How to generate sequence when start is greater than stop

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I would like to generate sequence somewhat like 10, 7, 4, 1

seq function can't do it (start is greater than stop). What function can do this? I prefer not to loop over my sequence (it is going to be very time consuming as I have a large number of vectors needed to be processed like that).

> seq(10, 0, by=3)

Error in seq.default(10, 0, by = 3) : wrong sign in 'by' argument

edited Nov 22 at 15:23

Ronak Shah

30k103753

asked Nov 22 at 15:15

lizaveta

437

add a comment |

up vote
0
down vote

favorite

I would like to generate sequence somewhat like 10, 7, 4, 1

> seq(10, 0, by=3)

Error in seq.default(10, 0, by = 3) : wrong sign in 'by' argument

edited Nov 22 at 15:23

Ronak Shah

30k103753

asked Nov 22 at 15:15

lizaveta

437

add a comment |

up vote
0
down vote

favorite

I would like to generate sequence somewhat like 10, 7, 4, 1

> seq(10, 0, by=3)

Error in seq.default(10, 0, by = 3) : wrong sign in 'by' argument

edited Nov 22 at 15:23

Ronak Shah

30k103753

asked Nov 22 at 15:15

lizaveta

437

I would like to generate sequence somewhat like 10, 7, 4, 1

> seq(10, 0, by=3)

Error in seq.default(10, 0, by = 3) : wrong sign in 'by' argument

r vector seq

edited Nov 22 at 15:23

Ronak Shah

30k103753

asked Nov 22 at 15:15

lizaveta

437

edited Nov 22 at 15:23

Ronak Shah

30k103753

asked Nov 22 at 15:15

lizaveta

437

edited Nov 22 at 15:23

Ronak Shah

30k103753

edited Nov 22 at 15:23

Ronak Shah

30k103753

edited Nov 22 at 15:23

Ronak Shah

30k103753

asked Nov 22 at 15:15

lizaveta

437

asked Nov 22 at 15:15

lizaveta

437

asked Nov 22 at 15:15

lizaveta

437

add a comment |

3 Answers
3

active

oldest

votes

up vote
3
down vote

seq(from = 10, to = 0, by = -3)

edited Nov 22 at 15:20

David Arenburg

77.6k1092157

answered Nov 22 at 15:20

Matt Nolan

6217

add a comment |

up vote
0
down vote

Another way could be creating a logical vector and subsetting.

n <- 3

(10:0)[c(TRUE, rep(FALSE, n - 1))]

#[1] 10  7  4  1

answered Nov 22 at 15:21

Ronak Shah

30k103753

add a comment |

up vote
0
down vote

10 - 0:3 * 3

#[1] 10  7  4  1

Or to get integers (not floating point numbers) out:

typeof(10 - 0:3 * 3)

#[1] "double"



10L - 0:3 * 3L

#[1] 10  7  4  1

answered Nov 22 at 15:29

snoram

6,009830

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

up vote
3
down vote

seq(from = 10, to = 0, by = -3)

edited Nov 22 at 15:20

David Arenburg

77.6k1092157

answered Nov 22 at 15:20

Matt Nolan

6217

add a comment |

up vote
3
down vote

seq(from = 10, to = 0, by = -3)

edited Nov 22 at 15:20

David Arenburg

77.6k1092157

answered Nov 22 at 15:20

Matt Nolan

6217

add a comment |

up vote
3
down vote

seq(from = 10, to = 0, by = -3)

edited Nov 22 at 15:20

David Arenburg

77.6k1092157

answered Nov 22 at 15:20

Matt Nolan

6217

seq(from = 10, to = 0, by = -3)

edited Nov 22 at 15:20

David Arenburg

77.6k1092157

answered Nov 22 at 15:20

Matt Nolan

6217

edited Nov 22 at 15:20

David Arenburg

77.6k1092157

edited Nov 22 at 15:20

David Arenburg

77.6k1092157

edited Nov 22 at 15:20

David Arenburg

77.6k1092157

answered Nov 22 at 15:20

Matt Nolan

6217

answered Nov 22 at 15:20

Matt Nolan

6217

answered Nov 22 at 15:20

Matt Nolan

6217

add a comment |

up vote
0
down vote

Another way could be creating a logical vector and subsetting.

n <- 3

(10:0)[c(TRUE, rep(FALSE, n - 1))]

#[1] 10  7  4  1

answered Nov 22 at 15:21

Ronak Shah

30k103753

add a comment |

up vote
0
down vote

Another way could be creating a logical vector and subsetting.

n <- 3

(10:0)[c(TRUE, rep(FALSE, n - 1))]

#[1] 10  7  4  1

answered Nov 22 at 15:21

Ronak Shah

30k103753

add a comment |

up vote
0
down vote

Another way could be creating a logical vector and subsetting.

n <- 3

(10:0)[c(TRUE, rep(FALSE, n - 1))]

#[1] 10  7  4  1

answered Nov 22 at 15:21

Ronak Shah

30k103753

Another way could be creating a logical vector and subsetting.

n <- 3

(10:0)[c(TRUE, rep(FALSE, n - 1))]

#[1] 10  7  4  1

answered Nov 22 at 15:21

Ronak Shah

30k103753

answered Nov 22 at 15:21

Ronak Shah

30k103753

answered Nov 22 at 15:21

Ronak Shah

30k103753

answered Nov 22 at 15:21

Ronak Shah

30k103753

add a comment |

up vote
0
down vote

10 - 0:3 * 3

#[1] 10  7  4  1

Or to get integers (not floating point numbers) out:

typeof(10 - 0:3 * 3)

#[1] "double"



10L - 0:3 * 3L

#[1] 10  7  4  1

answered Nov 22 at 15:29

snoram

6,009830

add a comment |

up vote
0
down vote

10 - 0:3 * 3

#[1] 10  7  4  1

Or to get integers (not floating point numbers) out:

typeof(10 - 0:3 * 3)

#[1] "double"



10L - 0:3 * 3L

#[1] 10  7  4  1

answered Nov 22 at 15:29

snoram

6,009830

add a comment |

up vote
0
down vote

10 - 0:3 * 3

#[1] 10  7  4  1

Or to get integers (not floating point numbers) out:

typeof(10 - 0:3 * 3)

#[1] "double"



10L - 0:3 * 3L

#[1] 10  7  4  1

answered Nov 22 at 15:29

snoram

6,009830

10 - 0:3 * 3

#[1] 10  7  4  1

Or to get integers (not floating point numbers) out:

typeof(10 - 0:3 * 3)

#[1] "double"



10L - 0:3 * 3L

#[1] 10  7  4  1

answered Nov 22 at 15:29

snoram

6,009830

answered Nov 22 at 15:29

snoram

6,009830

answered Nov 22 at 15:29

snoram

6,009830

answered Nov 22 at 15:29

snoram

6,009830

add a comment |

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