Generating xml dynamically from a database using PHP











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I cannot figure out the error which says



'This page contains the following errors:
error on line 1 at column 2: StartTag: invalid element name
Below is a rendering of the page up to the first error.'



init.php



<?php
$servername = "localhost";
$username = "root";
$password = null;
$databaseName = "test";

$db = mysqli_connect($servername, $username,
$password, $databaseName)

?>


viewWishList.php



<?php                                            
header ("Content-Type:text/xml");
include ("config/init.php");
$query = "SELECT * FROM members";
$result = mysqli_query($connection, $query) or
die ("Error in query: $query. ".mysql_error());

$_xml = '<?xml version="1.0"?>'
$_xml .="<wishList>";

while($row = mysqli_fetch_array($result)) {

$_xml .="<wishlist>";

$_xml .="<wishlistID>".$row['wishlistID']."
</wishlistID>";
$_xml .="<bookName>".$row['bookName']."
</bookName>";
$_xml .="<bookType>".$row['bookType']."
</bookType>";

$_xml .="</wishlist>";

}

$_xml .="</wishList>";

$xmlobj=new SimpleXMLElement($_xml);
print $xmlobj->asXML();
$xmlobj->asXML(wishlist.xml);

?>









share|improve this question


















  • 1




    dont see ;(semicolon) $_xml = '<?xml version="1.0"?>'
    – suresh bambhaniya
    Nov 22 at 15:14










  • If you comment out header ("Content-Type:text/xml"); what is displayed?
    – Nigel Ren
    Nov 22 at 15:15










  • Notice: Undefined variable: connection in /opt/lampp/htdocs/a/viewWishList.php on line 27 Warning: mysqli_query() expects parameter 1 to be mysqli, null given in /opt/lampp/htdocs/a/viewWishList.php on line 27 Fatal error: Uncaught Error: Call to undefined function mysql_error() in /opt/lampp/htdocs/a/viewWishList.php:27 Stack trace: #0 {main} thrown in /opt/lampp/htdocs/a/viewWishList.php on line 27
    – Abhooshan Bhattarai
    Nov 22 at 16:09












  • Change the line to $result = mysqli_query($db, $query) or die ("Error in query: $query. ".mysqli_connect_error());
    – Nigel Ren
    Nov 22 at 19:02










  • @NigelRen Still facing the same error.
    – Abhooshan Bhattarai
    Nov 23 at 5:15















up vote
0
down vote

favorite












I cannot figure out the error which says



'This page contains the following errors:
error on line 1 at column 2: StartTag: invalid element name
Below is a rendering of the page up to the first error.'



init.php



<?php
$servername = "localhost";
$username = "root";
$password = null;
$databaseName = "test";

$db = mysqli_connect($servername, $username,
$password, $databaseName)

?>


viewWishList.php



<?php                                            
header ("Content-Type:text/xml");
include ("config/init.php");
$query = "SELECT * FROM members";
$result = mysqli_query($connection, $query) or
die ("Error in query: $query. ".mysql_error());

$_xml = '<?xml version="1.0"?>'
$_xml .="<wishList>";

while($row = mysqli_fetch_array($result)) {

$_xml .="<wishlist>";

$_xml .="<wishlistID>".$row['wishlistID']."
</wishlistID>";
$_xml .="<bookName>".$row['bookName']."
</bookName>";
$_xml .="<bookType>".$row['bookType']."
</bookType>";

$_xml .="</wishlist>";

}

$_xml .="</wishList>";

$xmlobj=new SimpleXMLElement($_xml);
print $xmlobj->asXML();
$xmlobj->asXML(wishlist.xml);

?>









share|improve this question


















  • 1




    dont see ;(semicolon) $_xml = '<?xml version="1.0"?>'
    – suresh bambhaniya
    Nov 22 at 15:14










  • If you comment out header ("Content-Type:text/xml"); what is displayed?
    – Nigel Ren
    Nov 22 at 15:15










  • Notice: Undefined variable: connection in /opt/lampp/htdocs/a/viewWishList.php on line 27 Warning: mysqli_query() expects parameter 1 to be mysqli, null given in /opt/lampp/htdocs/a/viewWishList.php on line 27 Fatal error: Uncaught Error: Call to undefined function mysql_error() in /opt/lampp/htdocs/a/viewWishList.php:27 Stack trace: #0 {main} thrown in /opt/lampp/htdocs/a/viewWishList.php on line 27
    – Abhooshan Bhattarai
    Nov 22 at 16:09












  • Change the line to $result = mysqli_query($db, $query) or die ("Error in query: $query. ".mysqli_connect_error());
    – Nigel Ren
    Nov 22 at 19:02










  • @NigelRen Still facing the same error.
    – Abhooshan Bhattarai
    Nov 23 at 5:15













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I cannot figure out the error which says



'This page contains the following errors:
error on line 1 at column 2: StartTag: invalid element name
Below is a rendering of the page up to the first error.'



init.php



<?php
$servername = "localhost";
$username = "root";
$password = null;
$databaseName = "test";

$db = mysqli_connect($servername, $username,
$password, $databaseName)

?>


viewWishList.php



<?php                                            
header ("Content-Type:text/xml");
include ("config/init.php");
$query = "SELECT * FROM members";
$result = mysqli_query($connection, $query) or
die ("Error in query: $query. ".mysql_error());

$_xml = '<?xml version="1.0"?>'
$_xml .="<wishList>";

while($row = mysqli_fetch_array($result)) {

$_xml .="<wishlist>";

$_xml .="<wishlistID>".$row['wishlistID']."
</wishlistID>";
$_xml .="<bookName>".$row['bookName']."
</bookName>";
$_xml .="<bookType>".$row['bookType']."
</bookType>";

$_xml .="</wishlist>";

}

$_xml .="</wishList>";

$xmlobj=new SimpleXMLElement($_xml);
print $xmlobj->asXML();
$xmlobj->asXML(wishlist.xml);

?>









share|improve this question













I cannot figure out the error which says



'This page contains the following errors:
error on line 1 at column 2: StartTag: invalid element name
Below is a rendering of the page up to the first error.'



init.php



<?php
$servername = "localhost";
$username = "root";
$password = null;
$databaseName = "test";

$db = mysqli_connect($servername, $username,
$password, $databaseName)

?>


viewWishList.php



<?php                                            
header ("Content-Type:text/xml");
include ("config/init.php");
$query = "SELECT * FROM members";
$result = mysqli_query($connection, $query) or
die ("Error in query: $query. ".mysql_error());

$_xml = '<?xml version="1.0"?>'
$_xml .="<wishList>";

while($row = mysqli_fetch_array($result)) {

$_xml .="<wishlist>";

$_xml .="<wishlistID>".$row['wishlistID']."
</wishlistID>";
$_xml .="<bookName>".$row['bookName']."
</bookName>";
$_xml .="<bookType>".$row['bookType']."
</bookType>";

$_xml .="</wishlist>";

}

$_xml .="</wishList>";

$xmlobj=new SimpleXMLElement($_xml);
print $xmlobj->asXML();
$xmlobj->asXML(wishlist.xml);

?>






php mysql xml






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share|improve this question











share|improve this question




share|improve this question










asked Nov 22 at 15:08









Abhooshan Bhattarai

618




618








  • 1




    dont see ;(semicolon) $_xml = '<?xml version="1.0"?>'
    – suresh bambhaniya
    Nov 22 at 15:14










  • If you comment out header ("Content-Type:text/xml"); what is displayed?
    – Nigel Ren
    Nov 22 at 15:15










  • Notice: Undefined variable: connection in /opt/lampp/htdocs/a/viewWishList.php on line 27 Warning: mysqli_query() expects parameter 1 to be mysqli, null given in /opt/lampp/htdocs/a/viewWishList.php on line 27 Fatal error: Uncaught Error: Call to undefined function mysql_error() in /opt/lampp/htdocs/a/viewWishList.php:27 Stack trace: #0 {main} thrown in /opt/lampp/htdocs/a/viewWishList.php on line 27
    – Abhooshan Bhattarai
    Nov 22 at 16:09












  • Change the line to $result = mysqli_query($db, $query) or die ("Error in query: $query. ".mysqli_connect_error());
    – Nigel Ren
    Nov 22 at 19:02










  • @NigelRen Still facing the same error.
    – Abhooshan Bhattarai
    Nov 23 at 5:15














  • 1




    dont see ;(semicolon) $_xml = '<?xml version="1.0"?>'
    – suresh bambhaniya
    Nov 22 at 15:14










  • If you comment out header ("Content-Type:text/xml"); what is displayed?
    – Nigel Ren
    Nov 22 at 15:15










  • Notice: Undefined variable: connection in /opt/lampp/htdocs/a/viewWishList.php on line 27 Warning: mysqli_query() expects parameter 1 to be mysqli, null given in /opt/lampp/htdocs/a/viewWishList.php on line 27 Fatal error: Uncaught Error: Call to undefined function mysql_error() in /opt/lampp/htdocs/a/viewWishList.php:27 Stack trace: #0 {main} thrown in /opt/lampp/htdocs/a/viewWishList.php on line 27
    – Abhooshan Bhattarai
    Nov 22 at 16:09












  • Change the line to $result = mysqli_query($db, $query) or die ("Error in query: $query. ".mysqli_connect_error());
    – Nigel Ren
    Nov 22 at 19:02










  • @NigelRen Still facing the same error.
    – Abhooshan Bhattarai
    Nov 23 at 5:15








1




1




dont see ;(semicolon) $_xml = '<?xml version="1.0"?>'
– suresh bambhaniya
Nov 22 at 15:14




dont see ;(semicolon) $_xml = '<?xml version="1.0"?>'
– suresh bambhaniya
Nov 22 at 15:14












If you comment out header ("Content-Type:text/xml"); what is displayed?
– Nigel Ren
Nov 22 at 15:15




If you comment out header ("Content-Type:text/xml"); what is displayed?
– Nigel Ren
Nov 22 at 15:15












Notice: Undefined variable: connection in /opt/lampp/htdocs/a/viewWishList.php on line 27 Warning: mysqli_query() expects parameter 1 to be mysqli, null given in /opt/lampp/htdocs/a/viewWishList.php on line 27 Fatal error: Uncaught Error: Call to undefined function mysql_error() in /opt/lampp/htdocs/a/viewWishList.php:27 Stack trace: #0 {main} thrown in /opt/lampp/htdocs/a/viewWishList.php on line 27
– Abhooshan Bhattarai
Nov 22 at 16:09






Notice: Undefined variable: connection in /opt/lampp/htdocs/a/viewWishList.php on line 27 Warning: mysqli_query() expects parameter 1 to be mysqli, null given in /opt/lampp/htdocs/a/viewWishList.php on line 27 Fatal error: Uncaught Error: Call to undefined function mysql_error() in /opt/lampp/htdocs/a/viewWishList.php:27 Stack trace: #0 {main} thrown in /opt/lampp/htdocs/a/viewWishList.php on line 27
– Abhooshan Bhattarai
Nov 22 at 16:09














Change the line to $result = mysqli_query($db, $query) or die ("Error in query: $query. ".mysqli_connect_error());
– Nigel Ren
Nov 22 at 19:02




Change the line to $result = mysqli_query($db, $query) or die ("Error in query: $query. ".mysqli_connect_error());
– Nigel Ren
Nov 22 at 19:02












@NigelRen Still facing the same error.
– Abhooshan Bhattarai
Nov 23 at 5:15




@NigelRen Still facing the same error.
– Abhooshan Bhattarai
Nov 23 at 5:15

















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