Counting number of similar strings in Postgresql












2














I have a table that contains a list of search_terms in Postgresql and the number of times they were searched:



Search Term Table



I'm trying to write a query that groups them together i.e. I want to see that electric scooter has been searched 27 times rather than 20 with 4 misspelt one way and 3 misspelt the other. I want to use the similarity function so that I can play with the limit.



I have been trying something along the lines of grouping by similarity but with no success:



SELECT 
search_term,
SUM(count)

FROM
t2

GROUP BY (SELECT set_limit(0.8);

SELECT similarity(n1.search_term, n2.search_term) AS sim, n1.search_term, n2.search_term
FROM t2 n1
JOIN t2 n2 ON n1.search_term <> n2.search_term
AND n1.search_term % n2.search_term
ORDER BY sim DESC)


Any help greatly appreciated!










share|improve this question



























    2














    I have a table that contains a list of search_terms in Postgresql and the number of times they were searched:



    Search Term Table



    I'm trying to write a query that groups them together i.e. I want to see that electric scooter has been searched 27 times rather than 20 with 4 misspelt one way and 3 misspelt the other. I want to use the similarity function so that I can play with the limit.



    I have been trying something along the lines of grouping by similarity but with no success:



    SELECT 
    search_term,
    SUM(count)

    FROM
    t2

    GROUP BY (SELECT set_limit(0.8);

    SELECT similarity(n1.search_term, n2.search_term) AS sim, n1.search_term, n2.search_term
    FROM t2 n1
    JOIN t2 n2 ON n1.search_term <> n2.search_term
    AND n1.search_term % n2.search_term
    ORDER BY sim DESC)


    Any help greatly appreciated!










    share|improve this question

























      2












      2








      2







      I have a table that contains a list of search_terms in Postgresql and the number of times they were searched:



      Search Term Table



      I'm trying to write a query that groups them together i.e. I want to see that electric scooter has been searched 27 times rather than 20 with 4 misspelt one way and 3 misspelt the other. I want to use the similarity function so that I can play with the limit.



      I have been trying something along the lines of grouping by similarity but with no success:



      SELECT 
      search_term,
      SUM(count)

      FROM
      t2

      GROUP BY (SELECT set_limit(0.8);

      SELECT similarity(n1.search_term, n2.search_term) AS sim, n1.search_term, n2.search_term
      FROM t2 n1
      JOIN t2 n2 ON n1.search_term <> n2.search_term
      AND n1.search_term % n2.search_term
      ORDER BY sim DESC)


      Any help greatly appreciated!










      share|improve this question













      I have a table that contains a list of search_terms in Postgresql and the number of times they were searched:



      Search Term Table



      I'm trying to write a query that groups them together i.e. I want to see that electric scooter has been searched 27 times rather than 20 with 4 misspelt one way and 3 misspelt the other. I want to use the similarity function so that I can play with the limit.



      I have been trying something along the lines of grouping by similarity but with no success:



      SELECT 
      search_term,
      SUM(count)

      FROM
      t2

      GROUP BY (SELECT set_limit(0.8);

      SELECT similarity(n1.search_term, n2.search_term) AS sim, n1.search_term, n2.search_term
      FROM t2 n1
      JOIN t2 n2 ON n1.search_term <> n2.search_term
      AND n1.search_term % n2.search_term
      ORDER BY sim DESC)


      Any help greatly appreciated!







      postgresql grouping similarity






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 22 at 18:09









      user10670868

      111




      111
























          1 Answer
          1






          active

          oldest

          votes


















          0














          The value 0.8 is not enough. because similarity in your example is 0.6 and more



          Try this query



          SELECT sim, ss, sum(countt)
          FROM (
          SELECT sim, '|'||string_agg(s1, '|')||'|' ss
          FROM (
          SELECT similarity(n1.search_term, n2.search_term) AS sim,
          n1.search_term s1, n2.search_term s2
          FROM t1 n1
          JOIN t1 n2 ON n1.search_term <> n2.search_term
          AND n1.search_term % n2.search_term
          ) t2
          WHERE sim > 0.6
          GROUP BY sim
          ) t3
          LEFT JOIN t1 n3 ON ss like '%|'||n3.search_term||'|%'
          GROUP BY ss, sim
          ORDER BY sim DESC


          Here my sample - http://sqlfiddle.com/#!17/1d705/35






          share|improve this answer























          • Hey, thanks for the help but that didn't really work as it you try to add more terms to your schema, they get lost. For example, try: ('electric scooer',3), ('elecric scooter',4), ('electric scooter',20), ('road bicycle',5), ('camera',15), ('5D camera',12), ('segway longboard',15), ('boosted longboard',15);
            – user10670868
            Nov 23 at 15:48












          • @user10670868 you can check sqlfiddle.com/#!17/33cc1/5 link. There is data. But maybe, similarity value is low
            – Saidolim
            Nov 26 at 0:37











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          The value 0.8 is not enough. because similarity in your example is 0.6 and more



          Try this query



          SELECT sim, ss, sum(countt)
          FROM (
          SELECT sim, '|'||string_agg(s1, '|')||'|' ss
          FROM (
          SELECT similarity(n1.search_term, n2.search_term) AS sim,
          n1.search_term s1, n2.search_term s2
          FROM t1 n1
          JOIN t1 n2 ON n1.search_term <> n2.search_term
          AND n1.search_term % n2.search_term
          ) t2
          WHERE sim > 0.6
          GROUP BY sim
          ) t3
          LEFT JOIN t1 n3 ON ss like '%|'||n3.search_term||'|%'
          GROUP BY ss, sim
          ORDER BY sim DESC


          Here my sample - http://sqlfiddle.com/#!17/1d705/35






          share|improve this answer























          • Hey, thanks for the help but that didn't really work as it you try to add more terms to your schema, they get lost. For example, try: ('electric scooer',3), ('elecric scooter',4), ('electric scooter',20), ('road bicycle',5), ('camera',15), ('5D camera',12), ('segway longboard',15), ('boosted longboard',15);
            – user10670868
            Nov 23 at 15:48












          • @user10670868 you can check sqlfiddle.com/#!17/33cc1/5 link. There is data. But maybe, similarity value is low
            – Saidolim
            Nov 26 at 0:37
















          0














          The value 0.8 is not enough. because similarity in your example is 0.6 and more



          Try this query



          SELECT sim, ss, sum(countt)
          FROM (
          SELECT sim, '|'||string_agg(s1, '|')||'|' ss
          FROM (
          SELECT similarity(n1.search_term, n2.search_term) AS sim,
          n1.search_term s1, n2.search_term s2
          FROM t1 n1
          JOIN t1 n2 ON n1.search_term <> n2.search_term
          AND n1.search_term % n2.search_term
          ) t2
          WHERE sim > 0.6
          GROUP BY sim
          ) t3
          LEFT JOIN t1 n3 ON ss like '%|'||n3.search_term||'|%'
          GROUP BY ss, sim
          ORDER BY sim DESC


          Here my sample - http://sqlfiddle.com/#!17/1d705/35






          share|improve this answer























          • Hey, thanks for the help but that didn't really work as it you try to add more terms to your schema, they get lost. For example, try: ('electric scooer',3), ('elecric scooter',4), ('electric scooter',20), ('road bicycle',5), ('camera',15), ('5D camera',12), ('segway longboard',15), ('boosted longboard',15);
            – user10670868
            Nov 23 at 15:48












          • @user10670868 you can check sqlfiddle.com/#!17/33cc1/5 link. There is data. But maybe, similarity value is low
            – Saidolim
            Nov 26 at 0:37














          0












          0








          0






          The value 0.8 is not enough. because similarity in your example is 0.6 and more



          Try this query



          SELECT sim, ss, sum(countt)
          FROM (
          SELECT sim, '|'||string_agg(s1, '|')||'|' ss
          FROM (
          SELECT similarity(n1.search_term, n2.search_term) AS sim,
          n1.search_term s1, n2.search_term s2
          FROM t1 n1
          JOIN t1 n2 ON n1.search_term <> n2.search_term
          AND n1.search_term % n2.search_term
          ) t2
          WHERE sim > 0.6
          GROUP BY sim
          ) t3
          LEFT JOIN t1 n3 ON ss like '%|'||n3.search_term||'|%'
          GROUP BY ss, sim
          ORDER BY sim DESC


          Here my sample - http://sqlfiddle.com/#!17/1d705/35






          share|improve this answer














          The value 0.8 is not enough. because similarity in your example is 0.6 and more



          Try this query



          SELECT sim, ss, sum(countt)
          FROM (
          SELECT sim, '|'||string_agg(s1, '|')||'|' ss
          FROM (
          SELECT similarity(n1.search_term, n2.search_term) AS sim,
          n1.search_term s1, n2.search_term s2
          FROM t1 n1
          JOIN t1 n2 ON n1.search_term <> n2.search_term
          AND n1.search_term % n2.search_term
          ) t2
          WHERE sim > 0.6
          GROUP BY sim
          ) t3
          LEFT JOIN t1 n3 ON ss like '%|'||n3.search_term||'|%'
          GROUP BY ss, sim
          ORDER BY sim DESC


          Here my sample - http://sqlfiddle.com/#!17/1d705/35







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 22 at 19:59

























          answered Nov 22 at 19:53









          Saidolim

          339717




          339717












          • Hey, thanks for the help but that didn't really work as it you try to add more terms to your schema, they get lost. For example, try: ('electric scooer',3), ('elecric scooter',4), ('electric scooter',20), ('road bicycle',5), ('camera',15), ('5D camera',12), ('segway longboard',15), ('boosted longboard',15);
            – user10670868
            Nov 23 at 15:48












          • @user10670868 you can check sqlfiddle.com/#!17/33cc1/5 link. There is data. But maybe, similarity value is low
            – Saidolim
            Nov 26 at 0:37


















          • Hey, thanks for the help but that didn't really work as it you try to add more terms to your schema, they get lost. For example, try: ('electric scooer',3), ('elecric scooter',4), ('electric scooter',20), ('road bicycle',5), ('camera',15), ('5D camera',12), ('segway longboard',15), ('boosted longboard',15);
            – user10670868
            Nov 23 at 15:48












          • @user10670868 you can check sqlfiddle.com/#!17/33cc1/5 link. There is data. But maybe, similarity value is low
            – Saidolim
            Nov 26 at 0:37
















          Hey, thanks for the help but that didn't really work as it you try to add more terms to your schema, they get lost. For example, try: ('electric scooer',3), ('elecric scooter',4), ('electric scooter',20), ('road bicycle',5), ('camera',15), ('5D camera',12), ('segway longboard',15), ('boosted longboard',15);
          – user10670868
          Nov 23 at 15:48






          Hey, thanks for the help but that didn't really work as it you try to add more terms to your schema, they get lost. For example, try: ('electric scooer',3), ('elecric scooter',4), ('electric scooter',20), ('road bicycle',5), ('camera',15), ('5D camera',12), ('segway longboard',15), ('boosted longboard',15);
          – user10670868
          Nov 23 at 15:48














          @user10670868 you can check sqlfiddle.com/#!17/33cc1/5 link. There is data. But maybe, similarity value is low
          – Saidolim
          Nov 26 at 0:37




          @user10670868 you can check sqlfiddle.com/#!17/33cc1/5 link. There is data. But maybe, similarity value is low
          – Saidolim
          Nov 26 at 0:37


















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