Dynamic 2D array in C not reading first element











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My uni tasked me with writing a program that reads the input and stores it into a dynamic 2D array, but we haven't covered that topic. I'm encountering a problem with my implementation, as it is skipping the first character in each line. I know the code is not top quality, but I just can't figure out why it skips the first char.



#include <stdio.h>
#include <stdlib.h>
#include <assert.h>


#define MULT 3
#define DIV 2

char *read_line(int *col_size, int *max_c) {
char *line = NULL;
int size = *col_size;
int i, c;
line = malloc(size * sizeof *line);
for (i = 0; ((c = getchar()) != 'n') && (c != EOF); ++i) {
if (i == size) {
size = 1 + size * MULT / DIV;
line = realloc(line, size * sizeof *line);
assert(line != NULL);
}
line[i] = c;
}
if (i > *max_c)
*max_c = i;
if (size > *col_size)
*col_size = size;
return line;
}

char **read(int *row, int *col) {
char **input = NULL;
int row_size = 0;
int col_size = 0;
int i, c;
int max_c = 0;

for (i = 0; (c = getchar()) != EOF; ++i) {
if (i == row_size) {
row_size = 1 + row_size * MULT / DIV;
input = realloc(input, row_size * sizeof *input);
assert(input != NULL);
}
input[i] = read_line(&col_size, &max_c);
}
*row = i;
*col = max_c;
return input;
}


int main(void) {
int row_size, col_size, i, j;
char **board = read(&row_size, &col_size);
for (i = 0; i < row_size; ++i) {
for (j = 0; j < col_size; ++j)
putchar(board[i][j]);
putchar('n');
}
free(board);
return 0;
}









share|improve this question






















  • I've really only glanced at your code, but the one thing jumps out is you have ++i, not i++ in your for loops.
    – whoasked
    Nov 22 at 16:58






  • 4




    @whoasked It doesn't matter which one is used because that statement's value doesn't matter. It's not uncommon to use ++i because it may be slightly more efficient on some systems, depending on optimizations.
    – Thomas Jager
    Nov 22 at 17:08















up vote
0
down vote

favorite












My uni tasked me with writing a program that reads the input and stores it into a dynamic 2D array, but we haven't covered that topic. I'm encountering a problem with my implementation, as it is skipping the first character in each line. I know the code is not top quality, but I just can't figure out why it skips the first char.



#include <stdio.h>
#include <stdlib.h>
#include <assert.h>


#define MULT 3
#define DIV 2

char *read_line(int *col_size, int *max_c) {
char *line = NULL;
int size = *col_size;
int i, c;
line = malloc(size * sizeof *line);
for (i = 0; ((c = getchar()) != 'n') && (c != EOF); ++i) {
if (i == size) {
size = 1 + size * MULT / DIV;
line = realloc(line, size * sizeof *line);
assert(line != NULL);
}
line[i] = c;
}
if (i > *max_c)
*max_c = i;
if (size > *col_size)
*col_size = size;
return line;
}

char **read(int *row, int *col) {
char **input = NULL;
int row_size = 0;
int col_size = 0;
int i, c;
int max_c = 0;

for (i = 0; (c = getchar()) != EOF; ++i) {
if (i == row_size) {
row_size = 1 + row_size * MULT / DIV;
input = realloc(input, row_size * sizeof *input);
assert(input != NULL);
}
input[i] = read_line(&col_size, &max_c);
}
*row = i;
*col = max_c;
return input;
}


int main(void) {
int row_size, col_size, i, j;
char **board = read(&row_size, &col_size);
for (i = 0; i < row_size; ++i) {
for (j = 0; j < col_size; ++j)
putchar(board[i][j]);
putchar('n');
}
free(board);
return 0;
}









share|improve this question






















  • I've really only glanced at your code, but the one thing jumps out is you have ++i, not i++ in your for loops.
    – whoasked
    Nov 22 at 16:58






  • 4




    @whoasked It doesn't matter which one is used because that statement's value doesn't matter. It's not uncommon to use ++i because it may be slightly more efficient on some systems, depending on optimizations.
    – Thomas Jager
    Nov 22 at 17:08













up vote
0
down vote

favorite









up vote
0
down vote

favorite











My uni tasked me with writing a program that reads the input and stores it into a dynamic 2D array, but we haven't covered that topic. I'm encountering a problem with my implementation, as it is skipping the first character in each line. I know the code is not top quality, but I just can't figure out why it skips the first char.



#include <stdio.h>
#include <stdlib.h>
#include <assert.h>


#define MULT 3
#define DIV 2

char *read_line(int *col_size, int *max_c) {
char *line = NULL;
int size = *col_size;
int i, c;
line = malloc(size * sizeof *line);
for (i = 0; ((c = getchar()) != 'n') && (c != EOF); ++i) {
if (i == size) {
size = 1 + size * MULT / DIV;
line = realloc(line, size * sizeof *line);
assert(line != NULL);
}
line[i] = c;
}
if (i > *max_c)
*max_c = i;
if (size > *col_size)
*col_size = size;
return line;
}

char **read(int *row, int *col) {
char **input = NULL;
int row_size = 0;
int col_size = 0;
int i, c;
int max_c = 0;

for (i = 0; (c = getchar()) != EOF; ++i) {
if (i == row_size) {
row_size = 1 + row_size * MULT / DIV;
input = realloc(input, row_size * sizeof *input);
assert(input != NULL);
}
input[i] = read_line(&col_size, &max_c);
}
*row = i;
*col = max_c;
return input;
}


int main(void) {
int row_size, col_size, i, j;
char **board = read(&row_size, &col_size);
for (i = 0; i < row_size; ++i) {
for (j = 0; j < col_size; ++j)
putchar(board[i][j]);
putchar('n');
}
free(board);
return 0;
}









share|improve this question













My uni tasked me with writing a program that reads the input and stores it into a dynamic 2D array, but we haven't covered that topic. I'm encountering a problem with my implementation, as it is skipping the first character in each line. I know the code is not top quality, but I just can't figure out why it skips the first char.



#include <stdio.h>
#include <stdlib.h>
#include <assert.h>


#define MULT 3
#define DIV 2

char *read_line(int *col_size, int *max_c) {
char *line = NULL;
int size = *col_size;
int i, c;
line = malloc(size * sizeof *line);
for (i = 0; ((c = getchar()) != 'n') && (c != EOF); ++i) {
if (i == size) {
size = 1 + size * MULT / DIV;
line = realloc(line, size * sizeof *line);
assert(line != NULL);
}
line[i] = c;
}
if (i > *max_c)
*max_c = i;
if (size > *col_size)
*col_size = size;
return line;
}

char **read(int *row, int *col) {
char **input = NULL;
int row_size = 0;
int col_size = 0;
int i, c;
int max_c = 0;

for (i = 0; (c = getchar()) != EOF; ++i) {
if (i == row_size) {
row_size = 1 + row_size * MULT / DIV;
input = realloc(input, row_size * sizeof *input);
assert(input != NULL);
}
input[i] = read_line(&col_size, &max_c);
}
*row = i;
*col = max_c;
return input;
}


int main(void) {
int row_size, col_size, i, j;
char **board = read(&row_size, &col_size);
for (i = 0; i < row_size; ++i) {
for (j = 0; j < col_size; ++j)
putchar(board[i][j]);
putchar('n');
}
free(board);
return 0;
}






c






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share|improve this question










asked Nov 22 at 16:54









guben

185




185












  • I've really only glanced at your code, but the one thing jumps out is you have ++i, not i++ in your for loops.
    – whoasked
    Nov 22 at 16:58






  • 4




    @whoasked It doesn't matter which one is used because that statement's value doesn't matter. It's not uncommon to use ++i because it may be slightly more efficient on some systems, depending on optimizations.
    – Thomas Jager
    Nov 22 at 17:08


















  • I've really only glanced at your code, but the one thing jumps out is you have ++i, not i++ in your for loops.
    – whoasked
    Nov 22 at 16:58






  • 4




    @whoasked It doesn't matter which one is used because that statement's value doesn't matter. It's not uncommon to use ++i because it may be slightly more efficient on some systems, depending on optimizations.
    – Thomas Jager
    Nov 22 at 17:08
















I've really only glanced at your code, but the one thing jumps out is you have ++i, not i++ in your for loops.
– whoasked
Nov 22 at 16:58




I've really only glanced at your code, but the one thing jumps out is you have ++i, not i++ in your for loops.
– whoasked
Nov 22 at 16:58




4




4




@whoasked It doesn't matter which one is used because that statement's value doesn't matter. It's not uncommon to use ++i because it may be slightly more efficient on some systems, depending on optimizations.
– Thomas Jager
Nov 22 at 17:08




@whoasked It doesn't matter which one is used because that statement's value doesn't matter. It's not uncommon to use ++i because it may be slightly more efficient on some systems, depending on optimizations.
– Thomas Jager
Nov 22 at 17:08












1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted











for (i = 0; (c = getchar()) != EOF; ++i) {



in read() eats up the first character of a line before read_line() gets to see it. You'll have to find some other way to check for EOF. For example with



for (i = 0; !feof(stdin); ++i) {




Also, you don't zero-terminate your strings. Change your reading loop to



char *read_line(int *col_size, int *max_c) {
int size = *col_size ? *col_size : 1; // at least 1 for the terminating 0
char *line = malloc(size * sizeof *line);

if(!line)
return NULL;

int i, c;
for (i = 0; ((c = getchar()) != 'n') && (c != EOF); ++i) {
if(i == size) {
size = 2 + size * MULT / DIV; // note the 2
// ...
}
// ...
}
line[i] = '';


to do so.






for (i = 0; i < row_size; ++i) {
for (j = 0; j < col_size; ++j)
putchar(board[i][j]); // accesses memory that isn't yours
putchar('n'); // if not all rows are of the same length.
}



To avoid reading memory out-of-bounds, change that to



for (i = 0; i < row_size; ++i) {
for (j = 0; board[i][j] != ''; ++j)
putchar(board[i][j]);
putchar('n');
}


since you now have zero-terminated strings. Or why not just use puts()?



for (i = 0; i < row_size; ++i)
puts(board[i]);





free(board);



That won't deallocate the memory you allocated for the rows. You'd have to



for (i = 0; i < row_size; ++i)
free(bard[i]);
free(board);





share|improve this answer























  • Thank you so much! I see there's a lot I have to learn yet ;)))
    – guben
    Nov 22 at 20:04










  • Altough, it's possible that the program is going to try to place the '' at an index that isn't allocated, since it's outside the loop that checks wether i is small enough.
    – guben
    Nov 22 at 20:14










  • @guben You are right. size = 1 + size * MULT / DIV; should be size = 2 + size * MULT / DIV; Where does that idea of MULT / DIV come from?
    – Swordfish
    Nov 22 at 20:19












  • From the example code given by my uni professor, who said that usually, it's multiplied by 2, but here it's better to multiply by 3/2. He didn't tell us why though xD
    – guben
    Nov 22 at 20:37












  • Actually, Valgrind throws an invalid write error, when given an empty row :/
    – guben
    Nov 22 at 21:11











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted











for (i = 0; (c = getchar()) != EOF; ++i) {



in read() eats up the first character of a line before read_line() gets to see it. You'll have to find some other way to check for EOF. For example with



for (i = 0; !feof(stdin); ++i) {




Also, you don't zero-terminate your strings. Change your reading loop to



char *read_line(int *col_size, int *max_c) {
int size = *col_size ? *col_size : 1; // at least 1 for the terminating 0
char *line = malloc(size * sizeof *line);

if(!line)
return NULL;

int i, c;
for (i = 0; ((c = getchar()) != 'n') && (c != EOF); ++i) {
if(i == size) {
size = 2 + size * MULT / DIV; // note the 2
// ...
}
// ...
}
line[i] = '';


to do so.






for (i = 0; i < row_size; ++i) {
for (j = 0; j < col_size; ++j)
putchar(board[i][j]); // accesses memory that isn't yours
putchar('n'); // if not all rows are of the same length.
}



To avoid reading memory out-of-bounds, change that to



for (i = 0; i < row_size; ++i) {
for (j = 0; board[i][j] != ''; ++j)
putchar(board[i][j]);
putchar('n');
}


since you now have zero-terminated strings. Or why not just use puts()?



for (i = 0; i < row_size; ++i)
puts(board[i]);





free(board);



That won't deallocate the memory you allocated for the rows. You'd have to



for (i = 0; i < row_size; ++i)
free(bard[i]);
free(board);





share|improve this answer























  • Thank you so much! I see there's a lot I have to learn yet ;)))
    – guben
    Nov 22 at 20:04










  • Altough, it's possible that the program is going to try to place the '' at an index that isn't allocated, since it's outside the loop that checks wether i is small enough.
    – guben
    Nov 22 at 20:14










  • @guben You are right. size = 1 + size * MULT / DIV; should be size = 2 + size * MULT / DIV; Where does that idea of MULT / DIV come from?
    – Swordfish
    Nov 22 at 20:19












  • From the example code given by my uni professor, who said that usually, it's multiplied by 2, but here it's better to multiply by 3/2. He didn't tell us why though xD
    – guben
    Nov 22 at 20:37












  • Actually, Valgrind throws an invalid write error, when given an empty row :/
    – guben
    Nov 22 at 21:11















up vote
1
down vote



accepted











for (i = 0; (c = getchar()) != EOF; ++i) {



in read() eats up the first character of a line before read_line() gets to see it. You'll have to find some other way to check for EOF. For example with



for (i = 0; !feof(stdin); ++i) {




Also, you don't zero-terminate your strings. Change your reading loop to



char *read_line(int *col_size, int *max_c) {
int size = *col_size ? *col_size : 1; // at least 1 for the terminating 0
char *line = malloc(size * sizeof *line);

if(!line)
return NULL;

int i, c;
for (i = 0; ((c = getchar()) != 'n') && (c != EOF); ++i) {
if(i == size) {
size = 2 + size * MULT / DIV; // note the 2
// ...
}
// ...
}
line[i] = '';


to do so.






for (i = 0; i < row_size; ++i) {
for (j = 0; j < col_size; ++j)
putchar(board[i][j]); // accesses memory that isn't yours
putchar('n'); // if not all rows are of the same length.
}



To avoid reading memory out-of-bounds, change that to



for (i = 0; i < row_size; ++i) {
for (j = 0; board[i][j] != ''; ++j)
putchar(board[i][j]);
putchar('n');
}


since you now have zero-terminated strings. Or why not just use puts()?



for (i = 0; i < row_size; ++i)
puts(board[i]);





free(board);



That won't deallocate the memory you allocated for the rows. You'd have to



for (i = 0; i < row_size; ++i)
free(bard[i]);
free(board);





share|improve this answer























  • Thank you so much! I see there's a lot I have to learn yet ;)))
    – guben
    Nov 22 at 20:04










  • Altough, it's possible that the program is going to try to place the '' at an index that isn't allocated, since it's outside the loop that checks wether i is small enough.
    – guben
    Nov 22 at 20:14










  • @guben You are right. size = 1 + size * MULT / DIV; should be size = 2 + size * MULT / DIV; Where does that idea of MULT / DIV come from?
    – Swordfish
    Nov 22 at 20:19












  • From the example code given by my uni professor, who said that usually, it's multiplied by 2, but here it's better to multiply by 3/2. He didn't tell us why though xD
    – guben
    Nov 22 at 20:37












  • Actually, Valgrind throws an invalid write error, when given an empty row :/
    – guben
    Nov 22 at 21:11













up vote
1
down vote



accepted







up vote
1
down vote



accepted







for (i = 0; (c = getchar()) != EOF; ++i) {



in read() eats up the first character of a line before read_line() gets to see it. You'll have to find some other way to check for EOF. For example with



for (i = 0; !feof(stdin); ++i) {




Also, you don't zero-terminate your strings. Change your reading loop to



char *read_line(int *col_size, int *max_c) {
int size = *col_size ? *col_size : 1; // at least 1 for the terminating 0
char *line = malloc(size * sizeof *line);

if(!line)
return NULL;

int i, c;
for (i = 0; ((c = getchar()) != 'n') && (c != EOF); ++i) {
if(i == size) {
size = 2 + size * MULT / DIV; // note the 2
// ...
}
// ...
}
line[i] = '';


to do so.






for (i = 0; i < row_size; ++i) {
for (j = 0; j < col_size; ++j)
putchar(board[i][j]); // accesses memory that isn't yours
putchar('n'); // if not all rows are of the same length.
}



To avoid reading memory out-of-bounds, change that to



for (i = 0; i < row_size; ++i) {
for (j = 0; board[i][j] != ''; ++j)
putchar(board[i][j]);
putchar('n');
}


since you now have zero-terminated strings. Or why not just use puts()?



for (i = 0; i < row_size; ++i)
puts(board[i]);





free(board);



That won't deallocate the memory you allocated for the rows. You'd have to



for (i = 0; i < row_size; ++i)
free(bard[i]);
free(board);





share|improve this answer















for (i = 0; (c = getchar()) != EOF; ++i) {



in read() eats up the first character of a line before read_line() gets to see it. You'll have to find some other way to check for EOF. For example with



for (i = 0; !feof(stdin); ++i) {




Also, you don't zero-terminate your strings. Change your reading loop to



char *read_line(int *col_size, int *max_c) {
int size = *col_size ? *col_size : 1; // at least 1 for the terminating 0
char *line = malloc(size * sizeof *line);

if(!line)
return NULL;

int i, c;
for (i = 0; ((c = getchar()) != 'n') && (c != EOF); ++i) {
if(i == size) {
size = 2 + size * MULT / DIV; // note the 2
// ...
}
// ...
}
line[i] = '';


to do so.






for (i = 0; i < row_size; ++i) {
for (j = 0; j < col_size; ++j)
putchar(board[i][j]); // accesses memory that isn't yours
putchar('n'); // if not all rows are of the same length.
}



To avoid reading memory out-of-bounds, change that to



for (i = 0; i < row_size; ++i) {
for (j = 0; board[i][j] != ''; ++j)
putchar(board[i][j]);
putchar('n');
}


since you now have zero-terminated strings. Or why not just use puts()?



for (i = 0; i < row_size; ++i)
puts(board[i]);





free(board);



That won't deallocate the memory you allocated for the rows. You'd have to



for (i = 0; i < row_size; ++i)
free(bard[i]);
free(board);






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 22 at 20:24

























answered Nov 22 at 17:18









Swordfish

1




1












  • Thank you so much! I see there's a lot I have to learn yet ;)))
    – guben
    Nov 22 at 20:04










  • Altough, it's possible that the program is going to try to place the '' at an index that isn't allocated, since it's outside the loop that checks wether i is small enough.
    – guben
    Nov 22 at 20:14










  • @guben You are right. size = 1 + size * MULT / DIV; should be size = 2 + size * MULT / DIV; Where does that idea of MULT / DIV come from?
    – Swordfish
    Nov 22 at 20:19












  • From the example code given by my uni professor, who said that usually, it's multiplied by 2, but here it's better to multiply by 3/2. He didn't tell us why though xD
    – guben
    Nov 22 at 20:37












  • Actually, Valgrind throws an invalid write error, when given an empty row :/
    – guben
    Nov 22 at 21:11


















  • Thank you so much! I see there's a lot I have to learn yet ;)))
    – guben
    Nov 22 at 20:04










  • Altough, it's possible that the program is going to try to place the '' at an index that isn't allocated, since it's outside the loop that checks wether i is small enough.
    – guben
    Nov 22 at 20:14










  • @guben You are right. size = 1 + size * MULT / DIV; should be size = 2 + size * MULT / DIV; Where does that idea of MULT / DIV come from?
    – Swordfish
    Nov 22 at 20:19












  • From the example code given by my uni professor, who said that usually, it's multiplied by 2, but here it's better to multiply by 3/2. He didn't tell us why though xD
    – guben
    Nov 22 at 20:37












  • Actually, Valgrind throws an invalid write error, when given an empty row :/
    – guben
    Nov 22 at 21:11
















Thank you so much! I see there's a lot I have to learn yet ;)))
– guben
Nov 22 at 20:04




Thank you so much! I see there's a lot I have to learn yet ;)))
– guben
Nov 22 at 20:04












Altough, it's possible that the program is going to try to place the '' at an index that isn't allocated, since it's outside the loop that checks wether i is small enough.
– guben
Nov 22 at 20:14




Altough, it's possible that the program is going to try to place the '' at an index that isn't allocated, since it's outside the loop that checks wether i is small enough.
– guben
Nov 22 at 20:14












@guben You are right. size = 1 + size * MULT / DIV; should be size = 2 + size * MULT / DIV; Where does that idea of MULT / DIV come from?
– Swordfish
Nov 22 at 20:19






@guben You are right. size = 1 + size * MULT / DIV; should be size = 2 + size * MULT / DIV; Where does that idea of MULT / DIV come from?
– Swordfish
Nov 22 at 20:19














From the example code given by my uni professor, who said that usually, it's multiplied by 2, but here it's better to multiply by 3/2. He didn't tell us why though xD
– guben
Nov 22 at 20:37






From the example code given by my uni professor, who said that usually, it's multiplied by 2, but here it's better to multiply by 3/2. He didn't tell us why though xD
– guben
Nov 22 at 20:37














Actually, Valgrind throws an invalid write error, when given an empty row :/
– guben
Nov 22 at 21:11




Actually, Valgrind throws an invalid write error, when given an empty row :/
– guben
Nov 22 at 21:11


















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