Compute Normalized Cross-Correlation in Python
I have been struggling the last days trying to compute the degrees of freedom of two pair of vectors (x and y) following reference of Chelton (1983) which is:
degrees of freedom according to Chelton(1983)
and I can't find a proper way to calculate the normalized cross correlation function using np.correlate,
I always get an output that it isn't in between -1, 1.
Is there any easy way to get the cross correlation function normalized in order to compute the degrees of freedom of two vectors?
python numpy correlation cross-correlation
add a comment |
I have been struggling the last days trying to compute the degrees of freedom of two pair of vectors (x and y) following reference of Chelton (1983) which is:
degrees of freedom according to Chelton(1983)
and I can't find a proper way to calculate the normalized cross correlation function using np.correlate,
I always get an output that it isn't in between -1, 1.
Is there any easy way to get the cross correlation function normalized in order to compute the degrees of freedom of two vectors?
python numpy correlation cross-correlation
add a comment |
I have been struggling the last days trying to compute the degrees of freedom of two pair of vectors (x and y) following reference of Chelton (1983) which is:
degrees of freedom according to Chelton(1983)
and I can't find a proper way to calculate the normalized cross correlation function using np.correlate,
I always get an output that it isn't in between -1, 1.
Is there any easy way to get the cross correlation function normalized in order to compute the degrees of freedom of two vectors?
python numpy correlation cross-correlation
I have been struggling the last days trying to compute the degrees of freedom of two pair of vectors (x and y) following reference of Chelton (1983) which is:
degrees of freedom according to Chelton(1983)
and I can't find a proper way to calculate the normalized cross correlation function using np.correlate,
I always get an output that it isn't in between -1, 1.
Is there any easy way to get the cross correlation function normalized in order to compute the degrees of freedom of two vectors?
python numpy correlation cross-correlation
python numpy correlation cross-correlation
edited Nov 22 at 22:31
asked Nov 22 at 18:04
Daniela Belén Risaro
184
184
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Nice Question. There is no direct way but you can "normalize" the input vectors before using np.correlate
like this and reasonable values will be returned within a range of [-1,1]:
If a and b are the vectors:
a = (a - np.mean(a)) / (np.std(a) * len(a))
b = (b - np.mean(b)) / (np.std(b))
c = np.correlate(a, b, 'full')
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53436231%2fcompute-normalized-cross-correlation-in-python%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Nice Question. There is no direct way but you can "normalize" the input vectors before using np.correlate
like this and reasonable values will be returned within a range of [-1,1]:
If a and b are the vectors:
a = (a - np.mean(a)) / (np.std(a) * len(a))
b = (b - np.mean(b)) / (np.std(b))
c = np.correlate(a, b, 'full')
add a comment |
Nice Question. There is no direct way but you can "normalize" the input vectors before using np.correlate
like this and reasonable values will be returned within a range of [-1,1]:
If a and b are the vectors:
a = (a - np.mean(a)) / (np.std(a) * len(a))
b = (b - np.mean(b)) / (np.std(b))
c = np.correlate(a, b, 'full')
add a comment |
Nice Question. There is no direct way but you can "normalize" the input vectors before using np.correlate
like this and reasonable values will be returned within a range of [-1,1]:
If a and b are the vectors:
a = (a - np.mean(a)) / (np.std(a) * len(a))
b = (b - np.mean(b)) / (np.std(b))
c = np.correlate(a, b, 'full')
Nice Question. There is no direct way but you can "normalize" the input vectors before using np.correlate
like this and reasonable values will be returned within a range of [-1,1]:
If a and b are the vectors:
a = (a - np.mean(a)) / (np.std(a) * len(a))
b = (b - np.mean(b)) / (np.std(b))
c = np.correlate(a, b, 'full')
answered Nov 22 at 18:12
seralouk
5,62522338
5,62522338
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53436231%2fcompute-normalized-cross-correlation-in-python%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown