Qfyilyi

Need help with getting rid of half of a string in android studio. The string is:

final String strOrigin = String.valueOf(origin).trim();

The value that is returned is;

"Point{type=Point, bbox=null, coordinates=[27.993726079654873,-26.14686805145815]}"

I want to be left with only the numbers of that, in the String. I have tried;

strOrigin.replace("Point{type=Point, bbox=null, coordinates=", "");

But it isn't working. Any help would be appreciated.

In Java strings are immutable. You must assign the result to a new string:

String strResult = strOrigin.replace("Point{type=Point, bbox=null, coordinates=", "");

Maybe you forgot that replace() returns the result and you must assign it to a string:

String strOrigin = "Point{type=Point, bbox=null, coordinates=[27.993726079654873,-26.14686805145815]}";

String str = strOrigin

        .replace("Point{type=Point, bbox=null, coordinates=", "")

        .replace("}","");

System.out.println(str);

will print:

[27.993726079654873,-26.14686805145815]

Make your life simpler by just getting the coordinates:

final String strOigin = origin.coordinates().stream()

    .map(String::valueOf)

    .collect(Collectors.joining(",","{","}"));

Or, if you're stuck on java 7:

final String strOigin = String.format(

    "{%s,%s}",

    String.valueOf(origin.latitude()), 

    String.valueOf(origin.longitude())

);

This should do the trick

    String s="blabla coordinates=[27.993726079654873,-26.14686805145815] ";

    String requiredString = s.substring(s.indexOf("[") + 1, s.indexOf("]"));

will print:

27.993726079654873,-26.14686805145815

Than you can cast it to double or latlong format

Have a look at regular expressions, they allow you to define more flexible search patterns. In your example you only find the coordinates if the rest of the string matches the pattern exactly, but if you happen to get some other value of bbox, or even extra space it will not work. This will always match everything between a pair of square brackets:

String c = origin.replaceAll(".+?(\[.+?\]).+?", "$1");

http://www.vogella.com/tutorials/JavaRegularExpressions/article.html
https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html