ggplot2 facet labeller with bquote
up vote
1
down vote
favorite
Yet another labeller question... I am struggling using math expressions in labellers with ggplot2 > 3
library(ggplot2)
var.lab1 = as_labeller(c(
"setosa" = "se",
"versicolor" = "ve",
"virginica" = "vi"
))
var.lab2 = as_labeller(c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
))
This works as expected
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab1) +
geom_point()
This doesn't work (the labeller has no effect)
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab2) +
geom_point()
And this works
var.lab3 = c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
)
vlabeller <- function (variable, value) {
return(var.lab3[value])
}
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = vlabeller) +
geom_point()
But ggplot2 is unhappy "Warning message: The labeller API has been updated. Labellers taking variable and value arguments are now deprecated. See labellers documentation."
r ggplot2
asked Nov 22 at 17:14
user2165907
6493719
add a comment |
up vote
1
down vote
favorite
Yet another labeller question... I am struggling using math expressions in labellers with ggplot2 > 3
library(ggplot2)
var.lab1 = as_labeller(c(
"setosa" = "se",
"versicolor" = "ve",
"virginica" = "vi"
))
var.lab2 = as_labeller(c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
))
This works as expected
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab1) +
geom_point()
This doesn't work (the labeller has no effect)
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab2) +
geom_point()
And this works
var.lab3 = c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
)
vlabeller <- function (variable, value) {
return(var.lab3[value])
}
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = vlabeller) +
geom_point()
But ggplot2 is unhappy "Warning message: The labeller API has been updated. Labellers taking variable and value arguments are now deprecated. See labellers documentation."
r ggplot2
asked Nov 22 at 17:14
user2165907
6493719
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Yet another labeller question... I am struggling using math expressions in labellers with ggplot2 > 3
library(ggplot2)
var.lab1 = as_labeller(c(
"setosa" = "se",
"versicolor" = "ve",
"virginica" = "vi"
))
var.lab2 = as_labeller(c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
))
This works as expected
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab1) +
geom_point()
This doesn't work (the labeller has no effect)
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab2) +
geom_point()
And this works
var.lab3 = c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
)
vlabeller <- function (variable, value) {
return(var.lab3[value])
}
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = vlabeller) +
geom_point()
But ggplot2 is unhappy "Warning message: The labeller API has been updated. Labellers taking variable and value arguments are now deprecated. See labellers documentation."
r ggplot2
asked Nov 22 at 17:14
user2165907
6493719
Yet another labeller question... I am struggling using math expressions in labellers with ggplot2 > 3
library(ggplot2)
var.lab1 = as_labeller(c(
"setosa" = "se",
"versicolor" = "ve",
"virginica" = "vi"
))
var.lab2 = as_labeller(c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
))
This works as expected
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab1) +
geom_point()
This doesn't work (the labeller has no effect)
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab2) +
geom_point()
And this works
var.lab3 = c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
)
vlabeller <- function (variable, value) {
return(var.lab3[value])
}
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = vlabeller) +
geom_point()
But ggplot2 is unhappy "Warning message: The labeller API has been updated. Labellers taking variable and value arguments are now deprecated. See labellers documentation."
r ggplot2
r ggplot2
asked Nov 22 at 17:14
user2165907
6493719
asked Nov 22 at 17:14
user2165907
6493719
edited Nov 22 at 18:00
asked Nov 22 at 17:14
user2165907
6493719
asked Nov 22 at 17:14
user2165907
6493719
asked Nov 22 at 17:14
user2165907
6493719
6493719
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
2
down vote
accepted
You could just use label_bquote and substr to get what you want. No need for a custom labeller.
library(ggplot2)
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
geom_point()
Created on 2018-11-22 by the reprex package (v0.2.1)
answered Nov 22 at 17:36
Jake Kaupp
5,15721428
Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
– user2165907
Nov 22 at 17:54
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
You could just use label_bquote and substr to get what you want. No need for a custom labeller.
library(ggplot2)
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
geom_point()
Created on 2018-11-22 by the reprex package (v0.2.1)
answered Nov 22 at 17:36
Jake Kaupp
5,15721428
Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
– user2165907
Nov 22 at 17:54
add a comment |
up vote
2
down vote
accepted
You could just use label_bquote and substr to get what you want. No need for a custom labeller.
library(ggplot2)
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
geom_point()
Created on 2018-11-22 by the reprex package (v0.2.1)
answered Nov 22 at 17:36
Jake Kaupp
5,15721428
Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
– user2165907
Nov 22 at 17:54
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
You could just use label_bquote and substr to get what you want. No need for a custom labeller.
library(ggplot2)
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
geom_point()
Created on 2018-11-22 by the reprex package (v0.2.1)
answered Nov 22 at 17:36
Jake Kaupp
5,15721428
You could just use label_bquote and substr to get what you want. No need for a custom labeller.
library(ggplot2)
ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
geom_point()
Created on 2018-11-22 by the reprex package (v0.2.1)
answered Nov 22 at 17:36
Jake Kaupp
5,15721428
answered Nov 22 at 17:36
Jake Kaupp
5,15721428
answered Nov 22 at 17:36
Jake Kaupp
5,15721428
answered Nov 22 at 17:36
Jake Kaupp
5,15721428
5,15721428
Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
– user2165907
Nov 22 at 17:54
add a comment |
Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
– user2165907
Nov 22 at 17:54
Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
– user2165907
Nov 22 at 17:54
Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
– user2165907
Nov 22 at 17:54
add a comment |
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