Custom ranking based on multiple criteria in Rails











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0
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I need to rank records in a database table based on two columns:




availability_date




and




updated_at




They're both datetime-type columns, but the conditions for ranking are not linear in time. So, for example, in a scale of 0 to 10, 'updated_at' values:



between 14 and 30 days ago would get a 10,



whereas 13 to 9 days ago would get 9.5,



31 to 60 would get 9,



etc.



The same applies to the 'availability_date' column.



The final ranking/ordering result should be the average of values of both scales for each record.



I'm trying to write that logic in a controller and ideally wanted to avoid adding columns in the database to build the indexes.



I'm using Ruby 2.5.1 and Rails 5.2.



Does anyone know if that's feasible?



Thanks a lot in advance.










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  • Do you want to do it in a single SQL/NON SQL request ? If so what database are you using ?
    – LolWalid
    Nov 22 at 15:46










  • Yes, it should be in a single request. I'm using a MySQL 8.0 database.
    – Johnny
    Nov 22 at 15:52















up vote
0
down vote

favorite












I need to rank records in a database table based on two columns:




availability_date




and




updated_at




They're both datetime-type columns, but the conditions for ranking are not linear in time. So, for example, in a scale of 0 to 10, 'updated_at' values:



between 14 and 30 days ago would get a 10,



whereas 13 to 9 days ago would get 9.5,



31 to 60 would get 9,



etc.



The same applies to the 'availability_date' column.



The final ranking/ordering result should be the average of values of both scales for each record.



I'm trying to write that logic in a controller and ideally wanted to avoid adding columns in the database to build the indexes.



I'm using Ruby 2.5.1 and Rails 5.2.



Does anyone know if that's feasible?



Thanks a lot in advance.










share|improve this question






















  • Do you want to do it in a single SQL/NON SQL request ? If so what database are you using ?
    – LolWalid
    Nov 22 at 15:46










  • Yes, it should be in a single request. I'm using a MySQL 8.0 database.
    – Johnny
    Nov 22 at 15:52













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I need to rank records in a database table based on two columns:




availability_date




and




updated_at




They're both datetime-type columns, but the conditions for ranking are not linear in time. So, for example, in a scale of 0 to 10, 'updated_at' values:



between 14 and 30 days ago would get a 10,



whereas 13 to 9 days ago would get 9.5,



31 to 60 would get 9,



etc.



The same applies to the 'availability_date' column.



The final ranking/ordering result should be the average of values of both scales for each record.



I'm trying to write that logic in a controller and ideally wanted to avoid adding columns in the database to build the indexes.



I'm using Ruby 2.5.1 and Rails 5.2.



Does anyone know if that's feasible?



Thanks a lot in advance.










share|improve this question













I need to rank records in a database table based on two columns:




availability_date




and




updated_at




They're both datetime-type columns, but the conditions for ranking are not linear in time. So, for example, in a scale of 0 to 10, 'updated_at' values:



between 14 and 30 days ago would get a 10,



whereas 13 to 9 days ago would get 9.5,



31 to 60 would get 9,



etc.



The same applies to the 'availability_date' column.



The final ranking/ordering result should be the average of values of both scales for each record.



I'm trying to write that logic in a controller and ideally wanted to avoid adding columns in the database to build the indexes.



I'm using Ruby 2.5.1 and Rails 5.2.



Does anyone know if that's feasible?



Thanks a lot in advance.







ruby-on-rails ranking






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share|improve this question











share|improve this question




share|improve this question










asked Nov 22 at 15:30









Johnny

155




155












  • Do you want to do it in a single SQL/NON SQL request ? If so what database are you using ?
    – LolWalid
    Nov 22 at 15:46










  • Yes, it should be in a single request. I'm using a MySQL 8.0 database.
    – Johnny
    Nov 22 at 15:52


















  • Do you want to do it in a single SQL/NON SQL request ? If so what database are you using ?
    – LolWalid
    Nov 22 at 15:46










  • Yes, it should be in a single request. I'm using a MySQL 8.0 database.
    – Johnny
    Nov 22 at 15:52
















Do you want to do it in a single SQL/NON SQL request ? If so what database are you using ?
– LolWalid
Nov 22 at 15:46




Do you want to do it in a single SQL/NON SQL request ? If so what database are you using ?
– LolWalid
Nov 22 at 15:46












Yes, it should be in a single request. I'm using a MySQL 8.0 database.
– Johnny
Nov 22 at 15:52




Yes, it should be in a single request. I'm using a MySQL 8.0 database.
– Johnny
Nov 22 at 15:52












1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










As your question currently stands, of course it is feasible. Try using sort_by, where you give a block specifying how to sort your data.



In this block you should write exactly the logic you are stating: translate the date to a value depending on how old it is and getting the average of those two values.



I can imagine something like:



def date_to_val(date)
days_ago = (Time.now - date).to_i / 1.day
return 10 if days_ago.between?(14, 30)
return 9.5 if days_ago.between?(9, 13)
return 9 if days_ago.between?(31, 60)
# and so on
end

def my_controller_action
@records = SomeClass.where(some_attr: some_val)
ordered = @records.sort_by do |e|
[
date_to_val(e.created_at),
date_to_val(e.availability_date)
].sum / 2.0
end
# do something with ordered
end


Now, if you want to do it purely with SQL queries, then that is another question.






share|improve this answer





















  • That's exactly what I was looking for. Thank you so much.
    – Johnny
    Nov 22 at 16:03











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










As your question currently stands, of course it is feasible. Try using sort_by, where you give a block specifying how to sort your data.



In this block you should write exactly the logic you are stating: translate the date to a value depending on how old it is and getting the average of those two values.



I can imagine something like:



def date_to_val(date)
days_ago = (Time.now - date).to_i / 1.day
return 10 if days_ago.between?(14, 30)
return 9.5 if days_ago.between?(9, 13)
return 9 if days_ago.between?(31, 60)
# and so on
end

def my_controller_action
@records = SomeClass.where(some_attr: some_val)
ordered = @records.sort_by do |e|
[
date_to_val(e.created_at),
date_to_val(e.availability_date)
].sum / 2.0
end
# do something with ordered
end


Now, if you want to do it purely with SQL queries, then that is another question.






share|improve this answer





















  • That's exactly what I was looking for. Thank you so much.
    – Johnny
    Nov 22 at 16:03















up vote
2
down vote



accepted










As your question currently stands, of course it is feasible. Try using sort_by, where you give a block specifying how to sort your data.



In this block you should write exactly the logic you are stating: translate the date to a value depending on how old it is and getting the average of those two values.



I can imagine something like:



def date_to_val(date)
days_ago = (Time.now - date).to_i / 1.day
return 10 if days_ago.between?(14, 30)
return 9.5 if days_ago.between?(9, 13)
return 9 if days_ago.between?(31, 60)
# and so on
end

def my_controller_action
@records = SomeClass.where(some_attr: some_val)
ordered = @records.sort_by do |e|
[
date_to_val(e.created_at),
date_to_val(e.availability_date)
].sum / 2.0
end
# do something with ordered
end


Now, if you want to do it purely with SQL queries, then that is another question.






share|improve this answer





















  • That's exactly what I was looking for. Thank you so much.
    – Johnny
    Nov 22 at 16:03













up vote
2
down vote



accepted







up vote
2
down vote



accepted






As your question currently stands, of course it is feasible. Try using sort_by, where you give a block specifying how to sort your data.



In this block you should write exactly the logic you are stating: translate the date to a value depending on how old it is and getting the average of those two values.



I can imagine something like:



def date_to_val(date)
days_ago = (Time.now - date).to_i / 1.day
return 10 if days_ago.between?(14, 30)
return 9.5 if days_ago.between?(9, 13)
return 9 if days_ago.between?(31, 60)
# and so on
end

def my_controller_action
@records = SomeClass.where(some_attr: some_val)
ordered = @records.sort_by do |e|
[
date_to_val(e.created_at),
date_to_val(e.availability_date)
].sum / 2.0
end
# do something with ordered
end


Now, if you want to do it purely with SQL queries, then that is another question.






share|improve this answer












As your question currently stands, of course it is feasible. Try using sort_by, where you give a block specifying how to sort your data.



In this block you should write exactly the logic you are stating: translate the date to a value depending on how old it is and getting the average of those two values.



I can imagine something like:



def date_to_val(date)
days_ago = (Time.now - date).to_i / 1.day
return 10 if days_ago.between?(14, 30)
return 9.5 if days_ago.between?(9, 13)
return 9 if days_ago.between?(31, 60)
# and so on
end

def my_controller_action
@records = SomeClass.where(some_attr: some_val)
ordered = @records.sort_by do |e|
[
date_to_val(e.created_at),
date_to_val(e.availability_date)
].sum / 2.0
end
# do something with ordered
end


Now, if you want to do it purely with SQL queries, then that is another question.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 22 at 15:52









byrdEmmanuel

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  • That's exactly what I was looking for. Thank you so much.
    – Johnny
    Nov 22 at 16:03


















  • That's exactly what I was looking for. Thank you so much.
    – Johnny
    Nov 22 at 16:03
















That's exactly what I was looking for. Thank you so much.
– Johnny
Nov 22 at 16:03




That's exactly what I was looking for. Thank you so much.
– Johnny
Nov 22 at 16:03


















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