How to get value from file in sh? [duplicate]
This question already has an answer here:
How to read a file into a variable in shell?
6 answers
Difference between sh and bash
9 answers
Setup:
File a
contains:
22
File b
contains:
12
I have shell script 1.sh
:
#!/bin/sh
a=$(< a)
b=$(< b)
echo $(($a*$b)) > c
The script should get values from file a
and b
, multiply them *
, and save to file c
.
However after setting permission $ chmod a+rx 1.sh
and running it $ ./1.sh
it returns an error:
./1.sh: 5: ./1.sh: arithmetic expression: expecting primary: "*"
This error occurs because the variables $a
and $b
doesn't get value form files a
and b
.
- If I
echo $a
andecho $b
it returns nothing; - If I define
a=22
andb=12
values in the script it works; - I also tried other ways of getting contents of files like
a=$(< 'a')
,a=$(< "a")
,a=$(< "~/a")
, and evena=$(< cat a)
. None of those worked.
Plot Twist:
However, if I change shebang line to #!/bin/bash
so that Bash shell is used - it works.
Question:
How to properly get data from file in sh?
bash unix sh
marked as duplicate by Benjamin W., not2qubit, tripleee
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Nov 23 at 5:18
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
How to read a file into a variable in shell?
6 answers
Difference between sh and bash
9 answers
Setup:
File a
contains:
22
File b
contains:
12
I have shell script 1.sh
:
#!/bin/sh
a=$(< a)
b=$(< b)
echo $(($a*$b)) > c
The script should get values from file a
and b
, multiply them *
, and save to file c
.
However after setting permission $ chmod a+rx 1.sh
and running it $ ./1.sh
it returns an error:
./1.sh: 5: ./1.sh: arithmetic expression: expecting primary: "*"
This error occurs because the variables $a
and $b
doesn't get value form files a
and b
.
- If I
echo $a
andecho $b
it returns nothing; - If I define
a=22
andb=12
values in the script it works; - I also tried other ways of getting contents of files like
a=$(< 'a')
,a=$(< "a")
,a=$(< "~/a")
, and evena=$(< cat a)
. None of those worked.
Plot Twist:
However, if I change shebang line to #!/bin/bash
so that Bash shell is used - it works.
Question:
How to properly get data from file in sh?
bash unix sh
marked as duplicate by Benjamin W., not2qubit, tripleee
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Nov 23 at 5:18
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
Add output ofhexdump -C a
andhexdump -C b
to your question.
– Cyrus
Nov 22 at 18:41
$(< file)
is a Bash extension. For POSIX sh,$(cat file)
instead.
– Benjamin W.
Nov 22 at 19:01
shellcheck.net would tell you "Warning (SC2039): In POSIX sh, $(<file) to read files is undefined." if you used the#!/bin/sh
shebang.
– Benjamin W.
Nov 22 at 19:02
add a comment |
This question already has an answer here:
How to read a file into a variable in shell?
6 answers
Difference between sh and bash
9 answers
Setup:
File a
contains:
22
File b
contains:
12
I have shell script 1.sh
:
#!/bin/sh
a=$(< a)
b=$(< b)
echo $(($a*$b)) > c
The script should get values from file a
and b
, multiply them *
, and save to file c
.
However after setting permission $ chmod a+rx 1.sh
and running it $ ./1.sh
it returns an error:
./1.sh: 5: ./1.sh: arithmetic expression: expecting primary: "*"
This error occurs because the variables $a
and $b
doesn't get value form files a
and b
.
- If I
echo $a
andecho $b
it returns nothing; - If I define
a=22
andb=12
values in the script it works; - I also tried other ways of getting contents of files like
a=$(< 'a')
,a=$(< "a")
,a=$(< "~/a")
, and evena=$(< cat a)
. None of those worked.
Plot Twist:
However, if I change shebang line to #!/bin/bash
so that Bash shell is used - it works.
Question:
How to properly get data from file in sh?
bash unix sh
This question already has an answer here:
How to read a file into a variable in shell?
6 answers
Difference between sh and bash
9 answers
Setup:
File a
contains:
22
File b
contains:
12
I have shell script 1.sh
:
#!/bin/sh
a=$(< a)
b=$(< b)
echo $(($a*$b)) > c
The script should get values from file a
and b
, multiply them *
, and save to file c
.
However after setting permission $ chmod a+rx 1.sh
and running it $ ./1.sh
it returns an error:
./1.sh: 5: ./1.sh: arithmetic expression: expecting primary: "*"
This error occurs because the variables $a
and $b
doesn't get value form files a
and b
.
- If I
echo $a
andecho $b
it returns nothing; - If I define
a=22
andb=12
values in the script it works; - I also tried other ways of getting contents of files like
a=$(< 'a')
,a=$(< "a")
,a=$(< "~/a")
, and evena=$(< cat a)
. None of those worked.
Plot Twist:
However, if I change shebang line to #!/bin/bash
so that Bash shell is used - it works.
Question:
How to properly get data from file in sh?
This question already has an answer here:
How to read a file into a variable in shell?
6 answers
Difference between sh and bash
9 answers
bash unix sh
bash unix sh
asked Nov 22 at 18:37
Artūrs Laizāns
113
113
marked as duplicate by Benjamin W., not2qubit, tripleee
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Nov 23 at 5:18
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Benjamin W., not2qubit, tripleee
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Nov 23 at 5:18
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
Add output ofhexdump -C a
andhexdump -C b
to your question.
– Cyrus
Nov 22 at 18:41
$(< file)
is a Bash extension. For POSIX sh,$(cat file)
instead.
– Benjamin W.
Nov 22 at 19:01
shellcheck.net would tell you "Warning (SC2039): In POSIX sh, $(<file) to read files is undefined." if you used the#!/bin/sh
shebang.
– Benjamin W.
Nov 22 at 19:02
add a comment |
Add output ofhexdump -C a
andhexdump -C b
to your question.
– Cyrus
Nov 22 at 18:41
$(< file)
is a Bash extension. For POSIX sh,$(cat file)
instead.
– Benjamin W.
Nov 22 at 19:01
shellcheck.net would tell you "Warning (SC2039): In POSIX sh, $(<file) to read files is undefined." if you used the#!/bin/sh
shebang.
– Benjamin W.
Nov 22 at 19:02
Add output of
hexdump -C a
and hexdump -C b
to your question.– Cyrus
Nov 22 at 18:41
Add output of
hexdump -C a
and hexdump -C b
to your question.– Cyrus
Nov 22 at 18:41
$(< file)
is a Bash extension. For POSIX sh, $(cat file)
instead.– Benjamin W.
Nov 22 at 19:01
$(< file)
is a Bash extension. For POSIX sh, $(cat file)
instead.– Benjamin W.
Nov 22 at 19:01
shellcheck.net would tell you "Warning (SC2039): In POSIX sh, $(<file) to read files is undefined." if you used the
#!/bin/sh
shebang.– Benjamin W.
Nov 22 at 19:02
shellcheck.net would tell you "Warning (SC2039): In POSIX sh, $(<file) to read files is undefined." if you used the
#!/bin/sh
shebang.– Benjamin W.
Nov 22 at 19:02
add a comment |
3 Answers
3
active
oldest
votes
Ignore everything from file a and b but numbers:
#!/bin/sh
a=$(tr -cd 0-9 < a)
b=$(tr -cd 0-9 < b)
echo $(($a*$b))
See: man tr
Could also do justecho $((a*b))
.
– Benjamin W.
Nov 22 at 19:12
add a comment |
If you're looking for "true" Bourne-Shell compatibility, as opposed to Bash's emulation, then you have to go old school:
#!/bin/sh
a=`cat a`
b=`cat b`
expr $a * $b > c
I tried your original example under #!/bin/sh
on both macOS and Linux (FC26), and it behaved properly, assuming a
and b
had UNIX line-endings. If that can't be guaranteed, and you need to run under #!/bin/sh
(as emulated by bash
), then something like this will work:
#!/bin/sh
a=$(<a)
b=$(<b)
echo $(( ${a%%[^0-9]*} * ${b%%[^0-9]*} )) > c
1
Even the most ancient shells support command substitution with$(...)
instead of backticks. You have to go back many decades to find one that doesn't. POSIX definitely supports it. On the other hand, even when/bin/sh
is Bash, it does not support$(<a)
.
– Benjamin W.
Nov 23 at 3:16
To your first point, try /sbin/sh on Solaris 2.10. To your second point, try /bin/sh on Fedora 26.
– DjPadz
Nov 23 at 3:33
add a comment |
There are many ways. One obvious way is to pipe in a sub-process by Command Substitution:
A=$(cat fileA.txt) # 22
B=$(cat fileB.txt) # 12
echo $((A*B))
# <do it in your head!>
If there are any other problems with multiple lines, you need to look into how to use the Bash variable $IFS
(Internal File Separator). Usually IFS
is defined by: IFS=$' tn'
, so if you need to be able to reliably read lines endings from both Windows and Linux EOL's you may need to modify it.
ADDENDUM:
Process Substitution
Bash, Zsh, and AT&T ksh{88,93} (but not pdksh/mksh) support process
substitution. Process substitution isn't specified by POSIX. You may
use NamedPipes to accomplish the same things. Coprocesses can also do
everything process substitutions can, and are slightly more portable
(though the syntax for using them is not).
This also means that most Android OS does not allow process substitution, since their shells are most often based on mksh.
From man bash
:
Process Substitution
Process substitution allows a process's input or output to be referred to using a filename. It takes the form of <(list) or >(list). The
process list is run asynchronously, and its input or output appears as a filename. This filename is passed as an argument to the current
command as the result of the expansion. If the >(list) form is used, writing to the file will provide input for list. If the <(list) form
is used, the file passed as an argument should be read to obtain the output of list. Process substitution is supported on systems that sup-
port named pipes (FIFOs) or the /dev/fd method of naming open files.
When available, process substitution is performed simultaneously with parameter and variable expansion, command substitution, and arithmetic
expansion.
Notice that process substitution (<(...)
) isn't the same as command substitution ($(...)
).
– Benjamin W.
Nov 23 at 3:10
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Ignore everything from file a and b but numbers:
#!/bin/sh
a=$(tr -cd 0-9 < a)
b=$(tr -cd 0-9 < b)
echo $(($a*$b))
See: man tr
Could also do justecho $((a*b))
.
– Benjamin W.
Nov 22 at 19:12
add a comment |
Ignore everything from file a and b but numbers:
#!/bin/sh
a=$(tr -cd 0-9 < a)
b=$(tr -cd 0-9 < b)
echo $(($a*$b))
See: man tr
Could also do justecho $((a*b))
.
– Benjamin W.
Nov 22 at 19:12
add a comment |
Ignore everything from file a and b but numbers:
#!/bin/sh
a=$(tr -cd 0-9 < a)
b=$(tr -cd 0-9 < b)
echo $(($a*$b))
See: man tr
Ignore everything from file a and b but numbers:
#!/bin/sh
a=$(tr -cd 0-9 < a)
b=$(tr -cd 0-9 < b)
echo $(($a*$b))
See: man tr
edited Nov 22 at 18:51
answered Nov 22 at 18:45
Cyrus
45.1k43676
45.1k43676
Could also do justecho $((a*b))
.
– Benjamin W.
Nov 22 at 19:12
add a comment |
Could also do justecho $((a*b))
.
– Benjamin W.
Nov 22 at 19:12
Could also do just
echo $((a*b))
.– Benjamin W.
Nov 22 at 19:12
Could also do just
echo $((a*b))
.– Benjamin W.
Nov 22 at 19:12
add a comment |
If you're looking for "true" Bourne-Shell compatibility, as opposed to Bash's emulation, then you have to go old school:
#!/bin/sh
a=`cat a`
b=`cat b`
expr $a * $b > c
I tried your original example under #!/bin/sh
on both macOS and Linux (FC26), and it behaved properly, assuming a
and b
had UNIX line-endings. If that can't be guaranteed, and you need to run under #!/bin/sh
(as emulated by bash
), then something like this will work:
#!/bin/sh
a=$(<a)
b=$(<b)
echo $(( ${a%%[^0-9]*} * ${b%%[^0-9]*} )) > c
1
Even the most ancient shells support command substitution with$(...)
instead of backticks. You have to go back many decades to find one that doesn't. POSIX definitely supports it. On the other hand, even when/bin/sh
is Bash, it does not support$(<a)
.
– Benjamin W.
Nov 23 at 3:16
To your first point, try /sbin/sh on Solaris 2.10. To your second point, try /bin/sh on Fedora 26.
– DjPadz
Nov 23 at 3:33
add a comment |
If you're looking for "true" Bourne-Shell compatibility, as opposed to Bash's emulation, then you have to go old school:
#!/bin/sh
a=`cat a`
b=`cat b`
expr $a * $b > c
I tried your original example under #!/bin/sh
on both macOS and Linux (FC26), and it behaved properly, assuming a
and b
had UNIX line-endings. If that can't be guaranteed, and you need to run under #!/bin/sh
(as emulated by bash
), then something like this will work:
#!/bin/sh
a=$(<a)
b=$(<b)
echo $(( ${a%%[^0-9]*} * ${b%%[^0-9]*} )) > c
1
Even the most ancient shells support command substitution with$(...)
instead of backticks. You have to go back many decades to find one that doesn't. POSIX definitely supports it. On the other hand, even when/bin/sh
is Bash, it does not support$(<a)
.
– Benjamin W.
Nov 23 at 3:16
To your first point, try /sbin/sh on Solaris 2.10. To your second point, try /bin/sh on Fedora 26.
– DjPadz
Nov 23 at 3:33
add a comment |
If you're looking for "true" Bourne-Shell compatibility, as opposed to Bash's emulation, then you have to go old school:
#!/bin/sh
a=`cat a`
b=`cat b`
expr $a * $b > c
I tried your original example under #!/bin/sh
on both macOS and Linux (FC26), and it behaved properly, assuming a
and b
had UNIX line-endings. If that can't be guaranteed, and you need to run under #!/bin/sh
(as emulated by bash
), then something like this will work:
#!/bin/sh
a=$(<a)
b=$(<b)
echo $(( ${a%%[^0-9]*} * ${b%%[^0-9]*} )) > c
If you're looking for "true" Bourne-Shell compatibility, as opposed to Bash's emulation, then you have to go old school:
#!/bin/sh
a=`cat a`
b=`cat b`
expr $a * $b > c
I tried your original example under #!/bin/sh
on both macOS and Linux (FC26), and it behaved properly, assuming a
and b
had UNIX line-endings. If that can't be guaranteed, and you need to run under #!/bin/sh
(as emulated by bash
), then something like this will work:
#!/bin/sh
a=$(<a)
b=$(<b)
echo $(( ${a%%[^0-9]*} * ${b%%[^0-9]*} )) > c
edited Nov 22 at 19:29
answered Nov 22 at 19:23
DjPadz
3614
3614
1
Even the most ancient shells support command substitution with$(...)
instead of backticks. You have to go back many decades to find one that doesn't. POSIX definitely supports it. On the other hand, even when/bin/sh
is Bash, it does not support$(<a)
.
– Benjamin W.
Nov 23 at 3:16
To your first point, try /sbin/sh on Solaris 2.10. To your second point, try /bin/sh on Fedora 26.
– DjPadz
Nov 23 at 3:33
add a comment |
1
Even the most ancient shells support command substitution with$(...)
instead of backticks. You have to go back many decades to find one that doesn't. POSIX definitely supports it. On the other hand, even when/bin/sh
is Bash, it does not support$(<a)
.
– Benjamin W.
Nov 23 at 3:16
To your first point, try /sbin/sh on Solaris 2.10. To your second point, try /bin/sh on Fedora 26.
– DjPadz
Nov 23 at 3:33
1
1
Even the most ancient shells support command substitution with
$(...)
instead of backticks. You have to go back many decades to find one that doesn't. POSIX definitely supports it. On the other hand, even when /bin/sh
is Bash, it does not support $(<a)
.– Benjamin W.
Nov 23 at 3:16
Even the most ancient shells support command substitution with
$(...)
instead of backticks. You have to go back many decades to find one that doesn't. POSIX definitely supports it. On the other hand, even when /bin/sh
is Bash, it does not support $(<a)
.– Benjamin W.
Nov 23 at 3:16
To your first point, try /sbin/sh on Solaris 2.10. To your second point, try /bin/sh on Fedora 26.
– DjPadz
Nov 23 at 3:33
To your first point, try /sbin/sh on Solaris 2.10. To your second point, try /bin/sh on Fedora 26.
– DjPadz
Nov 23 at 3:33
add a comment |
There are many ways. One obvious way is to pipe in a sub-process by Command Substitution:
A=$(cat fileA.txt) # 22
B=$(cat fileB.txt) # 12
echo $((A*B))
# <do it in your head!>
If there are any other problems with multiple lines, you need to look into how to use the Bash variable $IFS
(Internal File Separator). Usually IFS
is defined by: IFS=$' tn'
, so if you need to be able to reliably read lines endings from both Windows and Linux EOL's you may need to modify it.
ADDENDUM:
Process Substitution
Bash, Zsh, and AT&T ksh{88,93} (but not pdksh/mksh) support process
substitution. Process substitution isn't specified by POSIX. You may
use NamedPipes to accomplish the same things. Coprocesses can also do
everything process substitutions can, and are slightly more portable
(though the syntax for using them is not).
This also means that most Android OS does not allow process substitution, since their shells are most often based on mksh.
From man bash
:
Process Substitution
Process substitution allows a process's input or output to be referred to using a filename. It takes the form of <(list) or >(list). The
process list is run asynchronously, and its input or output appears as a filename. This filename is passed as an argument to the current
command as the result of the expansion. If the >(list) form is used, writing to the file will provide input for list. If the <(list) form
is used, the file passed as an argument should be read to obtain the output of list. Process substitution is supported on systems that sup-
port named pipes (FIFOs) or the /dev/fd method of naming open files.
When available, process substitution is performed simultaneously with parameter and variable expansion, command substitution, and arithmetic
expansion.
Notice that process substitution (<(...)
) isn't the same as command substitution ($(...)
).
– Benjamin W.
Nov 23 at 3:10
add a comment |
There are many ways. One obvious way is to pipe in a sub-process by Command Substitution:
A=$(cat fileA.txt) # 22
B=$(cat fileB.txt) # 12
echo $((A*B))
# <do it in your head!>
If there are any other problems with multiple lines, you need to look into how to use the Bash variable $IFS
(Internal File Separator). Usually IFS
is defined by: IFS=$' tn'
, so if you need to be able to reliably read lines endings from both Windows and Linux EOL's you may need to modify it.
ADDENDUM:
Process Substitution
Bash, Zsh, and AT&T ksh{88,93} (but not pdksh/mksh) support process
substitution. Process substitution isn't specified by POSIX. You may
use NamedPipes to accomplish the same things. Coprocesses can also do
everything process substitutions can, and are slightly more portable
(though the syntax for using them is not).
This also means that most Android OS does not allow process substitution, since their shells are most often based on mksh.
From man bash
:
Process Substitution
Process substitution allows a process's input or output to be referred to using a filename. It takes the form of <(list) or >(list). The
process list is run asynchronously, and its input or output appears as a filename. This filename is passed as an argument to the current
command as the result of the expansion. If the >(list) form is used, writing to the file will provide input for list. If the <(list) form
is used, the file passed as an argument should be read to obtain the output of list. Process substitution is supported on systems that sup-
port named pipes (FIFOs) or the /dev/fd method of naming open files.
When available, process substitution is performed simultaneously with parameter and variable expansion, command substitution, and arithmetic
expansion.
Notice that process substitution (<(...)
) isn't the same as command substitution ($(...)
).
– Benjamin W.
Nov 23 at 3:10
add a comment |
There are many ways. One obvious way is to pipe in a sub-process by Command Substitution:
A=$(cat fileA.txt) # 22
B=$(cat fileB.txt) # 12
echo $((A*B))
# <do it in your head!>
If there are any other problems with multiple lines, you need to look into how to use the Bash variable $IFS
(Internal File Separator). Usually IFS
is defined by: IFS=$' tn'
, so if you need to be able to reliably read lines endings from both Windows and Linux EOL's you may need to modify it.
ADDENDUM:
Process Substitution
Bash, Zsh, and AT&T ksh{88,93} (but not pdksh/mksh) support process
substitution. Process substitution isn't specified by POSIX. You may
use NamedPipes to accomplish the same things. Coprocesses can also do
everything process substitutions can, and are slightly more portable
(though the syntax for using them is not).
This also means that most Android OS does not allow process substitution, since their shells are most often based on mksh.
From man bash
:
Process Substitution
Process substitution allows a process's input or output to be referred to using a filename. It takes the form of <(list) or >(list). The
process list is run asynchronously, and its input or output appears as a filename. This filename is passed as an argument to the current
command as the result of the expansion. If the >(list) form is used, writing to the file will provide input for list. If the <(list) form
is used, the file passed as an argument should be read to obtain the output of list. Process substitution is supported on systems that sup-
port named pipes (FIFOs) or the /dev/fd method of naming open files.
When available, process substitution is performed simultaneously with parameter and variable expansion, command substitution, and arithmetic
expansion.
There are many ways. One obvious way is to pipe in a sub-process by Command Substitution:
A=$(cat fileA.txt) # 22
B=$(cat fileB.txt) # 12
echo $((A*B))
# <do it in your head!>
If there are any other problems with multiple lines, you need to look into how to use the Bash variable $IFS
(Internal File Separator). Usually IFS
is defined by: IFS=$' tn'
, so if you need to be able to reliably read lines endings from both Windows and Linux EOL's you may need to modify it.
ADDENDUM:
Process Substitution
Bash, Zsh, and AT&T ksh{88,93} (but not pdksh/mksh) support process
substitution. Process substitution isn't specified by POSIX. You may
use NamedPipes to accomplish the same things. Coprocesses can also do
everything process substitutions can, and are slightly more portable
(though the syntax for using them is not).
This also means that most Android OS does not allow process substitution, since their shells are most often based on mksh.
From man bash
:
Process Substitution
Process substitution allows a process's input or output to be referred to using a filename. It takes the form of <(list) or >(list). The
process list is run asynchronously, and its input or output appears as a filename. This filename is passed as an argument to the current
command as the result of the expansion. If the >(list) form is used, writing to the file will provide input for list. If the <(list) form
is used, the file passed as an argument should be read to obtain the output of list. Process substitution is supported on systems that sup-
port named pipes (FIFOs) or the /dev/fd method of naming open files.
When available, process substitution is performed simultaneously with parameter and variable expansion, command substitution, and arithmetic
expansion.
edited Dec 1 at 9:07
answered Nov 22 at 18:44
not2qubit
4,04813260
4,04813260
Notice that process substitution (<(...)
) isn't the same as command substitution ($(...)
).
– Benjamin W.
Nov 23 at 3:10
add a comment |
Notice that process substitution (<(...)
) isn't the same as command substitution ($(...)
).
– Benjamin W.
Nov 23 at 3:10
Notice that process substitution (
<(...)
) isn't the same as command substitution ($(...)
).– Benjamin W.
Nov 23 at 3:10
Notice that process substitution (
<(...)
) isn't the same as command substitution ($(...)
).– Benjamin W.
Nov 23 at 3:10
add a comment |
Add output of
hexdump -C a
andhexdump -C b
to your question.– Cyrus
Nov 22 at 18:41
$(< file)
is a Bash extension. For POSIX sh,$(cat file)
instead.– Benjamin W.
Nov 22 at 19:01
shellcheck.net would tell you "Warning (SC2039): In POSIX sh, $(<file) to read files is undefined." if you used the
#!/bin/sh
shebang.– Benjamin W.
Nov 22 at 19:02