Qfyilyi

Consider the following MWE:

documentclass[tikz]{standalone}

usetikzlibrary{backgrounds}

definecolor{filz}{RGB}{56,114,73}

%pagecolor{filz}

newcommand{roulette}[1]{

%   pgfmathsetseed{3}

    pgfmathsetmacrorandom{10*random(0,36)}

    foreach n in {0,10,...,random}

%   foreach n in {random,...,random}

    {

        begin{tikzpicture}

            useasboundingbox (-.5,-.75) rectangle (3.5,2.75);



                begin{scope}[scale=.25,shift={(-2,10)}]

                    foreach x in {1,...,3}

                    foreach y in {1,...,12}

                    {

                        pgfmathsetmacronumber{int(x+3*(y-1))} 

                        pgfmathsetmacrotestnumber{int(mod(number,2))}



                        ifnumtestnumber=0

                            node[scale=.25,text=white,fill=red,minimum height=1.01cm,minimum width=1.01cm] at (x,-y) {Hugenumber};

                        else

                            node[scale=.25,text=white,fill,minimum height=1.01cm,minimum width=1.01cm] at (x,-y) {Hugenumber};

                        fi

                    }



                    node[scale=.25,text=white,fill=red,minimum height=1.01cm,minimum width=3.01cm] at (2,0) {Huge 0};



                    pgfmathsetmacrotesting{#1}

                    pgfmathsetmacrosecure{int(mod(int(testing),3))}



                    ifnumsecure=0

                        pgfmathsetmacroxpos{mod(testing,3)+3}

                        pgfmathsetmacroypos{-int(testing/3)}

                    else

                        pgfmathsetmacroxpos{mod(testing,3)}

                        pgfmathsetmacroypos{-int(testing/3)-1}

                    fi



                    ifnum#1>0

                    pgfmathsetmacroanothertest{int(mod(#1,2))}

                    ifnumanothertest=0

                        draw[black,thick,fill=red] (xpos,ypos) circle(.2);

                    else

                        draw[red,thick,fill=black] (xpos,ypos) circle(.2);

                    fi

                    else

                        draw[black,thick,fill=red] (1,0) circle(.2);

                    fi

                end{scope}



                begin{scope}[shift={(2,1)}]

                    foreach[count=xx] x in {0,20,...,340}

                    {

                        fill[red] (x:1) arc(x:x+10:1) -- (x+10:.75) arc(x+10:x:.75) -- cycle;

                        fill[rotate=10] (x:1) arc(x:x+10:1) -- (x+10:.75) arc(x+10:x:.75) -- cycle;

                            draw[fill=white] (x:1) arc(x:x+10:1) -- (x+10:1.25) arc(x+10:x:1.25) -- cycle;

                            draw[fill=white,rotate=10] (x:1) arc(x:x+10:1) -- (x+10:1.25) arc(x+10:x:1.25) -- cycle;

                    pgfmathsetmacronn{int(2*(xx-1))}

                        pgfmathsetmacronnn{int(2*xx-1)}

                            node[red,rotate=x,scale=.5] at (x+5:1.1) {nn};

                            node[scale=.5,rotate=x+15] at (x+15:1.1) {nnn};

                    }

                    fill[ball color=white] (n+5:{1-.05-(((1-2*.05)-.75)/2)}) circle(.05);

                end{scope}



                begin{pgfonlayer}{background}

                    fill[filz] (current bounding box.south west) rectangle (current bounding box.north east);

                end{pgfonlayer}

        end{tikzpicture}

    }

}



begin{document}

    roulette{0}

end{document}

Here is the output:

I know, that the numbers are not in the right order and that there is one number missing, but it's not important. My question is:

How can I achieve, that the roulette slice is rotating clockwise, while the ball is rotating counter-clockwise to the slice and that the both stop rotating, when the ball falls into a cell. The rotating should be just like in real life, i.e. the rotation is at the beginning faster than at the end.

I followed a slightly different approach from @samcarter's and just assumed that the angular velocity decreases linearly from some maximal value vmax to zero. Then I integrated the angular velocity to get an angle. Sorry, I had to shorten your code a bit to produce a gif that can be uploaded. Unfortunately, I do not know how to upload mp4 files, which can be produced as described in this other answer by @samcarter.

documentclass[tikz,border=3.14mm]{standalone}

begin{document}

pgfmathsetmacro{Frame}{0}

tikzset{declare function={tmax=100;

vmax=40;

rot(t)=(t/2)*(2-t/tmax)*vmax;}}

foreach Frame in {0,...,100}

{begin{tikzpicture}

foreach Y [evaluate=Y as X using {10*Y+rot(Frame)}] in {0,...,35}

{

ifoddY

fill (X-5:2.5) -- (X-5:2) arc(X-5:X+5:2) -- (X+5:2.5) arc(X+5:X-5:2.5);

node[rotate=X] at (X:2.75){Y};

else

fill[red] (X-5:2.5) -- (X-5:2) arc(X-5:X+5:2) -- (X+5:2.5) arc(X+5:X-5:2.5);

node[rotate=X,red] at (X:2.75){Y};

fi

draw (X-5:2.5) -- (X-5:3) arc(X-5:X+5:3) 

-- (X+5:2.5) arc(X+5:X-5:2.5);

}

shade[ball color=gray] ({-rot(Frame)}:2.25) circle (1mm);

end{tikzpicture}}

end{document}

For the part of your question about the slowing down:

A simple solution would be to write a wrapper document that displays each page of your animation an increasing number of times.

For example if your animation creates 16 pages, the following document will show the first page one time, the second page two times etc. You could also use other functions, this linear function is just an example:

documentclass{beamer}



setbeamertemplate{navigation symbols}{}

usepackage{tikz}



definecolor{filz}{RGB}{56,114,73}

setbeamercolor{background canvas}{bg=filz}



begin{document}



foreach n in {1,...,16}{



begin{frame}[plain]

foreach x in {1,...,insertframenumber}{

includegraphics<+>[height=paperheight,page=insertframenumber]{document}}

end{frame}



}



end{document}

(sorry for the tiny image, the .gif would otherwise be too big to upload)