Could I name a number in tikz?












5














I have been drawing some pictures using tikz, and am wondering if I can name a number.



For example, I pick a point $A$ with position angle $alpha=45degree$ on a circle, and a line going through that point with direction angle $beta=alpha+90degree=135degree$ (wich is perpendicular to the position vector).



Later I change the point $A$ to be $alpha=60degree$, and then $beta=150 degree$.



Now I change both angles manually. If I can name the first angle $alpha$ and the second angle $beta$, then I only need to change $alpha$: $beta$ will vary accordingly.



Is there a way to do this, naming a number? Thanks!










share|improve this question




















  • 2




    I didn't understand correctly. Can you add an example of what you want to achieve in the end but can't?
    – AndréC
    21 hours ago






  • 1




    Named numbers are called variables or constants. But named points may be named as nodes.
    – God Must Be Crazy
    20 hours ago
















5














I have been drawing some pictures using tikz, and am wondering if I can name a number.



For example, I pick a point $A$ with position angle $alpha=45degree$ on a circle, and a line going through that point with direction angle $beta=alpha+90degree=135degree$ (wich is perpendicular to the position vector).



Later I change the point $A$ to be $alpha=60degree$, and then $beta=150 degree$.



Now I change both angles manually. If I can name the first angle $alpha$ and the second angle $beta$, then I only need to change $alpha$: $beta$ will vary accordingly.



Is there a way to do this, naming a number? Thanks!










share|improve this question




















  • 2




    I didn't understand correctly. Can you add an example of what you want to achieve in the end but can't?
    – AndréC
    21 hours ago






  • 1




    Named numbers are called variables or constants. But named points may be named as nodes.
    – God Must Be Crazy
    20 hours ago














5












5








5







I have been drawing some pictures using tikz, and am wondering if I can name a number.



For example, I pick a point $A$ with position angle $alpha=45degree$ on a circle, and a line going through that point with direction angle $beta=alpha+90degree=135degree$ (wich is perpendicular to the position vector).



Later I change the point $A$ to be $alpha=60degree$, and then $beta=150 degree$.



Now I change both angles manually. If I can name the first angle $alpha$ and the second angle $beta$, then I only need to change $alpha$: $beta$ will vary accordingly.



Is there a way to do this, naming a number? Thanks!










share|improve this question















I have been drawing some pictures using tikz, and am wondering if I can name a number.



For example, I pick a point $A$ with position angle $alpha=45degree$ on a circle, and a line going through that point with direction angle $beta=alpha+90degree=135degree$ (wich is perpendicular to the position vector).



Later I change the point $A$ to be $alpha=60degree$, and then $beta=150 degree$.



Now I change both angles manually. If I can name the first angle $alpha$ and the second angle $beta$, then I only need to change $alpha$: $beta$ will vary accordingly.



Is there a way to do this, naming a number? Thanks!







tikz-pgf






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 19 hours ago









AboAmmar

32.7k22882




32.7k22882










asked 21 hours ago









Pengfei

1386




1386








  • 2




    I didn't understand correctly. Can you add an example of what you want to achieve in the end but can't?
    – AndréC
    21 hours ago






  • 1




    Named numbers are called variables or constants. But named points may be named as nodes.
    – God Must Be Crazy
    20 hours ago














  • 2




    I didn't understand correctly. Can you add an example of what you want to achieve in the end but can't?
    – AndréC
    21 hours ago






  • 1




    Named numbers are called variables or constants. But named points may be named as nodes.
    – God Must Be Crazy
    20 hours ago








2




2




I didn't understand correctly. Can you add an example of what you want to achieve in the end but can't?
– AndréC
21 hours ago




I didn't understand correctly. Can you add an example of what you want to achieve in the end but can't?
– AndréC
21 hours ago




1




1




Named numbers are called variables or constants. But named points may be named as nodes.
– God Must Be Crazy
20 hours ago




Named numbers are called variables or constants. But named points may be named as nodes.
– God Must Be Crazy
20 hours ago










4 Answers
4






active

oldest

votes


















8














You can also use tikzmath from math tikzlibrary



    documentclass[border=1cm,multi]{standalone}
usepackage{tikz}
usetikzlibrary{math,angles,quotes}

begin{document}
tikzmath{
R=2; % circle radius
d=3; % distance between A and B
a1=30; % angle alpha
a2=a1 + 90; % angle beta
}
begin{tikzpicture}
draw (0,0)circle[radius=R cm];
path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
draw (A)--(B);

coordinate(O) at(0,0);
coordinate(x) at(1,0);
draw(x)--(O)--(A);
pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

end{tikzpicture}
tikzmath{
R=2; % circle radius
d=3; % distance between A and B
a1=60; % angle alpha
a2=a1 + 90; % angle beta
}
begin{tikzpicture}
draw (0,0)circle[radius=R cm];
path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
draw (A)--(B);

coordinate(O) at(0,0);
coordinate(x) at(1,0);
draw(x)--(O)--(A);
pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

end{tikzpicture}
end{document}


enter image description here






share|improve this answer























  • Thank you! This is exactly what I wanted.
    – Pengfei
    19 hours ago



















5














You can use insert path in order to insert paths that are largely the same. This is illustrated in the MWE most of which is illustration.



documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}[insert points/.style={insert path={%
(#1:1) coordinate(A) (#1+90:1) coordinate(B)}}]
% with 45 degrees
path[insert points=45];
% only illustration
draw circle (1);
foreach X in {A,B}
{node[fill,inner sep=1pt,label=right:X] at (X){};}
% second example (shifted to avoid interference)
begin{scope}[xshift=4cm]
% with 60 degrees
path[insert points=60];
% only illustration
draw circle (1);
foreach X in {A,B}
{node[fill,inner sep=1pt,label=right:X] at (X){};}
end{scope}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer





















  • Thank you very much!
    – Pengfei
    19 hours ago



















5














If I understood correctly, you want to place a point A on a circle at a certain angle and then a point placed on the perpendicular to this 90 degree radius.



Then you want these two angles to be relative. It is possible to define a constant with the LaTeX macro def and to define the other one with the calc library which allows to place a point with respect to two others with a given angle (see pages 143 and 144 of the manual 3.0.1a).



Here is an example:



capture



documentclass[tikz,border=5mm]{standalone}
usetikzlibrary{calc}
begin{document}
defalpha{45}

begin{tikzpicture}
draw (0,0)circle (2cm)circle(1pt);
draw (alpha:2) coordinate(A)circle(1pt);
draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
end{tikzpicture}

end{document}


And as a Christmas gift, a little animation:



animation



documentclass[tikz,border=5mm]{standalone}
usetikzlibrary{calc}
begin{document}
defalpha{40}
foreach alpha in {0,5,...,180}{
begin{tikzpicture}
useasboundingbox (-3,-3) rectangle (3,3);
draw (0,0)circle (2cm)circle(1pt);
draw (alpha:2) coordinate(A)circle(1pt);
draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
end{tikzpicture}
}
end{document}





share|improve this answer



















  • 1




    Thanks a lot. Now I know how to create a gif!
    – Pengfei
    19 hours ago



















3














A PSTricks solution only for fun purposes.



Still image



documentclass[pstricks,12pt]{standalone}
usepackage{pst-eucl}
begin{document}
pspicture(8,8)
pstGeonode(4,4){O}([nodesep=2,angle=60]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
pstCircleOA{O}{A}
psline(X)(Y)
endpspicture
end{document}


enter image description here



Animated



documentclass[pstricks,12pt]{standalone}
usepackage{pst-eucl}
begin{document}
foreach i in {0,30,...,330}{%
pspicture(8,8)
pstGeonode(4,4){O}([nodesep=2,angle=i]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
pstCircleOA{O}{A}
psline(X)(Y)
endpspicture}
end{document}


enter image description here






share|improve this answer





















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    4 Answers
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    4 Answers
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    active

    oldest

    votes









    8














    You can also use tikzmath from math tikzlibrary



        documentclass[border=1cm,multi]{standalone}
    usepackage{tikz}
    usetikzlibrary{math,angles,quotes}

    begin{document}
    tikzmath{
    R=2; % circle radius
    d=3; % distance between A and B
    a1=30; % angle alpha
    a2=a1 + 90; % angle beta
    }
    begin{tikzpicture}
    draw (0,0)circle[radius=R cm];
    path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
    draw (A)--(B);

    coordinate(O) at(0,0);
    coordinate(x) at(1,0);
    draw(x)--(O)--(A);
    pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

    end{tikzpicture}
    tikzmath{
    R=2; % circle radius
    d=3; % distance between A and B
    a1=60; % angle alpha
    a2=a1 + 90; % angle beta
    }
    begin{tikzpicture}
    draw (0,0)circle[radius=R cm];
    path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
    draw (A)--(B);

    coordinate(O) at(0,0);
    coordinate(x) at(1,0);
    draw(x)--(O)--(A);
    pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer























    • Thank you! This is exactly what I wanted.
      – Pengfei
      19 hours ago
















    8














    You can also use tikzmath from math tikzlibrary



        documentclass[border=1cm,multi]{standalone}
    usepackage{tikz}
    usetikzlibrary{math,angles,quotes}

    begin{document}
    tikzmath{
    R=2; % circle radius
    d=3; % distance between A and B
    a1=30; % angle alpha
    a2=a1 + 90; % angle beta
    }
    begin{tikzpicture}
    draw (0,0)circle[radius=R cm];
    path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
    draw (A)--(B);

    coordinate(O) at(0,0);
    coordinate(x) at(1,0);
    draw(x)--(O)--(A);
    pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

    end{tikzpicture}
    tikzmath{
    R=2; % circle radius
    d=3; % distance between A and B
    a1=60; % angle alpha
    a2=a1 + 90; % angle beta
    }
    begin{tikzpicture}
    draw (0,0)circle[radius=R cm];
    path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
    draw (A)--(B);

    coordinate(O) at(0,0);
    coordinate(x) at(1,0);
    draw(x)--(O)--(A);
    pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer























    • Thank you! This is exactly what I wanted.
      – Pengfei
      19 hours ago














    8












    8








    8






    You can also use tikzmath from math tikzlibrary



        documentclass[border=1cm,multi]{standalone}
    usepackage{tikz}
    usetikzlibrary{math,angles,quotes}

    begin{document}
    tikzmath{
    R=2; % circle radius
    d=3; % distance between A and B
    a1=30; % angle alpha
    a2=a1 + 90; % angle beta
    }
    begin{tikzpicture}
    draw (0,0)circle[radius=R cm];
    path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
    draw (A)--(B);

    coordinate(O) at(0,0);
    coordinate(x) at(1,0);
    draw(x)--(O)--(A);
    pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

    end{tikzpicture}
    tikzmath{
    R=2; % circle radius
    d=3; % distance between A and B
    a1=60; % angle alpha
    a2=a1 + 90; % angle beta
    }
    begin{tikzpicture}
    draw (0,0)circle[radius=R cm];
    path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
    draw (A)--(B);

    coordinate(O) at(0,0);
    coordinate(x) at(1,0);
    draw(x)--(O)--(A);
    pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer














    You can also use tikzmath from math tikzlibrary



        documentclass[border=1cm,multi]{standalone}
    usepackage{tikz}
    usetikzlibrary{math,angles,quotes}

    begin{document}
    tikzmath{
    R=2; % circle radius
    d=3; % distance between A and B
    a1=30; % angle alpha
    a2=a1 + 90; % angle beta
    }
    begin{tikzpicture}
    draw (0,0)circle[radius=R cm];
    path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
    draw (A)--(B);

    coordinate(O) at(0,0);
    coordinate(x) at(1,0);
    draw(x)--(O)--(A);
    pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

    end{tikzpicture}
    tikzmath{
    R=2; % circle radius
    d=3; % distance between A and B
    a1=60; % angle alpha
    a2=a1 + 90; % angle beta
    }
    begin{tikzpicture}
    draw (0,0)circle[radius=R cm];
    path (a1:R) coordinate[label=(A)] (A) +(a2:d)coordinate[label=(B)](B);
    draw (A)--(B);

    coordinate(O) at(0,0);
    coordinate(x) at(1,0);
    draw(x)--(O)--(A);
    pic[draw,"(alpha=a1)",angle eccentricity=2.25]{angle=x--O--A};

    end{tikzpicture}
    end{document}


    enter image description here







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 20 hours ago

























    answered 20 hours ago









    Hafid Boukhoulda

    1,5541516




    1,5541516












    • Thank you! This is exactly what I wanted.
      – Pengfei
      19 hours ago


















    • Thank you! This is exactly what I wanted.
      – Pengfei
      19 hours ago
















    Thank you! This is exactly what I wanted.
    – Pengfei
    19 hours ago




    Thank you! This is exactly what I wanted.
    – Pengfei
    19 hours ago











    5














    You can use insert path in order to insert paths that are largely the same. This is illustrated in the MWE most of which is illustration.



    documentclass[tikz,border=3.14mm]{standalone}
    begin{document}
    begin{tikzpicture}[insert points/.style={insert path={%
    (#1:1) coordinate(A) (#1+90:1) coordinate(B)}}]
    % with 45 degrees
    path[insert points=45];
    % only illustration
    draw circle (1);
    foreach X in {A,B}
    {node[fill,inner sep=1pt,label=right:X] at (X){};}
    % second example (shifted to avoid interference)
    begin{scope}[xshift=4cm]
    % with 60 degrees
    path[insert points=60];
    % only illustration
    draw circle (1);
    foreach X in {A,B}
    {node[fill,inner sep=1pt,label=right:X] at (X){};}
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer





















    • Thank you very much!
      – Pengfei
      19 hours ago
















    5














    You can use insert path in order to insert paths that are largely the same. This is illustrated in the MWE most of which is illustration.



    documentclass[tikz,border=3.14mm]{standalone}
    begin{document}
    begin{tikzpicture}[insert points/.style={insert path={%
    (#1:1) coordinate(A) (#1+90:1) coordinate(B)}}]
    % with 45 degrees
    path[insert points=45];
    % only illustration
    draw circle (1);
    foreach X in {A,B}
    {node[fill,inner sep=1pt,label=right:X] at (X){};}
    % second example (shifted to avoid interference)
    begin{scope}[xshift=4cm]
    % with 60 degrees
    path[insert points=60];
    % only illustration
    draw circle (1);
    foreach X in {A,B}
    {node[fill,inner sep=1pt,label=right:X] at (X){};}
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer





















    • Thank you very much!
      – Pengfei
      19 hours ago














    5












    5








    5






    You can use insert path in order to insert paths that are largely the same. This is illustrated in the MWE most of which is illustration.



    documentclass[tikz,border=3.14mm]{standalone}
    begin{document}
    begin{tikzpicture}[insert points/.style={insert path={%
    (#1:1) coordinate(A) (#1+90:1) coordinate(B)}}]
    % with 45 degrees
    path[insert points=45];
    % only illustration
    draw circle (1);
    foreach X in {A,B}
    {node[fill,inner sep=1pt,label=right:X] at (X){};}
    % second example (shifted to avoid interference)
    begin{scope}[xshift=4cm]
    % with 60 degrees
    path[insert points=60];
    % only illustration
    draw circle (1);
    foreach X in {A,B}
    {node[fill,inner sep=1pt,label=right:X] at (X){};}
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer












    You can use insert path in order to insert paths that are largely the same. This is illustrated in the MWE most of which is illustration.



    documentclass[tikz,border=3.14mm]{standalone}
    begin{document}
    begin{tikzpicture}[insert points/.style={insert path={%
    (#1:1) coordinate(A) (#1+90:1) coordinate(B)}}]
    % with 45 degrees
    path[insert points=45];
    % only illustration
    draw circle (1);
    foreach X in {A,B}
    {node[fill,inner sep=1pt,label=right:X] at (X){};}
    % second example (shifted to avoid interference)
    begin{scope}[xshift=4cm]
    % with 60 degrees
    path[insert points=60];
    % only illustration
    draw circle (1);
    foreach X in {A,B}
    {node[fill,inner sep=1pt,label=right:X] at (X){};}
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 21 hours ago









    marmot

    85.9k499183




    85.9k499183












    • Thank you very much!
      – Pengfei
      19 hours ago


















    • Thank you very much!
      – Pengfei
      19 hours ago
















    Thank you very much!
    – Pengfei
    19 hours ago




    Thank you very much!
    – Pengfei
    19 hours ago











    5














    If I understood correctly, you want to place a point A on a circle at a certain angle and then a point placed on the perpendicular to this 90 degree radius.



    Then you want these two angles to be relative. It is possible to define a constant with the LaTeX macro def and to define the other one with the calc library which allows to place a point with respect to two others with a given angle (see pages 143 and 144 of the manual 3.0.1a).



    Here is an example:



    capture



    documentclass[tikz,border=5mm]{standalone}
    usetikzlibrary{calc}
    begin{document}
    defalpha{45}

    begin{tikzpicture}
    draw (0,0)circle (2cm)circle(1pt);
    draw (alpha:2) coordinate(A)circle(1pt);
    draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
    end{tikzpicture}

    end{document}


    And as a Christmas gift, a little animation:



    animation



    documentclass[tikz,border=5mm]{standalone}
    usetikzlibrary{calc}
    begin{document}
    defalpha{40}
    foreach alpha in {0,5,...,180}{
    begin{tikzpicture}
    useasboundingbox (-3,-3) rectangle (3,3);
    draw (0,0)circle (2cm)circle(1pt);
    draw (alpha:2) coordinate(A)circle(1pt);
    draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
    end{tikzpicture}
    }
    end{document}





    share|improve this answer



















    • 1




      Thanks a lot. Now I know how to create a gif!
      – Pengfei
      19 hours ago
















    5














    If I understood correctly, you want to place a point A on a circle at a certain angle and then a point placed on the perpendicular to this 90 degree radius.



    Then you want these two angles to be relative. It is possible to define a constant with the LaTeX macro def and to define the other one with the calc library which allows to place a point with respect to two others with a given angle (see pages 143 and 144 of the manual 3.0.1a).



    Here is an example:



    capture



    documentclass[tikz,border=5mm]{standalone}
    usetikzlibrary{calc}
    begin{document}
    defalpha{45}

    begin{tikzpicture}
    draw (0,0)circle (2cm)circle(1pt);
    draw (alpha:2) coordinate(A)circle(1pt);
    draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
    end{tikzpicture}

    end{document}


    And as a Christmas gift, a little animation:



    animation



    documentclass[tikz,border=5mm]{standalone}
    usetikzlibrary{calc}
    begin{document}
    defalpha{40}
    foreach alpha in {0,5,...,180}{
    begin{tikzpicture}
    useasboundingbox (-3,-3) rectangle (3,3);
    draw (0,0)circle (2cm)circle(1pt);
    draw (alpha:2) coordinate(A)circle(1pt);
    draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
    end{tikzpicture}
    }
    end{document}





    share|improve this answer



















    • 1




      Thanks a lot. Now I know how to create a gif!
      – Pengfei
      19 hours ago














    5












    5








    5






    If I understood correctly, you want to place a point A on a circle at a certain angle and then a point placed on the perpendicular to this 90 degree radius.



    Then you want these two angles to be relative. It is possible to define a constant with the LaTeX macro def and to define the other one with the calc library which allows to place a point with respect to two others with a given angle (see pages 143 and 144 of the manual 3.0.1a).



    Here is an example:



    capture



    documentclass[tikz,border=5mm]{standalone}
    usetikzlibrary{calc}
    begin{document}
    defalpha{45}

    begin{tikzpicture}
    draw (0,0)circle (2cm)circle(1pt);
    draw (alpha:2) coordinate(A)circle(1pt);
    draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
    end{tikzpicture}

    end{document}


    And as a Christmas gift, a little animation:



    animation



    documentclass[tikz,border=5mm]{standalone}
    usetikzlibrary{calc}
    begin{document}
    defalpha{40}
    foreach alpha in {0,5,...,180}{
    begin{tikzpicture}
    useasboundingbox (-3,-3) rectangle (3,3);
    draw (0,0)circle (2cm)circle(1pt);
    draw (alpha:2) coordinate(A)circle(1pt);
    draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
    end{tikzpicture}
    }
    end{document}





    share|improve this answer














    If I understood correctly, you want to place a point A on a circle at a certain angle and then a point placed on the perpendicular to this 90 degree radius.



    Then you want these two angles to be relative. It is possible to define a constant with the LaTeX macro def and to define the other one with the calc library which allows to place a point with respect to two others with a given angle (see pages 143 and 144 of the manual 3.0.1a).



    Here is an example:



    capture



    documentclass[tikz,border=5mm]{standalone}
    usetikzlibrary{calc}
    begin{document}
    defalpha{45}

    begin{tikzpicture}
    draw (0,0)circle (2cm)circle(1pt);
    draw (alpha:2) coordinate(A)circle(1pt);
    draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
    end{tikzpicture}

    end{document}


    And as a Christmas gift, a little animation:



    animation



    documentclass[tikz,border=5mm]{standalone}
    usetikzlibrary{calc}
    begin{document}
    defalpha{40}
    foreach alpha in {0,5,...,180}{
    begin{tikzpicture}
    useasboundingbox (-3,-3) rectangle (3,3);
    draw (0,0)circle (2cm)circle(1pt);
    draw (alpha:2) coordinate(A)circle(1pt);
    draw ($(A)!1!-90:(0,0)$)--($(A)!1!90:(0,0)$);
    end{tikzpicture}
    }
    end{document}






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 20 hours ago









    Blincer

    1718




    1718










    answered 20 hours ago









    AndréC

    7,47711440




    7,47711440








    • 1




      Thanks a lot. Now I know how to create a gif!
      – Pengfei
      19 hours ago














    • 1




      Thanks a lot. Now I know how to create a gif!
      – Pengfei
      19 hours ago








    1




    1




    Thanks a lot. Now I know how to create a gif!
    – Pengfei
    19 hours ago




    Thanks a lot. Now I know how to create a gif!
    – Pengfei
    19 hours ago











    3














    A PSTricks solution only for fun purposes.



    Still image



    documentclass[pstricks,12pt]{standalone}
    usepackage{pst-eucl}
    begin{document}
    pspicture(8,8)
    pstGeonode(4,4){O}([nodesep=2,angle=60]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
    pstCircleOA{O}{A}
    psline(X)(Y)
    endpspicture
    end{document}


    enter image description here



    Animated



    documentclass[pstricks,12pt]{standalone}
    usepackage{pst-eucl}
    begin{document}
    foreach i in {0,30,...,330}{%
    pspicture(8,8)
    pstGeonode(4,4){O}([nodesep=2,angle=i]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
    pstCircleOA{O}{A}
    psline(X)(Y)
    endpspicture}
    end{document}


    enter image description here






    share|improve this answer


























      3














      A PSTricks solution only for fun purposes.



      Still image



      documentclass[pstricks,12pt]{standalone}
      usepackage{pst-eucl}
      begin{document}
      pspicture(8,8)
      pstGeonode(4,4){O}([nodesep=2,angle=60]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
      pstCircleOA{O}{A}
      psline(X)(Y)
      endpspicture
      end{document}


      enter image description here



      Animated



      documentclass[pstricks,12pt]{standalone}
      usepackage{pst-eucl}
      begin{document}
      foreach i in {0,30,...,330}{%
      pspicture(8,8)
      pstGeonode(4,4){O}([nodesep=2,angle=i]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
      pstCircleOA{O}{A}
      psline(X)(Y)
      endpspicture}
      end{document}


      enter image description here






      share|improve this answer
























        3












        3








        3






        A PSTricks solution only for fun purposes.



        Still image



        documentclass[pstricks,12pt]{standalone}
        usepackage{pst-eucl}
        begin{document}
        pspicture(8,8)
        pstGeonode(4,4){O}([nodesep=2,angle=60]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
        pstCircleOA{O}{A}
        psline(X)(Y)
        endpspicture
        end{document}


        enter image description here



        Animated



        documentclass[pstricks,12pt]{standalone}
        usepackage{pst-eucl}
        begin{document}
        foreach i in {0,30,...,330}{%
        pspicture(8,8)
        pstGeonode(4,4){O}([nodesep=2,angle=i]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
        pstCircleOA{O}{A}
        psline(X)(Y)
        endpspicture}
        end{document}


        enter image description here






        share|improve this answer












        A PSTricks solution only for fun purposes.



        Still image



        documentclass[pstricks,12pt]{standalone}
        usepackage{pst-eucl}
        begin{document}
        pspicture(8,8)
        pstGeonode(4,4){O}([nodesep=2,angle=60]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
        pstCircleOA{O}{A}
        psline(X)(Y)
        endpspicture
        end{document}


        enter image description here



        Animated



        documentclass[pstricks,12pt]{standalone}
        usepackage{pst-eucl}
        begin{document}
        foreach i in {0,30,...,330}{%
        pspicture(8,8)
        pstGeonode(4,4){O}([nodesep=2,angle=i]O){A}([offset=-2]{O}A){X}([offset=2]{O}A){Y}
        pstCircleOA{O}{A}
        psline(X)(Y)
        endpspicture}
        end{document}


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 19 hours ago









        God Must Be Crazy

        5,43011039




        5,43011039






























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