Using Jquery How to remove items from the model collection












0














I have model collection in jquery



thiz.tprListSearchesAndViews.searchParameters[0].parameters


This has 16 parameters list, as shown in the fist screenshot, I need to remove 2 items in the the parameters collection. Could you please help me, how I can do this. I am not getting any idea how I can approach on this using Jquery.



Image2



Image1










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  • Check this out: stackoverflow.com/questions/3596089/…
    – Marcelo Myara
    Nov 22 at 18:03










  • It's what you're [probably] looking for. It will show you how to remove elements from a given array using jQuery.
    – Marcelo Myara
    Nov 22 at 18:04










  • Thanks Myara, for your response, Basically mine is not simple array, its a complex model collection, so can you please suggest me how To remove items from thr
    – Kannan
    Nov 22 at 18:24
















0














I have model collection in jquery



thiz.tprListSearchesAndViews.searchParameters[0].parameters


This has 16 parameters list, as shown in the fist screenshot, I need to remove 2 items in the the parameters collection. Could you please help me, how I can do this. I am not getting any idea how I can approach on this using Jquery.



Image2



Image1










share|improve this question
























  • Check this out: stackoverflow.com/questions/3596089/…
    – Marcelo Myara
    Nov 22 at 18:03










  • It's what you're [probably] looking for. It will show you how to remove elements from a given array using jQuery.
    – Marcelo Myara
    Nov 22 at 18:04










  • Thanks Myara, for your response, Basically mine is not simple array, its a complex model collection, so can you please suggest me how To remove items from thr
    – Kannan
    Nov 22 at 18:24














0












0








0







I have model collection in jquery



thiz.tprListSearchesAndViews.searchParameters[0].parameters


This has 16 parameters list, as shown in the fist screenshot, I need to remove 2 items in the the parameters collection. Could you please help me, how I can do this. I am not getting any idea how I can approach on this using Jquery.



Image2



Image1










share|improve this question















I have model collection in jquery



thiz.tprListSearchesAndViews.searchParameters[0].parameters


This has 16 parameters list, as shown in the fist screenshot, I need to remove 2 items in the the parameters collection. Could you please help me, how I can do this. I am not getting any idea how I can approach on this using Jquery.



Image2



Image1







jquery






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 at 17:48









Foo

1




1










asked Nov 22 at 17:45









Kannan

12




12












  • Check this out: stackoverflow.com/questions/3596089/…
    – Marcelo Myara
    Nov 22 at 18:03










  • It's what you're [probably] looking for. It will show you how to remove elements from a given array using jQuery.
    – Marcelo Myara
    Nov 22 at 18:04










  • Thanks Myara, for your response, Basically mine is not simple array, its a complex model collection, so can you please suggest me how To remove items from thr
    – Kannan
    Nov 22 at 18:24


















  • Check this out: stackoverflow.com/questions/3596089/…
    – Marcelo Myara
    Nov 22 at 18:03










  • It's what you're [probably] looking for. It will show you how to remove elements from a given array using jQuery.
    – Marcelo Myara
    Nov 22 at 18:04










  • Thanks Myara, for your response, Basically mine is not simple array, its a complex model collection, so can you please suggest me how To remove items from thr
    – Kannan
    Nov 22 at 18:24
















Check this out: stackoverflow.com/questions/3596089/…
– Marcelo Myara
Nov 22 at 18:03




Check this out: stackoverflow.com/questions/3596089/…
– Marcelo Myara
Nov 22 at 18:03












It's what you're [probably] looking for. It will show you how to remove elements from a given array using jQuery.
– Marcelo Myara
Nov 22 at 18:04




It's what you're [probably] looking for. It will show you how to remove elements from a given array using jQuery.
– Marcelo Myara
Nov 22 at 18:04












Thanks Myara, for your response, Basically mine is not simple array, its a complex model collection, so can you please suggest me how To remove items from thr
– Kannan
Nov 22 at 18:24




Thanks Myara, for your response, Basically mine is not simple array, its a complex model collection, so can you please suggest me how To remove items from thr
– Kannan
Nov 22 at 18:24












1 Answer
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oldest

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0














removing I think this is what you're looking for:



let resultingArray = jQuery.grep(yourArray, function(obj, idx) {
//if you want to remove based on some of the element's properties
//use "obj". E.G.: return (obj['id'] === 3204);

//Otherwise, use idx for element position on the array.
return ([1, 7].indexOf(idx) === -1);
});


in your code:



thiz.tprListSearchesAndViews.searchParameters = jQuery.grep(thiz.tprListSearchesAndViews.searchParameters, function(obj, idx) {
//Filtering by position (removing items at 1 and 7)
return ([1, 7].indexOf(idx) === -1);
});





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    1 Answer
    1






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    0














    removing I think this is what you're looking for:



    let resultingArray = jQuery.grep(yourArray, function(obj, idx) {
    //if you want to remove based on some of the element's properties
    //use "obj". E.G.: return (obj['id'] === 3204);

    //Otherwise, use idx for element position on the array.
    return ([1, 7].indexOf(idx) === -1);
    });


    in your code:



    thiz.tprListSearchesAndViews.searchParameters = jQuery.grep(thiz.tprListSearchesAndViews.searchParameters, function(obj, idx) {
    //Filtering by position (removing items at 1 and 7)
    return ([1, 7].indexOf(idx) === -1);
    });





    share|improve this answer


























      0














      removing I think this is what you're looking for:



      let resultingArray = jQuery.grep(yourArray, function(obj, idx) {
      //if you want to remove based on some of the element's properties
      //use "obj". E.G.: return (obj['id'] === 3204);

      //Otherwise, use idx for element position on the array.
      return ([1, 7].indexOf(idx) === -1);
      });


      in your code:



      thiz.tprListSearchesAndViews.searchParameters = jQuery.grep(thiz.tprListSearchesAndViews.searchParameters, function(obj, idx) {
      //Filtering by position (removing items at 1 and 7)
      return ([1, 7].indexOf(idx) === -1);
      });





      share|improve this answer
























        0












        0








        0






        removing I think this is what you're looking for:



        let resultingArray = jQuery.grep(yourArray, function(obj, idx) {
        //if you want to remove based on some of the element's properties
        //use "obj". E.G.: return (obj['id'] === 3204);

        //Otherwise, use idx for element position on the array.
        return ([1, 7].indexOf(idx) === -1);
        });


        in your code:



        thiz.tprListSearchesAndViews.searchParameters = jQuery.grep(thiz.tprListSearchesAndViews.searchParameters, function(obj, idx) {
        //Filtering by position (removing items at 1 and 7)
        return ([1, 7].indexOf(idx) === -1);
        });





        share|improve this answer












        removing I think this is what you're looking for:



        let resultingArray = jQuery.grep(yourArray, function(obj, idx) {
        //if you want to remove based on some of the element's properties
        //use "obj". E.G.: return (obj['id'] === 3204);

        //Otherwise, use idx for element position on the array.
        return ([1, 7].indexOf(idx) === -1);
        });


        in your code:



        thiz.tprListSearchesAndViews.searchParameters = jQuery.grep(thiz.tprListSearchesAndViews.searchParameters, function(obj, idx) {
        //Filtering by position (removing items at 1 and 7)
        return ([1, 7].indexOf(idx) === -1);
        });






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 at 19:20









        Marcelo Myara

        1,3881829




        1,3881829






























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