jQuery: How to add div with a dynamic id that increments when button is clicked?












0














I have this problem in jQuery:



I have a button that when clicked calls a function to create a div with an incremental id, equal to the number of clicks made. Here's my simplified solution:



$(document).ready(function() {
var count = 0;
});

$("#button").click(function() {
count = count + 1;
addDiv(count);
});


But, if I define the function click here, the id on my div is NaN while if I put the function of click in document.ready(), it creates two divs. I only want to create a div with incremental Id for each click!










share|improve this question
























  • Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
    – Andreas
    Nov 22 at 18:45












  • I think the problem is that you have to change the elements attribute and not just a javascript variable
    – tobifasc
    Nov 22 at 18:53










  • The problem is in variable scope check jsfiddle.net/f9ug1dyv
    – Mohammad
    Nov 22 at 18:57
















0














I have this problem in jQuery:



I have a button that when clicked calls a function to create a div with an incremental id, equal to the number of clicks made. Here's my simplified solution:



$(document).ready(function() {
var count = 0;
});

$("#button").click(function() {
count = count + 1;
addDiv(count);
});


But, if I define the function click here, the id on my div is NaN while if I put the function of click in document.ready(), it creates two divs. I only want to create a div with incremental Id for each click!










share|improve this question
























  • Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
    – Andreas
    Nov 22 at 18:45












  • I think the problem is that you have to change the elements attribute and not just a javascript variable
    – tobifasc
    Nov 22 at 18:53










  • The problem is in variable scope check jsfiddle.net/f9ug1dyv
    – Mohammad
    Nov 22 at 18:57














0












0








0







I have this problem in jQuery:



I have a button that when clicked calls a function to create a div with an incremental id, equal to the number of clicks made. Here's my simplified solution:



$(document).ready(function() {
var count = 0;
});

$("#button").click(function() {
count = count + 1;
addDiv(count);
});


But, if I define the function click here, the id on my div is NaN while if I put the function of click in document.ready(), it creates two divs. I only want to create a div with incremental Id for each click!










share|improve this question















I have this problem in jQuery:



I have a button that when clicked calls a function to create a div with an incremental id, equal to the number of clicks made. Here's my simplified solution:



$(document).ready(function() {
var count = 0;
});

$("#button").click(function() {
count = count + 1;
addDiv(count);
});


But, if I define the function click here, the id on my div is NaN while if I put the function of click in document.ready(), it creates two divs. I only want to create a div with incremental Id for each click!







javascript jquery html






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edited Nov 22 at 19:42









Roy Scheffers

2,15291725




2,15291725










asked Nov 22 at 18:42









user10276822

43




43












  • Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
    – Andreas
    Nov 22 at 18:45












  • I think the problem is that you have to change the elements attribute and not just a javascript variable
    – tobifasc
    Nov 22 at 18:53










  • The problem is in variable scope check jsfiddle.net/f9ug1dyv
    – Mohammad
    Nov 22 at 18:57


















  • Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
    – Andreas
    Nov 22 at 18:45












  • I think the problem is that you have to change the elements attribute and not just a javascript variable
    – tobifasc
    Nov 22 at 18:53










  • The problem is in variable scope check jsfiddle.net/f9ug1dyv
    – Mohammad
    Nov 22 at 18:57
















Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– Andreas
Nov 22 at 18:45






Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– Andreas
Nov 22 at 18:45














I think the problem is that you have to change the elements attribute and not just a javascript variable
– tobifasc
Nov 22 at 18:53




I think the problem is that you have to change the elements attribute and not just a javascript variable
– tobifasc
Nov 22 at 18:53












The problem is in variable scope check jsfiddle.net/f9ug1dyv
– Mohammad
Nov 22 at 18:57




The problem is in variable scope check jsfiddle.net/f9ug1dyv
– Mohammad
Nov 22 at 18:57












5 Answers
5






active

oldest

votes


















1














try this






var count=0;
$(document).ready(function(){
$("#add-div").click(function(){
count++;
$("body").append('<div id="'+count+'">div number '+count+'</div>');
});
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<button id="add-div">add div</button>
<br>
<br>
</body>








share|improve this answer





















  • Please, Don't just "Try this". Explain in a couple of paragraph why this works.
    – Roko C. Buljan
    Nov 22 at 19:02










  • thanks, but this is a simple code, he will know the error
    – abdulsattar-alkhalaf
    Nov 22 at 19:04



















1














This was due to scope issue.
Try this code:



  $( document ).ready(function() {
var count =0;
console.log(count);
$( "#button" ).click(function() {
count=count+1;
addDiv(count);
});
});





share|improve this answer





















  • You can remove console.log statement I used this for debugging purpose.
    – Jahanzeb Awan
    Nov 22 at 19:11



















0














This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






  $( document ).ready(function() 
{
//var count =0;
});

var count=0;
$('#button').on('click', function(){
count = count + 1;
alert(count);
});


//$( "#button" ).click(function() {
// count=count+1;
// addDiv(count);
//});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button id='button'>Click Me</button>








share|improve this answer





























    0














    if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






    //global scope
    var count = 0;
    $( "#button" ).click(function() {
    //function restrict scope
    $('#increment').append(`<div>${count}</div>`)
    count++;
    });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
    <body>
    <button id="button">Click Me!</button>
    <div id="increment">
    </body>





    See more at this page






    share|improve this answer





























      0














      It's a scope problem.
      If you don't want to expose variables to the outer scope, you can use a closure.



      let addDiv = function(){
      let counter = 0;
      return function(){
      counter++;
      let wrapper = $("#someDiv");
      wrapper.append(`<div> id: ${counter}</div>`)
      }
      }();
      button.on("click", function(){
      addDiv();
      });





      share|improve this answer





















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        5 Answers
        5






        active

        oldest

        votes








        5 Answers
        5






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        1














        try this






        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>








        share|improve this answer





















        • Please, Don't just "Try this". Explain in a couple of paragraph why this works.
          – Roko C. Buljan
          Nov 22 at 19:02










        • thanks, but this is a simple code, he will know the error
          – abdulsattar-alkhalaf
          Nov 22 at 19:04
















        1














        try this






        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>








        share|improve this answer





















        • Please, Don't just "Try this". Explain in a couple of paragraph why this works.
          – Roko C. Buljan
          Nov 22 at 19:02










        • thanks, but this is a simple code, he will know the error
          – abdulsattar-alkhalaf
          Nov 22 at 19:04














        1












        1








        1






        try this






        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>








        share|improve this answer












        try this






        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>








        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>





        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 at 18:57









        abdulsattar-alkhalaf

        31715




        31715












        • Please, Don't just "Try this". Explain in a couple of paragraph why this works.
          – Roko C. Buljan
          Nov 22 at 19:02










        • thanks, but this is a simple code, he will know the error
          – abdulsattar-alkhalaf
          Nov 22 at 19:04


















        • Please, Don't just "Try this". Explain in a couple of paragraph why this works.
          – Roko C. Buljan
          Nov 22 at 19:02










        • thanks, but this is a simple code, he will know the error
          – abdulsattar-alkhalaf
          Nov 22 at 19:04
















        Please, Don't just "Try this". Explain in a couple of paragraph why this works.
        – Roko C. Buljan
        Nov 22 at 19:02




        Please, Don't just "Try this". Explain in a couple of paragraph why this works.
        – Roko C. Buljan
        Nov 22 at 19:02












        thanks, but this is a simple code, he will know the error
        – abdulsattar-alkhalaf
        Nov 22 at 19:04




        thanks, but this is a simple code, he will know the error
        – abdulsattar-alkhalaf
        Nov 22 at 19:04













        1














        This was due to scope issue.
        Try this code:



          $( document ).ready(function() {
        var count =0;
        console.log(count);
        $( "#button" ).click(function() {
        count=count+1;
        addDiv(count);
        });
        });





        share|improve this answer





















        • You can remove console.log statement I used this for debugging purpose.
          – Jahanzeb Awan
          Nov 22 at 19:11
















        1














        This was due to scope issue.
        Try this code:



          $( document ).ready(function() {
        var count =0;
        console.log(count);
        $( "#button" ).click(function() {
        count=count+1;
        addDiv(count);
        });
        });





        share|improve this answer





















        • You can remove console.log statement I used this for debugging purpose.
          – Jahanzeb Awan
          Nov 22 at 19:11














        1












        1








        1






        This was due to scope issue.
        Try this code:



          $( document ).ready(function() {
        var count =0;
        console.log(count);
        $( "#button" ).click(function() {
        count=count+1;
        addDiv(count);
        });
        });





        share|improve this answer












        This was due to scope issue.
        Try this code:



          $( document ).ready(function() {
        var count =0;
        console.log(count);
        $( "#button" ).click(function() {
        count=count+1;
        addDiv(count);
        });
        });






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 at 19:09









        Jahanzeb Awan

        569




        569












        • You can remove console.log statement I used this for debugging purpose.
          – Jahanzeb Awan
          Nov 22 at 19:11


















        • You can remove console.log statement I used this for debugging purpose.
          – Jahanzeb Awan
          Nov 22 at 19:11
















        You can remove console.log statement I used this for debugging purpose.
        – Jahanzeb Awan
        Nov 22 at 19:11




        You can remove console.log statement I used this for debugging purpose.
        – Jahanzeb Awan
        Nov 22 at 19:11











        0














        This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
        What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



        Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






          $( document ).ready(function() 
        {
        //var count =0;
        });

        var count=0;
        $('#button').on('click', function(){
        count = count + 1;
        alert(count);
        });


        //$( "#button" ).click(function() {
        // count=count+1;
        // addDiv(count);
        //});

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

        <button id='button'>Click Me</button>








        share|improve this answer


























          0














          This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
          What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



          Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






            $( document ).ready(function() 
          {
          //var count =0;
          });

          var count=0;
          $('#button').on('click', function(){
          count = count + 1;
          alert(count);
          });


          //$( "#button" ).click(function() {
          // count=count+1;
          // addDiv(count);
          //});

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <button id='button'>Click Me</button>








          share|improve this answer
























            0












            0








            0






            This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
            What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



            Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






              $( document ).ready(function() 
            {
            //var count =0;
            });

            var count=0;
            $('#button').on('click', function(){
            count = count + 1;
            alert(count);
            });


            //$( "#button" ).click(function() {
            // count=count+1;
            // addDiv(count);
            //});

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

            <button id='button'>Click Me</button>








            share|improve this answer












            This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
            What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



            Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






              $( document ).ready(function() 
            {
            //var count =0;
            });

            var count=0;
            $('#button').on('click', function(){
            count = count + 1;
            alert(count);
            });


            //$( "#button" ).click(function() {
            // count=count+1;
            // addDiv(count);
            //});

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

            <button id='button'>Click Me</button>








              $( document ).ready(function() 
            {
            //var count =0;
            });

            var count=0;
            $('#button').on('click', function(){
            count = count + 1;
            alert(count);
            });


            //$( "#button" ).click(function() {
            // count=count+1;
            // addDiv(count);
            //});

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

            <button id='button'>Click Me</button>





              $( document ).ready(function() 
            {
            //var count =0;
            });

            var count=0;
            $('#button').on('click', function(){
            count = count + 1;
            alert(count);
            });


            //$( "#button" ).click(function() {
            // count=count+1;
            // addDiv(count);
            //});

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

            <button id='button'>Click Me</button>






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 22 at 19:00









            Sahil Sharma

            795619




            795619























                0














                if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






                //global scope
                var count = 0;
                $( "#button" ).click(function() {
                //function restrict scope
                $('#increment').append(`<div>${count}</div>`)
                count++;
                });

                    <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                <body>
                <button id="button">Click Me!</button>
                <div id="increment">
                </body>





                See more at this page






                share|improve this answer


























                  0














                  if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






                  //global scope
                  var count = 0;
                  $( "#button" ).click(function() {
                  //function restrict scope
                  $('#increment').append(`<div>${count}</div>`)
                  count++;
                  });

                      <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                  <body>
                  <button id="button">Click Me!</button>
                  <div id="increment">
                  </body>





                  See more at this page






                  share|improve this answer
























                    0












                    0








                    0






                    if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






                    //global scope
                    var count = 0;
                    $( "#button" ).click(function() {
                    //function restrict scope
                    $('#increment').append(`<div>${count}</div>`)
                    count++;
                    });

                        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                    <body>
                    <button id="button">Click Me!</button>
                    <div id="increment">
                    </body>





                    See more at this page






                    share|improve this answer












                    if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






                    //global scope
                    var count = 0;
                    $( "#button" ).click(function() {
                    //function restrict scope
                    $('#increment').append(`<div>${count}</div>`)
                    count++;
                    });

                        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                    <body>
                    <button id="button">Click Me!</button>
                    <div id="increment">
                    </body>





                    See more at this page






                    //global scope
                    var count = 0;
                    $( "#button" ).click(function() {
                    //function restrict scope
                    $('#increment').append(`<div>${count}</div>`)
                    count++;
                    });

                        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                    <body>
                    <button id="button">Click Me!</button>
                    <div id="increment">
                    </body>





                    //global scope
                    var count = 0;
                    $( "#button" ).click(function() {
                    //function restrict scope
                    $('#increment').append(`<div>${count}</div>`)
                    count++;
                    });

                        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                    <body>
                    <button id="button">Click Me!</button>
                    <div id="increment">
                    </body>






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 22 at 19:05









                    Demian

                    1637




                    1637























                        0














                        It's a scope problem.
                        If you don't want to expose variables to the outer scope, you can use a closure.



                        let addDiv = function(){
                        let counter = 0;
                        return function(){
                        counter++;
                        let wrapper = $("#someDiv");
                        wrapper.append(`<div> id: ${counter}</div>`)
                        }
                        }();
                        button.on("click", function(){
                        addDiv();
                        });





                        share|improve this answer


























                          0














                          It's a scope problem.
                          If you don't want to expose variables to the outer scope, you can use a closure.



                          let addDiv = function(){
                          let counter = 0;
                          return function(){
                          counter++;
                          let wrapper = $("#someDiv");
                          wrapper.append(`<div> id: ${counter}</div>`)
                          }
                          }();
                          button.on("click", function(){
                          addDiv();
                          });





                          share|improve this answer
























                            0












                            0








                            0






                            It's a scope problem.
                            If you don't want to expose variables to the outer scope, you can use a closure.



                            let addDiv = function(){
                            let counter = 0;
                            return function(){
                            counter++;
                            let wrapper = $("#someDiv");
                            wrapper.append(`<div> id: ${counter}</div>`)
                            }
                            }();
                            button.on("click", function(){
                            addDiv();
                            });





                            share|improve this answer












                            It's a scope problem.
                            If you don't want to expose variables to the outer scope, you can use a closure.



                            let addDiv = function(){
                            let counter = 0;
                            return function(){
                            counter++;
                            let wrapper = $("#someDiv");
                            wrapper.append(`<div> id: ${counter}</div>`)
                            }
                            }();
                            button.on("click", function(){
                            addDiv();
                            });






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Nov 22 at 19:22









                            Dmitry Shevchenko

                            1




                            1






























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