Entity Association syntax issue with graphql queries
up vote
0
down vote
favorite
I am trying to understand graphql's query and mutation syntax. Given this example:
type Author {
id: Int!
firstName: String
lastName: String
posts: [Post]
}
type Post {
id: Int!
title: String
author: Author
votes: Int
}
type Query {
posts: [Post]
author(id: Int!): Author
}
What should the queries look like to associate a post with the author? Is this where connections come into play or is that something else? Here is my attempt at trying to solve the problem but to avail.
mutation createAuthor {
createAuthor(input: {
id: 123
firstName: "Bob"
lastName: "Smith"
}) {
id
firstName
lastName
}
}
query listAuthors {
listAuthors {
items {
id
firstName
lastName
}
}
}
mutation createPost {
createPost(input: {
id: 12345
title: "Title"
votes: 345
author: {
lastName: {
contains: "Bob"
}
}
}) {
id
title
votes
author {
id
firstName
lastName
}
}
}
Any help on this would be appreciated. My Goal is to Query an author and return all of the post's associated with that author as well as create a Post Mutation that adds a post to an author.
graphql aws-appsync
asked Nov 21 at 23:41
Jghorton14
1441215
add a comment |
up vote
0
down vote
favorite
I am trying to understand graphql's query and mutation syntax. Given this example:
type Author {
id: Int!
firstName: String
lastName: String
posts: [Post]
}
type Post {
id: Int!
title: String
author: Author
votes: Int
}
type Query {
posts: [Post]
author(id: Int!): Author
}
What should the queries look like to associate a post with the author? Is this where connections come into play or is that something else? Here is my attempt at trying to solve the problem but to avail.
mutation createAuthor {
createAuthor(input: {
id: 123
firstName: "Bob"
lastName: "Smith"
}) {
id
firstName
lastName
}
}
query listAuthors {
listAuthors {
items {
id
firstName
lastName
}
}
}
mutation createPost {
createPost(input: {
id: 12345
title: "Title"
votes: 345
author: {
lastName: {
contains: "Bob"
}
}
}) {
id
title
votes
author {
id
firstName
lastName
}
}
}
Any help on this would be appreciated. My Goal is to Query an author and return all of the post's associated with that author as well as create a Post Mutation that adds a post to an author.
graphql aws-appsync
asked Nov 21 at 23:41
Jghorton14
1441215
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am trying to understand graphql's query and mutation syntax. Given this example:
type Author {
id: Int!
firstName: String
lastName: String
posts: [Post]
}
type Post {
id: Int!
title: String
author: Author
votes: Int
}
type Query {
posts: [Post]
author(id: Int!): Author
}
What should the queries look like to associate a post with the author? Is this where connections come into play or is that something else? Here is my attempt at trying to solve the problem but to avail.
mutation createAuthor {
createAuthor(input: {
id: 123
firstName: "Bob"
lastName: "Smith"
}) {
id
firstName
lastName
}
}
query listAuthors {
listAuthors {
items {
id
firstName
lastName
}
}
}
mutation createPost {
createPost(input: {
id: 12345
title: "Title"
votes: 345
author: {
lastName: {
contains: "Bob"
}
}
}) {
id
title
votes
author {
id
firstName
lastName
}
}
}
Any help on this would be appreciated. My Goal is to Query an author and return all of the post's associated with that author as well as create a Post Mutation that adds a post to an author.
graphql aws-appsync
asked Nov 21 at 23:41
Jghorton14
1441215
I am trying to understand graphql's query and mutation syntax. Given this example:
type Author {
id: Int!
firstName: String
lastName: String
posts: [Post]
}
type Post {
id: Int!
title: String
author: Author
votes: Int
}
type Query {
posts: [Post]
author(id: Int!): Author
}
What should the queries look like to associate a post with the author? Is this where connections come into play or is that something else? Here is my attempt at trying to solve the problem but to avail.
mutation createAuthor {
createAuthor(input: {
id: 123
firstName: "Bob"
lastName: "Smith"
}) {
id
firstName
lastName
}
}
query listAuthors {
listAuthors {
items {
id
firstName
lastName
}
}
}
mutation createPost {
createPost(input: {
id: 12345
title: "Title"
votes: 345
author: {
lastName: {
contains: "Bob"
}
}
}) {
id
title
votes
author {
id
firstName
lastName
}
}
}
Any help on this would be appreciated. My Goal is to Query an author and return all of the post's associated with that author as well as create a Post Mutation that adds a post to an author.
graphql aws-appsync
graphql aws-appsync
asked Nov 21 at 23:41
Jghorton14
1441215
asked Nov 21 at 23:41
Jghorton14
1441215
edited Nov 22 at 0:05
asked Nov 21 at 23:41
Jghorton14
1441215
asked Nov 21 at 23:41
Jghorton14
1441215
asked Nov 21 at 23:41
Jghorton14
1441215
1441215
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
There are 2 questions in one, so I'll answer in the order there were asked.
1. return all of the posts associated with an author
Your schema looks correct. The query would look like:
query {
author(id: 1) {
id
posts {
id
title
}
}
}
2. create Post and attach to an author
In your example if you want to expose an interface to create a Post, then you would have to expose a mutation field in your schema
e.g:
type Mutation {
createPost(input: CreatePostInput): Post
}
if you want at the same time of creating a post, to also attach it to an author then you could add the authorId as part of the input, here we only want to attach the Post to an existing Author:
input CreatePostInput {
title: String
authorId: ID!
votes: Int
}
of course this is only the interface definition. We need to actually create the Post and link it to the Author inside the resolver.
The mutation query will look like:
mutation createPost {
createPost(input: {
title: "Title"
votes: 345
authorId: "authorId1"
}) {
id
title
votes
author {
id
firstName
lastName
}
}
}
Hope that helps!
answered Nov 22 at 1:55
Tinou
4,00441319
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
There are 2 questions in one, so I'll answer in the order there were asked.
1. return all of the posts associated with an author
Your schema looks correct. The query would look like:
query {
author(id: 1) {
id
posts {
id
title
}
}
}
2. create Post and attach to an author
In your example if you want to expose an interface to create a Post, then you would have to expose a mutation field in your schema
e.g:
type Mutation {
createPost(input: CreatePostInput): Post
}
if you want at the same time of creating a post, to also attach it to an author then you could add the authorId as part of the input, here we only want to attach the Post to an existing Author:
input CreatePostInput {
title: String
authorId: ID!
votes: Int
}
of course this is only the interface definition. We need to actually create the Post and link it to the Author inside the resolver.
The mutation query will look like:
mutation createPost {
createPost(input: {
title: "Title"
votes: 345
authorId: "authorId1"
}) {
id
title
votes
author {
id
firstName
lastName
}
}
}
Hope that helps!
answered Nov 22 at 1:55
Tinou
4,00441319
add a comment |
up vote
1
down vote
accepted
There are 2 questions in one, so I'll answer in the order there were asked.
1. return all of the posts associated with an author
Your schema looks correct. The query would look like:
query {
author(id: 1) {
id
posts {
id
title
}
}
}
2. create Post and attach to an author
In your example if you want to expose an interface to create a Post, then you would have to expose a mutation field in your schema
e.g:
type Mutation {
createPost(input: CreatePostInput): Post
}
if you want at the same time of creating a post, to also attach it to an author then you could add the authorId as part of the input, here we only want to attach the Post to an existing Author:
input CreatePostInput {
title: String
authorId: ID!
votes: Int
}
of course this is only the interface definition. We need to actually create the Post and link it to the Author inside the resolver.
The mutation query will look like:
mutation createPost {
createPost(input: {
title: "Title"
votes: 345
authorId: "authorId1"
}) {
id
title
votes
author {
id
firstName
lastName
}
}
}
Hope that helps!
answered Nov 22 at 1:55
Tinou
4,00441319
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
There are 2 questions in one, so I'll answer in the order there were asked.
1. return all of the posts associated with an author
Your schema looks correct. The query would look like:
query {
author(id: 1) {
id
posts {
id
title
}
}
}
2. create Post and attach to an author
In your example if you want to expose an interface to create a Post, then you would have to expose a mutation field in your schema
e.g:
type Mutation {
createPost(input: CreatePostInput): Post
}
if you want at the same time of creating a post, to also attach it to an author then you could add the authorId as part of the input, here we only want to attach the Post to an existing Author:
input CreatePostInput {
title: String
authorId: ID!
votes: Int
}
of course this is only the interface definition. We need to actually create the Post and link it to the Author inside the resolver.
The mutation query will look like:
mutation createPost {
createPost(input: {
title: "Title"
votes: 345
authorId: "authorId1"
}) {
id
title
votes
author {
id
firstName
lastName
}
}
}
Hope that helps!
answered Nov 22 at 1:55
Tinou
4,00441319
There are 2 questions in one, so I'll answer in the order there were asked.
1. return all of the posts associated with an author
Your schema looks correct. The query would look like:
query {
author(id: 1) {
id
posts {
id
title
}
}
}
2. create Post and attach to an author
In your example if you want to expose an interface to create a Post, then you would have to expose a mutation field in your schema
e.g:
type Mutation {
createPost(input: CreatePostInput): Post
}
if you want at the same time of creating a post, to also attach it to an author then you could add the authorId as part of the input, here we only want to attach the Post to an existing Author:
input CreatePostInput {
title: String
authorId: ID!
votes: Int
}
of course this is only the interface definition. We need to actually create the Post and link it to the Author inside the resolver.
The mutation query will look like:
mutation createPost {
createPost(input: {
title: "Title"
votes: 345
authorId: "authorId1"
}) {
id
title
votes
author {
id
firstName
lastName
}
}
}
Hope that helps!
answered Nov 22 at 1:55
Tinou
4,00441319
answered Nov 22 at 1:55
Tinou
4,00441319
answered Nov 22 at 1:55
Tinou
4,00441319
answered Nov 22 at 1:55
Tinou
4,00441319
4,00441319
add a comment |
add a comment |
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53421982%2fentity-association-syntax-issue-with-graphql-queries%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
