split XML node by half (XSLT transformation)
Could you please help how to split in half node with subnodes.
Input:
<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
Output:
<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="hard-coded guid1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule Id="hard-coded guid2">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
Unfortunatly I dont have expirience with xslt and did not find such an examples how to do it.
Updated
I tried one of the suggested approach below and have this https://xsltfiddle.liberty-development.net/jyH9rNq/3 nodes doesn't copy
xslt:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:variable name="fileHash" select="/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />
<xsl:template match="/">
<RuleCollection>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfa</xsl:attribute>
<Conditions>
<FileHashCondition>
<xsl:copy-of select="$fileHash[position() <= $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfb</xsl:attribute>
<Conditions>
<FileHashCondition>
<xsl:copy-of select="$fileHash[position() > $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
</xsl:template>
</xsl:stylesheet>
Output:
<?xml version="1.0" encoding="UTF-8"?>
<RuleCollection>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfa">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfb">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
</RuleCollection>
xml xslt-1.0
add a comment |
Could you please help how to split in half node with subnodes.
Input:
<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
Output:
<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="hard-coded guid1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule Id="hard-coded guid2">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
Unfortunatly I dont have expirience with xslt and did not find such an examples how to do it.
Updated
I tried one of the suggested approach below and have this https://xsltfiddle.liberty-development.net/jyH9rNq/3 nodes doesn't copy
xslt:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:variable name="fileHash" select="/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />
<xsl:template match="/">
<RuleCollection>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfa</xsl:attribute>
<Conditions>
<FileHashCondition>
<xsl:copy-of select="$fileHash[position() <= $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfb</xsl:attribute>
<Conditions>
<FileHashCondition>
<xsl:copy-of select="$fileHash[position() > $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
</xsl:template>
</xsl:stylesheet>
Output:
<?xml version="1.0" encoding="UTF-8"?>
<RuleCollection>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfa">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfb">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
</RuleCollection>
xml xslt-1.0
Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
– michael.hor257k
Nov 23 '18 at 12:12
@michael.hor257k, corrected, about half, doesnt matter
– Alexander
Nov 23 '18 at 12:22
When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
– Michael Kay
Nov 23 '18 at 12:26
You keep changing your input XML format. Now that you have added theRuleCollection
wrapper, you must change thefileHash
variable definition to:<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
- see: xsltfiddle.liberty-development.net/jyH9rNq/4
– michael.hor257k
Nov 24 '18 at 9:01
@michael.hor257k, Thanks a lot, works great. what I need
– Alexander
Nov 24 '18 at 20:37
add a comment |
Could you please help how to split in half node with subnodes.
Input:
<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
Output:
<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="hard-coded guid1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule Id="hard-coded guid2">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
Unfortunatly I dont have expirience with xslt and did not find such an examples how to do it.
Updated
I tried one of the suggested approach below and have this https://xsltfiddle.liberty-development.net/jyH9rNq/3 nodes doesn't copy
xslt:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:variable name="fileHash" select="/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />
<xsl:template match="/">
<RuleCollection>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfa</xsl:attribute>
<Conditions>
<FileHashCondition>
<xsl:copy-of select="$fileHash[position() <= $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfb</xsl:attribute>
<Conditions>
<FileHashCondition>
<xsl:copy-of select="$fileHash[position() > $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
</xsl:template>
</xsl:stylesheet>
Output:
<?xml version="1.0" encoding="UTF-8"?>
<RuleCollection>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfa">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfb">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
</RuleCollection>
xml xslt-1.0
Could you please help how to split in half node with subnodes.
Input:
<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
Output:
<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="hard-coded guid1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule Id="hard-coded guid2">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
Unfortunatly I dont have expirience with xslt and did not find such an examples how to do it.
Updated
I tried one of the suggested approach below and have this https://xsltfiddle.liberty-development.net/jyH9rNq/3 nodes doesn't copy
xslt:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:variable name="fileHash" select="/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />
<xsl:template match="/">
<RuleCollection>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfa</xsl:attribute>
<Conditions>
<FileHashCondition>
<xsl:copy-of select="$fileHash[position() <= $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfb</xsl:attribute>
<Conditions>
<FileHashCondition>
<xsl:copy-of select="$fileHash[position() > $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>
</xsl:template>
</xsl:stylesheet>
Output:
<?xml version="1.0" encoding="UTF-8"?>
<RuleCollection>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfa">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfb">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
</RuleCollection>
xml xslt-1.0
xml xslt-1.0
edited Nov 24 '18 at 8:21
Alexander
asked Nov 23 '18 at 11:15
AlexanderAlexander
103
103
Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
– michael.hor257k
Nov 23 '18 at 12:12
@michael.hor257k, corrected, about half, doesnt matter
– Alexander
Nov 23 '18 at 12:22
When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
– Michael Kay
Nov 23 '18 at 12:26
You keep changing your input XML format. Now that you have added theRuleCollection
wrapper, you must change thefileHash
variable definition to:<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
- see: xsltfiddle.liberty-development.net/jyH9rNq/4
– michael.hor257k
Nov 24 '18 at 9:01
@michael.hor257k, Thanks a lot, works great. what I need
– Alexander
Nov 24 '18 at 20:37
add a comment |
Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
– michael.hor257k
Nov 23 '18 at 12:12
@michael.hor257k, corrected, about half, doesnt matter
– Alexander
Nov 23 '18 at 12:22
When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
– Michael Kay
Nov 23 '18 at 12:26
You keep changing your input XML format. Now that you have added theRuleCollection
wrapper, you must change thefileHash
variable definition to:<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
- see: xsltfiddle.liberty-development.net/jyH9rNq/4
– michael.hor257k
Nov 24 '18 at 9:01
@michael.hor257k, Thanks a lot, works great. what I need
– Alexander
Nov 24 '18 at 20:37
Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
– michael.hor257k
Nov 23 '18 at 12:12
Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
– michael.hor257k
Nov 23 '18 at 12:12
@michael.hor257k, corrected, about half, doesnt matter
– Alexander
Nov 23 '18 at 12:22
@michael.hor257k, corrected, about half, doesnt matter
– Alexander
Nov 23 '18 at 12:22
When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
– Michael Kay
Nov 23 '18 at 12:26
When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
– Michael Kay
Nov 23 '18 at 12:26
You keep changing your input XML format. Now that you have added the
RuleCollection
wrapper, you must change the fileHash
variable definition to: <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
- see: xsltfiddle.liberty-development.net/jyH9rNq/4– michael.hor257k
Nov 24 '18 at 9:01
You keep changing your input XML format. Now that you have added the
RuleCollection
wrapper, you must change the fileHash
variable definition to: <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
- see: xsltfiddle.liberty-development.net/jyH9rNq/4– michael.hor257k
Nov 24 '18 at 9:01
@michael.hor257k, Thanks a lot, works great. what I need
– Alexander
Nov 24 '18 at 20:37
@michael.hor257k, Thanks a lot, works great. what I need
– Alexander
Nov 24 '18 at 20:37
add a comment |
3 Answers
3
active
oldest
votes
You could find the half point quite simply by:
<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />
Then just create the two FileHashRule
elements and use:
<xsl:copy-of select="$fileHash[position() <= $half]" />
to populate the first one, and:
<xsl:copy-of select="$fileHash[position() > $half]" />
for the second one.
add a comment |
You can start from something like (XSLT Fiddle):
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="//xs">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() <= last() div 2]'/>
</xsl:copy>
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() > last() div 2]'/>
</xsl:copy>
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
It will split
<?xml version="1.0" encoding="utf-8" ?>
<data>
<xs a="b">
<will-not-be-copied/>
<x>1</x>
<x>2</x>
<x>3</x>
<x>4</x>
</xs>
</data>
into
<?xml version="1.0" encoding="UTF-8"?>
<data>
<xs a="b">
<x>1</x>
<x>2</x>
</xs>
<xs a="b">
<x>3</x>
<x>4</x>
</xs>
</data>
Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied>
and you might want to add your id
values to the splitted <xs>
tags.
Your wrappers are identical - unlike the expected output.
– michael.hor257k
Nov 23 '18 at 12:37
add a comment |
Here's one way:
<xsl:template match="@*|node()" mode="#all">
<xsl:copy>
<xsl:apply-templates select="@*|node()" mode="#current"/>
</xsl:copy>
</xsl:template>
<xsl:template match="FileHashRule">
<FileHashRule Id="{@Id}">
<xsl:apply-templates mode="one"/>
</FileHashRule>
<FileHashRule Id="{@Id + 1}">
<xsl:apply-templates mode="two"/>
</FileHashRule>
</xsl:template>
<xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
<xsl:template match="FileHash[position() <= last() div 2]" mode="two"/>
The first rule says: by default, copy nodes unchanged.
The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.
The third rule says: during the first phase, skip any FileHash element in the second half of the list.
The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You could find the half point quite simply by:
<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />
Then just create the two FileHashRule
elements and use:
<xsl:copy-of select="$fileHash[position() <= $half]" />
to populate the first one, and:
<xsl:copy-of select="$fileHash[position() > $half]" />
for the second one.
add a comment |
You could find the half point quite simply by:
<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />
Then just create the two FileHashRule
elements and use:
<xsl:copy-of select="$fileHash[position() <= $half]" />
to populate the first one, and:
<xsl:copy-of select="$fileHash[position() > $half]" />
for the second one.
add a comment |
You could find the half point quite simply by:
<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />
Then just create the two FileHashRule
elements and use:
<xsl:copy-of select="$fileHash[position() <= $half]" />
to populate the first one, and:
<xsl:copy-of select="$fileHash[position() > $half]" />
for the second one.
You could find the half point quite simply by:
<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />
Then just create the two FileHashRule
elements and use:
<xsl:copy-of select="$fileHash[position() <= $half]" />
to populate the first one, and:
<xsl:copy-of select="$fileHash[position() > $half]" />
for the second one.
edited Nov 24 '18 at 9:02
answered Nov 23 '18 at 12:34
michael.hor257kmichael.hor257k
73.8k42236
73.8k42236
add a comment |
add a comment |
You can start from something like (XSLT Fiddle):
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="//xs">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() <= last() div 2]'/>
</xsl:copy>
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() > last() div 2]'/>
</xsl:copy>
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
It will split
<?xml version="1.0" encoding="utf-8" ?>
<data>
<xs a="b">
<will-not-be-copied/>
<x>1</x>
<x>2</x>
<x>3</x>
<x>4</x>
</xs>
</data>
into
<?xml version="1.0" encoding="UTF-8"?>
<data>
<xs a="b">
<x>1</x>
<x>2</x>
</xs>
<xs a="b">
<x>3</x>
<x>4</x>
</xs>
</data>
Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied>
and you might want to add your id
values to the splitted <xs>
tags.
Your wrappers are identical - unlike the expected output.
– michael.hor257k
Nov 23 '18 at 12:37
add a comment |
You can start from something like (XSLT Fiddle):
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="//xs">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() <= last() div 2]'/>
</xsl:copy>
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() > last() div 2]'/>
</xsl:copy>
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
It will split
<?xml version="1.0" encoding="utf-8" ?>
<data>
<xs a="b">
<will-not-be-copied/>
<x>1</x>
<x>2</x>
<x>3</x>
<x>4</x>
</xs>
</data>
into
<?xml version="1.0" encoding="UTF-8"?>
<data>
<xs a="b">
<x>1</x>
<x>2</x>
</xs>
<xs a="b">
<x>3</x>
<x>4</x>
</xs>
</data>
Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied>
and you might want to add your id
values to the splitted <xs>
tags.
Your wrappers are identical - unlike the expected output.
– michael.hor257k
Nov 23 '18 at 12:37
add a comment |
You can start from something like (XSLT Fiddle):
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="//xs">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() <= last() div 2]'/>
</xsl:copy>
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() > last() div 2]'/>
</xsl:copy>
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
It will split
<?xml version="1.0" encoding="utf-8" ?>
<data>
<xs a="b">
<will-not-be-copied/>
<x>1</x>
<x>2</x>
<x>3</x>
<x>4</x>
</xs>
</data>
into
<?xml version="1.0" encoding="UTF-8"?>
<data>
<xs a="b">
<x>1</x>
<x>2</x>
</xs>
<xs a="b">
<x>3</x>
<x>4</x>
</xs>
</data>
Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied>
and you might want to add your id
values to the splitted <xs>
tags.
You can start from something like (XSLT Fiddle):
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="//xs">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() <= last() div 2]'/>
</xsl:copy>
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select='x[position() > last() div 2]'/>
</xsl:copy>
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
It will split
<?xml version="1.0" encoding="utf-8" ?>
<data>
<xs a="b">
<will-not-be-copied/>
<x>1</x>
<x>2</x>
<x>3</x>
<x>4</x>
</xs>
</data>
into
<?xml version="1.0" encoding="UTF-8"?>
<data>
<xs a="b">
<x>1</x>
<x>2</x>
</xs>
<xs a="b">
<x>3</x>
<x>4</x>
</xs>
</data>
Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied>
and you might want to add your id
values to the splitted <xs>
tags.
answered Nov 23 '18 at 12:32
Micha WiedenmannMicha Wiedenmann
10.3k1364103
10.3k1364103
Your wrappers are identical - unlike the expected output.
– michael.hor257k
Nov 23 '18 at 12:37
add a comment |
Your wrappers are identical - unlike the expected output.
– michael.hor257k
Nov 23 '18 at 12:37
Your wrappers are identical - unlike the expected output.
– michael.hor257k
Nov 23 '18 at 12:37
Your wrappers are identical - unlike the expected output.
– michael.hor257k
Nov 23 '18 at 12:37
add a comment |
Here's one way:
<xsl:template match="@*|node()" mode="#all">
<xsl:copy>
<xsl:apply-templates select="@*|node()" mode="#current"/>
</xsl:copy>
</xsl:template>
<xsl:template match="FileHashRule">
<FileHashRule Id="{@Id}">
<xsl:apply-templates mode="one"/>
</FileHashRule>
<FileHashRule Id="{@Id + 1}">
<xsl:apply-templates mode="two"/>
</FileHashRule>
</xsl:template>
<xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
<xsl:template match="FileHash[position() <= last() div 2]" mode="two"/>
The first rule says: by default, copy nodes unchanged.
The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.
The third rule says: during the first phase, skip any FileHash element in the second half of the list.
The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.
add a comment |
Here's one way:
<xsl:template match="@*|node()" mode="#all">
<xsl:copy>
<xsl:apply-templates select="@*|node()" mode="#current"/>
</xsl:copy>
</xsl:template>
<xsl:template match="FileHashRule">
<FileHashRule Id="{@Id}">
<xsl:apply-templates mode="one"/>
</FileHashRule>
<FileHashRule Id="{@Id + 1}">
<xsl:apply-templates mode="two"/>
</FileHashRule>
</xsl:template>
<xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
<xsl:template match="FileHash[position() <= last() div 2]" mode="two"/>
The first rule says: by default, copy nodes unchanged.
The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.
The third rule says: during the first phase, skip any FileHash element in the second half of the list.
The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.
add a comment |
Here's one way:
<xsl:template match="@*|node()" mode="#all">
<xsl:copy>
<xsl:apply-templates select="@*|node()" mode="#current"/>
</xsl:copy>
</xsl:template>
<xsl:template match="FileHashRule">
<FileHashRule Id="{@Id}">
<xsl:apply-templates mode="one"/>
</FileHashRule>
<FileHashRule Id="{@Id + 1}">
<xsl:apply-templates mode="two"/>
</FileHashRule>
</xsl:template>
<xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
<xsl:template match="FileHash[position() <= last() div 2]" mode="two"/>
The first rule says: by default, copy nodes unchanged.
The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.
The third rule says: during the first phase, skip any FileHash element in the second half of the list.
The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.
Here's one way:
<xsl:template match="@*|node()" mode="#all">
<xsl:copy>
<xsl:apply-templates select="@*|node()" mode="#current"/>
</xsl:copy>
</xsl:template>
<xsl:template match="FileHashRule">
<FileHashRule Id="{@Id}">
<xsl:apply-templates mode="one"/>
</FileHashRule>
<FileHashRule Id="{@Id + 1}">
<xsl:apply-templates mode="two"/>
</FileHashRule>
</xsl:template>
<xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
<xsl:template match="FileHash[position() <= last() div 2]" mode="two"/>
The first rule says: by default, copy nodes unchanged.
The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.
The third rule says: during the first phase, skip any FileHash element in the second half of the list.
The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.
answered Nov 23 '18 at 12:38
Michael KayMichael Kay
109k660114
109k660114
add a comment |
add a comment |
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Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
– michael.hor257k
Nov 23 '18 at 12:12
@michael.hor257k, corrected, about half, doesnt matter
– Alexander
Nov 23 '18 at 12:22
When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
– Michael Kay
Nov 23 '18 at 12:26
You keep changing your input XML format. Now that you have added the
RuleCollection
wrapper, you must change thefileHash
variable definition to:<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
- see: xsltfiddle.liberty-development.net/jyH9rNq/4– michael.hor257k
Nov 24 '18 at 9:01
@michael.hor257k, Thanks a lot, works great. what I need
– Alexander
Nov 24 '18 at 20:37