Variable inside regular expression php
up vote
6
down vote
favorite
I a stuck with regular expression and i need help.
So basically i want to do somethning like this:
$data = "hi";
$number = 4;
$reg = '/^[a-z"]{1,4}$/';
if(preg_match($reg,$data)) {
echo 'Match';
}else {
echo 'No match';
}
But i want to use variable
$reg = '/^[a-z"]{1, variable here }$/';
I have tried:
$reg = '/^[a-z"]{1, '. $number .'}$/';
$reg = "/^[a-z"]{1, $number}$/";
But not getting right result.
Tnx for help
php regex variables
asked Sep 12 '14 at 17:51
EstSiim
124129
add a comment |
up vote
6
down vote
favorite
I a stuck with regular expression and i need help.
So basically i want to do somethning like this:
$data = "hi";
$number = 4;
$reg = '/^[a-z"]{1,4}$/';
if(preg_match($reg,$data)) {
echo 'Match';
}else {
echo 'No match';
}
But i want to use variable
$reg = '/^[a-z"]{1, variable here }$/';
I have tried:
$reg = '/^[a-z"]{1, '. $number .'}$/';
$reg = "/^[a-z"]{1, $number}$/";
But not getting right result.
Tnx for help
php regex variables
asked Sep 12 '14 at 17:51
EstSiim
124129
1
In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.
– Alex W
Sep 12 '14 at 17:54
3
@AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add$numbervia.operator
– Drecker
Sep 12 '14 at 18:00
1
@Drecker I was referring to the example above that. Where he putvariable here.
– Alex W
Sep 12 '14 at 18:01
add a comment |
up vote
6
down vote
favorite
up vote
6
down vote
favorite
I a stuck with regular expression and i need help.
So basically i want to do somethning like this:
$data = "hi";
$number = 4;
$reg = '/^[a-z"]{1,4}$/';
if(preg_match($reg,$data)) {
echo 'Match';
}else {
echo 'No match';
}
But i want to use variable
$reg = '/^[a-z"]{1, variable here }$/';
I have tried:
$reg = '/^[a-z"]{1, '. $number .'}$/';
$reg = "/^[a-z"]{1, $number}$/";
But not getting right result.
Tnx for help
php regex variables
asked Sep 12 '14 at 17:51
EstSiim
124129
I a stuck with regular expression and i need help.
So basically i want to do somethning like this:
$data = "hi";
$number = 4;
$reg = '/^[a-z"]{1,4}$/';
if(preg_match($reg,$data)) {
echo 'Match';
}else {
echo 'No match';
}
But i want to use variable
$reg = '/^[a-z"]{1, variable here }$/';
I have tried:
$reg = '/^[a-z"]{1, '. $number .'}$/';
$reg = "/^[a-z"]{1, $number}$/";
But not getting right result.
Tnx for help
php regex variables
php regex variables
asked Sep 12 '14 at 17:51
EstSiim
124129
asked Sep 12 '14 at 17:51
EstSiim
124129
asked Sep 12 '14 at 17:51
EstSiim
124129
asked Sep 12 '14 at 17:51
EstSiim
124129
asked Sep 12 '14 at 17:51
EstSiim
124129
124129
1
In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.
– Alex W
Sep 12 '14 at 17:54
3
@AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add$numbervia.operator
– Drecker
Sep 12 '14 at 18:00
1
@Drecker I was referring to the example above that. Where he putvariable here.
– Alex W
Sep 12 '14 at 18:01
add a comment |
1
In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.
– Alex W
Sep 12 '14 at 17:54
3
@AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add$numbervia.operator
– Drecker
Sep 12 '14 at 18:00
1
@Drecker I was referring to the example above that. Where he putvariable here.
– Alex W
Sep 12 '14 at 18:01
1
1
In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.
– Alex W
Sep 12 '14 at 17:54
In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.
– Alex W
Sep 12 '14 at 17:54
3
3
@AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add
$number via . operator– Drecker
Sep 12 '14 at 18:00
@AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add
$number via . operator– Drecker
Sep 12 '14 at 18:00
1
1
@Drecker I was referring to the example above that. Where he put
variable here.– Alex W
Sep 12 '14 at 18:01
@Drecker I was referring to the example above that. Where he put
variable here.– Alex W
Sep 12 '14 at 18:01
add a comment |
2 Answers
2
active
oldest
votes
up vote
16
down vote
accepted
In the first example you have space where you shouldn't have one,
you have:
$reg = '/^[a-z"]{1, '. $number .'}$/';
your should have:
$reg = '/^[a-z"]{1,'. $number .'}$/';
then it works just fine
Update: You have same error in second example - thanks to AbraCadaver
answered Sep 12 '14 at 17:57
Drecker
411417
@AbraCadaver - thanks, i've edited answer so it will be more visible
– Drecker
Sep 12 '14 at 18:03
add a comment |
up vote
1
down vote
Another way to use variables in regex is through the use of sprintf.
For example:
$nonWhiteSpace = "^s";
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
var_dump($pattern); //gives you /[^s]{1,10}/
edited Dec 21 '17 at 17:29
sintakonte
3,86941229
answered Dec 21 '17 at 17:10
cbernard73
112
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
16
down vote
accepted
In the first example you have space where you shouldn't have one,
you have:
$reg = '/^[a-z"]{1, '. $number .'}$/';
your should have:
$reg = '/^[a-z"]{1,'. $number .'}$/';
then it works just fine
Update: You have same error in second example - thanks to AbraCadaver
answered Sep 12 '14 at 17:57
Drecker
411417
@AbraCadaver - thanks, i've edited answer so it will be more visible
– Drecker
Sep 12 '14 at 18:03
add a comment |
up vote
16
down vote
accepted
In the first example you have space where you shouldn't have one,
you have:
$reg = '/^[a-z"]{1, '. $number .'}$/';
your should have:
$reg = '/^[a-z"]{1,'. $number .'}$/';
then it works just fine
Update: You have same error in second example - thanks to AbraCadaver
answered Sep 12 '14 at 17:57
Drecker
411417
@AbraCadaver - thanks, i've edited answer so it will be more visible
– Drecker
Sep 12 '14 at 18:03
add a comment |
up vote
16
down vote
accepted
up vote
16
down vote
accepted
In the first example you have space where you shouldn't have one,
you have:
$reg = '/^[a-z"]{1, '. $number .'}$/';
your should have:
$reg = '/^[a-z"]{1,'. $number .'}$/';
then it works just fine
Update: You have same error in second example - thanks to AbraCadaver
answered Sep 12 '14 at 17:57
Drecker
411417
In the first example you have space where you shouldn't have one,
you have:
$reg = '/^[a-z"]{1, '. $number .'}$/';
your should have:
$reg = '/^[a-z"]{1,'. $number .'}$/';
then it works just fine
Update: You have same error in second example - thanks to AbraCadaver
answered Sep 12 '14 at 17:57
Drecker
411417
answered Sep 12 '14 at 17:57
Drecker
411417
answered Sep 12 '14 at 17:57
Drecker
411417
answered Sep 12 '14 at 17:57
Drecker
411417
411417
@AbraCadaver - thanks, i've edited answer so it will be more visible
– Drecker
Sep 12 '14 at 18:03
add a comment |
@AbraCadaver - thanks, i've edited answer so it will be more visible
– Drecker
Sep 12 '14 at 18:03
@AbraCadaver - thanks, i've edited answer so it will be more visible
– Drecker
Sep 12 '14 at 18:03
@AbraCadaver - thanks, i've edited answer so it will be more visible
– Drecker
Sep 12 '14 at 18:03
add a comment |
up vote
1
down vote
Another way to use variables in regex is through the use of sprintf.
For example:
$nonWhiteSpace = "^s";
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
var_dump($pattern); //gives you /[^s]{1,10}/
edited Dec 21 '17 at 17:29
sintakonte
3,86941229
answered Dec 21 '17 at 17:10
cbernard73
112
add a comment |
up vote
1
down vote
Another way to use variables in regex is through the use of sprintf.
For example:
$nonWhiteSpace = "^s";
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
var_dump($pattern); //gives you /[^s]{1,10}/
edited Dec 21 '17 at 17:29
sintakonte
3,86941229
answered Dec 21 '17 at 17:10
cbernard73
112
add a comment |
up vote
1
down vote
up vote
1
down vote
Another way to use variables in regex is through the use of sprintf.
For example:
$nonWhiteSpace = "^s";
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
var_dump($pattern); //gives you /[^s]{1,10}/
edited Dec 21 '17 at 17:29
sintakonte
3,86941229
answered Dec 21 '17 at 17:10
cbernard73
112
Another way to use variables in regex is through the use of sprintf.
For example:
$nonWhiteSpace = "^s";
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
var_dump($pattern); //gives you /[^s]{1,10}/
edited Dec 21 '17 at 17:29
sintakonte
3,86941229
answered Dec 21 '17 at 17:10
cbernard73
112
edited Dec 21 '17 at 17:29
sintakonte
3,86941229
edited Dec 21 '17 at 17:29
sintakonte
3,86941229
edited Dec 21 '17 at 17:29
sintakonte
3,86941229
3,86941229
answered Dec 21 '17 at 17:10
cbernard73
112
answered Dec 21 '17 at 17:10
cbernard73
112
answered Dec 21 '17 at 17:10
cbernard73
112
112
add a comment |
add a comment |
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1
In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.
– Alex W
Sep 12 '14 at 17:54
3
@AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add
$numbervia.operator– Drecker
Sep 12 '14 at 18:00
1
@Drecker I was referring to the example above that. Where he put
variable here.– Alex W
Sep 12 '14 at 18:01