Traversing path in C#
Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder and not \folder1anotherFolder?
While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder")); prints \folder1folder2anotherFolder as I would expect it.
It seems as if I can not escape the first two folders of my path. But every folder after the two.
Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));
Which explains the behaviour.
c# .net path
asked Nov 22 at 18:11
chbest
134
add a comment |
Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder and not \folder1anotherFolder?
While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder")); prints \folder1folder2anotherFolder as I would expect it.
It seems as if I can not escape the first two folders of my path. But every folder after the two.
Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));
Which explains the behaviour.
c# .net path
asked Nov 22 at 18:11
chbest
134
2
With@you do not need `\`. If you want to use an UNC path, don't call a server folder1.
– Henk Holterman
Nov 22 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 at 10:15
add a comment |
Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder and not \folder1anotherFolder?
While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder")); prints \folder1folder2anotherFolder as I would expect it.
It seems as if I can not escape the first two folders of my path. But every folder after the two.
Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));
Which explains the behaviour.
c# .net path
asked Nov 22 at 18:11
chbest
134
Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder and not \folder1anotherFolder?
While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder")); prints \folder1folder2anotherFolder as I would expect it.
It seems as if I can not escape the first two folders of my path. But every folder after the two.
Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));
Which explains the behaviour.
c# .net path
c# .net path
asked Nov 22 at 18:11
chbest
134
asked Nov 22 at 18:11
chbest
134
edited Nov 23 at 10:18
asked Nov 22 at 18:11
chbest
134
asked Nov 22 at 18:11
chbest
134
asked Nov 22 at 18:11
chbest
134
134
2
With@you do not need `\`. If you want to use an UNC path, don't call a server folder1.
– Henk Holterman
Nov 22 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 at 10:15
add a comment |
2
With@you do not need `\`. If you want to use an UNC path, don't call a server folder1.
– Henk Holterman
Nov 22 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 at 10:15
2
2
With
@ you do not need `\`. If you want to use an UNC path, don't call a server folder1.– Henk Holterman
Nov 22 at 18:21
With
@ you do not need `\`. If you want to use an UNC path, don't call a server folder1.– Henk Holterman
Nov 22 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 at 10:15
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 at 10:15
add a comment |
1 Answer
1
active
oldest
votes
When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.
answered Nov 22 at 22:13
iakobski
1564
add a comment |
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1 Answer
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votes
When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.
answered Nov 22 at 22:13
iakobski
1564
add a comment |
When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.
answered Nov 22 at 22:13
iakobski
1564
add a comment |
When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.
answered Nov 22 at 22:13
iakobski
1564
When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.
answered Nov 22 at 22:13
iakobski
1564
answered Nov 22 at 22:13
iakobski
1564
answered Nov 22 at 22:13
iakobski
1564
answered Nov 22 at 22:13
iakobski
1564
1564
add a comment |
add a comment |
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2
With
@you do not need `\`. If you want to use an UNC path, don't call a server folder1.– Henk Holterman
Nov 22 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 at 10:15