MongoDB Embedded Reference Duplicate Error
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I am new to MongoDB, and coming from Sql database systems. I am confused about embedded reference's of mongodb.
I use Java Spring Framework and MongoRepository interface of Spring. I have a class (User) that annotated with @Document and has a String field (id) of annotated @Indexed(unique = true). I have second class (Device) that has an embedded User object in it. It's like many-to-one relation (many devices may belong one user), however when I try to save second device with same User, application throws en error E11000 duplicate key error collection: test.device index: user.id dup key: { : "5a8549fbeed7ae612d6a10d1" }.
I tried making User object in Devices reference (with @DBRef annotation), and @Indexed(unique = false), I could manage to save two devices. However, I dont want to use reference document, embedding document will be better.
I just wonder, is my approach wrong? Or my configuration was wrong?
java spring mongodb
edited Feb 15 at 9:10
pvpkiran
11.4k42141
asked Feb 15 at 9:08
Black Glix
151317
add a comment |
up vote
0
down vote
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I am new to MongoDB, and coming from Sql database systems. I am confused about embedded reference's of mongodb.
I use Java Spring Framework and MongoRepository interface of Spring. I have a class (User) that annotated with @Document and has a String field (id) of annotated @Indexed(unique = true). I have second class (Device) that has an embedded User object in it. It's like many-to-one relation (many devices may belong one user), however when I try to save second device with same User, application throws en error E11000 duplicate key error collection: test.device index: user.id dup key: { : "5a8549fbeed7ae612d6a10d1" }.
I tried making User object in Devices reference (with @DBRef annotation), and @Indexed(unique = false), I could manage to save two devices. However, I dont want to use reference document, embedding document will be better.
I just wonder, is my approach wrong? Or my configuration was wrong?
java spring mongodb
edited Feb 15 at 9:10
pvpkiran
11.4k42141
asked Feb 15 at 9:08
Black Glix
151317
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am new to MongoDB, and coming from Sql database systems. I am confused about embedded reference's of mongodb.
I use Java Spring Framework and MongoRepository interface of Spring. I have a class (User) that annotated with @Document and has a String field (id) of annotated @Indexed(unique = true). I have second class (Device) that has an embedded User object in it. It's like many-to-one relation (many devices may belong one user), however when I try to save second device with same User, application throws en error E11000 duplicate key error collection: test.device index: user.id dup key: { : "5a8549fbeed7ae612d6a10d1" }.
I tried making User object in Devices reference (with @DBRef annotation), and @Indexed(unique = false), I could manage to save two devices. However, I dont want to use reference document, embedding document will be better.
I just wonder, is my approach wrong? Or my configuration was wrong?
java spring mongodb
edited Feb 15 at 9:10
pvpkiran
11.4k42141
asked Feb 15 at 9:08
Black Glix
151317
I am new to MongoDB, and coming from Sql database systems. I am confused about embedded reference's of mongodb.
I use Java Spring Framework and MongoRepository interface of Spring. I have a class (User) that annotated with @Document and has a String field (id) of annotated @Indexed(unique = true). I have second class (Device) that has an embedded User object in it. It's like many-to-one relation (many devices may belong one user), however when I try to save second device with same User, application throws en error E11000 duplicate key error collection: test.device index: user.id dup key: { : "5a8549fbeed7ae612d6a10d1" }.
I tried making User object in Devices reference (with @DBRef annotation), and @Indexed(unique = false), I could manage to save two devices. However, I dont want to use reference document, embedding document will be better.
I just wonder, is my approach wrong? Or my configuration was wrong?
java spring mongodb
java spring mongodb
edited Feb 15 at 9:10
pvpkiran
11.4k42141
asked Feb 15 at 9:08
Black Glix
151317
edited Feb 15 at 9:10
pvpkiran
11.4k42141
asked Feb 15 at 9:08
Black Glix
151317
edited Feb 15 at 9:10
pvpkiran
11.4k42141
edited Feb 15 at 9:10
pvpkiran
11.4k42141
edited Feb 15 at 9:10
pvpkiran
11.4k42141
11.4k42141
asked Feb 15 at 9:08
Black Glix
151317
asked Feb 15 at 9:08
Black Glix
151317
asked Feb 15 at 9:08
Black Glix
151317
151317
add a comment |
add a comment |
1 Answer
1
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0
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You can use @Transient annotation over Device.user field if the user information is not relevant. If you need the User information in Device document try to use the User.id field (sql approach).
edited Nov 22 at 15:30
L.Butz
1,3241137
answered Nov 22 at 14:53
David Cadena
1
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You can use @Transient annotation over Device.user field if the user information is not relevant. If you need the User information in Device document try to use the User.id field (sql approach).
edited Nov 22 at 15:30
L.Butz
1,3241137
answered Nov 22 at 14:53
David Cadena
1
add a comment |
up vote
0
down vote
You can use @Transient annotation over Device.user field if the user information is not relevant. If you need the User information in Device document try to use the User.id field (sql approach).
edited Nov 22 at 15:30
L.Butz
1,3241137
answered Nov 22 at 14:53
David Cadena
1
add a comment |
up vote
0
down vote
up vote
0
down vote
You can use @Transient annotation over Device.user field if the user information is not relevant. If you need the User information in Device document try to use the User.id field (sql approach).
edited Nov 22 at 15:30
L.Butz
1,3241137
answered Nov 22 at 14:53
David Cadena
1
You can use @Transient annotation over Device.user field if the user information is not relevant. If you need the User information in Device document try to use the User.id field (sql approach).
edited Nov 22 at 15:30
L.Butz
1,3241137
answered Nov 22 at 14:53
David Cadena
1
edited Nov 22 at 15:30
L.Butz
1,3241137
edited Nov 22 at 15:30
L.Butz
1,3241137
edited Nov 22 at 15:30
L.Butz
1,3241137
1,3241137
answered Nov 22 at 14:53
David Cadena
1
answered Nov 22 at 14:53
David Cadena
1
answered Nov 22 at 14:53
David Cadena
1
1
add a comment |
add a comment |
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