = dirname(fils),
file = basename(fils),
stringsAsFactors = FALSE
)
answered Nov 22 at 15:36
hrbrmstr
59.7k585146
answered Nov 22 at 15:36
hrbrmstr
59.7k585146
answered Nov 22 at 15:36
hrbrmstr
59.7k585146
answered Nov 22 at 15:36
hrbrmstr
59.7k585146
59.7k585146
add a comment |
add a comment |
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2
Welcome to SO and 👍🏼 job crafting and tweaking the question (you incrementally made it super clear what you're asking for which really helps folks figure out possible answers). Having said that, what do you mean by "doesn't work"? Is
all_filesempty?– hrbrmstr
Nov 22 at 15:38
Thanks! When I use all_files<-list.files(pattern = ".", recursive = TRUE), the result is a single row with all the file names in a list. I want them in a column one below the other.
– Sunil Babu Vudimudi
Nov 22 at 15:44