Two parallel wires with no resistance - why it's wrong?











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I've built the scheme below in circuit simulator and it didn't work because of "wire loop" mistake. Why it's wrong? Why it's wrong physically?



The simulator is falstad.com/circuit



enter image description here






parallel loop







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  • 7




    Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
    – Andy aka
    8 hours ago






  • 1




    Which simulator? It might just be upset that it can't determine how much current flows through each wire.
    – The Photon
    8 hours ago










  • @Andyaka why it doesn't work in a simulator?
    – Артур Клочко
    8 hours ago










  • @ThePhoton falstad
    – Артур Клочко
    8 hours ago






  • 2




    Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
    – TimWescott
    7 hours ago















up vote
2
down vote

favorite












I've built the scheme below in circuit simulator and it didn't work because of "wire loop" mistake. Why it's wrong? Why it's wrong physically?



The simulator is falstad.com/circuit



enter image description here






parallel loop







share|improve this question









New contributor




Артур Клочко is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 7




    Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
    – Andy aka
    8 hours ago






  • 1




    Which simulator? It might just be upset that it can't determine how much current flows through each wire.
    – The Photon
    8 hours ago










  • @Andyaka why it doesn't work in a simulator?
    – Артур Клочко
    8 hours ago










  • @ThePhoton falstad
    – Артур Клочко
    8 hours ago






  • 2




    Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
    – TimWescott
    7 hours ago













up vote
2
down vote

favorite









up vote
2
down vote

favorite











I've built the scheme below in circuit simulator and it didn't work because of "wire loop" mistake. Why it's wrong? Why it's wrong physically?



The simulator is falstad.com/circuit



enter image description here






parallel loop







share|improve this question









New contributor




Артур Клочко is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I've built the scheme below in circuit simulator and it didn't work because of "wire loop" mistake. Why it's wrong? Why it's wrong physically?



The simulator is falstad.com/circuit



enter image description here






parallel loop




parallel loop






share|improve this question









New contributor




Артур Клочко is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Артур Клочко is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 8 hours ago





















New contributor




Артур Клочко is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 8 hours ago









Артур Клочко

1133




1133




New contributor




Артур Клочко is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Артур Клочко is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Артур Клочко is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 7




    Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
    – Andy aka
    8 hours ago






  • 1




    Which simulator? It might just be upset that it can't determine how much current flows through each wire.
    – The Photon
    8 hours ago










  • @Andyaka why it doesn't work in a simulator?
    – Артур Клочко
    8 hours ago










  • @ThePhoton falstad
    – Артур Клочко
    8 hours ago






  • 2




    Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
    – TimWescott
    7 hours ago














  • 7




    Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
    – Andy aka
    8 hours ago






  • 1




    Which simulator? It might just be upset that it can't determine how much current flows through each wire.
    – The Photon
    8 hours ago










  • @Andyaka why it doesn't work in a simulator?
    – Артур Клочко
    8 hours ago










  • @ThePhoton falstad
    – Артур Клочко
    8 hours ago






  • 2




    Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
    – TimWescott
    7 hours ago








7




7




Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
– Andy aka
8 hours ago




Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
– Andy aka
8 hours ago




1




1




Which simulator? It might just be upset that it can't determine how much current flows through each wire.
– The Photon
8 hours ago




Which simulator? It might just be upset that it can't determine how much current flows through each wire.
– The Photon
8 hours ago












@Andyaka why it doesn't work in a simulator?
– Артур Клочко
8 hours ago




@Andyaka why it doesn't work in a simulator?
– Артур Клочко
8 hours ago












@ThePhoton falstad
– Артур Клочко
8 hours ago




@ThePhoton falstad
– Артур Клочко
8 hours ago




2




2




Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
– TimWescott
7 hours ago




Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
– TimWescott
7 hours ago










2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










Falstad wants to be able to animate the circuit, showing how much current flows in each wire.



In this circuit, that isn't possible, so it is indicating this as an error.






share|improve this answer





















  • I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
    – Артур Клочко
    7 hours ago






  • 1




    The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
    – The Photon
    7 hours ago






  • 1




    @АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
    – Ale..chenski
    7 hours ago


















up vote
4
down vote














Two parallel wires with no resistance - why it's wrong?




This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.






share|improve this answer





















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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote



    accepted










    Falstad wants to be able to animate the circuit, showing how much current flows in each wire.



    In this circuit, that isn't possible, so it is indicating this as an error.






    share|improve this answer





















    • I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
      – Артур Клочко
      7 hours ago






    • 1




      The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
      – The Photon
      7 hours ago






    • 1




      @АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
      – Ale..chenski
      7 hours ago















    up vote
    3
    down vote



    accepted










    Falstad wants to be able to animate the circuit, showing how much current flows in each wire.



    In this circuit, that isn't possible, so it is indicating this as an error.






    share|improve this answer





















    • I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
      – Артур Клочко
      7 hours ago






    • 1




      The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
      – The Photon
      7 hours ago






    • 1




      @АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
      – Ale..chenski
      7 hours ago













    up vote
    3
    down vote



    accepted







    up vote
    3
    down vote



    accepted






    Falstad wants to be able to animate the circuit, showing how much current flows in each wire.



    In this circuit, that isn't possible, so it is indicating this as an error.






    share|improve this answer












    Falstad wants to be able to animate the circuit, showing how much current flows in each wire.



    In this circuit, that isn't possible, so it is indicating this as an error.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 7 hours ago









    The Photon

    82.1k396193




    82.1k396193












    • I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
      – Артур Клочко
      7 hours ago






    • 1




      The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
      – The Photon
      7 hours ago






    • 1




      @АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
      – Ale..chenski
      7 hours ago


















    • I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
      – Артур Клочко
      7 hours ago






    • 1




      The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
      – The Photon
      7 hours ago






    • 1




      @АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
      – Ale..chenski
      7 hours ago
















    I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
    – Артур Клочко
    7 hours ago




    I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
    – Артур Клочко
    7 hours ago




    1




    1




    The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
    – The Photon
    7 hours ago




    The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
    – The Photon
    7 hours ago




    1




    1




    @АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
    – Ale..chenski
    7 hours ago




    @АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
    – Ale..chenski
    7 hours ago












    up vote
    4
    down vote














    Two parallel wires with no resistance - why it's wrong?




    This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.






    share|improve this answer

























      up vote
      4
      down vote














      Two parallel wires with no resistance - why it's wrong?




      This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.






      share|improve this answer























        up vote
        4
        down vote










        up vote
        4
        down vote










        Two parallel wires with no resistance - why it's wrong?




        This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.






        share|improve this answer













        Two parallel wires with no resistance - why it's wrong?




        This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 7 hours ago









        Ale..chenski

        25.9k11860




        25.9k11860






















            Артур Клочко is a new contributor. Be nice, and check out our Code of Conduct.










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