Can't use SQL lag sum
-3
My query is like this
SELECT
[day], [time],AvaliableTimes,
CASE
WHEN AvaliableTimes > 0
THEN SUM(AvaliableTimes) OVER (ORDER BY [day], [time], AvaliableTimes)
ELSE 0
END AS SumValue
FROM
[AvailableTimes]
WHERE
[day] = 1 AND BranchAreaId = 1
ORDER BY
[day], [time], AvaliableTimes
I want to start sum from 0 if value is null or 0.
Results:
sql
sql-server sum lag edited Nov 23 '18 at 5:51
marc_s
570k12811031251
asked Nov 23 '18 at 4:54
Sunil Paudel
83
add a comment |
-3
My query is like this
SELECT
[day], [time],AvaliableTimes,
CASE
WHEN AvaliableTimes > 0
THEN SUM(AvaliableTimes) OVER (ORDER BY [day], [time], AvaliableTimes)
ELSE 0
END AS SumValue
FROM
[AvailableTimes]
WHERE
[day] = 1 AND BranchAreaId = 1
ORDER BY
[day], [time], AvaliableTimes
I want to start sum from 0 if value is null or 0.
Results:
sql
sql-server sum lag edited Nov 23 '18 at 5:51
marc_s
570k12811031251
asked Nov 23 '18 at 4:54
Sunil Paudel
83
What is the problem? Show us db schema, sample data, current and expected output. Please read How-to-Ask And here is a great place to START to learn how improve your question quality and get better answers. How to create a Minimal, Complete, and Verifiable example
– Juan Carlos Oropeza
Nov 23 '18 at 5:00
Post the tables and data as text READ THIS
– Juan Carlos Oropeza
Nov 23 '18 at 5:04
add a comment |
-3
-3
-3
My query is like this
SELECT
[day], [time],AvaliableTimes,
CASE
WHEN AvaliableTimes > 0
THEN SUM(AvaliableTimes) OVER (ORDER BY [day], [time], AvaliableTimes)
ELSE 0
END AS SumValue
FROM
[AvailableTimes]
WHERE
[day] = 1 AND BranchAreaId = 1
ORDER BY
[day], [time], AvaliableTimes
I want to start sum from 0 if value is null or 0.
Results:
sql
sql-server sum lag edited Nov 23 '18 at 5:51
marc_s
570k12811031251
asked Nov 23 '18 at 4:54
Sunil Paudel
83
My query is like this
SELECT
[day], [time],AvaliableTimes,
CASE
WHEN AvaliableTimes > 0
THEN SUM(AvaliableTimes) OVER (ORDER BY [day], [time], AvaliableTimes)
ELSE 0
END AS SumValue
FROM
[AvailableTimes]
WHERE
[day] = 1 AND BranchAreaId = 1
ORDER BY
[day], [time], AvaliableTimes
I want to start sum from 0 if value is null or 0.
Results:
sql
sql-server sum lag sql
sql-server sum lag edited Nov 23 '18 at 5:51
marc_s
570k12811031251
asked Nov 23 '18 at 4:54
Sunil Paudel
83
edited Nov 23 '18 at 5:51
marc_s
570k12811031251
asked Nov 23 '18 at 4:54
Sunil Paudel
83
edited Nov 23 '18 at 5:51
marc_s
570k12811031251
edited Nov 23 '18 at 5:51
marc_s
570k12811031251
edited Nov 23 '18 at 5:51
marc_s
570k12811031251
570k12811031251
asked Nov 23 '18 at 4:54
Sunil Paudel
83
asked Nov 23 '18 at 4:54
Sunil Paudel
83
asked Nov 23 '18 at 4:54
Sunil Paudel
83
83
What is the problem? Show us db schema, sample data, current and expected output. Please read How-to-Ask And here is a great place to START to learn how improve your question quality and get better answers. How to create a Minimal, Complete, and Verifiable example
– Juan Carlos Oropeza
Nov 23 '18 at 5:00
Post the tables and data as text READ THIS
– Juan Carlos Oropeza
Nov 23 '18 at 5:04
add a comment |
What is the problem? Show us db schema, sample data, current and expected output. Please read How-to-Ask And here is a great place to START to learn how improve your question quality and get better answers. How to create a Minimal, Complete, and Verifiable example
– Juan Carlos Oropeza
Nov 23 '18 at 5:00
Post the tables and data as text READ THIS
– Juan Carlos Oropeza
Nov 23 '18 at 5:04
What is the problem? Show us db schema, sample data, current and expected output. Please read How-to-Ask And here is a great place to START to learn how improve your question quality and get better answers. How to create a Minimal, Complete, and Verifiable example
– Juan Carlos Oropeza
Nov 23 '18 at 5:00
What is the problem? Show us db schema, sample data, current and expected output. Please read How-to-Ask And here is a great place to START to learn how improve your question quality and get better answers. How to create a Minimal, Complete, and Verifiable example
– Juan Carlos Oropeza
Nov 23 '18 at 5:00
Post the tables and data as text READ THIS
– Juan Carlos Oropeza
Nov 23 '18 at 5:04
Post the tables and data as text READ THIS
– Juan Carlos Oropeza
Nov 23 '18 at 5:04
add a comment |
1 Answer
1
active
oldest
votes
0
you can use a recursive CTE to do it. Perform the cumulative sum in the rcte and if AvailableTimes = 0, reset it
; with
cte as
(
select *, rn = row_number() over (order by time)
from yourtable
),
rcte as
(
select *, sumvalues = AvailableTimes
from cte
where rn = 1
union all
select c.*, sumvalues = case when c.AvailableTimes <> 0
then r.sumvalues + c.AvailableTimes
else c.AvailableTimes
end
from cte c
inner join rcte r on c.rn = r.rn + 1
)
select day, time, AvailableTimes, sumvalues
from rcte
order by time
answered Nov 23 '18 at 5:09
Squirrel
11.7k22027
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
you can use a recursive CTE to do it. Perform the cumulative sum in the rcte and if AvailableTimes = 0, reset it
; with
cte as
(
select *, rn = row_number() over (order by time)
from yourtable
),
rcte as
(
select *, sumvalues = AvailableTimes
from cte
where rn = 1
union all
select c.*, sumvalues = case when c.AvailableTimes <> 0
then r.sumvalues + c.AvailableTimes
else c.AvailableTimes
end
from cte c
inner join rcte r on c.rn = r.rn + 1
)
select day, time, AvailableTimes, sumvalues
from rcte
order by time
answered Nov 23 '18 at 5:09
Squirrel
11.7k22027
add a comment |
0
you can use a recursive CTE to do it. Perform the cumulative sum in the rcte and if AvailableTimes = 0, reset it
; with
cte as
(
select *, rn = row_number() over (order by time)
from yourtable
),
rcte as
(
select *, sumvalues = AvailableTimes
from cte
where rn = 1
union all
select c.*, sumvalues = case when c.AvailableTimes <> 0
then r.sumvalues + c.AvailableTimes
else c.AvailableTimes
end
from cte c
inner join rcte r on c.rn = r.rn + 1
)
select day, time, AvailableTimes, sumvalues
from rcte
order by time
answered Nov 23 '18 at 5:09
Squirrel
11.7k22027
add a comment |
0
0
0
you can use a recursive CTE to do it. Perform the cumulative sum in the rcte and if AvailableTimes = 0, reset it
; with
cte as
(
select *, rn = row_number() over (order by time)
from yourtable
),
rcte as
(
select *, sumvalues = AvailableTimes
from cte
where rn = 1
union all
select c.*, sumvalues = case when c.AvailableTimes <> 0
then r.sumvalues + c.AvailableTimes
else c.AvailableTimes
end
from cte c
inner join rcte r on c.rn = r.rn + 1
)
select day, time, AvailableTimes, sumvalues
from rcte
order by time
answered Nov 23 '18 at 5:09
Squirrel
11.7k22027
you can use a recursive CTE to do it. Perform the cumulative sum in the rcte and if AvailableTimes = 0, reset it
; with
cte as
(
select *, rn = row_number() over (order by time)
from yourtable
),
rcte as
(
select *, sumvalues = AvailableTimes
from cte
where rn = 1
union all
select c.*, sumvalues = case when c.AvailableTimes <> 0
then r.sumvalues + c.AvailableTimes
else c.AvailableTimes
end
from cte c
inner join rcte r on c.rn = r.rn + 1
)
select day, time, AvailableTimes, sumvalues
from rcte
order by time
answered Nov 23 '18 at 5:09
Squirrel
11.7k22027
answered Nov 23 '18 at 5:09
Squirrel
11.7k22027
answered Nov 23 '18 at 5:09
Squirrel
11.7k22027
answered Nov 23 '18 at 5:09
Squirrel
11.7k22027
11.7k22027
add a comment |
add a comment |
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What is the problem? Show us db schema, sample data, current and expected output. Please read How-to-Ask And here is a great place to START to learn how improve your question quality and get better answers. How to create a Minimal, Complete, and Verifiable example
– Juan Carlos Oropeza
Nov 23 '18 at 5:00
Post the tables and data as text READ THIS
– Juan Carlos Oropeza
Nov 23 '18 at 5:04