Why Optional's or and flatMap method's supplier type parameter is a wildcard
up vote
6
down vote
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The Optional.or
method was added in Java 9. This is the method signature
public Optional<T> or(Supplier<? extends Optional<? extends T>> supplier)
Why is the type parameter of the Supplier
taking ? extends Optional
rather than just Optional
since Optional
is a final class.
The same is true for Optional.flatMap
method. This is a change from Java 8.
In Java 8, it was Function<? super T, Optional<U>> mapper
wherease it was changed to Function<? super T,? extends Optional<? extends U>>
in Java 9.
java optional java-9 supplier
add a comment |
up vote
6
down vote
favorite
The Optional.or
method was added in Java 9. This is the method signature
public Optional<T> or(Supplier<? extends Optional<? extends T>> supplier)
Why is the type parameter of the Supplier
taking ? extends Optional
rather than just Optional
since Optional
is a final class.
The same is true for Optional.flatMap
method. This is a change from Java 8.
In Java 8, it was Function<? super T, Optional<U>> mapper
wherease it was changed to Function<? super T,? extends Optional<? extends U>>
in Java 9.
java optional java-9 supplier
Kinda seems like they're positioning it to not be afinal
class in future version?
– nbrooks
5 hours ago
@nbrooks It is because of the nested generics (and yes.. partly to due with the future changes)
– user7
5 hours ago
add a comment |
up vote
6
down vote
favorite
up vote
6
down vote
favorite
The Optional.or
method was added in Java 9. This is the method signature
public Optional<T> or(Supplier<? extends Optional<? extends T>> supplier)
Why is the type parameter of the Supplier
taking ? extends Optional
rather than just Optional
since Optional
is a final class.
The same is true for Optional.flatMap
method. This is a change from Java 8.
In Java 8, it was Function<? super T, Optional<U>> mapper
wherease it was changed to Function<? super T,? extends Optional<? extends U>>
in Java 9.
java optional java-9 supplier
The Optional.or
method was added in Java 9. This is the method signature
public Optional<T> or(Supplier<? extends Optional<? extends T>> supplier)
Why is the type parameter of the Supplier
taking ? extends Optional
rather than just Optional
since Optional
is a final class.
The same is true for Optional.flatMap
method. This is a change from Java 8.
In Java 8, it was Function<? super T, Optional<U>> mapper
wherease it was changed to Function<? super T,? extends Optional<? extends U>>
in Java 9.
java optional java-9 supplier
java optional java-9 supplier
edited 3 hours ago
nullpointer
38k1073145
38k1073145
asked 5 hours ago
user7
8,89132040
8,89132040
Kinda seems like they're positioning it to not be afinal
class in future version?
– nbrooks
5 hours ago
@nbrooks It is because of the nested generics (and yes.. partly to due with the future changes)
– user7
5 hours ago
add a comment |
Kinda seems like they're positioning it to not be afinal
class in future version?
– nbrooks
5 hours ago
@nbrooks It is because of the nested generics (and yes.. partly to due with the future changes)
– user7
5 hours ago
Kinda seems like they're positioning it to not be a
final
class in future version?– nbrooks
5 hours ago
Kinda seems like they're positioning it to not be a
final
class in future version?– nbrooks
5 hours ago
@nbrooks It is because of the nested generics (and yes.. partly to due with the future changes)
– user7
5 hours ago
@nbrooks It is because of the nested generics (and yes.. partly to due with the future changes)
– user7
5 hours ago
add a comment |
1 Answer
1
active
oldest
votes
up vote
9
down vote
I found the reasoning behind this from Stuart Marks himself
http://mail.openjdk.java.net/pipermail/core-libs-dev/2016-October/044026.html
This has to do with nested generics (Optional
is nested within Function
).
From the mail thread
Function<..., Optional<StringBuilder>>
is not a subtype of
Function<..., Optional<? extends CharSequence>>
To get around this, we have to add the outer wildcard as well, so that
Function<..., Optional<StringBuilder>>
is a subtype of
Function<..., ? extends Optional<? extends CharSequence>>
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
9
down vote
I found the reasoning behind this from Stuart Marks himself
http://mail.openjdk.java.net/pipermail/core-libs-dev/2016-October/044026.html
This has to do with nested generics (Optional
is nested within Function
).
From the mail thread
Function<..., Optional<StringBuilder>>
is not a subtype of
Function<..., Optional<? extends CharSequence>>
To get around this, we have to add the outer wildcard as well, so that
Function<..., Optional<StringBuilder>>
is a subtype of
Function<..., ? extends Optional<? extends CharSequence>>
add a comment |
up vote
9
down vote
I found the reasoning behind this from Stuart Marks himself
http://mail.openjdk.java.net/pipermail/core-libs-dev/2016-October/044026.html
This has to do with nested generics (Optional
is nested within Function
).
From the mail thread
Function<..., Optional<StringBuilder>>
is not a subtype of
Function<..., Optional<? extends CharSequence>>
To get around this, we have to add the outer wildcard as well, so that
Function<..., Optional<StringBuilder>>
is a subtype of
Function<..., ? extends Optional<? extends CharSequence>>
add a comment |
up vote
9
down vote
up vote
9
down vote
I found the reasoning behind this from Stuart Marks himself
http://mail.openjdk.java.net/pipermail/core-libs-dev/2016-October/044026.html
This has to do with nested generics (Optional
is nested within Function
).
From the mail thread
Function<..., Optional<StringBuilder>>
is not a subtype of
Function<..., Optional<? extends CharSequence>>
To get around this, we have to add the outer wildcard as well, so that
Function<..., Optional<StringBuilder>>
is a subtype of
Function<..., ? extends Optional<? extends CharSequence>>
I found the reasoning behind this from Stuart Marks himself
http://mail.openjdk.java.net/pipermail/core-libs-dev/2016-October/044026.html
This has to do with nested generics (Optional
is nested within Function
).
From the mail thread
Function<..., Optional<StringBuilder>>
is not a subtype of
Function<..., Optional<? extends CharSequence>>
To get around this, we have to add the outer wildcard as well, so that
Function<..., Optional<StringBuilder>>
is a subtype of
Function<..., ? extends Optional<? extends CharSequence>>
answered 5 hours ago
user7
8,89132040
8,89132040
add a comment |
add a comment |
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Kinda seems like they're positioning it to not be a
final
class in future version?– nbrooks
5 hours ago
@nbrooks It is because of the nested generics (and yes.. partly to due with the future changes)
– user7
5 hours ago