Calculating the volume of a sphere after switching to spherical coordinates?
up vote
4
down vote
favorite
I used the code in the second answer on this page to switch from Cartesian to Spherical coordinates and integrate a function over the sphere. I would like to use this code to calculate the volume of a sphere. However if I set $ f(x, y, z) = 1 $, I get the following output:
$ -frac{1}{3}r^3 varphicos(theta) $
Here is the code I used:
Needs["VectorAnalysis`"]
JacobianDeterminant[Spherical[r, θ, ϕ]]
f[x_, y_, z_] := 1
Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[
Spherical @@ #] &@{r, θ, ϕ},
r, θ, ϕ]
How can I make the code return the volume of a sphere which is $frac{4}{3}pi r^3$?
calculus-and-analysis coordinate-transformation
add a comment |
up vote
4
down vote
favorite
I used the code in the second answer on this page to switch from Cartesian to Spherical coordinates and integrate a function over the sphere. I would like to use this code to calculate the volume of a sphere. However if I set $ f(x, y, z) = 1 $, I get the following output:
$ -frac{1}{3}r^3 varphicos(theta) $
Here is the code I used:
Needs["VectorAnalysis`"]
JacobianDeterminant[Spherical[r, θ, ϕ]]
f[x_, y_, z_] := 1
Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[
Spherical @@ #] &@{r, θ, ϕ},
r, θ, ϕ]
How can I make the code return the volume of a sphere which is $frac{4}{3}pi r^3$?
calculus-and-analysis coordinate-transformation
add a comment |
up vote
4
down vote
favorite
up vote
4
down vote
favorite
I used the code in the second answer on this page to switch from Cartesian to Spherical coordinates and integrate a function over the sphere. I would like to use this code to calculate the volume of a sphere. However if I set $ f(x, y, z) = 1 $, I get the following output:
$ -frac{1}{3}r^3 varphicos(theta) $
Here is the code I used:
Needs["VectorAnalysis`"]
JacobianDeterminant[Spherical[r, θ, ϕ]]
f[x_, y_, z_] := 1
Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[
Spherical @@ #] &@{r, θ, ϕ},
r, θ, ϕ]
How can I make the code return the volume of a sphere which is $frac{4}{3}pi r^3$?
calculus-and-analysis coordinate-transformation
I used the code in the second answer on this page to switch from Cartesian to Spherical coordinates and integrate a function over the sphere. I would like to use this code to calculate the volume of a sphere. However if I set $ f(x, y, z) = 1 $, I get the following output:
$ -frac{1}{3}r^3 varphicos(theta) $
Here is the code I used:
Needs["VectorAnalysis`"]
JacobianDeterminant[Spherical[r, θ, ϕ]]
f[x_, y_, z_] := 1
Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[
Spherical @@ #] &@{r, θ, ϕ},
r, θ, ϕ]
How can I make the code return the volume of a sphere which is $frac{4}{3}pi r^3$?
calculus-and-analysis coordinate-transformation
calculus-and-analysis coordinate-transformation
edited 2 hours ago
Αλέξανδρος Ζεγγ
3,7821927
3,7821927
asked 2 hours ago
sonicboom
1211
1211
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
3
down vote
Try this
transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
jdet f @@ coordi /. rules
]
f[x_, y_, z_] := 1
Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]
(4 π r^3)/3
add a comment |
up vote
3
down vote
Employing most of your own code;
Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
{r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
]
That is, you just have to add the integral boundaries.
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
Try this
transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
jdet f @@ coordi /. rules
]
f[x_, y_, z_] := 1
Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]
(4 π r^3)/3
add a comment |
up vote
3
down vote
Try this
transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
jdet f @@ coordi /. rules
]
f[x_, y_, z_] := 1
Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]
(4 π r^3)/3
add a comment |
up vote
3
down vote
up vote
3
down vote
Try this
transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
jdet f @@ coordi /. rules
]
f[x_, y_, z_] := 1
Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]
(4 π r^3)/3
Try this
transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
jdet f @@ coordi /. rules
]
f[x_, y_, z_] := 1
Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]
(4 π r^3)/3
edited 1 hour ago
answered 1 hour ago
Αλέξανδρος Ζεγγ
3,7821927
3,7821927
add a comment |
add a comment |
up vote
3
down vote
Employing most of your own code;
Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
{r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
]
That is, you just have to add the integral boundaries.
add a comment |
up vote
3
down vote
Employing most of your own code;
Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
{r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
]
That is, you just have to add the integral boundaries.
add a comment |
up vote
3
down vote
up vote
3
down vote
Employing most of your own code;
Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
{r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
]
That is, you just have to add the integral boundaries.
Employing most of your own code;
Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
{r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
]
That is, you just have to add the integral boundaries.
edited 1 hour ago
answered 1 hour ago
Henrik Schumacher
47.1k466134
47.1k466134
add a comment |
add a comment |
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f187765%2fcalculating-the-volume-of-a-sphere-after-switching-to-spherical-coordinates%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown