Postgresql REPL save query result into variable
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0
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In mysql REPL it's possible to do something like this:
set @x = 1;
set @d = (select now());
select @x, @d;
+------+---------------------+
| @x | @d |
+------+---------------------+
| 1 | 2018-11-22 16:38:11 |
+------+---------------------+
Now I try to do same in postgresql REPL. I've found this:
set var.x = 1;
select current_setting('var.x');
And it works, but I can't find the way how to store query result into variable. I've tried this:
set var.d = (select now());
ERROR: syntax error at or near "("
LINE 1: set var.d = (select now());
^
select now() into var.d;
ERROR: schema "var" does not exist
select now() into d;
-- creates new table, which is wrong
d := select now();
ERROR: syntax error at or near "d"
LINE 1: d := select now();
Could you please help find the solution? I'm ussing psql (PostgreSQL) 10.5.
postgresql
asked Nov 22 at 16:56
Vladimir Kovpak
10.6k43646
add a comment |
up vote
0
down vote
favorite
In mysql REPL it's possible to do something like this:
set @x = 1;
set @d = (select now());
select @x, @d;
+------+---------------------+
| @x | @d |
+------+---------------------+
| 1 | 2018-11-22 16:38:11 |
+------+---------------------+
Now I try to do same in postgresql REPL. I've found this:
set var.x = 1;
select current_setting('var.x');
And it works, but I can't find the way how to store query result into variable. I've tried this:
set var.d = (select now());
ERROR: syntax error at or near "("
LINE 1: set var.d = (select now());
^
select now() into var.d;
ERROR: schema "var" does not exist
select now() into d;
-- creates new table, which is wrong
d := select now();
ERROR: syntax error at or near "d"
LINE 1: d := select now();
Could you please help find the solution? I'm ussing psql (PostgreSQL) 10.5.
postgresql
asked Nov 22 at 16:56
Vladimir Kovpak
10.6k43646
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
In mysql REPL it's possible to do something like this:
set @x = 1;
set @d = (select now());
select @x, @d;
+------+---------------------+
| @x | @d |
+------+---------------------+
| 1 | 2018-11-22 16:38:11 |
+------+---------------------+
Now I try to do same in postgresql REPL. I've found this:
set var.x = 1;
select current_setting('var.x');
And it works, but I can't find the way how to store query result into variable. I've tried this:
set var.d = (select now());
ERROR: syntax error at or near "("
LINE 1: set var.d = (select now());
^
select now() into var.d;
ERROR: schema "var" does not exist
select now() into d;
-- creates new table, which is wrong
d := select now();
ERROR: syntax error at or near "d"
LINE 1: d := select now();
Could you please help find the solution? I'm ussing psql (PostgreSQL) 10.5.
postgresql
asked Nov 22 at 16:56
Vladimir Kovpak
10.6k43646
In mysql REPL it's possible to do something like this:
set @x = 1;
set @d = (select now());
select @x, @d;
+------+---------------------+
| @x | @d |
+------+---------------------+
| 1 | 2018-11-22 16:38:11 |
+------+---------------------+
Now I try to do same in postgresql REPL. I've found this:
set var.x = 1;
select current_setting('var.x');
And it works, but I can't find the way how to store query result into variable. I've tried this:
set var.d = (select now());
ERROR: syntax error at or near "("
LINE 1: set var.d = (select now());
^
select now() into var.d;
ERROR: schema "var" does not exist
select now() into d;
-- creates new table, which is wrong
d := select now();
ERROR: syntax error at or near "d"
LINE 1: d := select now();
Could you please help find the solution? I'm ussing psql (PostgreSQL) 10.5.
postgresql
postgresql
asked Nov 22 at 16:56
Vladimir Kovpak
10.6k43646
asked Nov 22 at 16:56
Vladimir Kovpak
10.6k43646
edited Nov 22 at 17:08
asked Nov 22 at 16:56
Vladimir Kovpak
10.6k43646
asked Nov 22 at 16:56
Vladimir Kovpak
10.6k43646
asked Nov 22 at 16:56
Vladimir Kovpak
10.6k43646
10.6k43646
add a comment |
add a comment |
1 Answer
1
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oldest
votes
up vote
1
down vote
accepted
Im not sure if this is what you are looking for, but there is this a way.
You can generate a result and store it to a variable like so:
set x 1
select now() gset
select :x, :'now';
Result will be:
?column? | ?column?
----------+-------------------------------
1 | 2018-11-22 19:50:38.391587+02
(1 row)
edited Nov 22 at 17:52
Vladimir Kovpak
10.6k43646
answered Nov 22 at 17:35
Tony 94
1336
Thank you @Tony!
– Vladimir Kovpak
Nov 22 at 18:26
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Im not sure if this is what you are looking for, but there is this a way.
You can generate a result and store it to a variable like so:
set x 1
select now() gset
select :x, :'now';
Result will be:
?column? | ?column?
----------+-------------------------------
1 | 2018-11-22 19:50:38.391587+02
(1 row)
edited Nov 22 at 17:52
Vladimir Kovpak
10.6k43646
answered Nov 22 at 17:35
Tony 94
1336
Thank you @Tony!
– Vladimir Kovpak
Nov 22 at 18:26
add a comment |
up vote
1
down vote
accepted
Im not sure if this is what you are looking for, but there is this a way.
You can generate a result and store it to a variable like so:
set x 1
select now() gset
select :x, :'now';
Result will be:
?column? | ?column?
----------+-------------------------------
1 | 2018-11-22 19:50:38.391587+02
(1 row)
edited Nov 22 at 17:52
Vladimir Kovpak
10.6k43646
answered Nov 22 at 17:35
Tony 94
1336
Thank you @Tony!
– Vladimir Kovpak
Nov 22 at 18:26
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Im not sure if this is what you are looking for, but there is this a way.
You can generate a result and store it to a variable like so:
set x 1
select now() gset
select :x, :'now';
Result will be:
?column? | ?column?
----------+-------------------------------
1 | 2018-11-22 19:50:38.391587+02
(1 row)
edited Nov 22 at 17:52
Vladimir Kovpak
10.6k43646
answered Nov 22 at 17:35
Tony 94
1336
Im not sure if this is what you are looking for, but there is this a way.
You can generate a result and store it to a variable like so:
set x 1
select now() gset
select :x, :'now';
Result will be:
?column? | ?column?
----------+-------------------------------
1 | 2018-11-22 19:50:38.391587+02
(1 row)
edited Nov 22 at 17:52
Vladimir Kovpak
10.6k43646
answered Nov 22 at 17:35
Tony 94
1336
edited Nov 22 at 17:52
Vladimir Kovpak
10.6k43646
edited Nov 22 at 17:52
Vladimir Kovpak
10.6k43646
edited Nov 22 at 17:52
Vladimir Kovpak
10.6k43646
10.6k43646
answered Nov 22 at 17:35
Tony 94
1336
answered Nov 22 at 17:35
Tony 94
1336
answered Nov 22 at 17:35
Tony 94
1336
1336
Thank you @Tony!
– Vladimir Kovpak
Nov 22 at 18:26
add a comment |
Thank you @Tony!
– Vladimir Kovpak
Nov 22 at 18:26
Thank you @Tony!
– Vladimir Kovpak
Nov 22 at 18:26
Thank you @Tony!
– Vladimir Kovpak
Nov 22 at 18:26
add a comment |
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