pandas convert lists in multiple columns within DataFrame to separate columns











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I am trying to convert a list within multiple columns of a pandas DataFrame into separate columns.



Say, I have a dataframe like this:



           0          1
0 [1, 2, 3] [4, 5, 6]
1 [1, 2, 3] [4, 5, 6]
2 [1, 2, 3] [4, 5, 6]


And would like to convert it to something like this:



   0  1  2  0  1  2
0 1 2 3 4 5 6
1 1 2 3 4 5 6
2 1 2 3 4 5 6


I have managed to do this in a loop. However, I would like to do this in fewer lines.
My code snippet so far is as follows:



import pandas as pd

df = pd.DataFrame([[[1,2,3],[4,5,6]],[[1,2,3],[4,5,6]],[[1,2,3],[4,5,6]]])
output1 = df[0].apply(pd.Series)
output2 = df[1].apply(pd.Series)

output = pd.concat([output1, output2], axis=1)









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  • Are you sure you want that output? Duplicate column names are allowed but not particularly useful...
    – Jon Clements
    Nov 22 at 15:13










  • At this point I am not really worried about the duplicated column names. I would like to reduce it to one line instead of implementing what will be loop/concat structure once applied to a dataframe with more than two columns
    – Christian
    Nov 22 at 15:18















up vote
0
down vote

favorite












I am trying to convert a list within multiple columns of a pandas DataFrame into separate columns.



Say, I have a dataframe like this:



           0          1
0 [1, 2, 3] [4, 5, 6]
1 [1, 2, 3] [4, 5, 6]
2 [1, 2, 3] [4, 5, 6]


And would like to convert it to something like this:



   0  1  2  0  1  2
0 1 2 3 4 5 6
1 1 2 3 4 5 6
2 1 2 3 4 5 6


I have managed to do this in a loop. However, I would like to do this in fewer lines.
My code snippet so far is as follows:



import pandas as pd

df = pd.DataFrame([[[1,2,3],[4,5,6]],[[1,2,3],[4,5,6]],[[1,2,3],[4,5,6]]])
output1 = df[0].apply(pd.Series)
output2 = df[1].apply(pd.Series)

output = pd.concat([output1, output2], axis=1)









share|improve this question






















  • Are you sure you want that output? Duplicate column names are allowed but not particularly useful...
    – Jon Clements
    Nov 22 at 15:13










  • At this point I am not really worried about the duplicated column names. I would like to reduce it to one line instead of implementing what will be loop/concat structure once applied to a dataframe with more than two columns
    – Christian
    Nov 22 at 15:18













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am trying to convert a list within multiple columns of a pandas DataFrame into separate columns.



Say, I have a dataframe like this:



           0          1
0 [1, 2, 3] [4, 5, 6]
1 [1, 2, 3] [4, 5, 6]
2 [1, 2, 3] [4, 5, 6]


And would like to convert it to something like this:



   0  1  2  0  1  2
0 1 2 3 4 5 6
1 1 2 3 4 5 6
2 1 2 3 4 5 6


I have managed to do this in a loop. However, I would like to do this in fewer lines.
My code snippet so far is as follows:



import pandas as pd

df = pd.DataFrame([[[1,2,3],[4,5,6]],[[1,2,3],[4,5,6]],[[1,2,3],[4,5,6]]])
output1 = df[0].apply(pd.Series)
output2 = df[1].apply(pd.Series)

output = pd.concat([output1, output2], axis=1)









share|improve this question













I am trying to convert a list within multiple columns of a pandas DataFrame into separate columns.



Say, I have a dataframe like this:



           0          1
0 [1, 2, 3] [4, 5, 6]
1 [1, 2, 3] [4, 5, 6]
2 [1, 2, 3] [4, 5, 6]


And would like to convert it to something like this:



   0  1  2  0  1  2
0 1 2 3 4 5 6
1 1 2 3 4 5 6
2 1 2 3 4 5 6


I have managed to do this in a loop. However, I would like to do this in fewer lines.
My code snippet so far is as follows:



import pandas as pd

df = pd.DataFrame([[[1,2,3],[4,5,6]],[[1,2,3],[4,5,6]],[[1,2,3],[4,5,6]]])
output1 = df[0].apply(pd.Series)
output2 = df[1].apply(pd.Series)

output = pd.concat([output1, output2], axis=1)






pandas dataframe apply






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share|improve this question




share|improve this question










asked Nov 22 at 15:08









Christian

14518




14518












  • Are you sure you want that output? Duplicate column names are allowed but not particularly useful...
    – Jon Clements
    Nov 22 at 15:13










  • At this point I am not really worried about the duplicated column names. I would like to reduce it to one line instead of implementing what will be loop/concat structure once applied to a dataframe with more than two columns
    – Christian
    Nov 22 at 15:18


















  • Are you sure you want that output? Duplicate column names are allowed but not particularly useful...
    – Jon Clements
    Nov 22 at 15:13










  • At this point I am not really worried about the duplicated column names. I would like to reduce it to one line instead of implementing what will be loop/concat structure once applied to a dataframe with more than two columns
    – Christian
    Nov 22 at 15:18
















Are you sure you want that output? Duplicate column names are allowed but not particularly useful...
– Jon Clements
Nov 22 at 15:13




Are you sure you want that output? Duplicate column names are allowed but not particularly useful...
– Jon Clements
Nov 22 at 15:13












At this point I am not really worried about the duplicated column names. I would like to reduce it to one line instead of implementing what will be loop/concat structure once applied to a dataframe with more than two columns
– Christian
Nov 22 at 15:18




At this point I am not really worried about the duplicated column names. I would like to reduce it to one line instead of implementing what will be loop/concat structure once applied to a dataframe with more than two columns
– Christian
Nov 22 at 15:18












2 Answers
2






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oldest

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up vote
2
down vote



accepted










If you don't care about the column names you could do:



>>> df.apply(np.hstack, axis=1).apply(pd.Series)
0 1 2 3 4 5
0 1 2 3 4 5 6
1 1 2 3 4 5 6
2 1 2 3 4 5 6





share|improve this answer




























    up vote
    1
    down vote













    Using sum



    pd.DataFrame(df.sum(1).tolist())
    0 1 2 3 4 5
    0 1 2 3 4 5 6
    1 1 2 3 4 5 6
    2 1 2 3 4 5 6





    share|improve this answer





















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      2
      down vote



      accepted










      If you don't care about the column names you could do:



      >>> df.apply(np.hstack, axis=1).apply(pd.Series)
      0 1 2 3 4 5
      0 1 2 3 4 5 6
      1 1 2 3 4 5 6
      2 1 2 3 4 5 6





      share|improve this answer

























        up vote
        2
        down vote



        accepted










        If you don't care about the column names you could do:



        >>> df.apply(np.hstack, axis=1).apply(pd.Series)
        0 1 2 3 4 5
        0 1 2 3 4 5 6
        1 1 2 3 4 5 6
        2 1 2 3 4 5 6





        share|improve this answer























          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          If you don't care about the column names you could do:



          >>> df.apply(np.hstack, axis=1).apply(pd.Series)
          0 1 2 3 4 5
          0 1 2 3 4 5 6
          1 1 2 3 4 5 6
          2 1 2 3 4 5 6





          share|improve this answer












          If you don't care about the column names you could do:



          >>> df.apply(np.hstack, axis=1).apply(pd.Series)
          0 1 2 3 4 5
          0 1 2 3 4 5 6
          1 1 2 3 4 5 6
          2 1 2 3 4 5 6






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 at 15:34









          w-m

          5,9992233




          5,9992233
























              up vote
              1
              down vote













              Using sum



              pd.DataFrame(df.sum(1).tolist())
              0 1 2 3 4 5
              0 1 2 3 4 5 6
              1 1 2 3 4 5 6
              2 1 2 3 4 5 6





              share|improve this answer

























                up vote
                1
                down vote













                Using sum



                pd.DataFrame(df.sum(1).tolist())
                0 1 2 3 4 5
                0 1 2 3 4 5 6
                1 1 2 3 4 5 6
                2 1 2 3 4 5 6





                share|improve this answer























                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  Using sum



                  pd.DataFrame(df.sum(1).tolist())
                  0 1 2 3 4 5
                  0 1 2 3 4 5 6
                  1 1 2 3 4 5 6
                  2 1 2 3 4 5 6





                  share|improve this answer












                  Using sum



                  pd.DataFrame(df.sum(1).tolist())
                  0 1 2 3 4 5
                  0 1 2 3 4 5 6
                  1 1 2 3 4 5 6
                  2 1 2 3 4 5 6






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 22 at 15:50









                  W-B

                  97.1k73162




                  97.1k73162






























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