Graphing Data over time with a line graph
So I need to graph on what day there where followers using a line graph. But nothing shows up heres my code
def follower_timeplot(self,g,node):
dic={node: list(g.predecessors(node))}
lst=
D={}
for item in dic[node]:
lst.append(g[item][node]['Timecreated'])
D = {x:lst.count(x) for x in lst}
df= pd.Series(D, name='DateValue')
df.index.name = 'Date'
df.columns=['cnt']
df.reset_index()
#print(df)
plt.plot(x='Date', y='cnt')
this is a method that takes in a graph from networkx and looks a certian node and any indegree "Timecreated" is put in a dateframe then graphed.
So in short i need a line graph of the people following exaple date in the data frame looks like
Date
2011-01-18 1
2016-09-30 2
2015-10-07 1
2018-05-08 1
2018-11-18 1
2013-02-05 2
2018-06-04 2
2018-11-17 1
2018-11-15 2
2018-08-22 2
2012-12-14 1
2018-03-13 1
2013-05-02 1
2017-11-19 1
2017-06-11 2
2017-12-17 2
python
add a comment |
So I need to graph on what day there where followers using a line graph. But nothing shows up heres my code
def follower_timeplot(self,g,node):
dic={node: list(g.predecessors(node))}
lst=
D={}
for item in dic[node]:
lst.append(g[item][node]['Timecreated'])
D = {x:lst.count(x) for x in lst}
df= pd.Series(D, name='DateValue')
df.index.name = 'Date'
df.columns=['cnt']
df.reset_index()
#print(df)
plt.plot(x='Date', y='cnt')
this is a method that takes in a graph from networkx and looks a certian node and any indegree "Timecreated" is put in a dateframe then graphed.
So in short i need a line graph of the people following exaple date in the data frame looks like
Date
2011-01-18 1
2016-09-30 2
2015-10-07 1
2018-05-08 1
2018-11-18 1
2013-02-05 2
2018-06-04 2
2018-11-17 1
2018-11-15 2
2018-08-22 2
2012-12-14 1
2018-03-13 1
2013-05-02 1
2017-11-19 1
2017-06-11 2
2017-12-17 2
python
Is this all of your code? You are missingplt.show()
– pxe
Nov 22 at 17:37
add a comment |
So I need to graph on what day there where followers using a line graph. But nothing shows up heres my code
def follower_timeplot(self,g,node):
dic={node: list(g.predecessors(node))}
lst=
D={}
for item in dic[node]:
lst.append(g[item][node]['Timecreated'])
D = {x:lst.count(x) for x in lst}
df= pd.Series(D, name='DateValue')
df.index.name = 'Date'
df.columns=['cnt']
df.reset_index()
#print(df)
plt.plot(x='Date', y='cnt')
this is a method that takes in a graph from networkx and looks a certian node and any indegree "Timecreated" is put in a dateframe then graphed.
So in short i need a line graph of the people following exaple date in the data frame looks like
Date
2011-01-18 1
2016-09-30 2
2015-10-07 1
2018-05-08 1
2018-11-18 1
2013-02-05 2
2018-06-04 2
2018-11-17 1
2018-11-15 2
2018-08-22 2
2012-12-14 1
2018-03-13 1
2013-05-02 1
2017-11-19 1
2017-06-11 2
2017-12-17 2
python
So I need to graph on what day there where followers using a line graph. But nothing shows up heres my code
def follower_timeplot(self,g,node):
dic={node: list(g.predecessors(node))}
lst=
D={}
for item in dic[node]:
lst.append(g[item][node]['Timecreated'])
D = {x:lst.count(x) for x in lst}
df= pd.Series(D, name='DateValue')
df.index.name = 'Date'
df.columns=['cnt']
df.reset_index()
#print(df)
plt.plot(x='Date', y='cnt')
this is a method that takes in a graph from networkx and looks a certian node and any indegree "Timecreated" is put in a dateframe then graphed.
So in short i need a line graph of the people following exaple date in the data frame looks like
Date
2011-01-18 1
2016-09-30 2
2015-10-07 1
2018-05-08 1
2018-11-18 1
2013-02-05 2
2018-06-04 2
2018-11-17 1
2018-11-15 2
2018-08-22 2
2012-12-14 1
2018-03-13 1
2013-05-02 1
2017-11-19 1
2017-06-11 2
2017-12-17 2
python
python
asked Nov 22 at 17:29
Bruce Craig
1
1
Is this all of your code? You are missingplt.show()
– pxe
Nov 22 at 17:37
add a comment |
Is this all of your code? You are missingplt.show()
– pxe
Nov 22 at 17:37
Is this all of your code? You are missing
plt.show()
– pxe
Nov 22 at 17:37
Is this all of your code? You are missing
plt.show()
– pxe
Nov 22 at 17:37
add a comment |
1 Answer
1
active
oldest
votes
Try to use pandas
plot function instead. Also remember to add plt.show()
to your code.
df.plot()
plt.show()
how would i space the graph out more its only by year
– Bruce Craig
Nov 23 at 20:34
I'm not sure I understand your question. If my answer does help you please consider to accept the question (green tick) and/or upvote. I think you should ask another question for what you mention in this comment and show the graph that results from your code and explain in detail what you expect.
– Cedric Zoppolo
Nov 23 at 21:11
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try to use pandas
plot function instead. Also remember to add plt.show()
to your code.
df.plot()
plt.show()
how would i space the graph out more its only by year
– Bruce Craig
Nov 23 at 20:34
I'm not sure I understand your question. If my answer does help you please consider to accept the question (green tick) and/or upvote. I think you should ask another question for what you mention in this comment and show the graph that results from your code and explain in detail what you expect.
– Cedric Zoppolo
Nov 23 at 21:11
add a comment |
Try to use pandas
plot function instead. Also remember to add plt.show()
to your code.
df.plot()
plt.show()
how would i space the graph out more its only by year
– Bruce Craig
Nov 23 at 20:34
I'm not sure I understand your question. If my answer does help you please consider to accept the question (green tick) and/or upvote. I think you should ask another question for what you mention in this comment and show the graph that results from your code and explain in detail what you expect.
– Cedric Zoppolo
Nov 23 at 21:11
add a comment |
Try to use pandas
plot function instead. Also remember to add plt.show()
to your code.
df.plot()
plt.show()
Try to use pandas
plot function instead. Also remember to add plt.show()
to your code.
df.plot()
plt.show()
answered Nov 22 at 18:21
Cedric Zoppolo
1,24711327
1,24711327
how would i space the graph out more its only by year
– Bruce Craig
Nov 23 at 20:34
I'm not sure I understand your question. If my answer does help you please consider to accept the question (green tick) and/or upvote. I think you should ask another question for what you mention in this comment and show the graph that results from your code and explain in detail what you expect.
– Cedric Zoppolo
Nov 23 at 21:11
add a comment |
how would i space the graph out more its only by year
– Bruce Craig
Nov 23 at 20:34
I'm not sure I understand your question. If my answer does help you please consider to accept the question (green tick) and/or upvote. I think you should ask another question for what you mention in this comment and show the graph that results from your code and explain in detail what you expect.
– Cedric Zoppolo
Nov 23 at 21:11
how would i space the graph out more its only by year
– Bruce Craig
Nov 23 at 20:34
how would i space the graph out more its only by year
– Bruce Craig
Nov 23 at 20:34
I'm not sure I understand your question. If my answer does help you please consider to accept the question (green tick) and/or upvote. I think you should ask another question for what you mention in this comment and show the graph that results from your code and explain in detail what you expect.
– Cedric Zoppolo
Nov 23 at 21:11
I'm not sure I understand your question. If my answer does help you please consider to accept the question (green tick) and/or upvote. I think you should ask another question for what you mention in this comment and show the graph that results from your code and explain in detail what you expect.
– Cedric Zoppolo
Nov 23 at 21:11
add a comment |
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Is this all of your code? You are missing
plt.show()
– pxe
Nov 22 at 17:37