Unable to retrieve single value from array of values











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0
down vote

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I'm trying to retrieve a value to do a String comparison test and I can't seem to retrieve the single value from an array of values. Here's my code:



function CoverageCalculator() {

  var sheet = SpreadsheetApp.getActiveSheet();



  var searchRange = sheet.getRange('D3:D20')

  var rangeValues = searchRange.getValues();



  var Test = searchRange[1][1];

}


In debug mode, "Test" is undefined, any ideas on why this might be the case?






google-apps-script google-sheets







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  • 2




    Shouldn't it be rangeValues[1][1]?
    – TheWizEd
    Nov 22 at 17:47















up vote
0
down vote

favorite












I'm trying to retrieve a value to do a String comparison test and I can't seem to retrieve the single value from an array of values. Here's my code:



function CoverageCalculator() {

  var sheet = SpreadsheetApp.getActiveSheet();



  var searchRange = sheet.getRange('D3:D20')

  var rangeValues = searchRange.getValues();



  var Test = searchRange[1][1];

}


In debug mode, "Test" is undefined, any ideas on why this might be the case?






google-apps-script google-sheets







share|improve this question




















  • 2




    Shouldn't it be rangeValues[1][1]?
    – TheWizEd
    Nov 22 at 17:47













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm trying to retrieve a value to do a String comparison test and I can't seem to retrieve the single value from an array of values. Here's my code:



function CoverageCalculator() {

  var sheet = SpreadsheetApp.getActiveSheet();



  var searchRange = sheet.getRange('D3:D20')

  var rangeValues = searchRange.getValues();



  var Test = searchRange[1][1];

}


In debug mode, "Test" is undefined, any ideas on why this might be the case?






google-apps-script google-sheets







share|improve this question















I'm trying to retrieve a value to do a String comparison test and I can't seem to retrieve the single value from an array of values. Here's my code:



function CoverageCalculator() {

  var sheet = SpreadsheetApp.getActiveSheet();



  var searchRange = sheet.getRange('D3:D20')

  var rangeValues = searchRange.getValues();



  var Test = searchRange[1][1];

}


In debug mode, "Test" is undefined, any ideas on why this might be the case?






google-apps-script google-sheets




google-apps-script google-sheets






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 at 19:01









Rubén

9,93043265




9,93043265










asked Nov 22 at 16:20









Nicholas Besse

31




31








  • 2




    Shouldn't it be rangeValues[1][1]?
    – TheWizEd
    Nov 22 at 17:47














  • 2




    Shouldn't it be rangeValues[1][1]?
    – TheWizEd
    Nov 22 at 17:47








2




2




Shouldn't it be rangeValues[1][1]?
– TheWizEd
Nov 22 at 17:47




Shouldn't it be rangeValues[1][1]?
– TheWizEd
Nov 22 at 17:47












1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










Change 



var Test = searchRange[1][1];


to



var Test = rangeValues[1][0];


The above because searchRange is a Range object, not an array, but rangeValues it's. Regarding the indexes, the first one determines the row, and the second the column and considering that the source range is D3:D20 the resulting array has 17 rows high and 1 column width, then the maximum valid index for the second index is 0.






share|improve this answer























  • Ah, yes. Typo on my part, though rangValues still returns an undefined
    – Nicholas Besse
    Nov 22 at 20:50










  • Since it's an array of width 1 (I think that's the right terminology?) ie, a column vector, I just need to declare an element, not a [row][column] So, var Test = rangeValues[1]; works Thank you!
    – Nicholas Besse
    Nov 22 at 20:52










  • @NicholasBesse I updated my answer.
    – Rubén
    Nov 22 at 21:34











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1 Answer
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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










Change 



var Test = searchRange[1][1];


to



var Test = rangeValues[1][0];


The above because searchRange is a Range object, not an array, but rangeValues it's. Regarding the indexes, the first one determines the row, and the second the column and considering that the source range is D3:D20 the resulting array has 17 rows high and 1 column width, then the maximum valid index for the second index is 0.






share|improve this answer























  • Ah, yes. Typo on my part, though rangValues still returns an undefined
    – Nicholas Besse
    Nov 22 at 20:50










  • Since it's an array of width 1 (I think that's the right terminology?) ie, a column vector, I just need to declare an element, not a [row][column] So, var Test = rangeValues[1]; works Thank you!
    – Nicholas Besse
    Nov 22 at 20:52










  • @NicholasBesse I updated my answer.
    – Rubén
    Nov 22 at 21:34















up vote
1
down vote



accepted










Change 



var Test = searchRange[1][1];


to



var Test = rangeValues[1][0];


The above because searchRange is a Range object, not an array, but rangeValues it's. Regarding the indexes, the first one determines the row, and the second the column and considering that the source range is D3:D20 the resulting array has 17 rows high and 1 column width, then the maximum valid index for the second index is 0.






share|improve this answer























  • Ah, yes. Typo on my part, though rangValues still returns an undefined
    – Nicholas Besse
    Nov 22 at 20:50










  • Since it's an array of width 1 (I think that's the right terminology?) ie, a column vector, I just need to declare an element, not a [row][column] So, var Test = rangeValues[1]; works Thank you!
    – Nicholas Besse
    Nov 22 at 20:52










  • @NicholasBesse I updated my answer.
    – Rubén
    Nov 22 at 21:34













up vote
1
down vote



accepted







up vote
1
down vote



accepted






Change 



var Test = searchRange[1][1];


to



var Test = rangeValues[1][0];


The above because searchRange is a Range object, not an array, but rangeValues it's. Regarding the indexes, the first one determines the row, and the second the column and considering that the source range is D3:D20 the resulting array has 17 rows high and 1 column width, then the maximum valid index for the second index is 0.






share|improve this answer














Change 



var Test = searchRange[1][1];


to



var Test = rangeValues[1][0];


The above because searchRange is a Range object, not an array, but rangeValues it's. Regarding the indexes, the first one determines the row, and the second the column and considering that the source range is D3:D20 the resulting array has 17 rows high and 1 column width, then the maximum valid index for the second index is 0.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 22 at 21:34

























answered Nov 22 at 19:03









Rubén

9,93043265




9,93043265












  • Ah, yes. Typo on my part, though rangValues still returns an undefined
    – Nicholas Besse
    Nov 22 at 20:50










  • Since it's an array of width 1 (I think that's the right terminology?) ie, a column vector, I just need to declare an element, not a [row][column] So, var Test = rangeValues[1]; works Thank you!
    – Nicholas Besse
    Nov 22 at 20:52










  • @NicholasBesse I updated my answer.
    – Rubén
    Nov 22 at 21:34


















  • Ah, yes. Typo on my part, though rangValues still returns an undefined
    – Nicholas Besse
    Nov 22 at 20:50










  • Since it's an array of width 1 (I think that's the right terminology?) ie, a column vector, I just need to declare an element, not a [row][column] So, var Test = rangeValues[1]; works Thank you!
    – Nicholas Besse
    Nov 22 at 20:52










  • @NicholasBesse I updated my answer.
    – Rubén
    Nov 22 at 21:34
















Ah, yes. Typo on my part, though rangValues still returns an undefined
– Nicholas Besse
Nov 22 at 20:50




Ah, yes. Typo on my part, though rangValues still returns an undefined
– Nicholas Besse
Nov 22 at 20:50












Since it's an array of width 1 (I think that's the right terminology?) ie, a column vector, I just need to declare an element, not a [row][column] So, var Test = rangeValues[1]; works Thank you!
– Nicholas Besse
Nov 22 at 20:52




Since it's an array of width 1 (I think that's the right terminology?) ie, a column vector, I just need to declare an element, not a [row][column] So, var Test = rangeValues[1]; works Thank you!
– Nicholas Besse
Nov 22 at 20:52












@NicholasBesse I updated my answer.
– Rubén
Nov 22 at 21:34




@NicholasBesse I updated my answer.
– Rubén
Nov 22 at 21:34


















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