Two parallel wires with no resistance - why it's wrong?
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I've built the scheme below in circuit simulator and it didn't work because of "wire loop" mistake. Why it's wrong? Why it's wrong physically?
The simulator is falstad.com/circuit
parallel loop
New contributor
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show 5 more comments
up vote
2
down vote
favorite
I've built the scheme below in circuit simulator and it didn't work because of "wire loop" mistake. Why it's wrong? Why it's wrong physically?
The simulator is falstad.com/circuit
parallel loop
New contributor
7
Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
– Andy aka
8 hours ago
1
Which simulator? It might just be upset that it can't determine how much current flows through each wire.
– The Photon
8 hours ago
@Andyaka why it doesn't work in a simulator?
– Артур Клочко
8 hours ago
@ThePhoton falstad
– Артур Клочко
8 hours ago
2
Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
– TimWescott
7 hours ago
|
show 5 more comments
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I've built the scheme below in circuit simulator and it didn't work because of "wire loop" mistake. Why it's wrong? Why it's wrong physically?
The simulator is falstad.com/circuit
parallel loop
New contributor
I've built the scheme below in circuit simulator and it didn't work because of "wire loop" mistake. Why it's wrong? Why it's wrong physically?
The simulator is falstad.com/circuit
parallel loop
parallel loop
New contributor
New contributor
edited 8 hours ago
New contributor
asked 8 hours ago
Артур Клочко
1133
1133
New contributor
New contributor
7
Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
– Andy aka
8 hours ago
1
Which simulator? It might just be upset that it can't determine how much current flows through each wire.
– The Photon
8 hours ago
@Andyaka why it doesn't work in a simulator?
– Артур Клочко
8 hours ago
@ThePhoton falstad
– Артур Клочко
8 hours ago
2
Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
– TimWescott
7 hours ago
|
show 5 more comments
7
Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
– Andy aka
8 hours ago
1
Which simulator? It might just be upset that it can't determine how much current flows through each wire.
– The Photon
8 hours ago
@Andyaka why it doesn't work in a simulator?
– Артур Клочко
8 hours ago
@ThePhoton falstad
– Артур Клочко
8 hours ago
2
Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
– TimWescott
7 hours ago
7
7
Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
– Andy aka
8 hours ago
Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
– Andy aka
8 hours ago
1
1
Which simulator? It might just be upset that it can't determine how much current flows through each wire.
– The Photon
8 hours ago
Which simulator? It might just be upset that it can't determine how much current flows through each wire.
– The Photon
8 hours ago
@Andyaka why it doesn't work in a simulator?
– Артур Клочко
8 hours ago
@Andyaka why it doesn't work in a simulator?
– Артур Клочко
8 hours ago
@ThePhoton falstad
– Артур Клочко
8 hours ago
@ThePhoton falstad
– Артур Клочко
8 hours ago
2
2
Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
– TimWescott
7 hours ago
Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
– TimWescott
7 hours ago
|
show 5 more comments
2 Answers
2
active
oldest
votes
up vote
3
down vote
accepted
Falstad wants to be able to animate the circuit, showing how much current flows in each wire.
In this circuit, that isn't possible, so it is indicating this as an error.
I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
– Артур Клочко
7 hours ago
1
The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
– The Photon
7 hours ago
1
@АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
– Ale..chenski
7 hours ago
add a comment |
up vote
4
down vote
Two parallel wires with no resistance - why it's wrong?
This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
Falstad wants to be able to animate the circuit, showing how much current flows in each wire.
In this circuit, that isn't possible, so it is indicating this as an error.
I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
– Артур Клочко
7 hours ago
1
The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
– The Photon
7 hours ago
1
@АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
– Ale..chenski
7 hours ago
add a comment |
up vote
3
down vote
accepted
Falstad wants to be able to animate the circuit, showing how much current flows in each wire.
In this circuit, that isn't possible, so it is indicating this as an error.
I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
– Артур Клочко
7 hours ago
1
The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
– The Photon
7 hours ago
1
@АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
– Ale..chenski
7 hours ago
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
Falstad wants to be able to animate the circuit, showing how much current flows in each wire.
In this circuit, that isn't possible, so it is indicating this as an error.
Falstad wants to be able to animate the circuit, showing how much current flows in each wire.
In this circuit, that isn't possible, so it is indicating this as an error.
answered 7 hours ago
The Photon
82.1k396193
82.1k396193
I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
– Артур Клочко
7 hours ago
1
The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
– The Photon
7 hours ago
1
@АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
– Ale..chenski
7 hours ago
add a comment |
I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
– Артур Клочко
7 hours ago
1
The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
– The Photon
7 hours ago
1
@АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
– Ale..chenski
7 hours ago
I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
– Артур Клочко
7 hours ago
I meant 100 Omhs, and it's not about wires, it's about resistor, that is near upper potential point. In real life, how much current will flow through one of parallel wire?
– Артур Клочко
7 hours ago
1
1
The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
– The Photon
7 hours ago
The total current between the two wires will be whatever the supply voltage is divided by 100 ohms. But you can't tell how much will flow through one wire and how much through the other. That's the whole problem.
– The Photon
7 hours ago
1
1
@АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
– Ale..chenski
7 hours ago
@АртурКлочко, in real life the current will be split in inverse proportion to real-life impedance of each wire, be this in micro-Ohms or else.
– Ale..chenski
7 hours ago
add a comment |
up vote
4
down vote
Two parallel wires with no resistance - why it's wrong?
This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.
add a comment |
up vote
4
down vote
Two parallel wires with no resistance - why it's wrong?
This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.
add a comment |
up vote
4
down vote
up vote
4
down vote
Two parallel wires with no resistance - why it's wrong?
This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.
Two parallel wires with no resistance - why it's wrong?
This is wrong because there are no wires with no resistance. When trying to resolve Kirchhoff equations for this loop (or whatever their algorithm is), the simulator would run into division by zero exception. To avoid program crash, it likely analyzes these conditions and declares the circuit as error. Try to replace wires with resistors with micro-Ohms value (or maybe even less), it should be fine.
answered 7 hours ago
Ale..chenski
25.9k11860
25.9k11860
add a comment |
add a comment |
Артур Клочко is a new contributor. Be nice, and check out our Code of Conduct.
Артур Клочко is a new contributor. Be nice, and check out our Code of Conduct.
Артур Клочко is a new contributor. Be nice, and check out our Code of Conduct.
Артур Клочко is a new contributor. Be nice, and check out our Code of Conduct.
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7
Why something is wrong "physically" has little relationship to why a circuit won't work in a simulator.
– Andy aka
8 hours ago
1
Which simulator? It might just be upset that it can't determine how much current flows through each wire.
– The Photon
8 hours ago
@Andyaka why it doesn't work in a simulator?
– Артур Клочко
8 hours ago
@ThePhoton falstad
– Артур Клочко
8 hours ago
2
Circuit simulators deal with idealized wires, which have zero resistance (and zero inductance, and zero capacitance). To model a real-world circuit that looks like what you drew on paper, estimate the resistance of each wire and put resistors into each leg in the circuit simulator.
– TimWescott
7 hours ago