Powershell Dynamic Menu Based on Mailbox Permission Entries











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I'm having trouble with creating a dynamic menu from mailbox permission entries in PowerShell. The below function gets a list of permission entries for the selected mailbox and outputs a table.



Function AuditSingleMailboxPermission($mbox) {
If ($mbox -like $null){
Write-Host "Please select the mailbox from the list below"
$mbox = SelectMailbox
}

$mboxPermissions = Get-MailboxPermission $mbox | where {$_.User -like "*@*"}
Return $mboxPermissions
}


The next function uses the output of the previous to build the menu.



Function SelectMailboxPermission($mbox) {
$rights = (AuditSingleMailboxPermission -mbox $mbox).User
Write-Host $rights
$menu = @{}
for ($i=1;$i -le $rights.count; $i++) {
Write-Host "$i. $($rights[$i-1])"
$menu.Add($i,($rights[$i-1]))
}
[int]$ans = Read-Host "Enter selection"
$selection = $menu.Item($ans)
Return $selection
}


The Write-Host $rights line shows the full username. However, the menu only returns the first letter of the username. This is a problem because the output of this function is used to remove user permissions on a mailbox. I can't figure this out for the life of me.










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  • Try $menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there
    – Theo
    Nov 22 at 14:11















up vote
1
down vote

favorite












I'm having trouble with creating a dynamic menu from mailbox permission entries in PowerShell. The below function gets a list of permission entries for the selected mailbox and outputs a table.



Function AuditSingleMailboxPermission($mbox) {
If ($mbox -like $null){
Write-Host "Please select the mailbox from the list below"
$mbox = SelectMailbox
}

$mboxPermissions = Get-MailboxPermission $mbox | where {$_.User -like "*@*"}
Return $mboxPermissions
}


The next function uses the output of the previous to build the menu.



Function SelectMailboxPermission($mbox) {
$rights = (AuditSingleMailboxPermission -mbox $mbox).User
Write-Host $rights
$menu = @{}
for ($i=1;$i -le $rights.count; $i++) {
Write-Host "$i. $($rights[$i-1])"
$menu.Add($i,($rights[$i-1]))
}
[int]$ans = Read-Host "Enter selection"
$selection = $menu.Item($ans)
Return $selection
}


The Write-Host $rights line shows the full username. However, the menu only returns the first letter of the username. This is a problem because the output of this function is used to remove user permissions on a mailbox. I can't figure this out for the life of me.










share|improve this question
























  • Try $menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there
    – Theo
    Nov 22 at 14:11













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I'm having trouble with creating a dynamic menu from mailbox permission entries in PowerShell. The below function gets a list of permission entries for the selected mailbox and outputs a table.



Function AuditSingleMailboxPermission($mbox) {
If ($mbox -like $null){
Write-Host "Please select the mailbox from the list below"
$mbox = SelectMailbox
}

$mboxPermissions = Get-MailboxPermission $mbox | where {$_.User -like "*@*"}
Return $mboxPermissions
}


The next function uses the output of the previous to build the menu.



Function SelectMailboxPermission($mbox) {
$rights = (AuditSingleMailboxPermission -mbox $mbox).User
Write-Host $rights
$menu = @{}
for ($i=1;$i -le $rights.count; $i++) {
Write-Host "$i. $($rights[$i-1])"
$menu.Add($i,($rights[$i-1]))
}
[int]$ans = Read-Host "Enter selection"
$selection = $menu.Item($ans)
Return $selection
}


The Write-Host $rights line shows the full username. However, the menu only returns the first letter of the username. This is a problem because the output of this function is used to remove user permissions on a mailbox. I can't figure this out for the life of me.










share|improve this question















I'm having trouble with creating a dynamic menu from mailbox permission entries in PowerShell. The below function gets a list of permission entries for the selected mailbox and outputs a table.



Function AuditSingleMailboxPermission($mbox) {
If ($mbox -like $null){
Write-Host "Please select the mailbox from the list below"
$mbox = SelectMailbox
}

$mboxPermissions = Get-MailboxPermission $mbox | where {$_.User -like "*@*"}
Return $mboxPermissions
}


The next function uses the output of the previous to build the menu.



Function SelectMailboxPermission($mbox) {
$rights = (AuditSingleMailboxPermission -mbox $mbox).User
Write-Host $rights
$menu = @{}
for ($i=1;$i -le $rights.count; $i++) {
Write-Host "$i. $($rights[$i-1])"
$menu.Add($i,($rights[$i-1]))
}
[int]$ans = Read-Host "Enter selection"
$selection = $menu.Item($ans)
Return $selection
}


The Write-Host $rights line shows the full username. However, the menu only returns the first letter of the username. This is a problem because the output of this function is used to remove user permissions on a mailbox. I can't figure this out for the life of me.







powershell






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edited Nov 22 at 14:05









Robert

4,0371251106




4,0371251106










asked Nov 22 at 13:59









OhSnapWord

102




102












  • Try $menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there
    – Theo
    Nov 22 at 14:11


















  • Try $menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there
    – Theo
    Nov 22 at 14:11
















Try $menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there
– Theo
Nov 22 at 14:11




Try $menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there
– Theo
Nov 22 at 14:11












1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.



Casting to Array should fix the issue:



$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User


Generic example:



PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F

PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO





share|improve this answer



















  • 1




    +1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use @(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of @(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
    – mklement0
    Nov 22 at 20:20













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1 Answer
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active

oldest

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1 Answer
1






active

oldest

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oldest

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active

oldest

votes








up vote
1
down vote



accepted










If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.



Casting to Array should fix the issue:



$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User


Generic example:



PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F

PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO





share|improve this answer



















  • 1




    +1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use @(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of @(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
    – mklement0
    Nov 22 at 20:20

















up vote
1
down vote



accepted










If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.



Casting to Array should fix the issue:



$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User


Generic example:



PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F

PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO





share|improve this answer



















  • 1




    +1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use @(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of @(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
    – mklement0
    Nov 22 at 20:20















up vote
1
down vote



accepted







up vote
1
down vote



accepted






If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.



Casting to Array should fix the issue:



$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User


Generic example:



PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F

PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO





share|improve this answer














If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.



Casting to Array should fix the issue:



$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User


Generic example:



PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F

PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 22 at 14:36

























answered Nov 22 at 14:31









Janne Tuukkanen

80329




80329








  • 1




    +1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use @(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of @(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
    – mklement0
    Nov 22 at 20:20
















  • 1




    +1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use @(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of @(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
    – mklement0
    Nov 22 at 20:20










1




1




+1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use @(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of @(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
– mklement0
Nov 22 at 20:20






+1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use @(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of @(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
– mklement0
Nov 22 at 20:20




















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