Qfyilyi

Please consider the following PHP:

function get_ship_class()

{

    $csv = array_map("str_getcsv", file("somefile.csv", "r")); 

    $header = array_shift($csv); 



    // Seperate the header from data

    $col = array_search("heavy_shipping_class", $header); 



    foreach ($csv as $row)

    {      

        $array = $row[$col]; 

    }

}

How do I pass the resulting array from the above function into

if( in_array() ){

    //code

}

?

A slightly abbreviated version, but the same as is being suggested is to return the required data from the function but using array_column() to extract the data...

function get_ship_class()

{

    $csv = array_map("str_getcsv", file("somefile.csv", "r")); 

    $header = array_shift($csv); 



    // Seperate the header from data

    $col = array_search("heavy_shipping_class", $header); 



    // Pass the extracted column back to calling method

    return array_column($csv,$col);

}

And to use it...

if ( in_array( "somevalue", get_ship_class() )) {

   //Process 

}

If you are going to use this returned value a few times, it may be worth storing it in a variable rather than passing it straight into the in_array() method.

This is the answer that the comments are suggesting.

function get_ship_class(){

    $array = array();

    $csv = array_map("str_getcsv", file("somefile.csv", "r")); 

    $header = array_shift($csv); 

    // Seperate the header from data    

    $col = array_search("heavy_shipping_class", $header); 

    foreach ($csv as $row) {      

    array_push($array, $row[$col]);

    // array_push($array, "$row[$col]"); // You may need it as a string instead.

    }

return $array;

}







if( in_array("whatever_you_are_looking_for", get_ship_class()) ){

//code

}