Run crontab in specific day but only if is in specific weekday












4














I wanna run command with crontab in a specific day, but only if this day is not sunday.
I tried with this




1 0 27 12 1-6 command.sh




but the command run also wednesday december 26th.
How can I tell to crontab run command only the december 27th?



Thanks
Max






cron







share|improve this question
























  • You want the job to run on 27 but that day must not be a sunday but can be any other day!
    – George Udosen
    10 hours ago










  • Try this 1 0 27 * 1-6
    – George Udosen
    10 hours ago










  • @GeorgeUdosen 1 0 27 * 1-6 will run on every 27th plus every Mon…Sat. Cron's syntax is mean.
    – PerlDuck
    9 hours ago
















4














I wanna run command with crontab in a specific day, but only if this day is not sunday.
I tried with this




1 0 27 12 1-6 command.sh




but the command run also wednesday december 26th.
How can I tell to crontab run command only the december 27th?



Thanks
Max






cron







share|improve this question
























  • You want the job to run on 27 but that day must not be a sunday but can be any other day!
    – George Udosen
    10 hours ago










  • Try this 1 0 27 * 1-6
    – George Udosen
    10 hours ago










  • @GeorgeUdosen 1 0 27 * 1-6 will run on every 27th plus every Mon…Sat. Cron's syntax is mean.
    – PerlDuck
    9 hours ago














4












4








4







I wanna run command with crontab in a specific day, but only if this day is not sunday.
I tried with this




1 0 27 12 1-6 command.sh




but the command run also wednesday december 26th.
How can I tell to crontab run command only the december 27th?



Thanks
Max






cron







share|improve this question















I wanna run command with crontab in a specific day, but only if this day is not sunday.
I tried with this




1 0 27 12 1-6 command.sh




but the command run also wednesday december 26th.
How can I tell to crontab run command only the december 27th?



Thanks
Max






cron




cron






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 11 hours ago

























asked 11 hours ago









maxranzy

312




312












  • You want the job to run on 27 but that day must not be a sunday but can be any other day!
    – George Udosen
    10 hours ago










  • Try this 1 0 27 * 1-6
    – George Udosen
    10 hours ago










  • @GeorgeUdosen 1 0 27 * 1-6 will run on every 27th plus every Mon…Sat. Cron's syntax is mean.
    – PerlDuck
    9 hours ago


















  • You want the job to run on 27 but that day must not be a sunday but can be any other day!
    – George Udosen
    10 hours ago










  • Try this 1 0 27 * 1-6
    – George Udosen
    10 hours ago










  • @GeorgeUdosen 1 0 27 * 1-6 will run on every 27th plus every Mon…Sat. Cron's syntax is mean.
    – PerlDuck
    9 hours ago
















You want the job to run on 27 but that day must not be a sunday but can be any other day!
– George Udosen
10 hours ago




You want the job to run on 27 but that day must not be a sunday but can be any other day!
– George Udosen
10 hours ago












Try this 1 0 27 * 1-6
– George Udosen
10 hours ago




Try this 1 0 27 * 1-6
– George Udosen
10 hours ago












@GeorgeUdosen 1 0 27 * 1-6 will run on every 27th plus every Mon…Sat. Cron's syntax is mean.
– PerlDuck
9 hours ago




@GeorgeUdosen 1 0 27 * 1-6 will run on every 27th plus every Mon…Sat. Cron's syntax is mean.
– PerlDuck
9 hours ago










1 Answer
1






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oldest

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4














I don't think it is possible with cron alone because the syntax doesn't
allow for "at 27th except on Sundays". It only allows
for "either 27th or non-Sundays (or both)".



I suggest to either change command.sh to immediately exit on non-Sundays
or put that check into the cronjob:



1 0 27 12 *   test $(date +%u) -ne 7   &&  command.sh


At the shell, date +%u returns the day of week (1…7, 1 is Monday). In
a cronjob we have to escape that % sign (%). The command will
check whether the current day is a non-Sunday and only then execute
command.sh.



The cronjob will run on every Dec 27th at 00:01 o'clock,
no matter what day of the week that is, but only for non-Sundays the
command.sh gets executed because the previous test only succeeds
for them.



Note: I sometimes use https://crontab.guru to check my cronjob's
timetables. It's quite handy.
Your definition translates to “At
00:01 on day-of-month 27 and on every day-of-week from Monday through
Saturday in December.” so it's quite the opposite of what you want.




From the manpage:




Note: The day of a command's execution can be specified by two fields
— day of month, and day of week. If both fields are restricted (i.e.,
aren't *), the command will be run when either field matches the
current time. For example, 30 4 1,15 * 5 would cause a command to
be run at 4:30 am on the 1st and 15th of each month, plus every
Friday. One can, however, achieve the desired result by adding a test
to the command (see the last example in EXAMPLE CRON FILE below).



…



# Run on every second Saturday of the month

0 4 8-14 * *    test $(date +%u) -eq 6 && echo "2nd Saturday"






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    1 Answer
    1






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    active

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    4














    I don't think it is possible with cron alone because the syntax doesn't
    allow for "at 27th except on Sundays". It only allows
    for "either 27th or non-Sundays (or both)".



    I suggest to either change command.sh to immediately exit on non-Sundays
    or put that check into the cronjob:



    1 0 27 12 *   test $(date +%u) -ne 7   &&  command.sh


    At the shell, date +%u returns the day of week (1…7, 1 is Monday). In
    a cronjob we have to escape that % sign (%). The command will
    check whether the current day is a non-Sunday and only then execute
    command.sh.



    The cronjob will run on every Dec 27th at 00:01 o'clock,
    no matter what day of the week that is, but only for non-Sundays the
    command.sh gets executed because the previous test only succeeds
    for them.



    Note: I sometimes use https://crontab.guru to check my cronjob's
    timetables. It's quite handy.
    Your definition translates to “At
    00:01 on day-of-month 27 and on every day-of-week from Monday through
    Saturday in December.”     so it's quite the opposite of what you want.




    From the manpage:




    Note: The day of a command's execution can be specified by two fields
    — day of month, and day of week. If both fields are restricted (i.e.,
    aren't *), the command will be run when either field matches the
    current time. For example, 30 4 1,15 * 5 would cause a command to
    be run at 4:30 am on the 1st and 15th of each month, plus every
    Friday. One can, however, achieve the desired result by adding a test
    to the command (see the last example in EXAMPLE CRON FILE below).



    …



    # Run on every second Saturday of the month
    
0 4 8-14 * *    test $(date +%u) -eq 6 && echo "2nd Saturday"






    share|improve this answer




























      4














      I don't think it is possible with cron alone because the syntax doesn't
      allow for "at 27th except on Sundays". It only allows
      for "either 27th or non-Sundays (or both)".



      I suggest to either change command.sh to immediately exit on non-Sundays
      or put that check into the cronjob:



      1 0 27 12 *   test $(date +%u) -ne 7   &&  command.sh


      At the shell, date +%u returns the day of week (1…7, 1 is Monday). In
      a cronjob we have to escape that % sign (%). The command will
      check whether the current day is a non-Sunday and only then execute
      command.sh.



      The cronjob will run on every Dec 27th at 00:01 o'clock,
      no matter what day of the week that is, but only for non-Sundays the
      command.sh gets executed because the previous test only succeeds
      for them.



      Note: I sometimes use https://crontab.guru to check my cronjob's
      timetables. It's quite handy.
      Your definition translates to “At
      00:01 on day-of-month 27 and on every day-of-week from Monday through
      Saturday in December.”       so it's quite the opposite of what you want.




      From the manpage:




      Note: The day of a command's execution can be specified by two fields
      — day of month, and day of week. If both fields are restricted (i.e.,
      aren't *), the command will be run when either field matches the
      current time. For example, 30 4 1,15 * 5 would cause a command to
      be run at 4:30 am on the 1st and 15th of each month, plus every
      Friday. One can, however, achieve the desired result by adding a test
      to the command (see the last example in EXAMPLE CRON FILE below).



      …



      # Run on every second Saturday of the month
      
0 4 8-14 * *    test $(date +%u) -eq 6 && echo "2nd Saturday"






      share|improve this answer


























        4












        4








        4






        I don't think it is possible with cron alone because the syntax doesn't
        allow for "at 27th except on Sundays". It only allows
        for "either 27th or non-Sundays (or both)".



        I suggest to either change command.sh to immediately exit on non-Sundays
        or put that check into the cronjob:



        1 0 27 12 *   test $(date +%u) -ne 7   &&  command.sh


        At the shell, date +%u returns the day of week (1…7, 1 is Monday). In
        a cronjob we have to escape that % sign (%). The command will
        check whether the current day is a non-Sunday and only then execute
        command.sh.



        The cronjob will run on every Dec 27th at 00:01 o'clock,
        no matter what day of the week that is, but only for non-Sundays the
        command.sh gets executed because the previous test only succeeds
        for them.



        Note: I sometimes use https://crontab.guru to check my cronjob's
        timetables. It's quite handy.
        Your definition translates to “At
        00:01 on day-of-month 27 and on every day-of-week from Monday through
        Saturday in December.”         so it's quite the opposite of what you want.




        From the manpage:




        Note: The day of a command's execution can be specified by two fields
        — day of month, and day of week. If both fields are restricted (i.e.,
        aren't *), the command will be run when either field matches the
        current time. For example, 30 4 1,15 * 5 would cause a command to
        be run at 4:30 am on the 1st and 15th of each month, plus every
        Friday. One can, however, achieve the desired result by adding a test
        to the command (see the last example in EXAMPLE CRON FILE below).



        …



        # Run on every second Saturday of the month
        
0 4 8-14 * *    test $(date +%u) -eq 6 && echo "2nd Saturday"






        share|improve this answer














        I don't think it is possible with cron alone because the syntax doesn't
        allow for "at 27th except on Sundays". It only allows
        for "either 27th or non-Sundays (or both)".



        I suggest to either change command.sh to immediately exit on non-Sundays
        or put that check into the cronjob:



        1 0 27 12 *   test $(date +%u) -ne 7   &&  command.sh


        At the shell, date +%u returns the day of week (1…7, 1 is Monday). In
        a cronjob we have to escape that % sign (%). The command will
        check whether the current day is a non-Sunday and only then execute
        command.sh.



        The cronjob will run on every Dec 27th at 00:01 o'clock,
        no matter what day of the week that is, but only for non-Sundays the
        command.sh gets executed because the previous test only succeeds
        for them.



        Note: I sometimes use https://crontab.guru to check my cronjob's
        timetables. It's quite handy.
        Your definition translates to “At
        00:01 on day-of-month 27 and on every day-of-week from Monday through
        Saturday in December.”         so it's quite the opposite of what you want.




        From the manpage:




        Note: The day of a command's execution can be specified by two fields
        — day of month, and day of week. If both fields are restricted (i.e.,
        aren't *), the command will be run when either field matches the
        current time. For example, 30 4 1,15 * 5 would cause a command to
        be run at 4:30 am on the 1st and 15th of each month, plus every
        Friday. One can, however, achieve the desired result by adding a test
        to the command (see the last example in EXAMPLE CRON FILE below).



        …



        # Run on every second Saturday of the month
        
0 4 8-14 * *    test $(date +%u) -eq 6 && echo "2nd Saturday"







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 9 hours ago

























        answered 9 hours ago









        PerlDuck

        5,25911231




        5,25911231






























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