Mysql error #2014 - Commands out of sync; you can't run this command now in a stored procedure











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I have the following stored procedure in mysql:



DELIMITER $$
CREATE DEFINER=`user`@`localhost` PROCEDURE `insert_patient`(IN `name` VARCHAR(45), IN `surname` VARCHAR(45), IN `middle_name` VARCHAR(45), IN `patient_gender` VARCHAR(15), IN `patient_weight` VARCHAR(15), IN `patient_height` VARCHAR(15), IN `patient_ethnic_origin` VARCHAR(45))
NO SQL
BEGIN

BEGIN
INSERT
INTO
patient(
name,
surname,
middle_name
)
VALUES(
name,
surname,
middle_name
) ;
SELECT
LAST_INSERT_ID() AS patient_local_id;
END;
BEGIN
INSERT
INTO
demographics(
patient_id,
gender,
weight,
height,
ethnic_origin
)
VALUES(
patient_local_id,
patient_gender,
patient_weight,
patient_height,
patient_ethnic_origin
) ;
END;
END$$
DELIMITER ;


When I'm trying to execute this stored-procedure from phpmyadmin I get the following error:



Unrecognized keyword. (near "ON" at position 25)
SQL query: Edit Edit

SET FOREIGN_KEY_CHECKS = ON;

MySQL said: Documentation

#2014 - Commands out of sync; you can't run this command now









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  • The line from the error message appears nowhere in your stored proc, at least not in the code which you actually showed us. But, you should use SET FOREIGN_KEY_CHECKS = 1.
    – Tim Biegeleisen
    Nov 22 at 13:51










  • @TimBiegeleisen Do I have to include SET FOREIGN_KEY_CHECKS = 1 in my stored-procedure code?
    – zinon
    Nov 22 at 13:52










  • Well, are you already doing this in your proc code? The error message seems to be yes.
    – Tim Biegeleisen
    Nov 22 at 13:53










  • @TimBiegeleisen I don't have it in my proc code. Maybe it's something that happens by default?
    – zinon
    Nov 22 at 13:54










  • SET FOREIGN_KEY_CHECKS = ON; isn't valid MySQL AFAIK. Something must be inserting this code.
    – Tim Biegeleisen
    Nov 22 at 13:54















up vote
1
down vote

favorite












I have the following stored procedure in mysql:



DELIMITER $$
CREATE DEFINER=`user`@`localhost` PROCEDURE `insert_patient`(IN `name` VARCHAR(45), IN `surname` VARCHAR(45), IN `middle_name` VARCHAR(45), IN `patient_gender` VARCHAR(15), IN `patient_weight` VARCHAR(15), IN `patient_height` VARCHAR(15), IN `patient_ethnic_origin` VARCHAR(45))
NO SQL
BEGIN

BEGIN
INSERT
INTO
patient(
name,
surname,
middle_name
)
VALUES(
name,
surname,
middle_name
) ;
SELECT
LAST_INSERT_ID() AS patient_local_id;
END;
BEGIN
INSERT
INTO
demographics(
patient_id,
gender,
weight,
height,
ethnic_origin
)
VALUES(
patient_local_id,
patient_gender,
patient_weight,
patient_height,
patient_ethnic_origin
) ;
END;
END$$
DELIMITER ;


When I'm trying to execute this stored-procedure from phpmyadmin I get the following error:



Unrecognized keyword. (near "ON" at position 25)
SQL query: Edit Edit

SET FOREIGN_KEY_CHECKS = ON;

MySQL said: Documentation

#2014 - Commands out of sync; you can't run this command now









share|improve this question






















  • The line from the error message appears nowhere in your stored proc, at least not in the code which you actually showed us. But, you should use SET FOREIGN_KEY_CHECKS = 1.
    – Tim Biegeleisen
    Nov 22 at 13:51










  • @TimBiegeleisen Do I have to include SET FOREIGN_KEY_CHECKS = 1 in my stored-procedure code?
    – zinon
    Nov 22 at 13:52










  • Well, are you already doing this in your proc code? The error message seems to be yes.
    – Tim Biegeleisen
    Nov 22 at 13:53










  • @TimBiegeleisen I don't have it in my proc code. Maybe it's something that happens by default?
    – zinon
    Nov 22 at 13:54










  • SET FOREIGN_KEY_CHECKS = ON; isn't valid MySQL AFAIK. Something must be inserting this code.
    – Tim Biegeleisen
    Nov 22 at 13:54













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I have the following stored procedure in mysql:



DELIMITER $$
CREATE DEFINER=`user`@`localhost` PROCEDURE `insert_patient`(IN `name` VARCHAR(45), IN `surname` VARCHAR(45), IN `middle_name` VARCHAR(45), IN `patient_gender` VARCHAR(15), IN `patient_weight` VARCHAR(15), IN `patient_height` VARCHAR(15), IN `patient_ethnic_origin` VARCHAR(45))
NO SQL
BEGIN

BEGIN
INSERT
INTO
patient(
name,
surname,
middle_name
)
VALUES(
name,
surname,
middle_name
) ;
SELECT
LAST_INSERT_ID() AS patient_local_id;
END;
BEGIN
INSERT
INTO
demographics(
patient_id,
gender,
weight,
height,
ethnic_origin
)
VALUES(
patient_local_id,
patient_gender,
patient_weight,
patient_height,
patient_ethnic_origin
) ;
END;
END$$
DELIMITER ;


When I'm trying to execute this stored-procedure from phpmyadmin I get the following error:



Unrecognized keyword. (near "ON" at position 25)
SQL query: Edit Edit

SET FOREIGN_KEY_CHECKS = ON;

MySQL said: Documentation

#2014 - Commands out of sync; you can't run this command now









share|improve this question













I have the following stored procedure in mysql:



DELIMITER $$
CREATE DEFINER=`user`@`localhost` PROCEDURE `insert_patient`(IN `name` VARCHAR(45), IN `surname` VARCHAR(45), IN `middle_name` VARCHAR(45), IN `patient_gender` VARCHAR(15), IN `patient_weight` VARCHAR(15), IN `patient_height` VARCHAR(15), IN `patient_ethnic_origin` VARCHAR(45))
NO SQL
BEGIN

BEGIN
INSERT
INTO
patient(
name,
surname,
middle_name
)
VALUES(
name,
surname,
middle_name
) ;
SELECT
LAST_INSERT_ID() AS patient_local_id;
END;
BEGIN
INSERT
INTO
demographics(
patient_id,
gender,
weight,
height,
ethnic_origin
)
VALUES(
patient_local_id,
patient_gender,
patient_weight,
patient_height,
patient_ethnic_origin
) ;
END;
END$$
DELIMITER ;


When I'm trying to execute this stored-procedure from phpmyadmin I get the following error:



Unrecognized keyword. (near "ON" at position 25)
SQL query: Edit Edit

SET FOREIGN_KEY_CHECKS = ON;

MySQL said: Documentation

#2014 - Commands out of sync; you can't run this command now






mysql stored-procedures phpmyadmin






share|improve this question













share|improve this question











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asked Nov 22 at 13:45









zinon

1,47742962




1,47742962












  • The line from the error message appears nowhere in your stored proc, at least not in the code which you actually showed us. But, you should use SET FOREIGN_KEY_CHECKS = 1.
    – Tim Biegeleisen
    Nov 22 at 13:51










  • @TimBiegeleisen Do I have to include SET FOREIGN_KEY_CHECKS = 1 in my stored-procedure code?
    – zinon
    Nov 22 at 13:52










  • Well, are you already doing this in your proc code? The error message seems to be yes.
    – Tim Biegeleisen
    Nov 22 at 13:53










  • @TimBiegeleisen I don't have it in my proc code. Maybe it's something that happens by default?
    – zinon
    Nov 22 at 13:54










  • SET FOREIGN_KEY_CHECKS = ON; isn't valid MySQL AFAIK. Something must be inserting this code.
    – Tim Biegeleisen
    Nov 22 at 13:54


















  • The line from the error message appears nowhere in your stored proc, at least not in the code which you actually showed us. But, you should use SET FOREIGN_KEY_CHECKS = 1.
    – Tim Biegeleisen
    Nov 22 at 13:51










  • @TimBiegeleisen Do I have to include SET FOREIGN_KEY_CHECKS = 1 in my stored-procedure code?
    – zinon
    Nov 22 at 13:52










  • Well, are you already doing this in your proc code? The error message seems to be yes.
    – Tim Biegeleisen
    Nov 22 at 13:53










  • @TimBiegeleisen I don't have it in my proc code. Maybe it's something that happens by default?
    – zinon
    Nov 22 at 13:54










  • SET FOREIGN_KEY_CHECKS = ON; isn't valid MySQL AFAIK. Something must be inserting this code.
    – Tim Biegeleisen
    Nov 22 at 13:54
















The line from the error message appears nowhere in your stored proc, at least not in the code which you actually showed us. But, you should use SET FOREIGN_KEY_CHECKS = 1.
– Tim Biegeleisen
Nov 22 at 13:51




The line from the error message appears nowhere in your stored proc, at least not in the code which you actually showed us. But, you should use SET FOREIGN_KEY_CHECKS = 1.
– Tim Biegeleisen
Nov 22 at 13:51












@TimBiegeleisen Do I have to include SET FOREIGN_KEY_CHECKS = 1 in my stored-procedure code?
– zinon
Nov 22 at 13:52




@TimBiegeleisen Do I have to include SET FOREIGN_KEY_CHECKS = 1 in my stored-procedure code?
– zinon
Nov 22 at 13:52












Well, are you already doing this in your proc code? The error message seems to be yes.
– Tim Biegeleisen
Nov 22 at 13:53




Well, are you already doing this in your proc code? The error message seems to be yes.
– Tim Biegeleisen
Nov 22 at 13:53












@TimBiegeleisen I don't have it in my proc code. Maybe it's something that happens by default?
– zinon
Nov 22 at 13:54




@TimBiegeleisen I don't have it in my proc code. Maybe it's something that happens by default?
– zinon
Nov 22 at 13:54












SET FOREIGN_KEY_CHECKS = ON; isn't valid MySQL AFAIK. Something must be inserting this code.
– Tim Biegeleisen
Nov 22 at 13:54




SET FOREIGN_KEY_CHECKS = ON; isn't valid MySQL AFAIK. Something must be inserting this code.
– Tim Biegeleisen
Nov 22 at 13:54












1 Answer
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I found the solution. When I was executing the stored-procedure I had the following box checked.



enter image description here






share|improve this answer





















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    1 Answer
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    active

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote



    accepted










    I found the solution. When I was executing the stored-procedure I had the following box checked.



    enter image description here






    share|improve this answer

























      up vote
      0
      down vote



      accepted










      I found the solution. When I was executing the stored-procedure I had the following box checked.



      enter image description here






      share|improve this answer























        up vote
        0
        down vote



        accepted







        up vote
        0
        down vote



        accepted






        I found the solution. When I was executing the stored-procedure I had the following box checked.



        enter image description here






        share|improve this answer












        I found the solution. When I was executing the stored-procedure I had the following box checked.



        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 at 14:27









        zinon

        1,47742962




        1,47742962






























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