Python re.finditer error at special characters
I have code that loops through a list of strings, then loops through each occurrence of that string inside another string. This seems to work until it reaches a string that begins with a question mark (? I).
This is the code.
dtID = 0
for datum in sorted(datumList, key=operator.attrgetter('Sum'), reverse = True):
datum.ID = dtID
for foundDatum in re.finditer(datum.Name, text):
datumLocList.append(DatumLoc(dtID,foundDatum.start()))
dtID += 1
How can I solve this?
Traceback (most recent call last):
File "C:UserstristDocumentsPythonThe CompressorThe Compressor.py", line 97, in <module>
compress()
File "C:UserstristDocumentsPythonThe CompressorThe Compressor.py", line 73, in compress
for foundDatum in re.finditer(datum.Name, text):
File "C:Program FilesPython37libre.py", line 230, in finditer
return _compile(pattern, flags).finditer(string)
File "C:Program FilesPython37libre.py", line 286, in _compile
p = sre_compile.compile(pattern, flags)
File "C:Program FilesPython37libsre_compile.py", line 764, in compile
p = sre_parse.parse(p, flags)
File "C:Program FilesPython37libsre_parse.py", line 930, in parse
p = _parse_sub(source, pattern, flags & SRE_FLAG_VERBOSE, 0)
File "C:Program FilesPython37libsre_parse.py", line 426, in _parse_sub
not nested and not items))
File "C:Program FilesPython37libsre_parse.py", line 651, in _parse
source.tell() - here + len(this))
re.error: nothing to repeat at position 0
python-3.x
asked Nov 23 '18 at 11:42
Tristan KingTristan King
659
add a comment |
I have code that loops through a list of strings, then loops through each occurrence of that string inside another string. This seems to work until it reaches a string that begins with a question mark (? I).
This is the code.
dtID = 0
for datum in sorted(datumList, key=operator.attrgetter('Sum'), reverse = True):
datum.ID = dtID
for foundDatum in re.finditer(datum.Name, text):
datumLocList.append(DatumLoc(dtID,foundDatum.start()))
dtID += 1
How can I solve this?
Traceback (most recent call last):
File "C:UserstristDocumentsPythonThe CompressorThe Compressor.py", line 97, in <module>
compress()
File "C:UserstristDocumentsPythonThe CompressorThe Compressor.py", line 73, in compress
for foundDatum in re.finditer(datum.Name, text):
File "C:Program FilesPython37libre.py", line 230, in finditer
return _compile(pattern, flags).finditer(string)
File "C:Program FilesPython37libre.py", line 286, in _compile
p = sre_compile.compile(pattern, flags)
File "C:Program FilesPython37libsre_compile.py", line 764, in compile
p = sre_parse.parse(p, flags)
File "C:Program FilesPython37libsre_parse.py", line 930, in parse
p = _parse_sub(source, pattern, flags & SRE_FLAG_VERBOSE, 0)
File "C:Program FilesPython37libsre_parse.py", line 426, in _parse_sub
not nested and not items))
File "C:Program FilesPython37libsre_parse.py", line 651, in _parse
source.tell() - here + len(this))
re.error: nothing to repeat at position 0
python-3.x
asked Nov 23 '18 at 11:42
Tristan KingTristan King
659
add a comment |
I have code that loops through a list of strings, then loops through each occurrence of that string inside another string. This seems to work until it reaches a string that begins with a question mark (? I).
This is the code.
dtID = 0
for datum in sorted(datumList, key=operator.attrgetter('Sum'), reverse = True):
datum.ID = dtID
for foundDatum in re.finditer(datum.Name, text):
datumLocList.append(DatumLoc(dtID,foundDatum.start()))
dtID += 1
How can I solve this?
Traceback (most recent call last):
File "C:UserstristDocumentsPythonThe CompressorThe Compressor.py", line 97, in <module>
compress()
File "C:UserstristDocumentsPythonThe CompressorThe Compressor.py", line 73, in compress
for foundDatum in re.finditer(datum.Name, text):
File "C:Program FilesPython37libre.py", line 230, in finditer
return _compile(pattern, flags).finditer(string)
File "C:Program FilesPython37libre.py", line 286, in _compile
p = sre_compile.compile(pattern, flags)
File "C:Program FilesPython37libsre_compile.py", line 764, in compile
p = sre_parse.parse(p, flags)
File "C:Program FilesPython37libsre_parse.py", line 930, in parse
p = _parse_sub(source, pattern, flags & SRE_FLAG_VERBOSE, 0)
File "C:Program FilesPython37libsre_parse.py", line 426, in _parse_sub
not nested and not items))
File "C:Program FilesPython37libsre_parse.py", line 651, in _parse
source.tell() - here + len(this))
re.error: nothing to repeat at position 0
python-3.x
asked Nov 23 '18 at 11:42
Tristan KingTristan King
659
I have code that loops through a list of strings, then loops through each occurrence of that string inside another string. This seems to work until it reaches a string that begins with a question mark (? I).
This is the code.
dtID = 0
for datum in sorted(datumList, key=operator.attrgetter('Sum'), reverse = True):
datum.ID = dtID
for foundDatum in re.finditer(datum.Name, text):
datumLocList.append(DatumLoc(dtID,foundDatum.start()))
dtID += 1
How can I solve this?
Traceback (most recent call last):
File "C:UserstristDocumentsPythonThe CompressorThe Compressor.py", line 97, in <module>
compress()
File "C:UserstristDocumentsPythonThe CompressorThe Compressor.py", line 73, in compress
for foundDatum in re.finditer(datum.Name, text):
File "C:Program FilesPython37libre.py", line 230, in finditer
return _compile(pattern, flags).finditer(string)
File "C:Program FilesPython37libre.py", line 286, in _compile
p = sre_compile.compile(pattern, flags)
File "C:Program FilesPython37libsre_compile.py", line 764, in compile
p = sre_parse.parse(p, flags)
File "C:Program FilesPython37libsre_parse.py", line 930, in parse
p = _parse_sub(source, pattern, flags & SRE_FLAG_VERBOSE, 0)
File "C:Program FilesPython37libsre_parse.py", line 426, in _parse_sub
not nested and not items))
File "C:Program FilesPython37libsre_parse.py", line 651, in _parse
source.tell() - here + len(this))
re.error: nothing to repeat at position 0
python-3.x
python-3.x
asked Nov 23 '18 at 11:42
Tristan KingTristan King
659
asked Nov 23 '18 at 11:42
Tristan KingTristan King
659
asked Nov 23 '18 at 11:42
Tristan KingTristan King
659
asked Nov 23 '18 at 11:42
Tristan KingTristan King
659
asked Nov 23 '18 at 11:42
Tristan KingTristan King
659
659
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Your pattern string containing a question mark is being treated as a regular expression special character. The ? symbol attempts to match 0 or 1 repetitions of the preceding regular expression. Since in your string the ? is the first character, it is attempting to match 0 or 1 repetitions of the preceding regular expression, which is nothing: hence your 'nothing to repeat at position 0' error.
To avoid this you can use the re.escape() method which will escape all RE special characters in your pattern string.
for foundDatum in re.finditer(re.escape(datum.Name), text):
datumLocList.append(DatumLoc(dtID,foundDatum.start()))
See https://docs.python.org/3/library/re.html#re.escape
answered Nov 23 '18 at 12:04
Robbie DunnRobbie Dunn
864
Works great, thanks.
– Tristan King
Nov 23 '18 at 12:51
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your pattern string containing a question mark is being treated as a regular expression special character. The ? symbol attempts to match 0 or 1 repetitions of the preceding regular expression. Since in your string the ? is the first character, it is attempting to match 0 or 1 repetitions of the preceding regular expression, which is nothing: hence your 'nothing to repeat at position 0' error.
To avoid this you can use the re.escape() method which will escape all RE special characters in your pattern string.
for foundDatum in re.finditer(re.escape(datum.Name), text):
datumLocList.append(DatumLoc(dtID,foundDatum.start()))
See https://docs.python.org/3/library/re.html#re.escape
answered Nov 23 '18 at 12:04
Robbie DunnRobbie Dunn
864
Works great, thanks.
– Tristan King
Nov 23 '18 at 12:51
add a comment |
Your pattern string containing a question mark is being treated as a regular expression special character. The ? symbol attempts to match 0 or 1 repetitions of the preceding regular expression. Since in your string the ? is the first character, it is attempting to match 0 or 1 repetitions of the preceding regular expression, which is nothing: hence your 'nothing to repeat at position 0' error.
To avoid this you can use the re.escape() method which will escape all RE special characters in your pattern string.
for foundDatum in re.finditer(re.escape(datum.Name), text):
datumLocList.append(DatumLoc(dtID,foundDatum.start()))
See https://docs.python.org/3/library/re.html#re.escape
answered Nov 23 '18 at 12:04
Robbie DunnRobbie Dunn
864
Works great, thanks.
– Tristan King
Nov 23 '18 at 12:51
add a comment |
Your pattern string containing a question mark is being treated as a regular expression special character. The ? symbol attempts to match 0 or 1 repetitions of the preceding regular expression. Since in your string the ? is the first character, it is attempting to match 0 or 1 repetitions of the preceding regular expression, which is nothing: hence your 'nothing to repeat at position 0' error.
To avoid this you can use the re.escape() method which will escape all RE special characters in your pattern string.
for foundDatum in re.finditer(re.escape(datum.Name), text):
datumLocList.append(DatumLoc(dtID,foundDatum.start()))
See https://docs.python.org/3/library/re.html#re.escape
answered Nov 23 '18 at 12:04
Robbie DunnRobbie Dunn
864
Your pattern string containing a question mark is being treated as a regular expression special character. The ? symbol attempts to match 0 or 1 repetitions of the preceding regular expression. Since in your string the ? is the first character, it is attempting to match 0 or 1 repetitions of the preceding regular expression, which is nothing: hence your 'nothing to repeat at position 0' error.
To avoid this you can use the re.escape() method which will escape all RE special characters in your pattern string.
for foundDatum in re.finditer(re.escape(datum.Name), text):
datumLocList.append(DatumLoc(dtID,foundDatum.start()))
See https://docs.python.org/3/library/re.html#re.escape
answered Nov 23 '18 at 12:04
Robbie DunnRobbie Dunn
864
answered Nov 23 '18 at 12:04
Robbie DunnRobbie Dunn
864
answered Nov 23 '18 at 12:04
Robbie DunnRobbie Dunn
864
answered Nov 23 '18 at 12:04
Robbie DunnRobbie Dunn
864
864
Works great, thanks.
– Tristan King
Nov 23 '18 at 12:51
add a comment |
Works great, thanks.
– Tristan King
Nov 23 '18 at 12:51
Works great, thanks.
– Tristan King
Nov 23 '18 at 12:51
Works great, thanks.
– Tristan King
Nov 23 '18 at 12:51
add a comment |
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