Calculating the volume of a sphere after switching to spherical coordinates?











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I used the code in the second answer on this page to switch from Cartesian to Spherical coordinates and integrate a function over the sphere. I would like to use this code to calculate the volume of a sphere. However if I set $ f(x, y, z) = 1 $, I get the following output:




$ -frac{1}{3}r^3 varphicos(theta) $




Here is the code I used:



Needs["VectorAnalysis`"]

JacobianDeterminant[Spherical[r, θ, ϕ]]

f[x_, y_, z_] := 1

Integrate[
f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[
Spherical @@ #] &@{r, θ, ϕ},
r, θ, ϕ]


How can I make the code return the volume of a sphere which is $frac{4}{3}pi r^3$?










share|improve this question




























    up vote
    4
    down vote

    favorite












    I used the code in the second answer on this page to switch from Cartesian to Spherical coordinates and integrate a function over the sphere. I would like to use this code to calculate the volume of a sphere. However if I set $ f(x, y, z) = 1 $, I get the following output:




    $ -frac{1}{3}r^3 varphicos(theta) $




    Here is the code I used:



    Needs["VectorAnalysis`"]

    JacobianDeterminant[Spherical[r, θ, ϕ]]

    f[x_, y_, z_] := 1

    Integrate[
    f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[
    Spherical @@ #] &@{r, θ, ϕ},
    r, θ, ϕ]


    How can I make the code return the volume of a sphere which is $frac{4}{3}pi r^3$?










    share|improve this question


























      up vote
      4
      down vote

      favorite









      up vote
      4
      down vote

      favorite











      I used the code in the second answer on this page to switch from Cartesian to Spherical coordinates and integrate a function over the sphere. I would like to use this code to calculate the volume of a sphere. However if I set $ f(x, y, z) = 1 $, I get the following output:




      $ -frac{1}{3}r^3 varphicos(theta) $




      Here is the code I used:



      Needs["VectorAnalysis`"]

      JacobianDeterminant[Spherical[r, θ, ϕ]]

      f[x_, y_, z_] := 1

      Integrate[
      f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[
      Spherical @@ #] &@{r, θ, ϕ},
      r, θ, ϕ]


      How can I make the code return the volume of a sphere which is $frac{4}{3}pi r^3$?










      share|improve this question















      I used the code in the second answer on this page to switch from Cartesian to Spherical coordinates and integrate a function over the sphere. I would like to use this code to calculate the volume of a sphere. However if I set $ f(x, y, z) = 1 $, I get the following output:




      $ -frac{1}{3}r^3 varphicos(theta) $




      Here is the code I used:



      Needs["VectorAnalysis`"]

      JacobianDeterminant[Spherical[r, θ, ϕ]]

      f[x_, y_, z_] := 1

      Integrate[
      f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[
      Spherical @@ #] &@{r, θ, ϕ},
      r, θ, ϕ]


      How can I make the code return the volume of a sphere which is $frac{4}{3}pi r^3$?







      calculus-and-analysis coordinate-transformation






      share|improve this question















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      share|improve this question








      edited 2 hours ago









      Αλέξανδρος Ζεγγ

      3,7821927




      3,7821927










      asked 2 hours ago









      sonicboom

      1211




      1211






















          2 Answers
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          3
          down vote













          Try this



          transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
          rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
          jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
          jdet f @@ coordi /. rules
          ]

          f[x_, y_, z_] := 1

          Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]



          (4 π r^3)/3






          share|improve this answer






























            up vote
            3
            down vote













            Employing most of your own code;



            Integrate[
            f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
            {r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
            ]


            That is, you just have to add the integral boundaries.






            share|improve this answer























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              2 Answers
              2






              active

              oldest

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              2 Answers
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              active

              oldest

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              active

              oldest

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              active

              oldest

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              up vote
              3
              down vote













              Try this



              transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
              rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
              jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
              jdet f @@ coordi /. rules
              ]

              f[x_, y_, z_] := 1

              Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]



              (4 π r^3)/3






              share|improve this answer



























                up vote
                3
                down vote













                Try this



                transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
                rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
                jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
                jdet f @@ coordi /. rules
                ]

                f[x_, y_, z_] := 1

                Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]



                (4 π r^3)/3






                share|improve this answer

























                  up vote
                  3
                  down vote










                  up vote
                  3
                  down vote









                  Try this



                  transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
                  rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
                  jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
                  jdet f @@ coordi /. rules
                  ]

                  f[x_, y_, z_] := 1

                  Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]



                  (4 π r^3)/3






                  share|improve this answer














                  Try this



                  transform[f : (_Function | _Symbol), coordi_: {x, y, z}, coordf_: {r, θ, ϕ}] := Module[{rules, jdet},
                  rules = Thread[coordi -> CoordinateTransformData["Spherical" -> "Cartesian", "Mapping", coordf]];
                  jdet = CoordinateTransformData["Spherical" -> "Cartesian", "MappingJacobianDeterminant", coordf];
                  jdet f @@ coordi /. rules
                  ]

                  f[x_, y_, z_] := 1

                  Integrate[transform[f], r, {θ, 0, π}, {ϕ, 0, 2 π}]



                  (4 π r^3)/3







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 1 hour ago

























                  answered 1 hour ago









                  Αλέξανδρος Ζεγγ

                  3,7821927




                  3,7821927






















                      up vote
                      3
                      down vote













                      Employing most of your own code;



                      Integrate[
                      f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
                      {r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
                      ]


                      That is, you just have to add the integral boundaries.






                      share|improve this answer



























                        up vote
                        3
                        down vote













                        Employing most of your own code;



                        Integrate[
                        f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
                        {r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
                        ]


                        That is, you just have to add the integral boundaries.






                        share|improve this answer

























                          up vote
                          3
                          down vote










                          up vote
                          3
                          down vote









                          Employing most of your own code;



                          Integrate[
                          f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
                          {r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
                          ]


                          That is, you just have to add the integral boundaries.






                          share|improve this answer














                          Employing most of your own code;



                          Integrate[
                          f @@ CoordinatesToCartesian[#, Spherical @@ #] JacobianDeterminant[Spherical @@ #] &@{r, θ, ϕ},
                          {r, 0, R}, {θ, 0,Pi}, {ϕ, -Pi, Pi}
                          ]


                          That is, you just have to add the integral boundaries.







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 1 hour ago

























                          answered 1 hour ago









                          Henrik Schumacher

                          47.1k466134




                          47.1k466134






























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