T-test and importing data from columns
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I am trying to conduct a T-test on two unequal samples using the following code.
import pandas as pd
import numpy as np
from scipy import stats
UG = pd.read_csv('Mostfrequentscores.csv')
print('Mean', UG['Iceland'].mean())
print('Mean', UG['Peru'].mean())
I = UG['Iceland']
P = UG['Peru']
t = stats.ttest_ind(I, P, equal_var = False)
The mean prints fine, which I assume means its reading the columns in the file - but the T-test keeps on giving me the following error:
C:UsersmsuAnaconda3libsite-packagesscipystats_distn_infrastructure.py:879:
RuntimeWarning: invalid value encountered in greater
Could this be due to my data which is a series of numbers from -3 to 3? Do I need to convert it using float?
python pandas scipy probability t-test
add a comment |
up vote
0
down vote
favorite
I am trying to conduct a T-test on two unequal samples using the following code.
import pandas as pd
import numpy as np
from scipy import stats
UG = pd.read_csv('Mostfrequentscores.csv')
print('Mean', UG['Iceland'].mean())
print('Mean', UG['Peru'].mean())
I = UG['Iceland']
P = UG['Peru']
t = stats.ttest_ind(I, P, equal_var = False)
The mean prints fine, which I assume means its reading the columns in the file - but the T-test keeps on giving me the following error:
C:UsersmsuAnaconda3libsite-packagesscipystats_distn_infrastructure.py:879:
RuntimeWarning: invalid value encountered in greater
Could this be due to my data which is a series of numbers from -3 to 3? Do I need to convert it using float?
python pandas scipy probability t-test
Have you checked ifI
orP
contain nan values ?
– Gusto
Nov 22 at 7:49
Thans for the reply Yes I did. Just negative, positive and 0 values.
– MS.TO
Nov 22 at 8:12
can you tell us what happens if you do convert to float? (would there be some zero integer mean used to divide and get variance or something?)
– Silmathoron
Nov 22 at 11:01
I get the same error. i tried the following for the one column: Per = UG['peru'].astype(float)
– MS.TO
Nov 22 at 20:08
You will have to post some of your data, otherwise it is hard to help.
– Cleb
Nov 23 at 13:39
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am trying to conduct a T-test on two unequal samples using the following code.
import pandas as pd
import numpy as np
from scipy import stats
UG = pd.read_csv('Mostfrequentscores.csv')
print('Mean', UG['Iceland'].mean())
print('Mean', UG['Peru'].mean())
I = UG['Iceland']
P = UG['Peru']
t = stats.ttest_ind(I, P, equal_var = False)
The mean prints fine, which I assume means its reading the columns in the file - but the T-test keeps on giving me the following error:
C:UsersmsuAnaconda3libsite-packagesscipystats_distn_infrastructure.py:879:
RuntimeWarning: invalid value encountered in greater
Could this be due to my data which is a series of numbers from -3 to 3? Do I need to convert it using float?
python pandas scipy probability t-test
I am trying to conduct a T-test on two unequal samples using the following code.
import pandas as pd
import numpy as np
from scipy import stats
UG = pd.read_csv('Mostfrequentscores.csv')
print('Mean', UG['Iceland'].mean())
print('Mean', UG['Peru'].mean())
I = UG['Iceland']
P = UG['Peru']
t = stats.ttest_ind(I, P, equal_var = False)
The mean prints fine, which I assume means its reading the columns in the file - but the T-test keeps on giving me the following error:
C:UsersmsuAnaconda3libsite-packagesscipystats_distn_infrastructure.py:879:
RuntimeWarning: invalid value encountered in greater
Could this be due to my data which is a series of numbers from -3 to 3? Do I need to convert it using float?
python pandas scipy probability t-test
python pandas scipy probability t-test
edited Nov 23 at 13:38
Cleb
10.1k115076
10.1k115076
asked Nov 22 at 7:18
MS.TO
82
82
Have you checked ifI
orP
contain nan values ?
– Gusto
Nov 22 at 7:49
Thans for the reply Yes I did. Just negative, positive and 0 values.
– MS.TO
Nov 22 at 8:12
can you tell us what happens if you do convert to float? (would there be some zero integer mean used to divide and get variance or something?)
– Silmathoron
Nov 22 at 11:01
I get the same error. i tried the following for the one column: Per = UG['peru'].astype(float)
– MS.TO
Nov 22 at 20:08
You will have to post some of your data, otherwise it is hard to help.
– Cleb
Nov 23 at 13:39
add a comment |
Have you checked ifI
orP
contain nan values ?
– Gusto
Nov 22 at 7:49
Thans for the reply Yes I did. Just negative, positive and 0 values.
– MS.TO
Nov 22 at 8:12
can you tell us what happens if you do convert to float? (would there be some zero integer mean used to divide and get variance or something?)
– Silmathoron
Nov 22 at 11:01
I get the same error. i tried the following for the one column: Per = UG['peru'].astype(float)
– MS.TO
Nov 22 at 20:08
You will have to post some of your data, otherwise it is hard to help.
– Cleb
Nov 23 at 13:39
Have you checked if
I
or P
contain nan values ?– Gusto
Nov 22 at 7:49
Have you checked if
I
or P
contain nan values ?– Gusto
Nov 22 at 7:49
Thans for the reply Yes I did. Just negative, positive and 0 values.
– MS.TO
Nov 22 at 8:12
Thans for the reply Yes I did. Just negative, positive and 0 values.
– MS.TO
Nov 22 at 8:12
can you tell us what happens if you do convert to float? (would there be some zero integer mean used to divide and get variance or something?)
– Silmathoron
Nov 22 at 11:01
can you tell us what happens if you do convert to float? (would there be some zero integer mean used to divide and get variance or something?)
– Silmathoron
Nov 22 at 11:01
I get the same error. i tried the following for the one column: Per = UG['peru'].astype(float)
– MS.TO
Nov 22 at 20:08
I get the same error. i tried the following for the one column: Per = UG['peru'].astype(float)
– MS.TO
Nov 22 at 20:08
You will have to post some of your data, otherwise it is hard to help.
– Cleb
Nov 23 at 13:39
You will have to post some of your data, otherwise it is hard to help.
– Cleb
Nov 23 at 13:39
add a comment |
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Have you checked if
I
orP
contain nan values ?– Gusto
Nov 22 at 7:49
Thans for the reply Yes I did. Just negative, positive and 0 values.
– MS.TO
Nov 22 at 8:12
can you tell us what happens if you do convert to float? (would there be some zero integer mean used to divide and get variance or something?)
– Silmathoron
Nov 22 at 11:01
I get the same error. i tried the following for the one column: Per = UG['peru'].astype(float)
– MS.TO
Nov 22 at 20:08
You will have to post some of your data, otherwise it is hard to help.
– Cleb
Nov 23 at 13:39