Python: Error! Setting an array element with a sequence












0














import sympy as sp
import numpy as np
import matplotlib.pyplot as plt
I = np.array([[0,1],[-1,0]])
n = 1


def euler_1(initP, change):
slope = I * initP
return initP + (change * slope)

def euler_2(N, u):
xRange = np.arange(0, 10*np.pi, 2*np.pi/N)
eulerApprox = np.zeros(len(xRange)+1)
change = xRange[1] - xRange[0]
eulerApprox[0] = u
for x in xRange:
eulerApprox[n] = euler_1(eulerApprox[n-1], change)
return eulerApprox


When I put this into my jupyter notebook with:
N1 = 700
plot((ode.euler_2(N1, np.array([1, 0]))), N1, "Euler's Method")
it gives me the error that I cannot set an array element with a sequence?










share|improve this question






















  • eulerApprox is a 1d array, so eulerApprox[n] is one slot that holds a float. What does the euler_1(...) call produce? You don't tell us which line produces the error, but that appears to be the most likely one.
    – hpaulj
    Nov 22 at 19:06


















0














import sympy as sp
import numpy as np
import matplotlib.pyplot as plt
I = np.array([[0,1],[-1,0]])
n = 1


def euler_1(initP, change):
slope = I * initP
return initP + (change * slope)

def euler_2(N, u):
xRange = np.arange(0, 10*np.pi, 2*np.pi/N)
eulerApprox = np.zeros(len(xRange)+1)
change = xRange[1] - xRange[0]
eulerApprox[0] = u
for x in xRange:
eulerApprox[n] = euler_1(eulerApprox[n-1], change)
return eulerApprox


When I put this into my jupyter notebook with:
N1 = 700
plot((ode.euler_2(N1, np.array([1, 0]))), N1, "Euler's Method")
it gives me the error that I cannot set an array element with a sequence?










share|improve this question






















  • eulerApprox is a 1d array, so eulerApprox[n] is one slot that holds a float. What does the euler_1(...) call produce? You don't tell us which line produces the error, but that appears to be the most likely one.
    – hpaulj
    Nov 22 at 19:06
















0












0








0







import sympy as sp
import numpy as np
import matplotlib.pyplot as plt
I = np.array([[0,1],[-1,0]])
n = 1


def euler_1(initP, change):
slope = I * initP
return initP + (change * slope)

def euler_2(N, u):
xRange = np.arange(0, 10*np.pi, 2*np.pi/N)
eulerApprox = np.zeros(len(xRange)+1)
change = xRange[1] - xRange[0]
eulerApprox[0] = u
for x in xRange:
eulerApprox[n] = euler_1(eulerApprox[n-1], change)
return eulerApprox


When I put this into my jupyter notebook with:
N1 = 700
plot((ode.euler_2(N1, np.array([1, 0]))), N1, "Euler's Method")
it gives me the error that I cannot set an array element with a sequence?










share|improve this question













import sympy as sp
import numpy as np
import matplotlib.pyplot as plt
I = np.array([[0,1],[-1,0]])
n = 1


def euler_1(initP, change):
slope = I * initP
return initP + (change * slope)

def euler_2(N, u):
xRange = np.arange(0, 10*np.pi, 2*np.pi/N)
eulerApprox = np.zeros(len(xRange)+1)
change = xRange[1] - xRange[0]
eulerApprox[0] = u
for x in xRange:
eulerApprox[n] = euler_1(eulerApprox[n-1], change)
return eulerApprox


When I put this into my jupyter notebook with:
N1 = 700
plot((ode.euler_2(N1, np.array([1, 0]))), N1, "Euler's Method")
it gives me the error that I cannot set an array element with a sequence?







numpy matplotlib sympy scientific-computing






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 22 at 18:14









user10631376

1




1












  • eulerApprox is a 1d array, so eulerApprox[n] is one slot that holds a float. What does the euler_1(...) call produce? You don't tell us which line produces the error, but that appears to be the most likely one.
    – hpaulj
    Nov 22 at 19:06




















  • eulerApprox is a 1d array, so eulerApprox[n] is one slot that holds a float. What does the euler_1(...) call produce? You don't tell us which line produces the error, but that appears to be the most likely one.
    – hpaulj
    Nov 22 at 19:06


















eulerApprox is a 1d array, so eulerApprox[n] is one slot that holds a float. What does the euler_1(...) call produce? You don't tell us which line produces the error, but that appears to be the most likely one.
– hpaulj
Nov 22 at 19:06






eulerApprox is a 1d array, so eulerApprox[n] is one slot that holds a float. What does the euler_1(...) call produce? You don't tell us which line produces the error, but that appears to be the most likely one.
– hpaulj
Nov 22 at 19:06



















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