How to show/hide div when we select 'all' option
0
I have a small requirement. I need to show and hide divs based on the option selected. Below is my code. Ho to show all green and red class div's when I select 'all' option. It works for red and green options. Thanks in advance.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
<script type="text/javascript">
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
$('.' + $(this).val()).show();
});
});
</script>
.box{
color: #fff;
display: none;
margin-top: 20px;
}
.red{ background: #ff0000; }
.green{ background: #228B22; }jquery
edited Nov 24 '18 at 0:16
Makyen
20.4k83970
asked Nov 23 '18 at 12:21
MeggiMeggi
63
add a comment |
0
I have a small requirement. I need to show and hide divs based on the option selected. Below is my code. Ho to show all green and red class div's when I select 'all' option. It works for red and green options. Thanks in advance.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
<script type="text/javascript">
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
$('.' + $(this).val()).show();
});
});
</script>
.box{
color: #fff;
display: none;
margin-top: 20px;
}
.red{ background: #ff0000; }
.green{ background: #228B22; }jquery
edited Nov 24 '18 at 0:16
Makyen
20.4k83970
asked Nov 23 '18 at 12:21
MeggiMeggi
63
2
Possible duplicate of show/hide div based on select option jquery
– dippas
Nov 23 '18 at 12:25
To Close Voters: This is not a duplicate of the proposed duplicate. The proposed duplicate is, like this question, a debugging question. While the title of the proposed duplicate makes it seem like it might be a duplicate, the issues in the two questions are completely different.
– Makyen
Nov 24 '18 at 0:20
add a comment |
0
0
0
0
I have a small requirement. I need to show and hide divs based on the option selected. Below is my code. Ho to show all green and red class div's when I select 'all' option. It works for red and green options. Thanks in advance.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
<script type="text/javascript">
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
$('.' + $(this).val()).show();
});
});
</script>
.box{
color: #fff;
display: none;
margin-top: 20px;
}
.red{ background: #ff0000; }
.green{ background: #228B22; }jquery
edited Nov 24 '18 at 0:16
Makyen
20.4k83970
asked Nov 23 '18 at 12:21
MeggiMeggi
63
I have a small requirement. I need to show and hide divs based on the option selected. Below is my code. Ho to show all green and red class div's when I select 'all' option. It works for red and green options. Thanks in advance.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
<script type="text/javascript">
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
$('.' + $(this).val()).show();
});
});
</script>
.box{
color: #fff;
display: none;
margin-top: 20px;
}
.red{ background: #ff0000; }
.green{ background: #228B22; }<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
<script type="text/javascript">
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
$('.' + $(this).val()).show();
});
});
</script>
.box{
color: #fff;
display: none;
margin-top: 20px;
}
.red{ background: #ff0000; }
.green{ background: #228B22; }<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
<script type="text/javascript">
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
$('.' + $(this).val()).show();
});
});
</script>
.box{
color: #fff;
display: none;
margin-top: 20px;
}
.red{ background: #ff0000; }
.green{ background: #228B22; }jquery
jquery
edited Nov 24 '18 at 0:16
Makyen
20.4k83970
asked Nov 23 '18 at 12:21
MeggiMeggi
63
edited Nov 24 '18 at 0:16
Makyen
20.4k83970
asked Nov 23 '18 at 12:21
MeggiMeggi
63
edited Nov 24 '18 at 0:16
Makyen
20.4k83970
edited Nov 24 '18 at 0:16
Makyen
20.4k83970
edited Nov 24 '18 at 0:16
Makyen
20.4k83970
20.4k83970
asked Nov 23 '18 at 12:21
MeggiMeggi
63
asked Nov 23 '18 at 12:21
MeggiMeggi
63
asked Nov 23 '18 at 12:21
MeggiMeggi
63
63
2
Possible duplicate of show/hide div based on select option jquery
– dippas
Nov 23 '18 at 12:25
To Close Voters: This is not a duplicate of the proposed duplicate. The proposed duplicate is, like this question, a debugging question. While the title of the proposed duplicate makes it seem like it might be a duplicate, the issues in the two questions are completely different.
– Makyen
Nov 24 '18 at 0:20
add a comment |
2
Possible duplicate of show/hide div based on select option jquery
– dippas
Nov 23 '18 at 12:25
To Close Voters: This is not a duplicate of the proposed duplicate. The proposed duplicate is, like this question, a debugging question. While the title of the proposed duplicate makes it seem like it might be a duplicate, the issues in the two questions are completely different.
– Makyen
Nov 24 '18 at 0:20
2
2
Possible duplicate of show/hide div based on select option jquery
– dippas
Nov 23 '18 at 12:25
Possible duplicate of show/hide div based on select option jquery
– dippas
Nov 23 '18 at 12:25
To Close Voters: This is not a duplicate of the proposed duplicate. The proposed duplicate is, like this question, a debugging question. While the title of the proposed duplicate makes it seem like it might be a duplicate, the issues in the two questions are completely different.
– Makyen
Nov 24 '18 at 0:20
To Close Voters: This is not a duplicate of the proposed duplicate. The proposed duplicate is, like this question, a debugging question. While the title of the proposed duplicate makes it seem like it might be a duplicate, the issues in the two questions are completely different.
– Makyen
Nov 24 '18 at 0:20
add a comment |
3 Answers
3
active
oldest
votes
-1
Since you'll only have one "all" option, you can do an "if" to check if that option was pressed:
$(function() {
$('#colorselector').change(function(){
if($(this).val()=="all"){
$('.box').show();
}else{
$('.box').hide();
$('.' + $(this).val()).show();
}
});
});
answered Nov 23 '18 at 12:24
J. AlmandosJ. Almandos
1828
Thank you so much for your help, J. Almandos.
– Meggi
Nov 23 '18 at 12:31
add a comment |
1
Try this code:
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
Script:
<script type="text/javascript">
$(function() {
$('#colorselector').on('change', function() {
var data = $(this).val();
if( data =='red')
{
$('.green').hide();
$('.red').show();
}
else if($(this).val() =='green')
{
$('.green').show();
$('.red').hide();
}
else
{
$('.green').show();
$('.red').show();
}
});
});
</script>
answered Nov 23 '18 at 12:43
Bhoomi patelBhoomi patel
40016
Thanks for your time Bhoomi, but my question is different.
– Meggi
Nov 23 '18 at 12:47
check updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:55
When I select the Red option it shows only red class, the green option it shows only green class and when I select all option it should show both red and green classes.
– Meggi
Nov 23 '18 at 12:56
check my updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:58
Yes, it works Thank you Bhoomi. Here small change in your code -- if( data =='red') { $('.green').hide(); $('.red').show(); }
– Meggi
Nov 23 '18 at 12:59
add a comment |
0
Use an if statement to detect if the user is selecting 'all'. Please check the below code.
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
//if user is selecting 'all', show all boxes
if($(this).val() == 'all'){
$('.box').show()
//otherwise only show the color they select
} else {
$('.' + $(this).val()).show();
}
});
});
Here is a working JS Fiddle Example
answered Nov 23 '18 at 12:40
SheharaShehara
1013
Thank for your time Shehara.
– Meggi
Nov 23 '18 at 12:43
No problem, if it worked please select as the answer, thanks
– Shehara
Nov 23 '18 at 12:48
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
-1
Since you'll only have one "all" option, you can do an "if" to check if that option was pressed:
$(function() {
$('#colorselector').change(function(){
if($(this).val()=="all"){
$('.box').show();
}else{
$('.box').hide();
$('.' + $(this).val()).show();
}
});
});
answered Nov 23 '18 at 12:24
J. AlmandosJ. Almandos
1828
Thank you so much for your help, J. Almandos.
– Meggi
Nov 23 '18 at 12:31
add a comment |
-1
Since you'll only have one "all" option, you can do an "if" to check if that option was pressed:
$(function() {
$('#colorselector').change(function(){
if($(this).val()=="all"){
$('.box').show();
}else{
$('.box').hide();
$('.' + $(this).val()).show();
}
});
});
answered Nov 23 '18 at 12:24
J. AlmandosJ. Almandos
1828
Thank you so much for your help, J. Almandos.
– Meggi
Nov 23 '18 at 12:31
add a comment |
-1
-1
-1
Since you'll only have one "all" option, you can do an "if" to check if that option was pressed:
$(function() {
$('#colorselector').change(function(){
if($(this).val()=="all"){
$('.box').show();
}else{
$('.box').hide();
$('.' + $(this).val()).show();
}
});
});
answered Nov 23 '18 at 12:24
J. AlmandosJ. Almandos
1828
Since you'll only have one "all" option, you can do an "if" to check if that option was pressed:
$(function() {
$('#colorselector').change(function(){
if($(this).val()=="all"){
$('.box').show();
}else{
$('.box').hide();
$('.' + $(this).val()).show();
}
});
});
answered Nov 23 '18 at 12:24
J. AlmandosJ. Almandos
1828
answered Nov 23 '18 at 12:24
J. AlmandosJ. Almandos
1828
answered Nov 23 '18 at 12:24
J. AlmandosJ. Almandos
1828
answered Nov 23 '18 at 12:24
J. AlmandosJ. Almandos
1828
1828
Thank you so much for your help, J. Almandos.
– Meggi
Nov 23 '18 at 12:31
add a comment |
Thank you so much for your help, J. Almandos.
– Meggi
Nov 23 '18 at 12:31
Thank you so much for your help, J. Almandos.
– Meggi
Nov 23 '18 at 12:31
Thank you so much for your help, J. Almandos.
– Meggi
Nov 23 '18 at 12:31
add a comment |
1
Try this code:
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
Script:
<script type="text/javascript">
$(function() {
$('#colorselector').on('change', function() {
var data = $(this).val();
if( data =='red')
{
$('.green').hide();
$('.red').show();
}
else if($(this).val() =='green')
{
$('.green').show();
$('.red').hide();
}
else
{
$('.green').show();
$('.red').show();
}
});
});
</script>
answered Nov 23 '18 at 12:43
Bhoomi patelBhoomi patel
40016
Thanks for your time Bhoomi, but my question is different.
– Meggi
Nov 23 '18 at 12:47
check updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:55
When I select the Red option it shows only red class, the green option it shows only green class and when I select all option it should show both red and green classes.
– Meggi
Nov 23 '18 at 12:56
check my updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:58
Yes, it works Thank you Bhoomi. Here small change in your code -- if( data =='red') { $('.green').hide(); $('.red').show(); }
– Meggi
Nov 23 '18 at 12:59
add a comment |
1
Try this code:
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
Script:
<script type="text/javascript">
$(function() {
$('#colorselector').on('change', function() {
var data = $(this).val();
if( data =='red')
{
$('.green').hide();
$('.red').show();
}
else if($(this).val() =='green')
{
$('.green').show();
$('.red').hide();
}
else
{
$('.green').show();
$('.red').show();
}
});
});
</script>
answered Nov 23 '18 at 12:43
Bhoomi patelBhoomi patel
40016
Thanks for your time Bhoomi, but my question is different.
– Meggi
Nov 23 '18 at 12:47
check updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:55
When I select the Red option it shows only red class, the green option it shows only green class and when I select all option it should show both red and green classes.
– Meggi
Nov 23 '18 at 12:56
check my updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:58
Yes, it works Thank you Bhoomi. Here small change in your code -- if( data =='red') { $('.green').hide(); $('.red').show(); }
– Meggi
Nov 23 '18 at 12:59
add a comment |
1
1
1
Try this code:
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
Script:
<script type="text/javascript">
$(function() {
$('#colorselector').on('change', function() {
var data = $(this).val();
if( data =='red')
{
$('.green').hide();
$('.red').show();
}
else if($(this).val() =='green')
{
$('.green').show();
$('.red').hide();
}
else
{
$('.green').show();
$('.red').show();
}
});
});
</script>
answered Nov 23 '18 at 12:43
Bhoomi patelBhoomi patel
40016
Try this code:
<select id="colorselector">
<option>Choose Color</option>
<option value="all">All</option>
<option value="red">Red</option>
<option value="green">Green</option>
</select>
<div class="red box">You have selected <strong>red option</strong> so i am here</div>
<div class="green box">You have selected <strong>green option</strong> so i am here</div>
Script:
<script type="text/javascript">
$(function() {
$('#colorselector').on('change', function() {
var data = $(this).val();
if( data =='red')
{
$('.green').hide();
$('.red').show();
}
else if($(this).val() =='green')
{
$('.green').show();
$('.red').hide();
}
else
{
$('.green').show();
$('.red').show();
}
});
});
</script>
answered Nov 23 '18 at 12:43
Bhoomi patelBhoomi patel
40016
edited Nov 23 '18 at 13:01
answered Nov 23 '18 at 12:43
Bhoomi patelBhoomi patel
40016
answered Nov 23 '18 at 12:43
Bhoomi patelBhoomi patel
40016
answered Nov 23 '18 at 12:43
Bhoomi patelBhoomi patel
40016
40016
Thanks for your time Bhoomi, but my question is different.
– Meggi
Nov 23 '18 at 12:47
check updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:55
When I select the Red option it shows only red class, the green option it shows only green class and when I select all option it should show both red and green classes.
– Meggi
Nov 23 '18 at 12:56
check my updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:58
Yes, it works Thank you Bhoomi. Here small change in your code -- if( data =='red') { $('.green').hide(); $('.red').show(); }
– Meggi
Nov 23 '18 at 12:59
add a comment |
Thanks for your time Bhoomi, but my question is different.
– Meggi
Nov 23 '18 at 12:47
check updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:55
When I select the Red option it shows only red class, the green option it shows only green class and when I select all option it should show both red and green classes.
– Meggi
Nov 23 '18 at 12:56
check my updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:58
Yes, it works Thank you Bhoomi. Here small change in your code -- if( data =='red') { $('.green').hide(); $('.red').show(); }
– Meggi
Nov 23 '18 at 12:59
Thanks for your time Bhoomi, but my question is different.
– Meggi
Nov 23 '18 at 12:47
Thanks for your time Bhoomi, but my question is different.
– Meggi
Nov 23 '18 at 12:47
check updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:55
check updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:55
When I select the Red option it shows only red class, the green option it shows only green class and when I select all option it should show both red and green classes.
– Meggi
Nov 23 '18 at 12:56
When I select the Red option it shows only red class, the green option it shows only green class and when I select all option it should show both red and green classes.
– Meggi
Nov 23 '18 at 12:56
check my updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:58
check my updated answer@Meggi
– Bhoomi patel
Nov 23 '18 at 12:58
Yes, it works Thank you Bhoomi. Here small change in your code -- if( data =='red') { $('.green').hide(); $('.red').show(); }
– Meggi
Nov 23 '18 at 12:59
Yes, it works Thank you Bhoomi. Here small change in your code -- if( data =='red') { $('.green').hide(); $('.red').show(); }
– Meggi
Nov 23 '18 at 12:59
add a comment |
0
Use an if statement to detect if the user is selecting 'all'. Please check the below code.
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
//if user is selecting 'all', show all boxes
if($(this).val() == 'all'){
$('.box').show()
//otherwise only show the color they select
} else {
$('.' + $(this).val()).show();
}
});
});
Here is a working JS Fiddle Example
answered Nov 23 '18 at 12:40
SheharaShehara
1013
Thank for your time Shehara.
– Meggi
Nov 23 '18 at 12:43
No problem, if it worked please select as the answer, thanks
– Shehara
Nov 23 '18 at 12:48
add a comment |
0
Use an if statement to detect if the user is selecting 'all'. Please check the below code.
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
//if user is selecting 'all', show all boxes
if($(this).val() == 'all'){
$('.box').show()
//otherwise only show the color they select
} else {
$('.' + $(this).val()).show();
}
});
});
Here is a working JS Fiddle Example
answered Nov 23 '18 at 12:40
SheharaShehara
1013
Thank for your time Shehara.
– Meggi
Nov 23 '18 at 12:43
No problem, if it worked please select as the answer, thanks
– Shehara
Nov 23 '18 at 12:48
add a comment |
0
0
0
Use an if statement to detect if the user is selecting 'all'. Please check the below code.
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
//if user is selecting 'all', show all boxes
if($(this).val() == 'all'){
$('.box').show()
//otherwise only show the color they select
} else {
$('.' + $(this).val()).show();
}
});
});
Here is a working JS Fiddle Example
answered Nov 23 '18 at 12:40
SheharaShehara
1013
Use an if statement to detect if the user is selecting 'all'. Please check the below code.
$(function() {
$('#colorselector').change(function(){
$('.box').hide();
//if user is selecting 'all', show all boxes
if($(this).val() == 'all'){
$('.box').show()
//otherwise only show the color they select
} else {
$('.' + $(this).val()).show();
}
});
});
Here is a working JS Fiddle Example
answered Nov 23 '18 at 12:40
SheharaShehara
1013
answered Nov 23 '18 at 12:40
SheharaShehara
1013
answered Nov 23 '18 at 12:40
SheharaShehara
1013
answered Nov 23 '18 at 12:40
SheharaShehara
1013
1013
Thank for your time Shehara.
– Meggi
Nov 23 '18 at 12:43
No problem, if it worked please select as the answer, thanks
– Shehara
Nov 23 '18 at 12:48
add a comment |
Thank for your time Shehara.
– Meggi
Nov 23 '18 at 12:43
No problem, if it worked please select as the answer, thanks
– Shehara
Nov 23 '18 at 12:48
Thank for your time Shehara.
– Meggi
Nov 23 '18 at 12:43
Thank for your time Shehara.
– Meggi
Nov 23 '18 at 12:43
No problem, if it worked please select as the answer, thanks
– Shehara
Nov 23 '18 at 12:48
No problem, if it worked please select as the answer, thanks
– Shehara
Nov 23 '18 at 12:48
add a comment |
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2
Possible duplicate of show/hide div based on select option jquery
– dippas
Nov 23 '18 at 12:25
To Close Voters: This is not a duplicate of the proposed duplicate. The proposed duplicate is, like this question, a debugging question. While the title of the proposed duplicate makes it seem like it might be a duplicate, the issues in the two questions are completely different.
– Makyen
Nov 24 '18 at 0:20