Removing neighboring duplicates in list in python [duplicate]
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This question already has an answer here:
Python - how to remove duplicates only if consecutive in a string?
9 answers
I convert string a to a list and I want the loop to create tabb = ['a', 'b', 'c', 'a']
a = aaabbbbcccaaa
taba = list(a)
tabb =
for i in taba:
for j in range(len(tabb)):
if not i[j] == i[j-1]:
tabb.append(i[j])
print (tabb)
But apparently my solution gives tabb =
Do You have any better and simple ideas to make it work?
python python-3.x list element
edited Nov 22 at 15:18
Ali AzG
607515
asked Nov 22 at 15:15
baqterya
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Nov 22 at 15:18
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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up vote
1
down vote
favorite
This question already has an answer here:
Python - how to remove duplicates only if consecutive in a string?
9 answers
I convert string a to a list and I want the loop to create tabb = ['a', 'b', 'c', 'a']
a = aaabbbbcccaaa
taba = list(a)
tabb =
for i in taba:
for j in range(len(tabb)):
if not i[j] == i[j-1]:
tabb.append(i[j])
print (tabb)
But apparently my solution gives tabb =
Do You have any better and simple ideas to make it work?
python python-3.x list element
edited Nov 22 at 15:18
Ali AzG
607515
asked Nov 22 at 15:15
baqterya
61
marked as duplicate by alex, Jon Clements♦ list
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Nov 22 at 15:18
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
@alex OP wants the second'a'in this example. The proposed duplicate is wrong in this case.
– Ev. Kounis
Nov 22 at 15:21
@Ev.Kounis not sure it's incorrect... the answers cover various approaches for unique characters for an entire string and also unique consecutive characters. I'm open to another more specific duplicate if you have one to mind?
– Jon Clements♦
Nov 22 at 15:28
@JonClements There is one good one but it is regex specific. There has to be one though.
– Ev. Kounis
Nov 22 at 15:30
@Ev.Kounis thought I also saw a groupby?
– Jon Clements♦
Nov 22 at 15:30
@JonClements this one maybe?
– Ev. Kounis
Nov 22 at 15:36
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show 1 more comment
up vote
1
down vote
favorite
up vote
1
down vote
favorite
This question already has an answer here:
Python - how to remove duplicates only if consecutive in a string?
9 answers
I convert string a to a list and I want the loop to create tabb = ['a', 'b', 'c', 'a']
a = aaabbbbcccaaa
taba = list(a)
tabb =
for i in taba:
for j in range(len(tabb)):
if not i[j] == i[j-1]:
tabb.append(i[j])
print (tabb)
But apparently my solution gives tabb =
Do You have any better and simple ideas to make it work?
python python-3.x list element
edited Nov 22 at 15:18
Ali AzG
607515
asked Nov 22 at 15:15
baqterya
61
This question already has an answer here:
Python - how to remove duplicates only if consecutive in a string?
9 answers
I convert string a to a list and I want the loop to create tabb = ['a', 'b', 'c', 'a']
a = aaabbbbcccaaa
taba = list(a)
tabb =
for i in taba:
for j in range(len(tabb)):
if not i[j] == i[j-1]:
tabb.append(i[j])
print (tabb)
But apparently my solution gives tabb =
Do You have any better and simple ideas to make it work?
This question already has an answer here:
Python - how to remove duplicates only if consecutive in a string?
9 answers
python python-3.x list element
python python-3.x list element
edited Nov 22 at 15:18
Ali AzG
607515
asked Nov 22 at 15:15
baqterya
61
edited Nov 22 at 15:18
Ali AzG
607515
asked Nov 22 at 15:15
baqterya
61
edited Nov 22 at 15:18
Ali AzG
607515
edited Nov 22 at 15:18
Ali AzG
607515
edited Nov 22 at 15:18
Ali AzG
607515
607515
asked Nov 22 at 15:15
baqterya
61
asked Nov 22 at 15:15
baqterya
61
asked Nov 22 at 15:15
baqterya
61
61
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Nov 22 at 15:18
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Nov 22 at 15:18
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
@alex OP wants the second'a'in this example. The proposed duplicate is wrong in this case.
– Ev. Kounis
Nov 22 at 15:21
@Ev.Kounis not sure it's incorrect... the answers cover various approaches for unique characters for an entire string and also unique consecutive characters. I'm open to another more specific duplicate if you have one to mind?
– Jon Clements♦
Nov 22 at 15:28
@JonClements There is one good one but it is regex specific. There has to be one though.
– Ev. Kounis
Nov 22 at 15:30
@Ev.Kounis thought I also saw a groupby?
– Jon Clements♦
Nov 22 at 15:30
@JonClements this one maybe?
– Ev. Kounis
Nov 22 at 15:36
|
show 1 more comment
1
@alex OP wants the second'a'in this example. The proposed duplicate is wrong in this case.
– Ev. Kounis
Nov 22 at 15:21
@Ev.Kounis not sure it's incorrect... the answers cover various approaches for unique characters for an entire string and also unique consecutive characters. I'm open to another more specific duplicate if you have one to mind?
– Jon Clements♦
Nov 22 at 15:28
@JonClements There is one good one but it is regex specific. There has to be one though.
– Ev. Kounis
Nov 22 at 15:30
@Ev.Kounis thought I also saw a groupby?
– Jon Clements♦
Nov 22 at 15:30
@JonClements this one maybe?
– Ev. Kounis
Nov 22 at 15:36
1
1
@alex OP wants the second
'a' in this example. The proposed duplicate is wrong in this case.– Ev. Kounis
Nov 22 at 15:21
@alex OP wants the second
'a' in this example. The proposed duplicate is wrong in this case.– Ev. Kounis
Nov 22 at 15:21
@Ev.Kounis not sure it's incorrect... the answers cover various approaches for unique characters for an entire string and also unique consecutive characters. I'm open to another more specific duplicate if you have one to mind?
– Jon Clements♦
Nov 22 at 15:28
@Ev.Kounis not sure it's incorrect... the answers cover various approaches for unique characters for an entire string and also unique consecutive characters. I'm open to another more specific duplicate if you have one to mind?
– Jon Clements♦
Nov 22 at 15:28
@JonClements There is one good one but it is regex specific. There has to be one though.
– Ev. Kounis
Nov 22 at 15:30
@JonClements There is one good one but it is regex specific. There has to be one though.
– Ev. Kounis
Nov 22 at 15:30
@Ev.Kounis thought I also saw a groupby?
– Jon Clements♦
Nov 22 at 15:30
@Ev.Kounis thought I also saw a groupby?
– Jon Clements♦
Nov 22 at 15:30
@JonClements this one maybe?
– Ev. Kounis
Nov 22 at 15:36
@JonClements this one maybe?
– Ev. Kounis
Nov 22 at 15:36
|
show 1 more comment
1 Answer
1
active
oldest
votes
up vote
1
down vote
groupby from itertools is your ally:
from itertools import groupby
a = 'aaabbbbcccaaa'
res = [x for x, _ in groupby(a)]
print(res) # -> ['a', 'b', 'c', 'a']
The solution without any libraries (the one you were trying to arrive at) would be:
res = [a[0]]
for i, c in enumerate(a[1:]):
if c != a[i]:
res.append(c)
which has the same outcome of course.
answered Nov 22 at 15:16
Ev. Kounis
10.4k21544
Thank you, it worked flawlessly! BTW I'm trying to make reverse function and I almost made it work but it seems that it can't reach the first element of array: goo.gl/3cHkWN ( link to code in google docs) /// If input = AAABBBBCAAAaaDD, string = A3B4CA3a2D2 decompressed should be AAABBBBAAAaaDD but is BBBBAAAaaDD. Can You see why the loop can't see taba[2-1]?
– baqterya
Nov 22 at 17:12
post this as a separate question. It is beneficial for the community
– Ev. Kounis
Nov 22 at 17:16
also note that the fact that you do not have a1after the'C'makes it much more complicated than it has to be. If you have control over the format of the input string, please add it.
– Ev. Kounis
Nov 22 at 17:20
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
groupby from itertools is your ally:
from itertools import groupby
a = 'aaabbbbcccaaa'
res = [x for x, _ in groupby(a)]
print(res) # -> ['a', 'b', 'c', 'a']
The solution without any libraries (the one you were trying to arrive at) would be:
res = [a[0]]
for i, c in enumerate(a[1:]):
if c != a[i]:
res.append(c)
which has the same outcome of course.
answered Nov 22 at 15:16
Ev. Kounis
10.4k21544
Thank you, it worked flawlessly! BTW I'm trying to make reverse function and I almost made it work but it seems that it can't reach the first element of array: goo.gl/3cHkWN ( link to code in google docs) /// If input = AAABBBBCAAAaaDD, string = A3B4CA3a2D2 decompressed should be AAABBBBAAAaaDD but is BBBBAAAaaDD. Can You see why the loop can't see taba[2-1]?
– baqterya
Nov 22 at 17:12
post this as a separate question. It is beneficial for the community
– Ev. Kounis
Nov 22 at 17:16
also note that the fact that you do not have a1after the'C'makes it much more complicated than it has to be. If you have control over the format of the input string, please add it.
– Ev. Kounis
Nov 22 at 17:20
add a comment |
up vote
1
down vote
groupby from itertools is your ally:
from itertools import groupby
a = 'aaabbbbcccaaa'
res = [x for x, _ in groupby(a)]
print(res) # -> ['a', 'b', 'c', 'a']
The solution without any libraries (the one you were trying to arrive at) would be:
res = [a[0]]
for i, c in enumerate(a[1:]):
if c != a[i]:
res.append(c)
which has the same outcome of course.
answered Nov 22 at 15:16
Ev. Kounis
10.4k21544
Thank you, it worked flawlessly! BTW I'm trying to make reverse function and I almost made it work but it seems that it can't reach the first element of array: goo.gl/3cHkWN ( link to code in google docs) /// If input = AAABBBBCAAAaaDD, string = A3B4CA3a2D2 decompressed should be AAABBBBAAAaaDD but is BBBBAAAaaDD. Can You see why the loop can't see taba[2-1]?
– baqterya
Nov 22 at 17:12
post this as a separate question. It is beneficial for the community
– Ev. Kounis
Nov 22 at 17:16
also note that the fact that you do not have a1after the'C'makes it much more complicated than it has to be. If you have control over the format of the input string, please add it.
– Ev. Kounis
Nov 22 at 17:20
add a comment |
up vote
1
down vote
up vote
1
down vote
groupby from itertools is your ally:
from itertools import groupby
a = 'aaabbbbcccaaa'
res = [x for x, _ in groupby(a)]
print(res) # -> ['a', 'b', 'c', 'a']
The solution without any libraries (the one you were trying to arrive at) would be:
res = [a[0]]
for i, c in enumerate(a[1:]):
if c != a[i]:
res.append(c)
which has the same outcome of course.
answered Nov 22 at 15:16
Ev. Kounis
10.4k21544
groupby from itertools is your ally:
from itertools import groupby
a = 'aaabbbbcccaaa'
res = [x for x, _ in groupby(a)]
print(res) # -> ['a', 'b', 'c', 'a']
The solution without any libraries (the one you were trying to arrive at) would be:
res = [a[0]]
for i, c in enumerate(a[1:]):
if c != a[i]:
res.append(c)
which has the same outcome of course.
answered Nov 22 at 15:16
Ev. Kounis
10.4k21544
answered Nov 22 at 15:16
Ev. Kounis
10.4k21544
answered Nov 22 at 15:16
Ev. Kounis
10.4k21544
answered Nov 22 at 15:16
Ev. Kounis
10.4k21544
10.4k21544
Thank you, it worked flawlessly! BTW I'm trying to make reverse function and I almost made it work but it seems that it can't reach the first element of array: goo.gl/3cHkWN ( link to code in google docs) /// If input = AAABBBBCAAAaaDD, string = A3B4CA3a2D2 decompressed should be AAABBBBAAAaaDD but is BBBBAAAaaDD. Can You see why the loop can't see taba[2-1]?
– baqterya
Nov 22 at 17:12
post this as a separate question. It is beneficial for the community
– Ev. Kounis
Nov 22 at 17:16
also note that the fact that you do not have a1after the'C'makes it much more complicated than it has to be. If you have control over the format of the input string, please add it.
– Ev. Kounis
Nov 22 at 17:20
add a comment |
Thank you, it worked flawlessly! BTW I'm trying to make reverse function and I almost made it work but it seems that it can't reach the first element of array: goo.gl/3cHkWN ( link to code in google docs) /// If input = AAABBBBCAAAaaDD, string = A3B4CA3a2D2 decompressed should be AAABBBBAAAaaDD but is BBBBAAAaaDD. Can You see why the loop can't see taba[2-1]?
– baqterya
Nov 22 at 17:12
post this as a separate question. It is beneficial for the community
– Ev. Kounis
Nov 22 at 17:16
also note that the fact that you do not have a1after the'C'makes it much more complicated than it has to be. If you have control over the format of the input string, please add it.
– Ev. Kounis
Nov 22 at 17:20
Thank you, it worked flawlessly! BTW I'm trying to make reverse function and I almost made it work but it seems that it can't reach the first element of array: goo.gl/3cHkWN ( link to code in google docs) /// If input = AAABBBBCAAAaaDD, string = A3B4CA3a2D2 decompressed should be AAABBBBAAAaaDD but is BBBBAAAaaDD. Can You see why the loop can't see taba[2-1]?
– baqterya
Nov 22 at 17:12
Thank you, it worked flawlessly! BTW I'm trying to make reverse function and I almost made it work but it seems that it can't reach the first element of array: goo.gl/3cHkWN ( link to code in google docs) /// If input = AAABBBBCAAAaaDD, string = A3B4CA3a2D2 decompressed should be AAABBBBAAAaaDD but is BBBBAAAaaDD. Can You see why the loop can't see taba[2-1]?
– baqterya
Nov 22 at 17:12
post this as a separate question. It is beneficial for the community
– Ev. Kounis
Nov 22 at 17:16
post this as a separate question. It is beneficial for the community
– Ev. Kounis
Nov 22 at 17:16
also note that the fact that you do not have a
1 after the 'C' makes it much more complicated than it has to be. If you have control over the format of the input string, please add it.– Ev. Kounis
Nov 22 at 17:20
also note that the fact that you do not have a
1 after the 'C' makes it much more complicated than it has to be. If you have control over the format of the input string, please add it.– Ev. Kounis
Nov 22 at 17:20
add a comment |
1
@alex OP wants the second
'a'in this example. The proposed duplicate is wrong in this case.– Ev. Kounis
Nov 22 at 15:21
@Ev.Kounis not sure it's incorrect... the answers cover various approaches for unique characters for an entire string and also unique consecutive characters. I'm open to another more specific duplicate if you have one to mind?
– Jon Clements♦
Nov 22 at 15:28
@JonClements There is one good one but it is regex specific. There has to be one though.
– Ev. Kounis
Nov 22 at 15:30
@Ev.Kounis thought I also saw a groupby?
– Jon Clements♦
Nov 22 at 15:30
@JonClements this one maybe?
– Ev. Kounis
Nov 22 at 15:36